Pandas dataframe narrow to wide with pivot table no aggregation









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I have a pandas dataframe that contains the iris dataset. I want to subset this dataframe to only include sepal_length and species, and then reshape it so that the columns are the unique values for species and the values are the values for that species.



# load data into a dataframe
df = pd.read_csv('https://raw.githubusercontent.com/mwaskom/seaborn-data/master/iris.csv')

head(df)
+----+---------------+--------------+---------------+--------------+---------+
| | sepal_length | sepal_width | petal_length | petal_width | species |
+----+---------------+--------------+---------------+--------------+---------+
| 0 | 5.1 | 3.5 | 1.4 | 0.2 | setosa |
| 1 | 4.9 | 3.0 | 1.4 | 0.2 | setosa |
| 2 | 4.7 | 3.2 | 1.3 | 0.2 | setosa |
| 3 | 4.6 | 3.1 | 1.5 | 0.2 | setosa |
| 4 | 5.0 | 3.6 | 1.4 | 0.2 | setosa |
+----+---------------+--------------+---------------+--------------+---------+


I can do this is I take the data out of Pandas as use a dictionary to reshape the data, but I can't figure out how to do it within pandas.



data = df.to_dict('records')

e =
for line in data:
e[line['species']] =

for line in data:
e[line['species']].append(line['sepal_length'])

new = pd.DataFrame(e)


This is what I want to end up with:



+----+---------+-------------+-----------+
| | setosa | versicolor | virginica |
+----+---------+-------------+-----------+
| 0 | 5.1 | 7.0 | 6.3 |
| 1 | 4.9 | 6.4 | 5.8 |
| 2 | 4.7 | 6.9 | 7.1 |
| 3 | 4.6 | 5.5 | 6.3 |
| 4 | 5.0 | 6.5 | 6.5 |
+----+---------+-------------+-----------+


I've tried using pd.crosstab(df['sepal_length'], df['species']) but that doesn't get me what I want. I've also tried using df.pivot_table('sepal_length', columns='species') and that also isn't it.



What am I missing here?










share|improve this question



















  • 2




    What does the initial dataframe look like?
    – today
    Nov 11 at 20:14














up vote
2
down vote

favorite
1












I have a pandas dataframe that contains the iris dataset. I want to subset this dataframe to only include sepal_length and species, and then reshape it so that the columns are the unique values for species and the values are the values for that species.



# load data into a dataframe
df = pd.read_csv('https://raw.githubusercontent.com/mwaskom/seaborn-data/master/iris.csv')

head(df)
+----+---------------+--------------+---------------+--------------+---------+
| | sepal_length | sepal_width | petal_length | petal_width | species |
+----+---------------+--------------+---------------+--------------+---------+
| 0 | 5.1 | 3.5 | 1.4 | 0.2 | setosa |
| 1 | 4.9 | 3.0 | 1.4 | 0.2 | setosa |
| 2 | 4.7 | 3.2 | 1.3 | 0.2 | setosa |
| 3 | 4.6 | 3.1 | 1.5 | 0.2 | setosa |
| 4 | 5.0 | 3.6 | 1.4 | 0.2 | setosa |
+----+---------------+--------------+---------------+--------------+---------+


I can do this is I take the data out of Pandas as use a dictionary to reshape the data, but I can't figure out how to do it within pandas.



data = df.to_dict('records')

e =
for line in data:
e[line['species']] =

for line in data:
e[line['species']].append(line['sepal_length'])

new = pd.DataFrame(e)


This is what I want to end up with:



+----+---------+-------------+-----------+
| | setosa | versicolor | virginica |
+----+---------+-------------+-----------+
| 0 | 5.1 | 7.0 | 6.3 |
| 1 | 4.9 | 6.4 | 5.8 |
| 2 | 4.7 | 6.9 | 7.1 |
| 3 | 4.6 | 5.5 | 6.3 |
| 4 | 5.0 | 6.5 | 6.5 |
+----+---------+-------------+-----------+


I've tried using pd.crosstab(df['sepal_length'], df['species']) but that doesn't get me what I want. I've also tried using df.pivot_table('sepal_length', columns='species') and that also isn't it.



What am I missing here?










share|improve this question



















  • 2




    What does the initial dataframe look like?
    – today
    Nov 11 at 20:14












up vote
2
down vote

favorite
1









up vote
2
down vote

favorite
1






1





I have a pandas dataframe that contains the iris dataset. I want to subset this dataframe to only include sepal_length and species, and then reshape it so that the columns are the unique values for species and the values are the values for that species.



# load data into a dataframe
df = pd.read_csv('https://raw.githubusercontent.com/mwaskom/seaborn-data/master/iris.csv')

head(df)
+----+---------------+--------------+---------------+--------------+---------+
| | sepal_length | sepal_width | petal_length | petal_width | species |
+----+---------------+--------------+---------------+--------------+---------+
| 0 | 5.1 | 3.5 | 1.4 | 0.2 | setosa |
| 1 | 4.9 | 3.0 | 1.4 | 0.2 | setosa |
| 2 | 4.7 | 3.2 | 1.3 | 0.2 | setosa |
| 3 | 4.6 | 3.1 | 1.5 | 0.2 | setosa |
| 4 | 5.0 | 3.6 | 1.4 | 0.2 | setosa |
+----+---------------+--------------+---------------+--------------+---------+


I can do this is I take the data out of Pandas as use a dictionary to reshape the data, but I can't figure out how to do it within pandas.



data = df.to_dict('records')

e =
for line in data:
e[line['species']] =

for line in data:
e[line['species']].append(line['sepal_length'])

new = pd.DataFrame(e)


This is what I want to end up with:



+----+---------+-------------+-----------+
| | setosa | versicolor | virginica |
+----+---------+-------------+-----------+
| 0 | 5.1 | 7.0 | 6.3 |
| 1 | 4.9 | 6.4 | 5.8 |
| 2 | 4.7 | 6.9 | 7.1 |
| 3 | 4.6 | 5.5 | 6.3 |
| 4 | 5.0 | 6.5 | 6.5 |
+----+---------+-------------+-----------+


I've tried using pd.crosstab(df['sepal_length'], df['species']) but that doesn't get me what I want. I've also tried using df.pivot_table('sepal_length', columns='species') and that also isn't it.



What am I missing here?










share|improve this question















I have a pandas dataframe that contains the iris dataset. I want to subset this dataframe to only include sepal_length and species, and then reshape it so that the columns are the unique values for species and the values are the values for that species.



# load data into a dataframe
df = pd.read_csv('https://raw.githubusercontent.com/mwaskom/seaborn-data/master/iris.csv')

head(df)
+----+---------------+--------------+---------------+--------------+---------+
| | sepal_length | sepal_width | petal_length | petal_width | species |
+----+---------------+--------------+---------------+--------------+---------+
| 0 | 5.1 | 3.5 | 1.4 | 0.2 | setosa |
| 1 | 4.9 | 3.0 | 1.4 | 0.2 | setosa |
| 2 | 4.7 | 3.2 | 1.3 | 0.2 | setosa |
| 3 | 4.6 | 3.1 | 1.5 | 0.2 | setosa |
| 4 | 5.0 | 3.6 | 1.4 | 0.2 | setosa |
+----+---------------+--------------+---------------+--------------+---------+


I can do this is I take the data out of Pandas as use a dictionary to reshape the data, but I can't figure out how to do it within pandas.



data = df.to_dict('records')

e =
for line in data:
e[line['species']] =

for line in data:
e[line['species']].append(line['sepal_length'])

new = pd.DataFrame(e)


This is what I want to end up with:



+----+---------+-------------+-----------+
| | setosa | versicolor | virginica |
+----+---------+-------------+-----------+
| 0 | 5.1 | 7.0 | 6.3 |
| 1 | 4.9 | 6.4 | 5.8 |
| 2 | 4.7 | 6.9 | 7.1 |
| 3 | 4.6 | 5.5 | 6.3 |
| 4 | 5.0 | 6.5 | 6.5 |
+----+---------+-------------+-----------+


I've tried using pd.crosstab(df['sepal_length'], df['species']) but that doesn't get me what I want. I've also tried using df.pivot_table('sepal_length', columns='species') and that also isn't it.



What am I missing here?







python pandas






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 11 at 21:26

























asked Nov 11 at 19:28









CurtLH

6921032




6921032







  • 2




    What does the initial dataframe look like?
    – today
    Nov 11 at 20:14












  • 2




    What does the initial dataframe look like?
    – today
    Nov 11 at 20:14







2




2




What does the initial dataframe look like?
– today
Nov 11 at 20:14




What does the initial dataframe look like?
– today
Nov 11 at 20:14












2 Answers
2






active

oldest

votes

















up vote
2
down vote



accepted










IIUC you can use grouby.cumcount on species col and set index, then use pivot instead of pivot_table which does not requires an agg func.



df1 = df.set_index(df.groupby('species').cumcount())

df1 = df1.pivot(columns='species', values='sepal_length').rename_axis(None,axis=1)

print (df1)

setosa versicolor virginica
0 5.1 7.0 6.3
1 4.9 6.4 5.8
2 4.7 6.9 7.1
3 4.6 5.5 6.3
4 5.0 6.5 6.5





share|improve this answer





























    up vote
    1
    down vote













    What you're trying to do will take a few steps. (The code below assumes use of the standard "Iris dataset").




    1. First, let's subset your DataFrame by only the columns we need.



      df_subset = df[['sepal_length','species']]



    2. Next, use pandas.pivot (intead of pandas.pivot_table) to convert your DataFrame from "long" to "flat".



      df_pivot = df_subset.pivot(columns='species',values='sepal_length')



    3. Now, we're close to what you wanted but because your three species columns run along the same index, the pivoted DataFrame returns NaNs for two of the three columns for any given row. We can work around this by column-wise concatenating the DataFrame while re-indexing it. (Essentially creating three DataFrames - one for each species - and joining them along a new index). We can do this one of two ways:




      • The compact solution:



        names = ['setosa','versicolor','virginica']

        df_final = pd.concat(map(lambda name: df_pivot[name].dropna().reset_index().drop('index',axis=1), names), axis=1)



      • Which is equivalent to:



        df_final = pd.concat([
        df_pivot['setosa'].dropna().reset_index().drop('index',axis=1),
        df_pivot['versicolor'].dropna().reset_index().drop('index',axis=1),
        df_pivot['virginica'].dropna().reset_index().drop('index',axis=1)],axis=1)







    share|improve this answer




















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      2
      down vote



      accepted










      IIUC you can use grouby.cumcount on species col and set index, then use pivot instead of pivot_table which does not requires an agg func.



      df1 = df.set_index(df.groupby('species').cumcount())

      df1 = df1.pivot(columns='species', values='sepal_length').rename_axis(None,axis=1)

      print (df1)

      setosa versicolor virginica
      0 5.1 7.0 6.3
      1 4.9 6.4 5.8
      2 4.7 6.9 7.1
      3 4.6 5.5 6.3
      4 5.0 6.5 6.5





      share|improve this answer


























        up vote
        2
        down vote



        accepted










        IIUC you can use grouby.cumcount on species col and set index, then use pivot instead of pivot_table which does not requires an agg func.



        df1 = df.set_index(df.groupby('species').cumcount())

        df1 = df1.pivot(columns='species', values='sepal_length').rename_axis(None,axis=1)

        print (df1)

        setosa versicolor virginica
        0 5.1 7.0 6.3
        1 4.9 6.4 5.8
        2 4.7 6.9 7.1
        3 4.6 5.5 6.3
        4 5.0 6.5 6.5





        share|improve this answer
























          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          IIUC you can use grouby.cumcount on species col and set index, then use pivot instead of pivot_table which does not requires an agg func.



          df1 = df.set_index(df.groupby('species').cumcount())

          df1 = df1.pivot(columns='species', values='sepal_length').rename_axis(None,axis=1)

          print (df1)

          setosa versicolor virginica
          0 5.1 7.0 6.3
          1 4.9 6.4 5.8
          2 4.7 6.9 7.1
          3 4.6 5.5 6.3
          4 5.0 6.5 6.5





          share|improve this answer














          IIUC you can use grouby.cumcount on species col and set index, then use pivot instead of pivot_table which does not requires an agg func.



          df1 = df.set_index(df.groupby('species').cumcount())

          df1 = df1.pivot(columns='species', values='sepal_length').rename_axis(None,axis=1)

          print (df1)

          setosa versicolor virginica
          0 5.1 7.0 6.3
          1 4.9 6.4 5.8
          2 4.7 6.9 7.1
          3 4.6 5.5 6.3
          4 5.0 6.5 6.5






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 12 at 10:34

























          answered Nov 12 at 6:48









          Abhi

          2,479320




          2,479320






















              up vote
              1
              down vote













              What you're trying to do will take a few steps. (The code below assumes use of the standard "Iris dataset").




              1. First, let's subset your DataFrame by only the columns we need.



                df_subset = df[['sepal_length','species']]



              2. Next, use pandas.pivot (intead of pandas.pivot_table) to convert your DataFrame from "long" to "flat".



                df_pivot = df_subset.pivot(columns='species',values='sepal_length')



              3. Now, we're close to what you wanted but because your three species columns run along the same index, the pivoted DataFrame returns NaNs for two of the three columns for any given row. We can work around this by column-wise concatenating the DataFrame while re-indexing it. (Essentially creating three DataFrames - one for each species - and joining them along a new index). We can do this one of two ways:




                • The compact solution:



                  names = ['setosa','versicolor','virginica']

                  df_final = pd.concat(map(lambda name: df_pivot[name].dropna().reset_index().drop('index',axis=1), names), axis=1)



                • Which is equivalent to:



                  df_final = pd.concat([
                  df_pivot['setosa'].dropna().reset_index().drop('index',axis=1),
                  df_pivot['versicolor'].dropna().reset_index().drop('index',axis=1),
                  df_pivot['virginica'].dropna().reset_index().drop('index',axis=1)],axis=1)







              share|improve this answer
























                up vote
                1
                down vote













                What you're trying to do will take a few steps. (The code below assumes use of the standard "Iris dataset").




                1. First, let's subset your DataFrame by only the columns we need.



                  df_subset = df[['sepal_length','species']]



                2. Next, use pandas.pivot (intead of pandas.pivot_table) to convert your DataFrame from "long" to "flat".



                  df_pivot = df_subset.pivot(columns='species',values='sepal_length')



                3. Now, we're close to what you wanted but because your three species columns run along the same index, the pivoted DataFrame returns NaNs for two of the three columns for any given row. We can work around this by column-wise concatenating the DataFrame while re-indexing it. (Essentially creating three DataFrames - one for each species - and joining them along a new index). We can do this one of two ways:




                  • The compact solution:



                    names = ['setosa','versicolor','virginica']

                    df_final = pd.concat(map(lambda name: df_pivot[name].dropna().reset_index().drop('index',axis=1), names), axis=1)



                  • Which is equivalent to:



                    df_final = pd.concat([
                    df_pivot['setosa'].dropna().reset_index().drop('index',axis=1),
                    df_pivot['versicolor'].dropna().reset_index().drop('index',axis=1),
                    df_pivot['virginica'].dropna().reset_index().drop('index',axis=1)],axis=1)







                share|improve this answer






















                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  What you're trying to do will take a few steps. (The code below assumes use of the standard "Iris dataset").




                  1. First, let's subset your DataFrame by only the columns we need.



                    df_subset = df[['sepal_length','species']]



                  2. Next, use pandas.pivot (intead of pandas.pivot_table) to convert your DataFrame from "long" to "flat".



                    df_pivot = df_subset.pivot(columns='species',values='sepal_length')



                  3. Now, we're close to what you wanted but because your three species columns run along the same index, the pivoted DataFrame returns NaNs for two of the three columns for any given row. We can work around this by column-wise concatenating the DataFrame while re-indexing it. (Essentially creating three DataFrames - one for each species - and joining them along a new index). We can do this one of two ways:




                    • The compact solution:



                      names = ['setosa','versicolor','virginica']

                      df_final = pd.concat(map(lambda name: df_pivot[name].dropna().reset_index().drop('index',axis=1), names), axis=1)



                    • Which is equivalent to:



                      df_final = pd.concat([
                      df_pivot['setosa'].dropna().reset_index().drop('index',axis=1),
                      df_pivot['versicolor'].dropna().reset_index().drop('index',axis=1),
                      df_pivot['virginica'].dropna().reset_index().drop('index',axis=1)],axis=1)







                  share|improve this answer












                  What you're trying to do will take a few steps. (The code below assumes use of the standard "Iris dataset").




                  1. First, let's subset your DataFrame by only the columns we need.



                    df_subset = df[['sepal_length','species']]



                  2. Next, use pandas.pivot (intead of pandas.pivot_table) to convert your DataFrame from "long" to "flat".



                    df_pivot = df_subset.pivot(columns='species',values='sepal_length')



                  3. Now, we're close to what you wanted but because your three species columns run along the same index, the pivoted DataFrame returns NaNs for two of the three columns for any given row. We can work around this by column-wise concatenating the DataFrame while re-indexing it. (Essentially creating three DataFrames - one for each species - and joining them along a new index). We can do this one of two ways:




                    • The compact solution:



                      names = ['setosa','versicolor','virginica']

                      df_final = pd.concat(map(lambda name: df_pivot[name].dropna().reset_index().drop('index',axis=1), names), axis=1)



                    • Which is equivalent to:



                      df_final = pd.concat([
                      df_pivot['setosa'].dropna().reset_index().drop('index',axis=1),
                      df_pivot['versicolor'].dropna().reset_index().drop('index',axis=1),
                      df_pivot['virginica'].dropna().reset_index().drop('index',axis=1)],axis=1)








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 11 at 21:25









                  dmitriys

                  15119




                  15119



























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