How to change source video based Query String in JS










0















first im sorry if my english bad.



How To change CHANGE_THIS besed from ID query in video source by JS.



example : if i access "localhost/index.html?id=video" source will change from "/files/CHANGE_THIS/1080p" to "/files/video/1080p"



<head>
<link href="https://vjs.zencdn.net/7.3.0/video-js.css" rel="stylesheet">
</head>

<body>
<video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
<source src="/files/CHANGE_THIS/1080p" type='video/mp4'>
</video>

<script src="https://vjs.zencdn.net/7.3.0/video.js"></script>

</script>
</body>









share|improve this question


























    0















    first im sorry if my english bad.



    How To change CHANGE_THIS besed from ID query in video source by JS.



    example : if i access "localhost/index.html?id=video" source will change from "/files/CHANGE_THIS/1080p" to "/files/video/1080p"



    <head>
    <link href="https://vjs.zencdn.net/7.3.0/video-js.css" rel="stylesheet">
    </head>

    <body>
    <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
    <source src="/files/CHANGE_THIS/1080p" type='video/mp4'>
    </video>

    <script src="https://vjs.zencdn.net/7.3.0/video.js"></script>

    </script>
    </body>









    share|improve this question
























      0












      0








      0








      first im sorry if my english bad.



      How To change CHANGE_THIS besed from ID query in video source by JS.



      example : if i access "localhost/index.html?id=video" source will change from "/files/CHANGE_THIS/1080p" to "/files/video/1080p"



      <head>
      <link href="https://vjs.zencdn.net/7.3.0/video-js.css" rel="stylesheet">
      </head>

      <body>
      <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
      <source src="/files/CHANGE_THIS/1080p" type='video/mp4'>
      </video>

      <script src="https://vjs.zencdn.net/7.3.0/video.js"></script>

      </script>
      </body>









      share|improve this question














      first im sorry if my english bad.



      How To change CHANGE_THIS besed from ID query in video source by JS.



      example : if i access "localhost/index.html?id=video" source will change from "/files/CHANGE_THIS/1080p" to "/files/video/1080p"



      <head>
      <link href="https://vjs.zencdn.net/7.3.0/video-js.css" rel="stylesheet">
      </head>

      <body>
      <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
      <source src="/files/CHANGE_THIS/1080p" type='video/mp4'>
      </video>

      <script src="https://vjs.zencdn.net/7.3.0/video.js"></script>

      </script>
      </body>






      javascript






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 13 '18 at 22:24









      Izul WahidinIzul Wahidin

      11




      11






















          2 Answers
          2






          active

          oldest

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          0














          give the source id :



           <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


          then in javascript :



           var url_string = window.location.href;
          var url = new URL(url_string);
          var c = url.searchParams.get("c");
          document.getElementById("source").src="/files/"+c+"/1080p" //your source





          share|improve this answer






























            0














            First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



            This can be seen in the following:






            const video = document.getElementById('my-video');
            const source = document.getElementsByTagName('source')[0];
            source.src = video.id + source.src;

            console.log(source.src);

            <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
            <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
            </video>





            Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






            share|improve this answer






















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              2 Answers
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              active

              oldest

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              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              0














              give the source id :



               <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


              then in javascript :



               var url_string = window.location.href;
              var url = new URL(url_string);
              var c = url.searchParams.get("c");
              document.getElementById("source").src="/files/"+c+"/1080p" //your source





              share|improve this answer



























                0














                give the source id :



                 <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


                then in javascript :



                 var url_string = window.location.href;
                var url = new URL(url_string);
                var c = url.searchParams.get("c");
                document.getElementById("source").src="/files/"+c+"/1080p" //your source





                share|improve this answer

























                  0












                  0








                  0







                  give the source id :



                   <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


                  then in javascript :



                   var url_string = window.location.href;
                  var url = new URL(url_string);
                  var c = url.searchParams.get("c");
                  document.getElementById("source").src="/files/"+c+"/1080p" //your source





                  share|improve this answer













                  give the source id :



                   <source id="source" src="/files/CHANGE_THIS/1080p" type='video/mp4'>


                  then in javascript :



                   var url_string = window.location.href;
                  var url = new URL(url_string);
                  var c = url.searchParams.get("c");
                  document.getElementById("source").src="/files/"+c+"/1080p" //your source






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 22:29









                  Sari MasriSari Masri

                  1297




                  1297























                      0














                      First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



                      This can be seen in the following:






                      const video = document.getElementById('my-video');
                      const source = document.getElementsByTagName('source')[0];
                      source.src = video.id + source.src;

                      console.log(source.src);

                      <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                      <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                      </video>





                      Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






                      share|improve this answer



























                        0














                        First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



                        This can be seen in the following:






                        const video = document.getElementById('my-video');
                        const source = document.getElementsByTagName('source')[0];
                        source.src = video.id + source.src;

                        console.log(source.src);

                        <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                        <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                        </video>





                        Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






                        share|improve this answer

























                          0












                          0








                          0







                          First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



                          This can be seen in the following:






                          const video = document.getElementById('my-video');
                          const source = document.getElementsByTagName('source')[0];
                          source.src = video.id + source.src;

                          console.log(source.src);

                          <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                          <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                          </video>





                          Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






                          share|improve this answer













                          First you want to grab the video element, which can be done with document.getElementById('my-video'). Then you want to grab the <source> element, which can be done with document.getElementsByTagName('source'). Note that this return a NodeList collection of all elements, even though there's only one in your example. As such, you'll need the first index, as document.getElementsByTagName('source')[0]. Finally, you simply want to set the .src of the source to be the .id of the video, plus what it was before.



                          This can be seen in the following:






                          const video = document.getElementById('my-video');
                          const source = document.getElementsByTagName('source')[0];
                          source.src = video.id + source.src;

                          console.log(source.src);

                          <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                          <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                          </video>





                          Note that you'll likely want to remove the first /, as that denotes the root of the website. Depending on your folder layout, you'll probably want to add this slash in manually, by removing it from the original source and making use of source.src = video.id + / + source.src.






                          const video = document.getElementById('my-video');
                          const source = document.getElementsByTagName('source')[0];
                          source.src = video.id + source.src;

                          console.log(source.src);

                          <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                          <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                          </video>





                          const video = document.getElementById('my-video');
                          const source = document.getElementsByTagName('source')[0];
                          source.src = video.id + source.src;

                          console.log(source.src);

                          <video id="my-video" class="video-js" controls preload="auto" width="640" height="264" poster="poster.jpg" data-setup='"fluid": true'>
                          <source src="/files/CHANGE_THIS_BY_QUERY/1080p" type='video/mp4'>
                          </video>






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 13 '18 at 22:30









                          Obsidian AgeObsidian Age

                          27.2k72344




                          27.2k72344



























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