How to change source video based Query String in JS










0















first im sorry if my english bad.



How To change CHANGE_THIS besed from ID query in video source by JS.



example : if i access "localhost/index.html?id=video" source will change from "/files/CHANGE_THIS/1080p" to "/files/video/1080p"



<head>
<link href="https://vjs.zencdn.net/7.3.0/video-js.css" rel="stylesheet">
</head>

<body>
<video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
<source src="/files/CHANGE_THIS/1080p" type='video/mp4'>
</video>

<script src="https://vjs.zencdn.net/7.3.0/video.js"></script>

</script>
</body>









share|improve this question


























    0















    first im sorry if my english bad.



    How To change CHANGE_THIS besed from ID query in video source by JS.



    example : if i access "localhost/index.html?id=video" source will change from "/files/CHANGE_THIS/1080p" to "/files/video/1080p"



    <head>
    <link href="https://vjs.zencdn.net/7.3.0/video-js.css" rel="stylesheet">
    </head>

    <body>
    <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
    <source src="/files/CHANGE_THIS/1080p" type='video/mp4'>
    </video>

    <script src="https://vjs.zencdn.net/7.3.0/video.js"></script>

    </script>
    </body>









    share|improve this question
























      0












      0








      0








      first im sorry if my english bad.



      How To change CHANGE_THIS besed from ID query in video source by JS.



      example : if i access "localhost/index.html?id=video" source will change from "/files/CHANGE_THIS/1080p" to "/files/video/1080p"



      <head>
      <link href="https://vjs.zencdn.net/7.3.0/video-js.css" rel="stylesheet">
      </head>

      <body>
      <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
      <source src="/files/CHANGE_THIS/1080p" type='video/mp4'>
      </video>

      <script src="https://vjs.zencdn.net/7.3.0/video.js"></script>

      </script>
      </body>









      share|improve this question














      first im sorry if my english bad.



      How To change CHANGE_THIS besed from ID query in video source by JS.



      example : if i access "localhost/index.html?id=video" source will change from "/files/CHANGE_THIS/1080p" to "/files/video/1080p"



      <head>
      <link href="https://vjs.zencdn.net/7.3.0/video-js.css" rel="stylesheet">
      </head>

      <body>
      <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
      <source src="/files/CHANGE_THIS/1080p" type='video/mp4'>
      </video>

      <script src="https://vjs.zencdn.net/7.3.0/video.js"></script>

      </script>
      </body>






      javascript






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 13 '18 at 22:24









      Izul WahidinIzul Wahidin

      11




      11






















          2 Answers
          2






          active

          oldest

          votes


















          0














          give the source id :



           <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


          then in javascript :



           var url_string = window.location.href;
          var url = new URL(url_string);
          var c = url.searchParams.get("c");
          document.getElementById("source").src="/files/"+c+"/1080p" //your source





          share|improve this answer






























            0














            First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



            This can be seen in the following:






            const video = document.getElementById('my-video');
            const source = document.getElementsByTagName('source')[0];
            source.src = video.id + source.src;

            console.log(source.src);

            <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
            <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
            </video>





            Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






            share|improve this answer






















              Your Answer






              StackExchange.ifUsing("editor", function ()
              StackExchange.using("externalEditor", function ()
              StackExchange.using("snippets", function ()
              StackExchange.snippets.init();
              );
              );
              , "code-snippets");

              StackExchange.ready(function()
              var channelOptions =
              tags: "".split(" "),
              id: "1"
              ;
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function()
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled)
              StackExchange.using("snippets", function()
              createEditor();
              );

              else
              createEditor();

              );

              function createEditor()
              StackExchange.prepareEditor(
              heartbeatType: 'answer',
              autoActivateHeartbeat: false,
              convertImagesToLinks: true,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: 10,
              bindNavPrevention: true,
              postfix: "",
              imageUploader:
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              ,
              onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              );



              );













              draft saved

              draft discarded


















              StackExchange.ready(
              function ()
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53290436%2fhow-to-change-source-video-based-query-string-in-js%23new-answer', 'question_page');

              );

              Post as a guest















              Required, but never shown

























              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              0














              give the source id :



               <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


              then in javascript :



               var url_string = window.location.href;
              var url = new URL(url_string);
              var c = url.searchParams.get("c");
              document.getElementById("source").src="/files/"+c+"/1080p" //your source





              share|improve this answer



























                0














                give the source id :



                 <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


                then in javascript :



                 var url_string = window.location.href;
                var url = new URL(url_string);
                var c = url.searchParams.get("c");
                document.getElementById("source").src="/files/"+c+"/1080p" //your source





                share|improve this answer

























                  0












                  0








                  0







                  give the source id :



                   <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


                  then in javascript :



                   var url_string = window.location.href;
                  var url = new URL(url_string);
                  var c = url.searchParams.get("c");
                  document.getElementById("source").src="/files/"+c+"/1080p" //your source





                  share|improve this answer













                  give the source id :



                   <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


                  then in javascript :



                   var url_string = window.location.href;
                  var url = new URL(url_string);
                  var c = url.searchParams.get("c");
                  document.getElementById("source").src="/files/"+c+"/1080p" //your source






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 22:29









                  Sari MasriSari Masri

                  1297




                  1297























                      0














                      First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



                      This can be seen in the following:






                      const video = document.getElementById('my-video');
                      const source = document.getElementsByTagName('source')[0];
                      source.src = video.id + source.src;

                      console.log(source.src);

                      <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                      <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                      </video>





                      Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






                      share|improve this answer



























                        0














                        First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



                        This can be seen in the following:






                        const video = document.getElementById('my-video');
                        const source = document.getElementsByTagName('source')[0];
                        source.src = video.id + source.src;

                        console.log(source.src);

                        <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                        <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                        </video>





                        Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






                        share|improve this answer

























                          0












                          0








                          0







                          First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



                          This can be seen in the following:






                          const video = document.getElementById('my-video');
                          const source = document.getElementsByTagName('source')[0];
                          source.src = video.id + source.src;

                          console.log(source.src);

                          <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                          <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                          </video>





                          Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






                          share|improve this answer













                          First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



                          This can be seen in the following:






                          const video = document.getElementById('my-video');
                          const source = document.getElementsByTagName('source')[0];
                          source.src = video.id + source.src;

                          console.log(source.src);

                          <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                          <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                          </video>





                          Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






                          const video = document.getElementById('my-video');
                          const source = document.getElementsByTagName('source')[0];
                          source.src = video.id + source.src;

                          console.log(source.src);

                          <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                          <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                          </video>





                          const video = document.getElementById('my-video');
                          const source = document.getElementsByTagName('source')[0];
                          source.src = video.id + source.src;

                          console.log(source.src);

                          <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                          <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                          </video>






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 13 '18 at 22:30









                          Obsidian AgeObsidian Age

                          27.2k72344




                          27.2k72344



























                              draft saved

                              draft discarded
















































                              Thanks for contributing an answer to Stack Overflow!


                              • Please be sure to answer the question. Provide details and share your research!

                              But avoid


                              • Asking for help, clarification, or responding to other answers.

                              • Making statements based on opinion; back them up with references or personal experience.

                              To learn more, see our tips on writing great answers.




                              draft saved


                              draft discarded














                              StackExchange.ready(
                              function ()
                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53290436%2fhow-to-change-source-video-based-query-string-in-js%23new-answer', 'question_page');

                              );

                              Post as a guest















                              Required, but never shown





















































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown

































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown







                              這個網誌中的熱門文章

                              How to read a connectionString WITH PROVIDER in .NET Core?

                              In R, how to develop a multiplot heatmap.2 figure showing key labels successfully

                              Museum of Modern and Contemporary Art of Trento and Rovereto