DAG: Symmetric closure of transitive closure vs. transitive closure of symmetric closure










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Am I right in deducing that if I apply first the transitive closure tran() on a directed acyclic graph and then the symmetric closure sym(), the result is different than if I first apply the symmetric closure and then the transitive closure. In the latter case, the reflexive closure is also computed (indirectly).



sym(tran(dag)) != tran(sym(dag))


A-->B-->C : (A,B),(B,C) =tran=> (A,B),(B,C),(A,C) =sym=> (A,B),(B,A),(B,C),(C,B),(A,C),(C,A)



A-->B-->C : (A,B),(B,C) =sym=> (A,B),(B,A),(B,C),(C,B) =tran=> (A,B),(B,A),(A,A),(B,C),(C,B),(B,B),(A,C),(C,A),(C,C)










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    Am I right in deducing that if I apply first the transitive closure tran() on a directed acyclic graph and then the symmetric closure sym(), the result is different than if I first apply the symmetric closure and then the transitive closure. In the latter case, the reflexive closure is also computed (indirectly).



    sym(tran(dag)) != tran(sym(dag))


    A-->B-->C : (A,B),(B,C) =tran=> (A,B),(B,C),(A,C) =sym=> (A,B),(B,A),(B,C),(C,B),(A,C),(C,A)



    A-->B-->C : (A,B),(B,C) =sym=> (A,B),(B,A),(B,C),(C,B) =tran=> (A,B),(B,A),(A,A),(B,C),(C,B),(B,B),(A,C),(C,A),(C,C)










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      Am I right in deducing that if I apply first the transitive closure tran() on a directed acyclic graph and then the symmetric closure sym(), the result is different than if I first apply the symmetric closure and then the transitive closure. In the latter case, the reflexive closure is also computed (indirectly).



      sym(tran(dag)) != tran(sym(dag))


      A-->B-->C : (A,B),(B,C) =tran=> (A,B),(B,C),(A,C) =sym=> (A,B),(B,A),(B,C),(C,B),(A,C),(C,A)



      A-->B-->C : (A,B),(B,C) =sym=> (A,B),(B,A),(B,C),(C,B) =tran=> (A,B),(B,A),(A,A),(B,C),(C,B),(B,B),(A,C),(C,A),(C,C)










      share|improve this question













      Am I right in deducing that if I apply first the transitive closure tran() on a directed acyclic graph and then the symmetric closure sym(), the result is different than if I first apply the symmetric closure and then the transitive closure. In the latter case, the reflexive closure is also computed (indirectly).



      sym(tran(dag)) != tran(sym(dag))


      A-->B-->C : (A,B),(B,C) =tran=> (A,B),(B,C),(A,C) =sym=> (A,B),(B,A),(B,C),(C,B),(A,C),(C,A)



      A-->B-->C : (A,B),(B,C) =sym=> (A,B),(B,A),(B,C),(C,B) =tran=> (A,B),(B,A),(A,A),(B,C),(C,B),(B,B),(A,C),(C,A),(C,C)







      closures directed-acyclic-graphs associativity symmetric transitive-closure






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      asked Nov 12 at 12:54









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