Congnos Ranking lowest as Rank 1
0
I am having hard time to rank lowest average number as rank 1, currently it ranking highest average number as rank 1. My current formula see below,
rank([Total Average], [Store Number])
I want it like below picture. How should I do that? Any help will be really appreciate. Thank you
cognos cognos-10 cognos-bi cognos-8 ranking-functions
asked Nov 13 '18 at 22:09
PrasadDPrasadD
257
|
show 1 more comment
0
I am having hard time to rank lowest average number as rank 1, currently it ranking highest average number as rank 1. My current formula see below,
rank([Total Average], [Store Number])
I want it like below picture. How should I do that? Any help will be really appreciate. Thank you
cognos cognos-10 cognos-bi cognos-8 ranking-functions
asked Nov 13 '18 at 22:09
PrasadDPrasadD
257
1
I'm sure you tried this but let just to be sure. Did you try adding ASC to the function?
– Aquatically Challenged Fish
Nov 14 '18 at 17:50
1
rank([Total Average], [Store Number] DESC). Note that the store number will effectively break any ties.
– Johnsonium
Nov 14 '18 at 19:11
@Johnsonium, I did thisrank([Total Average], [Store Number] DESC)Does not do anything. I wonder why is that.
– PrasadD
Nov 15 '18 at 18:13
1
I'm not sure. I created a sample report to make sure I was correct before commenting and it worked for me.
– Johnsonium
Nov 15 '18 at 18:31
@Johnsonium, you are correct your one work, but I figure it out why my one is not working. My total average is a query calculations (( [Post Paid Voice Gross Adds Rank LY] + [Prepaid Actual Rank LY] + [Accessory GP Rank LY] + [DTV Now Rank LY] + [Premium Video Rank LY] + [IPBB Rank LY] + [WTR Rank LY] + [IRPO Rank LY] )/8). When I removed /8 it works fine. I am not sure why is that tho. Anyway Thank you so much for the help.
– PrasadD
Nov 16 '18 at 0:29
|
show 1 more comment
0
0
0
I am having hard time to rank lowest average number as rank 1, currently it ranking highest average number as rank 1. My current formula see below,
rank([Total Average], [Store Number])
I want it like below picture. How should I do that? Any help will be really appreciate. Thank you
cognos cognos-10 cognos-bi cognos-8 ranking-functions
asked Nov 13 '18 at 22:09
PrasadDPrasadD
257
I am having hard time to rank lowest average number as rank 1, currently it ranking highest average number as rank 1. My current formula see below,
rank([Total Average], [Store Number])
I want it like below picture. How should I do that? Any help will be really appreciate. Thank you
cognos cognos-10 cognos-bi cognos-8 ranking-functions
cognos cognos-10 cognos-bi cognos-8 ranking-functions
asked Nov 13 '18 at 22:09
PrasadDPrasadD
257
asked Nov 13 '18 at 22:09
PrasadDPrasadD
257
asked Nov 13 '18 at 22:09
PrasadDPrasadD
257
asked Nov 13 '18 at 22:09
PrasadDPrasadD
257
asked Nov 13 '18 at 22:09
PrasadDPrasadD
257
257
1
I'm sure you tried this but let just to be sure. Did you try adding ASC to the function?
– Aquatically Challenged Fish
Nov 14 '18 at 17:50
1
rank([Total Average], [Store Number] DESC). Note that the store number will effectively break any ties.
– Johnsonium
Nov 14 '18 at 19:11
@Johnsonium, I did thisrank([Total Average], [Store Number] DESC)Does not do anything. I wonder why is that.
– PrasadD
Nov 15 '18 at 18:13
1
I'm not sure. I created a sample report to make sure I was correct before commenting and it worked for me.
– Johnsonium
Nov 15 '18 at 18:31
@Johnsonium, you are correct your one work, but I figure it out why my one is not working. My total average is a query calculations (( [Post Paid Voice Gross Adds Rank LY] + [Prepaid Actual Rank LY] + [Accessory GP Rank LY] + [DTV Now Rank LY] + [Premium Video Rank LY] + [IPBB Rank LY] + [WTR Rank LY] + [IRPO Rank LY] )/8). When I removed /8 it works fine. I am not sure why is that tho. Anyway Thank you so much for the help.
– PrasadD
Nov 16 '18 at 0:29
|
show 1 more comment
1
I'm sure you tried this but let just to be sure. Did you try adding ASC to the function?
– Aquatically Challenged Fish
Nov 14 '18 at 17:50
1
rank([Total Average], [Store Number] DESC). Note that the store number will effectively break any ties.
– Johnsonium
Nov 14 '18 at 19:11
@Johnsonium, I did thisrank([Total Average], [Store Number] DESC)Does not do anything. I wonder why is that.
– PrasadD
Nov 15 '18 at 18:13
1
I'm not sure. I created a sample report to make sure I was correct before commenting and it worked for me.
– Johnsonium
Nov 15 '18 at 18:31
@Johnsonium, you are correct your one work, but I figure it out why my one is not working. My total average is a query calculations (( [Post Paid Voice Gross Adds Rank LY] + [Prepaid Actual Rank LY] + [Accessory GP Rank LY] + [DTV Now Rank LY] + [Premium Video Rank LY] + [IPBB Rank LY] + [WTR Rank LY] + [IRPO Rank LY] )/8). When I removed /8 it works fine. I am not sure why is that tho. Anyway Thank you so much for the help.
– PrasadD
Nov 16 '18 at 0:29
1
1
I'm sure you tried this but let just to be sure. Did you try adding ASC to the function?
– Aquatically Challenged Fish
Nov 14 '18 at 17:50
I'm sure you tried this but let just to be sure. Did you try adding ASC to the function?
– Aquatically Challenged Fish
Nov 14 '18 at 17:50
1
1
rank([Total Average], [Store Number] DESC). Note that the store number will effectively break any ties.
– Johnsonium
Nov 14 '18 at 19:11
rank([Total Average], [Store Number] DESC). Note that the store number will effectively break any ties.
– Johnsonium
Nov 14 '18 at 19:11
@Johnsonium, I did this
rank([Total Average], [Store Number] DESC) Does not do anything. I wonder why is that.– PrasadD
Nov 15 '18 at 18:13
@Johnsonium, I did this
rank([Total Average], [Store Number] DESC) Does not do anything. I wonder why is that.– PrasadD
Nov 15 '18 at 18:13
1
1
I'm not sure. I created a sample report to make sure I was correct before commenting and it worked for me.
– Johnsonium
Nov 15 '18 at 18:31
I'm not sure. I created a sample report to make sure I was correct before commenting and it worked for me.
– Johnsonium
Nov 15 '18 at 18:31
@Johnsonium, you are correct your one work, but I figure it out why my one is not working. My total average is a query calculations (
( [Post Paid Voice Gross Adds Rank LY] + [Prepaid Actual Rank LY] + [Accessory GP Rank LY] + [DTV Now Rank LY] + [Premium Video Rank LY] + [IPBB Rank LY] + [WTR Rank LY] + [IRPO Rank LY] )/8). When I removed /8 it works fine. I am not sure why is that tho. Anyway Thank you so much for the help.– PrasadD
Nov 16 '18 at 0:29
@Johnsonium, you are correct your one work, but I figure it out why my one is not working. My total average is a query calculations (
( [Post Paid Voice Gross Adds Rank LY] + [Prepaid Actual Rank LY] + [Accessory GP Rank LY] + [DTV Now Rank LY] + [Premium Video Rank LY] + [IPBB Rank LY] + [WTR Rank LY] + [IRPO Rank LY] )/8). When I removed /8 it works fine. I am not sure why is that tho. Anyway Thank you so much for the help.– PrasadD
Nov 16 '18 at 0:29
|
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1
I'm sure you tried this but let just to be sure. Did you try adding ASC to the function?
– Aquatically Challenged Fish
Nov 14 '18 at 17:50
1
rank([Total Average], [Store Number] DESC). Note that the store number will effectively break any ties.
– Johnsonium
Nov 14 '18 at 19:11
@Johnsonium, I did this
rank([Total Average], [Store Number] DESC)Does not do anything. I wonder why is that.– PrasadD
Nov 15 '18 at 18:13
1
I'm not sure. I created a sample report to make sure I was correct before commenting and it worked for me.
– Johnsonium
Nov 15 '18 at 18:31
@Johnsonium, you are correct your one work, but I figure it out why my one is not working. My total average is a query calculations (
( [Post Paid Voice Gross Adds Rank LY] + [Prepaid Actual Rank LY] + [Accessory GP Rank LY] + [DTV Now Rank LY] + [Premium Video Rank LY] + [IPBB Rank LY] + [WTR Rank LY] + [IRPO Rank LY] )/8). When I removed /8 it works fine. I am not sure why is that tho. Anyway Thank you so much for the help.– PrasadD
Nov 16 '18 at 0:29