How to change the function of the adding, by one of multiplication or / and division? in FASM
0
I have made an adding function with two digit numbers, but also I want to multiply and divide two digit numbers.
Here is an abstract of the code that I got.
mov dx, result
mov ah,9 ;Prints a message for the result
int 21h
add bl,cl ;Gets the result of the addition of the first digit
sub bl,30h
add bh,ch ;Gets the result of the addition of the second digit
sub bh,30h
assembly fasm flatassembler
asked Nov 14 '18 at 5:49
Vinicio LópezVinicio López
113
add a comment |
0
I have made an adding function with two digit numbers, but also I want to multiply and divide two digit numbers.
Here is an abstract of the code that I got.
mov dx, result
mov ah,9 ;Prints a message for the result
int 21h
add bl,cl ;Gets the result of the addition of the first digit
sub bl,30h
add bh,ch ;Gets the result of the addition of the second digit
sub bh,30h
assembly fasm flatassembler
asked Nov 14 '18 at 5:49
Vinicio LópezVinicio López
113
So what's your question? The x86 instruction set has the instructions you need, right?
– David Wohlferd
Nov 14 '18 at 6:32
I am too new for this, I don't know how to do it
– Vinicio López
Nov 14 '18 at 6:48
The question is, how can I make a multiplication of two numbers with two digits?
– Vinicio López
Nov 14 '18 at 6:58
This code doesn't work for25 + 25, you'd get4:instead of50because you don't detect carry-out from the low digit. Normally you'd convert to a binary integer instead of dealing with ASCII decimal digits, and then multiply withimul bx, cxis trivial.
– Peter Cordes
Nov 14 '18 at 12:14
I don't get the result correctly using "imul bx, cx". I get this, for example: "04 x 02 = *("
– Vinicio López
Nov 14 '18 at 18:35
add a comment |
0
0
0
I have made an adding function with two digit numbers, but also I want to multiply and divide two digit numbers.
Here is an abstract of the code that I got.
mov dx, result
mov ah,9 ;Prints a message for the result
int 21h
add bl,cl ;Gets the result of the addition of the first digit
sub bl,30h
add bh,ch ;Gets the result of the addition of the second digit
sub bh,30h
assembly fasm flatassembler
asked Nov 14 '18 at 5:49
Vinicio LópezVinicio López
113
I have made an adding function with two digit numbers, but also I want to multiply and divide two digit numbers.
Here is an abstract of the code that I got.
mov dx, result
mov ah,9 ;Prints a message for the result
int 21h
add bl,cl ;Gets the result of the addition of the first digit
sub bl,30h
add bh,ch ;Gets the result of the addition of the second digit
sub bh,30h
assembly fasm flatassembler
assembly fasm flatassembler
asked Nov 14 '18 at 5:49
Vinicio LópezVinicio López
113
asked Nov 14 '18 at 5:49
Vinicio LópezVinicio López
113
asked Nov 14 '18 at 5:49
Vinicio LópezVinicio López
113
asked Nov 14 '18 at 5:49
Vinicio LópezVinicio López
113
asked Nov 14 '18 at 5:49
Vinicio LópezVinicio López
113
113
So what's your question? The x86 instruction set has the instructions you need, right?
– David Wohlferd
Nov 14 '18 at 6:32
I am too new for this, I don't know how to do it
– Vinicio López
Nov 14 '18 at 6:48
The question is, how can I make a multiplication of two numbers with two digits?
– Vinicio López
Nov 14 '18 at 6:58
This code doesn't work for25 + 25, you'd get4:instead of50because you don't detect carry-out from the low digit. Normally you'd convert to a binary integer instead of dealing with ASCII decimal digits, and then multiply withimul bx, cxis trivial.
– Peter Cordes
Nov 14 '18 at 12:14
I don't get the result correctly using "imul bx, cx". I get this, for example: "04 x 02 = *("
– Vinicio López
Nov 14 '18 at 18:35
add a comment |
So what's your question? The x86 instruction set has the instructions you need, right?
– David Wohlferd
Nov 14 '18 at 6:32
I am too new for this, I don't know how to do it
– Vinicio López
Nov 14 '18 at 6:48
The question is, how can I make a multiplication of two numbers with two digits?
– Vinicio López
Nov 14 '18 at 6:58
This code doesn't work for25 + 25, you'd get4:instead of50because you don't detect carry-out from the low digit. Normally you'd convert to a binary integer instead of dealing with ASCII decimal digits, and then multiply withimul bx, cxis trivial.
– Peter Cordes
Nov 14 '18 at 12:14
I don't get the result correctly using "imul bx, cx". I get this, for example: "04 x 02 = *("
– Vinicio López
Nov 14 '18 at 18:35
So what's your question? The x86 instruction set has the instructions you need, right?
– David Wohlferd
Nov 14 '18 at 6:32
So what's your question? The x86 instruction set has the instructions you need, right?
– David Wohlferd
Nov 14 '18 at 6:32
I am too new for this, I don't know how to do it
– Vinicio López
Nov 14 '18 at 6:48
I am too new for this, I don't know how to do it
– Vinicio López
Nov 14 '18 at 6:48
The question is, how can I make a multiplication of two numbers with two digits?
– Vinicio López
Nov 14 '18 at 6:58
The question is, how can I make a multiplication of two numbers with two digits?
– Vinicio López
Nov 14 '18 at 6:58
This code doesn't work for
25 + 25, you'd get 4: instead of 50 because you don't detect carry-out from the low digit. Normally you'd convert to a binary integer instead of dealing with ASCII decimal digits, and then multiply with imul bx, cx is trivial.– Peter Cordes
Nov 14 '18 at 12:14
This code doesn't work for
25 + 25, you'd get 4: instead of 50 because you don't detect carry-out from the low digit. Normally you'd convert to a binary integer instead of dealing with ASCII decimal digits, and then multiply with imul bx, cx is trivial.– Peter Cordes
Nov 14 '18 at 12:14
I don't get the result correctly using "imul bx, cx". I get this, for example: "04 x 02 = *("
– Vinicio López
Nov 14 '18 at 18:35
I don't get the result correctly using "imul bx, cx". I get this, for example: "04 x 02 = *("
– Vinicio López
Nov 14 '18 at 18:35
add a comment |
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So what's your question? The x86 instruction set has the instructions you need, right?
– David Wohlferd
Nov 14 '18 at 6:32
I am too new for this, I don't know how to do it
– Vinicio López
Nov 14 '18 at 6:48
The question is, how can I make a multiplication of two numbers with two digits?
– Vinicio López
Nov 14 '18 at 6:58
This code doesn't work for
25 + 25, you'd get4:instead of50because you don't detect carry-out from the low digit. Normally you'd convert to a binary integer instead of dealing with ASCII decimal digits, and then multiply withimul bx, cxis trivial.– Peter Cordes
Nov 14 '18 at 12:14
I don't get the result correctly using "imul bx, cx". I get this, for example: "04 x 02 = *("
– Vinicio López
Nov 14 '18 at 18:35