many to many field django how to join
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0
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I have no previous experience with many to many fields in django. This is the first time I´m using it, so I´m getting a little confused here.
So, this is what I have:
#models.py
class RefereciaCita(models.Model):
titulo = models.CharField(max_length=500, null=True, blank=True, help_text='título da pesquisa')
link = models.URLField(blank=True, null=True, help_text='link da pesquisa')
#pesquisador = models.ForeignKey('AutorPesquisa',null=True, blank=True,
#help_text='pesquisadores que participam da pesquisa', on_delete=models.SET_NULL)
pesq = models.ManyToManyField('AutoresPesq', related_name='autoresDaPesquisa',through='AutorRef', verbose_name='pesquisador')
def __str__(self):
return self.titulo
class Meta:
verbose_name = "Referência bibliográfica"
verbose_name_plural = "Referências bibliográficas"
class AutoresPesq(models.Model):
nome = models.CharField(max_length=500, null=True, blank=True, help_text='nome do pesquisador')
link = models.URLField(blank=True, null=True, help_text='link do currículo do pesquisador')
pesquisa = models.ManyToManyField('RefereciaCita', through='AutorRef', verbose_name='pesquisador',
related_name='pesquisaDoAutor', help_text='pesquisa que o autor participa')
def __str__(self):
return self.nome
class Meta:
verbose_name = "Autores Pesquisa"
verbose_name_plural = "Autores Pesquisa"
class AutorRef(models.Model):
pesquisa = models.ForeignKey(RefereciaCita, null=True, related_name='pesquisarn',
help_text='pesquisa que o autor participa', on_delete=models.CASCADE)
pesquisador = models.ForeignKey(AutoresPesq, null=True, related_name='autorDaPesquisa',
help_text='pesquisadores que participam da pesquisa', on_delete=models.CASCADE)
def __str__(self):
return self.pesquisador.nome + ", " + self.pesquisa.titulo[:190]
class Meta:
verbose_name = "Autor Pesquisa"
verbose_name_plural = "Autor Pesquisa"
I need to retrive, from each ReferenciaCita it´s respective(s) AutoresPesq
So in the template I would have something like the picture
So, I need to get for each 'researchPaper' it´s 'author'
But I´m getting confused with the queryset´s...
I´ve already tried with select_related and prefetch_related,
but I´m missing something here...
The middle table goes like this
Please help, I´m really stuck here, and have no clues...
django django-queryset jointable
add a comment |
up vote
0
down vote
favorite
I have no previous experience with many to many fields in django. This is the first time I´m using it, so I´m getting a little confused here.
So, this is what I have:
#models.py
class RefereciaCita(models.Model):
titulo = models.CharField(max_length=500, null=True, blank=True, help_text='título da pesquisa')
link = models.URLField(blank=True, null=True, help_text='link da pesquisa')
#pesquisador = models.ForeignKey('AutorPesquisa',null=True, blank=True,
#help_text='pesquisadores que participam da pesquisa', on_delete=models.SET_NULL)
pesq = models.ManyToManyField('AutoresPesq', related_name='autoresDaPesquisa',through='AutorRef', verbose_name='pesquisador')
def __str__(self):
return self.titulo
class Meta:
verbose_name = "Referência bibliográfica"
verbose_name_plural = "Referências bibliográficas"
class AutoresPesq(models.Model):
nome = models.CharField(max_length=500, null=True, blank=True, help_text='nome do pesquisador')
link = models.URLField(blank=True, null=True, help_text='link do currículo do pesquisador')
pesquisa = models.ManyToManyField('RefereciaCita', through='AutorRef', verbose_name='pesquisador',
related_name='pesquisaDoAutor', help_text='pesquisa que o autor participa')
def __str__(self):
return self.nome
class Meta:
verbose_name = "Autores Pesquisa"
verbose_name_plural = "Autores Pesquisa"
class AutorRef(models.Model):
pesquisa = models.ForeignKey(RefereciaCita, null=True, related_name='pesquisarn',
help_text='pesquisa que o autor participa', on_delete=models.CASCADE)
pesquisador = models.ForeignKey(AutoresPesq, null=True, related_name='autorDaPesquisa',
help_text='pesquisadores que participam da pesquisa', on_delete=models.CASCADE)
def __str__(self):
return self.pesquisador.nome + ", " + self.pesquisa.titulo[:190]
class Meta:
verbose_name = "Autor Pesquisa"
verbose_name_plural = "Autor Pesquisa"
I need to retrive, from each ReferenciaCita it´s respective(s) AutoresPesq
So in the template I would have something like the picture
So, I need to get for each 'researchPaper' it´s 'author'
But I´m getting confused with the queryset´s...
I´ve already tried with select_related and prefetch_related,
but I´m missing something here...
The middle table goes like this
Please help, I´m really stuck here, and have no clues...
django django-queryset jointable
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have no previous experience with many to many fields in django. This is the first time I´m using it, so I´m getting a little confused here.
So, this is what I have:
#models.py
class RefereciaCita(models.Model):
titulo = models.CharField(max_length=500, null=True, blank=True, help_text='título da pesquisa')
link = models.URLField(blank=True, null=True, help_text='link da pesquisa')
#pesquisador = models.ForeignKey('AutorPesquisa',null=True, blank=True,
#help_text='pesquisadores que participam da pesquisa', on_delete=models.SET_NULL)
pesq = models.ManyToManyField('AutoresPesq', related_name='autoresDaPesquisa',through='AutorRef', verbose_name='pesquisador')
def __str__(self):
return self.titulo
class Meta:
verbose_name = "Referência bibliográfica"
verbose_name_plural = "Referências bibliográficas"
class AutoresPesq(models.Model):
nome = models.CharField(max_length=500, null=True, blank=True, help_text='nome do pesquisador')
link = models.URLField(blank=True, null=True, help_text='link do currículo do pesquisador')
pesquisa = models.ManyToManyField('RefereciaCita', through='AutorRef', verbose_name='pesquisador',
related_name='pesquisaDoAutor', help_text='pesquisa que o autor participa')
def __str__(self):
return self.nome
class Meta:
verbose_name = "Autores Pesquisa"
verbose_name_plural = "Autores Pesquisa"
class AutorRef(models.Model):
pesquisa = models.ForeignKey(RefereciaCita, null=True, related_name='pesquisarn',
help_text='pesquisa que o autor participa', on_delete=models.CASCADE)
pesquisador = models.ForeignKey(AutoresPesq, null=True, related_name='autorDaPesquisa',
help_text='pesquisadores que participam da pesquisa', on_delete=models.CASCADE)
def __str__(self):
return self.pesquisador.nome + ", " + self.pesquisa.titulo[:190]
class Meta:
verbose_name = "Autor Pesquisa"
verbose_name_plural = "Autor Pesquisa"
I need to retrive, from each ReferenciaCita it´s respective(s) AutoresPesq
So in the template I would have something like the picture
So, I need to get for each 'researchPaper' it´s 'author'
But I´m getting confused with the queryset´s...
I´ve already tried with select_related and prefetch_related,
but I´m missing something here...
The middle table goes like this
Please help, I´m really stuck here, and have no clues...
django django-queryset jointable
I have no previous experience with many to many fields in django. This is the first time I´m using it, so I´m getting a little confused here.
So, this is what I have:
#models.py
class RefereciaCita(models.Model):
titulo = models.CharField(max_length=500, null=True, blank=True, help_text='título da pesquisa')
link = models.URLField(blank=True, null=True, help_text='link da pesquisa')
#pesquisador = models.ForeignKey('AutorPesquisa',null=True, blank=True,
#help_text='pesquisadores que participam da pesquisa', on_delete=models.SET_NULL)
pesq = models.ManyToManyField('AutoresPesq', related_name='autoresDaPesquisa',through='AutorRef', verbose_name='pesquisador')
def __str__(self):
return self.titulo
class Meta:
verbose_name = "Referência bibliográfica"
verbose_name_plural = "Referências bibliográficas"
class AutoresPesq(models.Model):
nome = models.CharField(max_length=500, null=True, blank=True, help_text='nome do pesquisador')
link = models.URLField(blank=True, null=True, help_text='link do currículo do pesquisador')
pesquisa = models.ManyToManyField('RefereciaCita', through='AutorRef', verbose_name='pesquisador',
related_name='pesquisaDoAutor', help_text='pesquisa que o autor participa')
def __str__(self):
return self.nome
class Meta:
verbose_name = "Autores Pesquisa"
verbose_name_plural = "Autores Pesquisa"
class AutorRef(models.Model):
pesquisa = models.ForeignKey(RefereciaCita, null=True, related_name='pesquisarn',
help_text='pesquisa que o autor participa', on_delete=models.CASCADE)
pesquisador = models.ForeignKey(AutoresPesq, null=True, related_name='autorDaPesquisa',
help_text='pesquisadores que participam da pesquisa', on_delete=models.CASCADE)
def __str__(self):
return self.pesquisador.nome + ", " + self.pesquisa.titulo[:190]
class Meta:
verbose_name = "Autor Pesquisa"
verbose_name_plural = "Autor Pesquisa"
I need to retrive, from each ReferenciaCita it´s respective(s) AutoresPesq
So in the template I would have something like the picture
So, I need to get for each 'researchPaper' it´s 'author'
But I´m getting confused with the queryset´s...
I´ve already tried with select_related and prefetch_related,
but I´m missing something here...
The middle table goes like this
Please help, I´m really stuck here, and have no clues...
django django-queryset jointable
django django-queryset jointable
asked Nov 11 at 18:57
Adriel Werlich
4319
4319
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
For your first question, you can do:
qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita
for referencia_cita in qs_referencia_cita:
for autores_pesq in referencia_cita.pesq.all():
# Use your autores_pesq
The rest is unclear what's you're asking.
PS: You don't need both relations as ManyToManyField
: The other relation is created automatically, see this part of the doc.
yes, thanks for the help... I´ve did like your example, but returned the following'RefereciaCita' object has no attribute 'autorespesq_set'
– Adriel Werlich
Nov 11 at 19:28
for rf in referencias: for au in rf.autorespesq_set.all(): print(au)
– Adriel Werlich
Nov 11 at 19:29
Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case,rf.pesq
is an object manager.
– Cyrlop
Nov 11 at 19:40
Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!
– Adriel Werlich
Nov 11 at 20:15
Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.
– Cyrlop
Nov 14 at 15:47
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
For your first question, you can do:
qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita
for referencia_cita in qs_referencia_cita:
for autores_pesq in referencia_cita.pesq.all():
# Use your autores_pesq
The rest is unclear what's you're asking.
PS: You don't need both relations as ManyToManyField
: The other relation is created automatically, see this part of the doc.
yes, thanks for the help... I´ve did like your example, but returned the following'RefereciaCita' object has no attribute 'autorespesq_set'
– Adriel Werlich
Nov 11 at 19:28
for rf in referencias: for au in rf.autorespesq_set.all(): print(au)
– Adriel Werlich
Nov 11 at 19:29
Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case,rf.pesq
is an object manager.
– Cyrlop
Nov 11 at 19:40
Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!
– Adriel Werlich
Nov 11 at 20:15
Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.
– Cyrlop
Nov 14 at 15:47
add a comment |
up vote
1
down vote
accepted
For your first question, you can do:
qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita
for referencia_cita in qs_referencia_cita:
for autores_pesq in referencia_cita.pesq.all():
# Use your autores_pesq
The rest is unclear what's you're asking.
PS: You don't need both relations as ManyToManyField
: The other relation is created automatically, see this part of the doc.
yes, thanks for the help... I´ve did like your example, but returned the following'RefereciaCita' object has no attribute 'autorespesq_set'
– Adriel Werlich
Nov 11 at 19:28
for rf in referencias: for au in rf.autorespesq_set.all(): print(au)
– Adriel Werlich
Nov 11 at 19:29
Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case,rf.pesq
is an object manager.
– Cyrlop
Nov 11 at 19:40
Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!
– Adriel Werlich
Nov 11 at 20:15
Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.
– Cyrlop
Nov 14 at 15:47
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
For your first question, you can do:
qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita
for referencia_cita in qs_referencia_cita:
for autores_pesq in referencia_cita.pesq.all():
# Use your autores_pesq
The rest is unclear what's you're asking.
PS: You don't need both relations as ManyToManyField
: The other relation is created automatically, see this part of the doc.
For your first question, you can do:
qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita
for referencia_cita in qs_referencia_cita:
for autores_pesq in referencia_cita.pesq.all():
# Use your autores_pesq
The rest is unclear what's you're asking.
PS: You don't need both relations as ManyToManyField
: The other relation is created automatically, see this part of the doc.
edited Nov 11 at 19:38
answered Nov 11 at 19:14
Cyrlop
1,3171818
1,3171818
yes, thanks for the help... I´ve did like your example, but returned the following'RefereciaCita' object has no attribute 'autorespesq_set'
– Adriel Werlich
Nov 11 at 19:28
for rf in referencias: for au in rf.autorespesq_set.all(): print(au)
– Adriel Werlich
Nov 11 at 19:29
Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case,rf.pesq
is an object manager.
– Cyrlop
Nov 11 at 19:40
Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!
– Adriel Werlich
Nov 11 at 20:15
Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.
– Cyrlop
Nov 14 at 15:47
add a comment |
yes, thanks for the help... I´ve did like your example, but returned the following'RefereciaCita' object has no attribute 'autorespesq_set'
– Adriel Werlich
Nov 11 at 19:28
for rf in referencias: for au in rf.autorespesq_set.all(): print(au)
– Adriel Werlich
Nov 11 at 19:29
Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case,rf.pesq
is an object manager.
– Cyrlop
Nov 11 at 19:40
Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!
– Adriel Werlich
Nov 11 at 20:15
Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.
– Cyrlop
Nov 14 at 15:47
yes, thanks for the help... I´ve did like your example, but returned the following
'RefereciaCita' object has no attribute 'autorespesq_set'
– Adriel Werlich
Nov 11 at 19:28
yes, thanks for the help... I´ve did like your example, but returned the following
'RefereciaCita' object has no attribute 'autorespesq_set'
– Adriel Werlich
Nov 11 at 19:28
for rf in referencias: for au in rf.autorespesq_set.all(): print(au)
– Adriel Werlich
Nov 11 at 19:29
for rf in referencias: for au in rf.autorespesq_set.all(): print(au)
– Adriel Werlich
Nov 11 at 19:29
Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case,
rf.pesq
is an object manager.– Cyrlop
Nov 11 at 19:40
Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case,
rf.pesq
is an object manager.– Cyrlop
Nov 11 at 19:40
Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!
– Adriel Werlich
Nov 11 at 20:15
Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!
– Adriel Werlich
Nov 11 at 20:15
Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.
– Cyrlop
Nov 14 at 15:47
Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.
– Cyrlop
Nov 14 at 15:47
add a comment |
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