numpy.argmin is giving me the maximum element index
I'm having some trouble with numpy and argmin. It seems as if argmin is returning the index of the maximum element. This sample code might clarify the case:
for i in range(20):
indmin = np.argmin(M[n-1, 1:-1])
print("M[n-1, indmin] = ", M[n-1, indmin])
print("indmin = ", indmin)
M[n-1, indmin] = inf
The output of this piece of code is:
M[n-1, indmin] = 5.806069439930625
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
...
M[n-1,-1:1] contains values ranging approximately from 0 to 15. What's happening here?
Edit:
n = 813;
inf = 100000000
Link to M dump:
[http://www.mediafire.com/file/wjbk11tiafjo3do/probarray/file][1]
numpy min
asked Nov 12 at 13:14
HastatusXXI
297
|
show 1 more comment
I'm having some trouble with numpy and argmin. It seems as if argmin is returning the index of the maximum element. This sample code might clarify the case:
for i in range(20):
indmin = np.argmin(M[n-1, 1:-1])
print("M[n-1, indmin] = ", M[n-1, indmin])
print("indmin = ", indmin)
M[n-1, indmin] = inf
The output of this piece of code is:
M[n-1, indmin] = 5.806069439930625
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
...
M[n-1,-1:1] contains values ranging approximately from 0 to 15. What's happening here?
Edit:
n = 813;
inf = 100000000
Link to M dump:
[http://www.mediafire.com/file/wjbk11tiafjo3do/probarray/file][1]
numpy min
asked Nov 12 at 13:14
HastatusXXI
297
1
Can you provideMso we can test your code?
– M. Doosti Lakhani
Nov 12 at 13:35
It would be easier for someone to help you if you provided a minimal, complete and verifiable example.
– Warren Weckesser
Nov 12 at 13:49
Yes, of course. I added a link to an M dump in my question and the corresponding value of n.
– HastatusXXI
Nov 12 at 14:35
Please, let me know if you have any problem loading M (I double checked it in my computer before uploading)
– HastatusXXI
Nov 12 at 15:27
The loop does not depend on i, is this the actual code that you ran?
– Pierre de Buyl
Nov 12 at 16:29
|
show 1 more comment
I'm having some trouble with numpy and argmin. It seems as if argmin is returning the index of the maximum element. This sample code might clarify the case:
for i in range(20):
indmin = np.argmin(M[n-1, 1:-1])
print("M[n-1, indmin] = ", M[n-1, indmin])
print("indmin = ", indmin)
M[n-1, indmin] = inf
The output of this piece of code is:
M[n-1, indmin] = 5.806069439930625
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
...
M[n-1,-1:1] contains values ranging approximately from 0 to 15. What's happening here?
Edit:
n = 813;
inf = 100000000
Link to M dump:
[http://www.mediafire.com/file/wjbk11tiafjo3do/probarray/file][1]
numpy min
asked Nov 12 at 13:14
HastatusXXI
297
I'm having some trouble with numpy and argmin. It seems as if argmin is returning the index of the maximum element. This sample code might clarify the case:
for i in range(20):
indmin = np.argmin(M[n-1, 1:-1])
print("M[n-1, indmin] = ", M[n-1, indmin])
print("indmin = ", indmin)
M[n-1, indmin] = inf
The output of this piece of code is:
M[n-1, indmin] = 5.806069439930625
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
M[n-1, indmin] = 100000000.0
indmin = 1150
...
M[n-1,-1:1] contains values ranging approximately from 0 to 15. What's happening here?
Edit:
n = 813;
inf = 100000000
Link to M dump:
[http://www.mediafire.com/file/wjbk11tiafjo3do/probarray/file][1]
numpy min
numpy min
asked Nov 12 at 13:14
HastatusXXI
297
asked Nov 12 at 13:14
HastatusXXI
297
edited Nov 12 at 14:34
asked Nov 12 at 13:14
HastatusXXI
297
asked Nov 12 at 13:14
HastatusXXI
297
asked Nov 12 at 13:14
HastatusXXI
297
297
1
Can you provideMso we can test your code?
– M. Doosti Lakhani
Nov 12 at 13:35
It would be easier for someone to help you if you provided a minimal, complete and verifiable example.
– Warren Weckesser
Nov 12 at 13:49
Yes, of course. I added a link to an M dump in my question and the corresponding value of n.
– HastatusXXI
Nov 12 at 14:35
Please, let me know if you have any problem loading M (I double checked it in my computer before uploading)
– HastatusXXI
Nov 12 at 15:27
The loop does not depend on i, is this the actual code that you ran?
– Pierre de Buyl
Nov 12 at 16:29
|
show 1 more comment
1
Can you provideMso we can test your code?
– M. Doosti Lakhani
Nov 12 at 13:35
It would be easier for someone to help you if you provided a minimal, complete and verifiable example.
– Warren Weckesser
Nov 12 at 13:49
Yes, of course. I added a link to an M dump in my question and the corresponding value of n.
– HastatusXXI
Nov 12 at 14:35
Please, let me know if you have any problem loading M (I double checked it in my computer before uploading)
– HastatusXXI
Nov 12 at 15:27
The loop does not depend on i, is this the actual code that you ran?
– Pierre de Buyl
Nov 12 at 16:29
1
1
Can you provide
M so we can test your code?– M. Doosti Lakhani
Nov 12 at 13:35
Can you provide
M so we can test your code?– M. Doosti Lakhani
Nov 12 at 13:35
It would be easier for someone to help you if you provided a minimal, complete and verifiable example.
– Warren Weckesser
Nov 12 at 13:49
It would be easier for someone to help you if you provided a minimal, complete and verifiable example.
– Warren Weckesser
Nov 12 at 13:49
Yes, of course. I added a link to an M dump in my question and the corresponding value of n.
– HastatusXXI
Nov 12 at 14:35
Yes, of course. I added a link to an M dump in my question and the corresponding value of n.
– HastatusXXI
Nov 12 at 14:35
Please, let me know if you have any problem loading M (I double checked it in my computer before uploading)
– HastatusXXI
Nov 12 at 15:27
Please, let me know if you have any problem loading M (I double checked it in my computer before uploading)
– HastatusXXI
Nov 12 at 15:27
The loop does not depend on i, is this the actual code that you ran?
– Pierre de Buyl
Nov 12 at 16:29
The loop does not depend on i, is this the actual code that you ran?
– Pierre de Buyl
Nov 12 at 16:29
|
show 1 more comment
1 Answer
1
active
oldest
votes
Try:
for i in range(20):
indmin = np.argmin(M[n-1, 1:-1])
print("M[n-1, indmin] = ", M[n-1, indmin])
print("indmin = ", indmin)
M[n-1, indmin+1] = inf # correction, the argmin was taken with an offset of 1
The argument to argmin is M[n-1, 1:-1] so the index you obtain is not one that matches the indexing of M. There is a shift of 1.
answered Nov 12 at 21:21
Pierre de Buyl
4,7982916
add a comment |
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Try:
for i in range(20):
indmin = np.argmin(M[n-1, 1:-1])
print("M[n-1, indmin] = ", M[n-1, indmin])
print("indmin = ", indmin)
M[n-1, indmin+1] = inf # correction, the argmin was taken with an offset of 1
The argument to argmin is M[n-1, 1:-1] so the index you obtain is not one that matches the indexing of M. There is a shift of 1.
answered Nov 12 at 21:21
Pierre de Buyl
4,7982916
add a comment |
Try:
for i in range(20):
indmin = np.argmin(M[n-1, 1:-1])
print("M[n-1, indmin] = ", M[n-1, indmin])
print("indmin = ", indmin)
M[n-1, indmin+1] = inf # correction, the argmin was taken with an offset of 1
The argument to argmin is M[n-1, 1:-1] so the index you obtain is not one that matches the indexing of M. There is a shift of 1.
answered Nov 12 at 21:21
Pierre de Buyl
4,7982916
add a comment |
Try:
for i in range(20):
indmin = np.argmin(M[n-1, 1:-1])
print("M[n-1, indmin] = ", M[n-1, indmin])
print("indmin = ", indmin)
M[n-1, indmin+1] = inf # correction, the argmin was taken with an offset of 1
The argument to argmin is M[n-1, 1:-1] so the index you obtain is not one that matches the indexing of M. There is a shift of 1.
answered Nov 12 at 21:21
Pierre de Buyl
4,7982916
Try:
for i in range(20):
indmin = np.argmin(M[n-1, 1:-1])
print("M[n-1, indmin] = ", M[n-1, indmin])
print("indmin = ", indmin)
M[n-1, indmin+1] = inf # correction, the argmin was taken with an offset of 1
The argument to argmin is M[n-1, 1:-1] so the index you obtain is not one that matches the indexing of M. There is a shift of 1.
answered Nov 12 at 21:21
Pierre de Buyl
4,7982916
answered Nov 12 at 21:21
Pierre de Buyl
4,7982916
answered Nov 12 at 21:21
Pierre de Buyl
4,7982916
answered Nov 12 at 21:21
Pierre de Buyl
4,7982916
4,7982916
add a comment |
add a comment |
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1
Can you provide
Mso we can test your code?– M. Doosti Lakhani
Nov 12 at 13:35
It would be easier for someone to help you if you provided a minimal, complete and verifiable example.
– Warren Weckesser
Nov 12 at 13:49
Yes, of course. I added a link to an M dump in my question and the corresponding value of n.
– HastatusXXI
Nov 12 at 14:35
Please, let me know if you have any problem loading M (I double checked it in my computer before uploading)
– HastatusXXI
Nov 12 at 15:27
The loop does not depend on i, is this the actual code that you ran?
– Pierre de Buyl
Nov 12 at 16:29