Freeze instance after step is complete using TypeIt.js
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I am using TypeIt.js to type a series of strings – https://typeitjs.com/docs/
There are a few features that I am trying to incorporate.
TypeIt.js allows for running a function after each letter is typed with 'afterStep()'. In the code below you will see that after each step there is a function being called which fits the texts inside the container by recalculation.
I want this typing function to run only when it is in view so I included an instance.freeze() and instance.unfreeze() with a function that checks when the element is in view or not.
This all works but the trouble I am having and would like help on is that when the instance is frozen, the next letter in the string is typed out and doesn't run the function ( window.initVarToWidth() ) inside afterStep...this causes the letter to flow out of it's container.
Is it possible to initiate instance.freeze() only after the function inside afterStep() is completed?
var instance = new TypeIt('#type',
strings: ["string1","string2"],
breakLines: false,
speed: 500,
loop: true,
afterStep: function(step, queue, instance)
//-- Execute your code here.
window.initVarToWidth();
,
);
function checkIfInView()
var docViewTop = $(window).scrollTop();
var docViewBottom = docViewTop + $(window).height();
var elemTop = $('#type').offset().top;
var elemBottom = elemTop + $('#type').height();
if ((elemBottom <= docViewBottom) && (elemTop >= docViewTop))
instance.unfreeze();
, 1000);
console.log('in view');
else
setTimeout(() =>
instance.freeze();
, 5000);
console.log('not in view');
}
javascript jquery
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up vote
0
down vote
favorite
I am using TypeIt.js to type a series of strings – https://typeitjs.com/docs/
There are a few features that I am trying to incorporate.
TypeIt.js allows for running a function after each letter is typed with 'afterStep()'. In the code below you will see that after each step there is a function being called which fits the texts inside the container by recalculation.
I want this typing function to run only when it is in view so I included an instance.freeze() and instance.unfreeze() with a function that checks when the element is in view or not.
This all works but the trouble I am having and would like help on is that when the instance is frozen, the next letter in the string is typed out and doesn't run the function ( window.initVarToWidth() ) inside afterStep...this causes the letter to flow out of it's container.
Is it possible to initiate instance.freeze() only after the function inside afterStep() is completed?
var instance = new TypeIt('#type',
strings: ["string1","string2"],
breakLines: false,
speed: 500,
loop: true,
afterStep: function(step, queue, instance)
//-- Execute your code here.
window.initVarToWidth();
,
);
function checkIfInView()
var docViewTop = $(window).scrollTop();
var docViewBottom = docViewTop + $(window).height();
var elemTop = $('#type').offset().top;
var elemBottom = elemTop + $('#type').height();
if ((elemBottom <= docViewBottom) && (elemTop >= docViewTop))
instance.unfreeze();
, 1000);
console.log('in view');
else
setTimeout(() =>
instance.freeze();
, 5000);
console.log('not in view');
}
javascript jquery
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am using TypeIt.js to type a series of strings – https://typeitjs.com/docs/
There are a few features that I am trying to incorporate.
TypeIt.js allows for running a function after each letter is typed with 'afterStep()'. In the code below you will see that after each step there is a function being called which fits the texts inside the container by recalculation.
I want this typing function to run only when it is in view so I included an instance.freeze() and instance.unfreeze() with a function that checks when the element is in view or not.
This all works but the trouble I am having and would like help on is that when the instance is frozen, the next letter in the string is typed out and doesn't run the function ( window.initVarToWidth() ) inside afterStep...this causes the letter to flow out of it's container.
Is it possible to initiate instance.freeze() only after the function inside afterStep() is completed?
var instance = new TypeIt('#type',
strings: ["string1","string2"],
breakLines: false,
speed: 500,
loop: true,
afterStep: function(step, queue, instance)
//-- Execute your code here.
window.initVarToWidth();
,
);
function checkIfInView()
var docViewTop = $(window).scrollTop();
var docViewBottom = docViewTop + $(window).height();
var elemTop = $('#type').offset().top;
var elemBottom = elemTop + $('#type').height();
if ((elemBottom <= docViewBottom) && (elemTop >= docViewTop))
instance.unfreeze();
, 1000);
console.log('in view');
else
setTimeout(() =>
instance.freeze();
, 5000);
console.log('not in view');
}
javascript jquery
I am using TypeIt.js to type a series of strings – https://typeitjs.com/docs/
There are a few features that I am trying to incorporate.
TypeIt.js allows for running a function after each letter is typed with 'afterStep()'. In the code below you will see that after each step there is a function being called which fits the texts inside the container by recalculation.
I want this typing function to run only when it is in view so I included an instance.freeze() and instance.unfreeze() with a function that checks when the element is in view or not.
This all works but the trouble I am having and would like help on is that when the instance is frozen, the next letter in the string is typed out and doesn't run the function ( window.initVarToWidth() ) inside afterStep...this causes the letter to flow out of it's container.
Is it possible to initiate instance.freeze() only after the function inside afterStep() is completed?
var instance = new TypeIt('#type',
strings: ["string1","string2"],
breakLines: false,
speed: 500,
loop: true,
afterStep: function(step, queue, instance)
//-- Execute your code here.
window.initVarToWidth();
,
);
function checkIfInView()
var docViewTop = $(window).scrollTop();
var docViewBottom = docViewTop + $(window).height();
var elemTop = $('#type').offset().top;
var elemBottom = elemTop + $('#type').height();
if ((elemBottom <= docViewBottom) && (elemTop >= docViewTop))
instance.unfreeze();
, 1000);
console.log('in view');
else
setTimeout(() =>
instance.freeze();
, 5000);
console.log('not in view');
}
javascript jquery
javascript jquery
asked Nov 11 at 21:53
NewbCake
1261213
1261213
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