adding elements to a vector in R










1















I'm trying to create a function that simulate dolling m dice, n times, calculate the minimum of the outcome of the dice in each roll and then calculate the mean of the minimum and store the values into a vector.



mindice = function(n = 10, m = 3)

v <- vector
for(i in 1:10)

minima= numeric(n)
for(i in 1:n)

minima[i] = min(sample(6,m,replace=T))

v[i] = mean(minima)

v



I'm calling the function like that: mindice()
and the output is: Error in v[i] <- mean(minima) : object of type 'closure' is not subsettable



any help will be appreciated










share|improve this question

















  • 2





    Try v <- vector(). The use of () invokes the function. Providing the function name alone makes v a copy of the function itself.

    – jdobres
    Nov 15 '18 at 13:29











  • I think you probably want for (i in 1:n), not 1:10.

    – Gregor
    Nov 15 '18 at 14:09











  • Also, I just want to clarify: your code seems to be calculating the cumulative mean of the minima - is that what you want? Or do you just want to overall mean?

    – Gregor
    Nov 15 '18 at 14:31











  • stackoverflow.com/questions/45866523/… :-)

    – Oliver Humphreys
    Nov 15 '18 at 15:01















1















I'm trying to create a function that simulate dolling m dice, n times, calculate the minimum of the outcome of the dice in each roll and then calculate the mean of the minimum and store the values into a vector.



mindice = function(n = 10, m = 3)

v <- vector
for(i in 1:10)

minima= numeric(n)
for(i in 1:n)

minima[i] = min(sample(6,m,replace=T))

v[i] = mean(minima)

v



I'm calling the function like that: mindice()
and the output is: Error in v[i] <- mean(minima) : object of type 'closure' is not subsettable



any help will be appreciated










share|improve this question

















  • 2





    Try v <- vector(). The use of () invokes the function. Providing the function name alone makes v a copy of the function itself.

    – jdobres
    Nov 15 '18 at 13:29











  • I think you probably want for (i in 1:n), not 1:10.

    – Gregor
    Nov 15 '18 at 14:09











  • Also, I just want to clarify: your code seems to be calculating the cumulative mean of the minima - is that what you want? Or do you just want to overall mean?

    – Gregor
    Nov 15 '18 at 14:31











  • stackoverflow.com/questions/45866523/… :-)

    – Oliver Humphreys
    Nov 15 '18 at 15:01













1












1








1








I'm trying to create a function that simulate dolling m dice, n times, calculate the minimum of the outcome of the dice in each roll and then calculate the mean of the minimum and store the values into a vector.



mindice = function(n = 10, m = 3)

v <- vector
for(i in 1:10)

minima= numeric(n)
for(i in 1:n)

minima[i] = min(sample(6,m,replace=T))

v[i] = mean(minima)

v



I'm calling the function like that: mindice()
and the output is: Error in v[i] <- mean(minima) : object of type 'closure' is not subsettable



any help will be appreciated










share|improve this question














I'm trying to create a function that simulate dolling m dice, n times, calculate the minimum of the outcome of the dice in each roll and then calculate the mean of the minimum and store the values into a vector.



mindice = function(n = 10, m = 3)

v <- vector
for(i in 1:10)

minima= numeric(n)
for(i in 1:n)

minima[i] = min(sample(6,m,replace=T))

v[i] = mean(minima)

v



I'm calling the function like that: mindice()
and the output is: Error in v[i] <- mean(minima) : object of type 'closure' is not subsettable



any help will be appreciated







r






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 15 '18 at 13:24









Umar Sheikh SalemUmar Sheikh Salem

73




73







  • 2





    Try v <- vector(). The use of () invokes the function. Providing the function name alone makes v a copy of the function itself.

    – jdobres
    Nov 15 '18 at 13:29











  • I think you probably want for (i in 1:n), not 1:10.

    – Gregor
    Nov 15 '18 at 14:09











  • Also, I just want to clarify: your code seems to be calculating the cumulative mean of the minima - is that what you want? Or do you just want to overall mean?

    – Gregor
    Nov 15 '18 at 14:31











  • stackoverflow.com/questions/45866523/… :-)

    – Oliver Humphreys
    Nov 15 '18 at 15:01












  • 2





    Try v <- vector(). The use of () invokes the function. Providing the function name alone makes v a copy of the function itself.

    – jdobres
    Nov 15 '18 at 13:29











  • I think you probably want for (i in 1:n), not 1:10.

    – Gregor
    Nov 15 '18 at 14:09











  • Also, I just want to clarify: your code seems to be calculating the cumulative mean of the minima - is that what you want? Or do you just want to overall mean?

    – Gregor
    Nov 15 '18 at 14:31











  • stackoverflow.com/questions/45866523/… :-)

    – Oliver Humphreys
    Nov 15 '18 at 15:01







2




2





Try v <- vector(). The use of () invokes the function. Providing the function name alone makes v a copy of the function itself.

– jdobres
Nov 15 '18 at 13:29





Try v <- vector(). The use of () invokes the function. Providing the function name alone makes v a copy of the function itself.

– jdobres
Nov 15 '18 at 13:29













I think you probably want for (i in 1:n), not 1:10.

– Gregor
Nov 15 '18 at 14:09





I think you probably want for (i in 1:n), not 1:10.

– Gregor
Nov 15 '18 at 14:09













Also, I just want to clarify: your code seems to be calculating the cumulative mean of the minima - is that what you want? Or do you just want to overall mean?

– Gregor
Nov 15 '18 at 14:31





Also, I just want to clarify: your code seems to be calculating the cumulative mean of the minima - is that what you want? Or do you just want to overall mean?

– Gregor
Nov 15 '18 at 14:31













stackoverflow.com/questions/45866523/… :-)

– Oliver Humphreys
Nov 15 '18 at 15:01





stackoverflow.com/questions/45866523/… :-)

– Oliver Humphreys
Nov 15 '18 at 15:01












2 Answers
2






active

oldest

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0














I don't know if this fits your expectations. This function returns both the vector for the minimum per roll and their average



mindice <- function(n = 10, m = 3)

minima <- vector("numeric")
for(i in 1:n)
minima = c(minima, min(sample(6,m,replace=T)))

list(minimum_values=minima,
mean_minima=mean(minima))

mindice()





share|improve this answer






























    0














    The comment about using v = vector() rather than v = vector should solve the bug in the way you've written the function. If you're interested in a more R-like way to do this function, try this:



    mindice2 = function(n = 10, m = 3) 
    rolls = sample(6, size = m * n, replace = TRUE)
    rolls = matrix(rolls, nrow = m)
    minima = apply(rolls, MARGIN = 2, FUN = min)
    cum_mean = cumsum(minima) / seq_along(minima)
    return(cum_mean)



    Rather than sampling each roll separately, we do all the rolls at once (more efficient), and then put them in a matrix where each column is a roll of m dice. We can then use apply to find the minima, and cumsum to calculate the mean minimum after each roll.






    share|improve this answer






















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      2 Answers
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      2 Answers
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      0














      I don't know if this fits your expectations. This function returns both the vector for the minimum per roll and their average



      mindice <- function(n = 10, m = 3)

      minima <- vector("numeric")
      for(i in 1:n)
      minima = c(minima, min(sample(6,m,replace=T)))

      list(minimum_values=minima,
      mean_minima=mean(minima))

      mindice()





      share|improve this answer



























        0














        I don't know if this fits your expectations. This function returns both the vector for the minimum per roll and their average



        mindice <- function(n = 10, m = 3)

        minima <- vector("numeric")
        for(i in 1:n)
        minima = c(minima, min(sample(6,m,replace=T)))

        list(minimum_values=minima,
        mean_minima=mean(minima))

        mindice()





        share|improve this answer

























          0












          0








          0







          I don't know if this fits your expectations. This function returns both the vector for the minimum per roll and their average



          mindice <- function(n = 10, m = 3)

          minima <- vector("numeric")
          for(i in 1:n)
          minima = c(minima, min(sample(6,m,replace=T)))

          list(minimum_values=minima,
          mean_minima=mean(minima))

          mindice()





          share|improve this answer













          I don't know if this fits your expectations. This function returns both the vector for the minimum per roll and their average



          mindice <- function(n = 10, m = 3)

          minima <- vector("numeric")
          for(i in 1:n)
          minima = c(minima, min(sample(6,m,replace=T)))

          list(minimum_values=minima,
          mean_minima=mean(minima))

          mindice()






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 13:53









          paoloeusebipaoloeusebi

          641414




          641414























              0














              The comment about using v = vector() rather than v = vector should solve the bug in the way you've written the function. If you're interested in a more R-like way to do this function, try this:



              mindice2 = function(n = 10, m = 3) 
              rolls = sample(6, size = m * n, replace = TRUE)
              rolls = matrix(rolls, nrow = m)
              minima = apply(rolls, MARGIN = 2, FUN = min)
              cum_mean = cumsum(minima) / seq_along(minima)
              return(cum_mean)



              Rather than sampling each roll separately, we do all the rolls at once (more efficient), and then put them in a matrix where each column is a roll of m dice. We can then use apply to find the minima, and cumsum to calculate the mean minimum after each roll.






              share|improve this answer



























                0














                The comment about using v = vector() rather than v = vector should solve the bug in the way you've written the function. If you're interested in a more R-like way to do this function, try this:



                mindice2 = function(n = 10, m = 3) 
                rolls = sample(6, size = m * n, replace = TRUE)
                rolls = matrix(rolls, nrow = m)
                minima = apply(rolls, MARGIN = 2, FUN = min)
                cum_mean = cumsum(minima) / seq_along(minima)
                return(cum_mean)



                Rather than sampling each roll separately, we do all the rolls at once (more efficient), and then put them in a matrix where each column is a roll of m dice. We can then use apply to find the minima, and cumsum to calculate the mean minimum after each roll.






                share|improve this answer

























                  0












                  0








                  0







                  The comment about using v = vector() rather than v = vector should solve the bug in the way you've written the function. If you're interested in a more R-like way to do this function, try this:



                  mindice2 = function(n = 10, m = 3) 
                  rolls = sample(6, size = m * n, replace = TRUE)
                  rolls = matrix(rolls, nrow = m)
                  minima = apply(rolls, MARGIN = 2, FUN = min)
                  cum_mean = cumsum(minima) / seq_along(minima)
                  return(cum_mean)



                  Rather than sampling each roll separately, we do all the rolls at once (more efficient), and then put them in a matrix where each column is a roll of m dice. We can then use apply to find the minima, and cumsum to calculate the mean minimum after each roll.






                  share|improve this answer













                  The comment about using v = vector() rather than v = vector should solve the bug in the way you've written the function. If you're interested in a more R-like way to do this function, try this:



                  mindice2 = function(n = 10, m = 3) 
                  rolls = sample(6, size = m * n, replace = TRUE)
                  rolls = matrix(rolls, nrow = m)
                  minima = apply(rolls, MARGIN = 2, FUN = min)
                  cum_mean = cumsum(minima) / seq_along(minima)
                  return(cum_mean)



                  Rather than sampling each roll separately, we do all the rolls at once (more efficient), and then put them in a matrix where each column is a roll of m dice. We can then use apply to find the minima, and cumsum to calculate the mean minimum after each roll.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 15 '18 at 14:37









                  GregorGregor

                  66.8k1092176




                  66.8k1092176



























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