Snakemake Using expand with dictionary










1















I am writing this rule:



rule process_files:
input:
dataout=expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref])
output:
"dataset/sample.ref.state.case.endresult.tsv"
shell:
do something ...


Were expand will get value from dictionary my_dictionary based on the ref value. I used wildcards like this my_dictionary[wildcards.ref]. But it ends up with this error name 'wildcards' is not defined



my_dictionary something like:
A:[1,2,3], B:[s1,s2..].....



I could use



def myfun(wildcards):
return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_dictionary[wildcards.ref])


and use myfun as input , but this does not answer why I can not use expand in place directly



Any suggestion how to fix it?










share|improve this question




























    1















    I am writing this rule:



    rule process_files:
    input:
    dataout=expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref])
    output:
    "dataset/sample.ref.state.case.endresult.tsv"
    shell:
    do something ...


    Were expand will get value from dictionary my_dictionary based on the ref value. I used wildcards like this my_dictionary[wildcards.ref]. But it ends up with this error name 'wildcards' is not defined



    my_dictionary something like:
    A:[1,2,3], B:[s1,s2..].....



    I could use



    def myfun(wildcards):
    return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_dictionary[wildcards.ref])


    and use myfun as input , but this does not answer why I can not use expand in place directly



    Any suggestion how to fix it?










    share|improve this question


























      1












      1








      1








      I am writing this rule:



      rule process_files:
      input:
      dataout=expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref])
      output:
      "dataset/sample.ref.state.case.endresult.tsv"
      shell:
      do something ...


      Were expand will get value from dictionary my_dictionary based on the ref value. I used wildcards like this my_dictionary[wildcards.ref]. But it ends up with this error name 'wildcards' is not defined



      my_dictionary something like:
      A:[1,2,3], B:[s1,s2..].....



      I could use



      def myfun(wildcards):
      return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_dictionary[wildcards.ref])


      and use myfun as input , but this does not answer why I can not use expand in place directly



      Any suggestion how to fix it?










      share|improve this question
















      I am writing this rule:



      rule process_files:
      input:
      dataout=expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref])
      output:
      "dataset/sample.ref.state.case.endresult.tsv"
      shell:
      do something ...


      Were expand will get value from dictionary my_dictionary based on the ref value. I used wildcards like this my_dictionary[wildcards.ref]. But it ends up with this error name 'wildcards' is not defined



      my_dictionary something like:
      A:[1,2,3], B:[s1,s2..].....



      I could use



      def myfun(wildcards):
      return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_dictionary[wildcards.ref])


      and use myfun as input , but this does not answer why I can not use expand in place directly



      Any suggestion how to fix it?







      expand snakemake






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 14 '18 at 15:22







      Medhat

















      asked Nov 13 '18 at 22:26









      MedhatMedhat

      934820




      934820






















          2 Answers
          2






          active

          oldest

          votes


















          0














          Your question seems similar to snakemake wildcards or expand command and the bottom line is that wildcards is not defined in the input. So your solution of using an input function (or a lambda function) seems correct.



          (As to why wildcards is not defined in input, I don't know...)






          share|improve this answer























          • Thanks, The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.

            – Medhat
            Nov 14 '18 at 16:37


















          0














          As @dariober mentioned there is the wildcards objects but this is only accesible in the run/shell portion but can be accessed using an input function in input.



          Here is an example implementation that will expand the input based on the wildcards.ref:



          rule all:
          input: expand("dataset/sample.ref.state.case.endresult.tsv", dataset=["D1", "D2"], sample=["S1", "S2"], ref=["R1", "R2"], state=["STATE1", "STATE2"], case=["C1", "C2"])


          my_list = "R1": [1, 2, 3], "R2": ["s1", "s2"]

          rule process_files:
          input:
          lambda wildcards: expand(
          "dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref])
          output:
          "dataset/sample.ref.state.case.endresult.tsv"
          shell:
          "echo 'input' > output"


          If you implement it as the lambda function example above, it should resolve the issue you mention:




          The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.







          share|improve this answer























          • Actually my function is the same as your lambda function and raises this error. def myfun(wildcards): return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref]) . to overcome the issue I need to resolve each var for example ref . would be `wildcards.ref`` and so on.

            – Medhat
            Nov 14 '18 at 19:38












          • There should not really be need to do that. You are saying you pass to expand, in the case of dataset, dataset = wildcards.dataset? Seems redundant. I am using snakemake 5.3.0 in the example and it works using your myfun or lambda.

            – JohnnyBD
            Nov 14 '18 at 20:43












          • The issue is after using expand; the variable passed to sample is sample so it would be sample=sample not the actual value of sample, which makes problem in processing for next step because now there is nothing called dataset/sample... in the input file

            – Medhat
            Nov 14 '18 at 21:23











          • I am sorry but I cannot seem to reproduce this issue you are mentioning. Could you maybe edit your question and provide example of what an input would look like for one input wildcard combination? Either I am misunderstanding what are you trying to do or our implementations are different? You want to have a single value for all the wildcards except name? Essentially group a set of name inputs together? In that case you should have sample in the result of expand as that wildcard will be deduced from rule all and output.

            – JohnnyBD
            Nov 14 '18 at 22:26










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          2 Answers
          2






          active

          oldest

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          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          Your question seems similar to snakemake wildcards or expand command and the bottom line is that wildcards is not defined in the input. So your solution of using an input function (or a lambda function) seems correct.



          (As to why wildcards is not defined in input, I don't know...)






          share|improve this answer























          • Thanks, The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.

            – Medhat
            Nov 14 '18 at 16:37















          0














          Your question seems similar to snakemake wildcards or expand command and the bottom line is that wildcards is not defined in the input. So your solution of using an input function (or a lambda function) seems correct.



          (As to why wildcards is not defined in input, I don't know...)






          share|improve this answer























          • Thanks, The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.

            – Medhat
            Nov 14 '18 at 16:37













          0












          0








          0







          Your question seems similar to snakemake wildcards or expand command and the bottom line is that wildcards is not defined in the input. So your solution of using an input function (or a lambda function) seems correct.



          (As to why wildcards is not defined in input, I don't know...)






          share|improve this answer













          Your question seems similar to snakemake wildcards or expand command and the bottom line is that wildcards is not defined in the input. So your solution of using an input function (or a lambda function) seems correct.



          (As to why wildcards is not defined in input, I don't know...)







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 14 '18 at 8:25









          darioberdariober

          1,0211221




          1,0211221












          • Thanks, The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.

            – Medhat
            Nov 14 '18 at 16:37

















          • Thanks, The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.

            – Medhat
            Nov 14 '18 at 16:37
















          Thanks, The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.

          – Medhat
          Nov 14 '18 at 16:37





          Thanks, The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.

          – Medhat
          Nov 14 '18 at 16:37













          0














          As @dariober mentioned there is the wildcards objects but this is only accesible in the run/shell portion but can be accessed using an input function in input.



          Here is an example implementation that will expand the input based on the wildcards.ref:



          rule all:
          input: expand("dataset/sample.ref.state.case.endresult.tsv", dataset=["D1", "D2"], sample=["S1", "S2"], ref=["R1", "R2"], state=["STATE1", "STATE2"], case=["C1", "C2"])


          my_list = "R1": [1, 2, 3], "R2": ["s1", "s2"]

          rule process_files:
          input:
          lambda wildcards: expand(
          "dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref])
          output:
          "dataset/sample.ref.state.case.endresult.tsv"
          shell:
          "echo 'input' > output"


          If you implement it as the lambda function example above, it should resolve the issue you mention:




          The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.







          share|improve this answer























          • Actually my function is the same as your lambda function and raises this error. def myfun(wildcards): return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref]) . to overcome the issue I need to resolve each var for example ref . would be `wildcards.ref`` and so on.

            – Medhat
            Nov 14 '18 at 19:38












          • There should not really be need to do that. You are saying you pass to expand, in the case of dataset, dataset = wildcards.dataset? Seems redundant. I am using snakemake 5.3.0 in the example and it works using your myfun or lambda.

            – JohnnyBD
            Nov 14 '18 at 20:43












          • The issue is after using expand; the variable passed to sample is sample so it would be sample=sample not the actual value of sample, which makes problem in processing for next step because now there is nothing called dataset/sample... in the input file

            – Medhat
            Nov 14 '18 at 21:23











          • I am sorry but I cannot seem to reproduce this issue you are mentioning. Could you maybe edit your question and provide example of what an input would look like for one input wildcard combination? Either I am misunderstanding what are you trying to do or our implementations are different? You want to have a single value for all the wildcards except name? Essentially group a set of name inputs together? In that case you should have sample in the result of expand as that wildcard will be deduced from rule all and output.

            – JohnnyBD
            Nov 14 '18 at 22:26















          0














          As @dariober mentioned there is the wildcards objects but this is only accesible in the run/shell portion but can be accessed using an input function in input.



          Here is an example implementation that will expand the input based on the wildcards.ref:



          rule all:
          input: expand("dataset/sample.ref.state.case.endresult.tsv", dataset=["D1", "D2"], sample=["S1", "S2"], ref=["R1", "R2"], state=["STATE1", "STATE2"], case=["C1", "C2"])


          my_list = "R1": [1, 2, 3], "R2": ["s1", "s2"]

          rule process_files:
          input:
          lambda wildcards: expand(
          "dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref])
          output:
          "dataset/sample.ref.state.case.endresult.tsv"
          shell:
          "echo 'input' > output"


          If you implement it as the lambda function example above, it should resolve the issue you mention:




          The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.







          share|improve this answer























          • Actually my function is the same as your lambda function and raises this error. def myfun(wildcards): return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref]) . to overcome the issue I need to resolve each var for example ref . would be `wildcards.ref`` and so on.

            – Medhat
            Nov 14 '18 at 19:38












          • There should not really be need to do that. You are saying you pass to expand, in the case of dataset, dataset = wildcards.dataset? Seems redundant. I am using snakemake 5.3.0 in the example and it works using your myfun or lambda.

            – JohnnyBD
            Nov 14 '18 at 20:43












          • The issue is after using expand; the variable passed to sample is sample so it would be sample=sample not the actual value of sample, which makes problem in processing for next step because now there is nothing called dataset/sample... in the input file

            – Medhat
            Nov 14 '18 at 21:23











          • I am sorry but I cannot seem to reproduce this issue you are mentioning. Could you maybe edit your question and provide example of what an input would look like for one input wildcard combination? Either I am misunderstanding what are you trying to do or our implementations are different? You want to have a single value for all the wildcards except name? Essentially group a set of name inputs together? In that case you should have sample in the result of expand as that wildcard will be deduced from rule all and output.

            – JohnnyBD
            Nov 14 '18 at 22:26













          0












          0








          0







          As @dariober mentioned there is the wildcards objects but this is only accesible in the run/shell portion but can be accessed using an input function in input.



          Here is an example implementation that will expand the input based on the wildcards.ref:



          rule all:
          input: expand("dataset/sample.ref.state.case.endresult.tsv", dataset=["D1", "D2"], sample=["S1", "S2"], ref=["R1", "R2"], state=["STATE1", "STATE2"], case=["C1", "C2"])


          my_list = "R1": [1, 2, 3], "R2": ["s1", "s2"]

          rule process_files:
          input:
          lambda wildcards: expand(
          "dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref])
          output:
          "dataset/sample.ref.state.case.endresult.tsv"
          shell:
          "echo 'input' > output"


          If you implement it as the lambda function example above, it should resolve the issue you mention:




          The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.







          share|improve this answer













          As @dariober mentioned there is the wildcards objects but this is only accesible in the run/shell portion but can be accessed using an input function in input.



          Here is an example implementation that will expand the input based on the wildcards.ref:



          rule all:
          input: expand("dataset/sample.ref.state.case.endresult.tsv", dataset=["D1", "D2"], sample=["S1", "S2"], ref=["R1", "R2"], state=["STATE1", "STATE2"], case=["C1", "C2"])


          my_list = "R1": [1, 2, 3], "R2": ["s1", "s2"]

          rule process_files:
          input:
          lambda wildcards: expand(
          "dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref])
          output:
          "dataset/sample.ref.state.case.endresult.tsv"
          shell:
          "echo 'input' > output"


          If you implement it as the lambda function example above, it should resolve the issue you mention:




          The function worked but it did not resolve the variable between double curly braces so it will ask for input for dataset/sample.ref.state.caseand raise an error.








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 14 '18 at 17:47









          JohnnyBDJohnnyBD

          11115




          11115












          • Actually my function is the same as your lambda function and raises this error. def myfun(wildcards): return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref]) . to overcome the issue I need to resolve each var for example ref . would be `wildcards.ref`` and so on.

            – Medhat
            Nov 14 '18 at 19:38












          • There should not really be need to do that. You are saying you pass to expand, in the case of dataset, dataset = wildcards.dataset? Seems redundant. I am using snakemake 5.3.0 in the example and it works using your myfun or lambda.

            – JohnnyBD
            Nov 14 '18 at 20:43












          • The issue is after using expand; the variable passed to sample is sample so it would be sample=sample not the actual value of sample, which makes problem in processing for next step because now there is nothing called dataset/sample... in the input file

            – Medhat
            Nov 14 '18 at 21:23











          • I am sorry but I cannot seem to reproduce this issue you are mentioning. Could you maybe edit your question and provide example of what an input would look like for one input wildcard combination? Either I am misunderstanding what are you trying to do or our implementations are different? You want to have a single value for all the wildcards except name? Essentially group a set of name inputs together? In that case you should have sample in the result of expand as that wildcard will be deduced from rule all and output.

            – JohnnyBD
            Nov 14 '18 at 22:26

















          • Actually my function is the same as your lambda function and raises this error. def myfun(wildcards): return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref]) . to overcome the issue I need to resolve each var for example ref . would be `wildcards.ref`` and so on.

            – Medhat
            Nov 14 '18 at 19:38












          • There should not really be need to do that. You are saying you pass to expand, in the case of dataset, dataset = wildcards.dataset? Seems redundant. I am using snakemake 5.3.0 in the example and it works using your myfun or lambda.

            – JohnnyBD
            Nov 14 '18 at 20:43












          • The issue is after using expand; the variable passed to sample is sample so it would be sample=sample not the actual value of sample, which makes problem in processing for next step because now there is nothing called dataset/sample... in the input file

            – Medhat
            Nov 14 '18 at 21:23











          • I am sorry but I cannot seem to reproduce this issue you are mentioning. Could you maybe edit your question and provide example of what an input would look like for one input wildcard combination? Either I am misunderstanding what are you trying to do or our implementations are different? You want to have a single value for all the wildcards except name? Essentially group a set of name inputs together? In that case you should have sample in the result of expand as that wildcard will be deduced from rule all and output.

            – JohnnyBD
            Nov 14 '18 at 22:26
















          Actually my function is the same as your lambda function and raises this error. def myfun(wildcards): return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref]) . to overcome the issue I need to resolve each var for example ref . would be `wildcards.ref`` and so on.

          – Medhat
          Nov 14 '18 at 19:38






          Actually my function is the same as your lambda function and raises this error. def myfun(wildcards): return expand("dataset/sample.ref.state.case.myresult.name.tsv", name=my_list[wildcards.ref]) . to overcome the issue I need to resolve each var for example ref . would be `wildcards.ref`` and so on.

          – Medhat
          Nov 14 '18 at 19:38














          There should not really be need to do that. You are saying you pass to expand, in the case of dataset, dataset = wildcards.dataset? Seems redundant. I am using snakemake 5.3.0 in the example and it works using your myfun or lambda.

          – JohnnyBD
          Nov 14 '18 at 20:43






          There should not really be need to do that. You are saying you pass to expand, in the case of dataset, dataset = wildcards.dataset? Seems redundant. I am using snakemake 5.3.0 in the example and it works using your myfun or lambda.

          – JohnnyBD
          Nov 14 '18 at 20:43














          The issue is after using expand; the variable passed to sample is sample so it would be sample=sample not the actual value of sample, which makes problem in processing for next step because now there is nothing called dataset/sample... in the input file

          – Medhat
          Nov 14 '18 at 21:23





          The issue is after using expand; the variable passed to sample is sample so it would be sample=sample not the actual value of sample, which makes problem in processing for next step because now there is nothing called dataset/sample... in the input file

          – Medhat
          Nov 14 '18 at 21:23













          I am sorry but I cannot seem to reproduce this issue you are mentioning. Could you maybe edit your question and provide example of what an input would look like for one input wildcard combination? Either I am misunderstanding what are you trying to do or our implementations are different? You want to have a single value for all the wildcards except name? Essentially group a set of name inputs together? In that case you should have sample in the result of expand as that wildcard will be deduced from rule all and output.

          – JohnnyBD
          Nov 14 '18 at 22:26





          I am sorry but I cannot seem to reproduce this issue you are mentioning. Could you maybe edit your question and provide example of what an input would look like for one input wildcard combination? Either I am misunderstanding what are you trying to do or our implementations are different? You want to have a single value for all the wildcards except name? Essentially group a set of name inputs together? In that case you should have sample in the result of expand as that wildcard will be deduced from rule all and output.

          – JohnnyBD
          Nov 14 '18 at 22:26

















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