How to set context variable of all Django generic views at once?









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I will have standard class-based views for CRUD operations that inherit from various generic views like ListView, DetailView and so on.
I will be setting all of their
context_object_name
attribute to the same value.



I was wondering if there is a way to do it more pythonic, to not repeat the operations many times in the code, but to be able to change that variable in one place if necessary?



ps. what comes to my mind is of course further inheritance, but maybe there is some more django-like way?










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  • Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
    – Daniel Roseman
    Nov 11 at 20:10














up vote
0
down vote

favorite












I will have standard class-based views for CRUD operations that inherit from various generic views like ListView, DetailView and so on.
I will be setting all of their
context_object_name
attribute to the same value.



I was wondering if there is a way to do it more pythonic, to not repeat the operations many times in the code, but to be able to change that variable in one place if necessary?



ps. what comes to my mind is of course further inheritance, but maybe there is some more django-like way?










share|improve this question





















  • Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
    – Daniel Roseman
    Nov 11 at 20:10












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I will have standard class-based views for CRUD operations that inherit from various generic views like ListView, DetailView and so on.
I will be setting all of their
context_object_name
attribute to the same value.



I was wondering if there is a way to do it more pythonic, to not repeat the operations many times in the code, but to be able to change that variable in one place if necessary?



ps. what comes to my mind is of course further inheritance, but maybe there is some more django-like way?










share|improve this question













I will have standard class-based views for CRUD operations that inherit from various generic views like ListView, DetailView and so on.
I will be setting all of their
context_object_name
attribute to the same value.



I was wondering if there is a way to do it more pythonic, to not repeat the operations many times in the code, but to be able to change that variable in one place if necessary?



ps. what comes to my mind is of course further inheritance, but maybe there is some more django-like way?







python django django-class-based-views






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asked Nov 11 at 19:52









tikej

244




244











  • Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
    – Daniel Roseman
    Nov 11 at 20:10
















  • Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
    – Daniel Roseman
    Nov 11 at 20:10















Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
– Daniel Roseman
Nov 11 at 20:10




Inheritance is the way to go here, it's pretty simple to define a base class that sets a single value.
– Daniel Roseman
Nov 11 at 20:10












2 Answers
2






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Middleware can do the trick



class SetContextObjectNameMiddleware:

def process_template_response(self, request, response):
if 'object' in response.context_data:
response.context_data['foo'] = response.context_data['object']
return response


Then add the middleware to your settings.py



It's not really setting the view's context_object_name but it achieves the same outcome.






share|improve this answer



























    up vote
    0
    down vote













    You can also use a mixin, instead of a middleware app:



    class CommonContextMixin(object):
    def get_context_data(self, *args, **kwargs):
    context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
    context['foo'] = 'bar'

    return context


    Then use that mixin in your views:



    class MyView(TemplateView, CommonContextMixin):
    """ This view now has the foo variable as part of its context. """


    Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/






    share|improve this answer




















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      2 Answers
      2






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      2 Answers
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      up vote
      0
      down vote













      Middleware can do the trick



      class SetContextObjectNameMiddleware:

      def process_template_response(self, request, response):
      if 'object' in response.context_data:
      response.context_data['foo'] = response.context_data['object']
      return response


      Then add the middleware to your settings.py



      It's not really setting the view's context_object_name but it achieves the same outcome.






      share|improve this answer
























        up vote
        0
        down vote













        Middleware can do the trick



        class SetContextObjectNameMiddleware:

        def process_template_response(self, request, response):
        if 'object' in response.context_data:
        response.context_data['foo'] = response.context_data['object']
        return response


        Then add the middleware to your settings.py



        It's not really setting the view's context_object_name but it achieves the same outcome.






        share|improve this answer






















          up vote
          0
          down vote










          up vote
          0
          down vote









          Middleware can do the trick



          class SetContextObjectNameMiddleware:

          def process_template_response(self, request, response):
          if 'object' in response.context_data:
          response.context_data['foo'] = response.context_data['object']
          return response


          Then add the middleware to your settings.py



          It's not really setting the view's context_object_name but it achieves the same outcome.






          share|improve this answer












          Middleware can do the trick



          class SetContextObjectNameMiddleware:

          def process_template_response(self, request, response):
          if 'object' in response.context_data:
          response.context_data['foo'] = response.context_data['object']
          return response


          Then add the middleware to your settings.py



          It's not really setting the view's context_object_name but it achieves the same outcome.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 12 at 0:50









          rikAtee

          4,73042956




          4,73042956






















              up vote
              0
              down vote













              You can also use a mixin, instead of a middleware app:



              class CommonContextMixin(object):
              def get_context_data(self, *args, **kwargs):
              context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
              context['foo'] = 'bar'

              return context


              Then use that mixin in your views:



              class MyView(TemplateView, CommonContextMixin):
              """ This view now has the foo variable as part of its context. """


              Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/






              share|improve this answer
























                up vote
                0
                down vote













                You can also use a mixin, instead of a middleware app:



                class CommonContextMixin(object):
                def get_context_data(self, *args, **kwargs):
                context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
                context['foo'] = 'bar'

                return context


                Then use that mixin in your views:



                class MyView(TemplateView, CommonContextMixin):
                """ This view now has the foo variable as part of its context. """


                Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/






                share|improve this answer






















                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  You can also use a mixin, instead of a middleware app:



                  class CommonContextMixin(object):
                  def get_context_data(self, *args, **kwargs):
                  context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
                  context['foo'] = 'bar'

                  return context


                  Then use that mixin in your views:



                  class MyView(TemplateView, CommonContextMixin):
                  """ This view now has the foo variable as part of its context. """


                  Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/






                  share|improve this answer












                  You can also use a mixin, instead of a middleware app:



                  class CommonContextMixin(object):
                  def get_context_data(self, *args, **kwargs):
                  context = super(CommonContextMixin, self).get_context_data(*args, **kwargs)
                  context['foo'] = 'bar'

                  return context


                  Then use that mixin in your views:



                  class MyView(TemplateView, CommonContextMixin):
                  """ This view now has the foo variable as part of its context. """


                  Relevant Django docs: https://docs.djangoproject.com/en/2.1/topics/class-based-views/mixins/







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 12 at 1:01









                  Victor Bruno

                  886610




                  886610



























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