Please I have A playfair cipher, it converts String inputs to Int, but I want Hex
import java.util.ArrayList;
import java.util.LinkedHashMap;
import java.util.Map;
This is the public class
public class Process
private String keywordAsString = "";
private String keyword = "";
// ArrayList to hold the letters of the keyword with duplicates removed.
private ArrayList<Integer> keywordAsIntsNoDup = new ArrayList<Integer>(0);
// Map for removing all duplicate letters in the keyword.
private Map<Integer, Integer> keywordLetters = new LinkedHashMap<Integer, Integer>(0);
// ArrayList to hold all 256 ASCII characters (as integers).
private ArrayList<Integer> asciiArray = new ArrayList<Integer>(0);
// ArrayList for storing the message from the file.
ArrayList<Integer> fileMessageAsInteger = new ArrayList<Integer>(0);
// Constructor
public void process()
public void processKeyword(String keyword)
// Copy incoming keyword String
this.keywordAsString = keyword;
// Pass incoming keyword String to the removeDuplicate method.
// removeDuplicate will first convert the letters to Integers,
// then remove any duplicate letters.
// Store the result in the keywordAsIntsNoDup ArrayList
this.keywordAsIntsNoDup = removeDuplicates(this.keywordAsString);
// Create ArrayList and fill it with all 256 ASCII characters (as integers).
createAsciiArr();
// Remove the keyword letters from the asciiArray.
for (int i=0; i<this.keywordAsIntsNoDup.size(); i++)
Integer letterToSearchFor = this.keywordAsIntsNoDup.get(i);
if (this.asciiArray.contains(letterToSearchFor))
this.asciiArray.remove(letterToSearchFor);
// END processKeyword()
public ArrayList<Integer> removeDuplicates(String keyword)
// Copy incoming keyword String
this.keyword = keyword;
I really would appreciate if someone would help me Java is really no piece of cake.
// Loop through the keywordAsIntArray ArrayList, putting each 'letter' of the keyword into the map.
// Duplicate letters will be overridden, so the map will contain the keyword without any duplicates.
for (int i=0; i
// Put the maps' key set (which holds the 'letters') into an ArrayList.
// This will make it easier to put the 'letters' into the Table later.
ArrayList<Integer> keyslist = new ArrayList<Integer>(this.keywordLetters.keySet());
System.out.println("n" + "map.keySet() from keyslist ArrayList = " + keyslist.toString());
return keyslist;
public void createAsciiArr()
// Use an enhanced for loop to fill the asciiArray ArrayList
// with all 256 ASCII characters as integers.
for (int i=0; i<256; i++)
this.asciiArray.add(i);
// END createAsciiArr()
// END class
Please I want to input String as keyword, then get back hex values as the encrypted code and not integers. Also Please I have more of the codes I dont really understand,am really new to Java. Please can anyone help me.
string integer hex
add a comment |
import java.util.ArrayList;
import java.util.LinkedHashMap;
import java.util.Map;
This is the public class
public class Process
private String keywordAsString = "";
private String keyword = "";
// ArrayList to hold the letters of the keyword with duplicates removed.
private ArrayList<Integer> keywordAsIntsNoDup = new ArrayList<Integer>(0);
// Map for removing all duplicate letters in the keyword.
private Map<Integer, Integer> keywordLetters = new LinkedHashMap<Integer, Integer>(0);
// ArrayList to hold all 256 ASCII characters (as integers).
private ArrayList<Integer> asciiArray = new ArrayList<Integer>(0);
// ArrayList for storing the message from the file.
ArrayList<Integer> fileMessageAsInteger = new ArrayList<Integer>(0);
// Constructor
public void process()
public void processKeyword(String keyword)
// Copy incoming keyword String
this.keywordAsString = keyword;
// Pass incoming keyword String to the removeDuplicate method.
// removeDuplicate will first convert the letters to Integers,
// then remove any duplicate letters.
// Store the result in the keywordAsIntsNoDup ArrayList
this.keywordAsIntsNoDup = removeDuplicates(this.keywordAsString);
// Create ArrayList and fill it with all 256 ASCII characters (as integers).
createAsciiArr();
// Remove the keyword letters from the asciiArray.
for (int i=0; i<this.keywordAsIntsNoDup.size(); i++)
Integer letterToSearchFor = this.keywordAsIntsNoDup.get(i);
if (this.asciiArray.contains(letterToSearchFor))
this.asciiArray.remove(letterToSearchFor);
// END processKeyword()
public ArrayList<Integer> removeDuplicates(String keyword)
// Copy incoming keyword String
this.keyword = keyword;
I really would appreciate if someone would help me Java is really no piece of cake.
// Loop through the keywordAsIntArray ArrayList, putting each 'letter' of the keyword into the map.
// Duplicate letters will be overridden, so the map will contain the keyword without any duplicates.
for (int i=0; i
// Put the maps' key set (which holds the 'letters') into an ArrayList.
// This will make it easier to put the 'letters' into the Table later.
ArrayList<Integer> keyslist = new ArrayList<Integer>(this.keywordLetters.keySet());
System.out.println("n" + "map.keySet() from keyslist ArrayList = " + keyslist.toString());
return keyslist;
public void createAsciiArr()
// Use an enhanced for loop to fill the asciiArray ArrayList
// with all 256 ASCII characters as integers.
for (int i=0; i<256; i++)
this.asciiArray.add(i);
// END createAsciiArr()
// END class
Please I want to input String as keyword, then get back hex values as the encrypted code and not integers. Also Please I have more of the codes I dont really understand,am really new to Java. Please can anyone help me.
string integer hex
1
Possible duplicate of Java converting int to hex and back again
– mx0
Nov 12 '18 at 17:26
From the question code: "all 256 ASCII characters". ASCII does not have 256 characters, it has about 95 displayable characters.
– zaph
Nov 12 '18 at 18:01
it is actually the expanded AScII which is 256
– Engr Arome
Nov 12 '18 at 21:09
Consider: Is 0x00 an ASCII character? 0x08?
– zaph
Nov 13 '18 at 7:26
add a comment |
import java.util.ArrayList;
import java.util.LinkedHashMap;
import java.util.Map;
This is the public class
public class Process
private String keywordAsString = "";
private String keyword = "";
// ArrayList to hold the letters of the keyword with duplicates removed.
private ArrayList<Integer> keywordAsIntsNoDup = new ArrayList<Integer>(0);
// Map for removing all duplicate letters in the keyword.
private Map<Integer, Integer> keywordLetters = new LinkedHashMap<Integer, Integer>(0);
// ArrayList to hold all 256 ASCII characters (as integers).
private ArrayList<Integer> asciiArray = new ArrayList<Integer>(0);
// ArrayList for storing the message from the file.
ArrayList<Integer> fileMessageAsInteger = new ArrayList<Integer>(0);
// Constructor
public void process()
public void processKeyword(String keyword)
// Copy incoming keyword String
this.keywordAsString = keyword;
// Pass incoming keyword String to the removeDuplicate method.
// removeDuplicate will first convert the letters to Integers,
// then remove any duplicate letters.
// Store the result in the keywordAsIntsNoDup ArrayList
this.keywordAsIntsNoDup = removeDuplicates(this.keywordAsString);
// Create ArrayList and fill it with all 256 ASCII characters (as integers).
createAsciiArr();
// Remove the keyword letters from the asciiArray.
for (int i=0; i<this.keywordAsIntsNoDup.size(); i++)
Integer letterToSearchFor = this.keywordAsIntsNoDup.get(i);
if (this.asciiArray.contains(letterToSearchFor))
this.asciiArray.remove(letterToSearchFor);
// END processKeyword()
public ArrayList<Integer> removeDuplicates(String keyword)
// Copy incoming keyword String
this.keyword = keyword;
I really would appreciate if someone would help me Java is really no piece of cake.
// Loop through the keywordAsIntArray ArrayList, putting each 'letter' of the keyword into the map.
// Duplicate letters will be overridden, so the map will contain the keyword without any duplicates.
for (int i=0; i
// Put the maps' key set (which holds the 'letters') into an ArrayList.
// This will make it easier to put the 'letters' into the Table later.
ArrayList<Integer> keyslist = new ArrayList<Integer>(this.keywordLetters.keySet());
System.out.println("n" + "map.keySet() from keyslist ArrayList = " + keyslist.toString());
return keyslist;
public void createAsciiArr()
// Use an enhanced for loop to fill the asciiArray ArrayList
// with all 256 ASCII characters as integers.
for (int i=0; i<256; i++)
this.asciiArray.add(i);
// END createAsciiArr()
// END class
Please I want to input String as keyword, then get back hex values as the encrypted code and not integers. Also Please I have more of the codes I dont really understand,am really new to Java. Please can anyone help me.
string integer hex
import java.util.ArrayList;
import java.util.LinkedHashMap;
import java.util.Map;
This is the public class
public class Process
private String keywordAsString = "";
private String keyword = "";
// ArrayList to hold the letters of the keyword with duplicates removed.
private ArrayList<Integer> keywordAsIntsNoDup = new ArrayList<Integer>(0);
// Map for removing all duplicate letters in the keyword.
private Map<Integer, Integer> keywordLetters = new LinkedHashMap<Integer, Integer>(0);
// ArrayList to hold all 256 ASCII characters (as integers).
private ArrayList<Integer> asciiArray = new ArrayList<Integer>(0);
// ArrayList for storing the message from the file.
ArrayList<Integer> fileMessageAsInteger = new ArrayList<Integer>(0);
// Constructor
public void process()
public void processKeyword(String keyword)
// Copy incoming keyword String
this.keywordAsString = keyword;
// Pass incoming keyword String to the removeDuplicate method.
// removeDuplicate will first convert the letters to Integers,
// then remove any duplicate letters.
// Store the result in the keywordAsIntsNoDup ArrayList
this.keywordAsIntsNoDup = removeDuplicates(this.keywordAsString);
// Create ArrayList and fill it with all 256 ASCII characters (as integers).
createAsciiArr();
// Remove the keyword letters from the asciiArray.
for (int i=0; i<this.keywordAsIntsNoDup.size(); i++)
Integer letterToSearchFor = this.keywordAsIntsNoDup.get(i);
if (this.asciiArray.contains(letterToSearchFor))
this.asciiArray.remove(letterToSearchFor);
// END processKeyword()
public ArrayList<Integer> removeDuplicates(String keyword)
// Copy incoming keyword String
this.keyword = keyword;
I really would appreciate if someone would help me Java is really no piece of cake.
// Loop through the keywordAsIntArray ArrayList, putting each 'letter' of the keyword into the map.
// Duplicate letters will be overridden, so the map will contain the keyword without any duplicates.
for (int i=0; i
// Put the maps' key set (which holds the 'letters') into an ArrayList.
// This will make it easier to put the 'letters' into the Table later.
ArrayList<Integer> keyslist = new ArrayList<Integer>(this.keywordLetters.keySet());
System.out.println("n" + "map.keySet() from keyslist ArrayList = " + keyslist.toString());
return keyslist;
public void createAsciiArr()
// Use an enhanced for loop to fill the asciiArray ArrayList
// with all 256 ASCII characters as integers.
for (int i=0; i<256; i++)
this.asciiArray.add(i);
// END createAsciiArr()
// END class
Please I want to input String as keyword, then get back hex values as the encrypted code and not integers. Also Please I have more of the codes I dont really understand,am really new to Java. Please can anyone help me.
string integer hex
string integer hex
asked Nov 12 '18 at 16:16
Engr Arome
41
41
1
Possible duplicate of Java converting int to hex and back again
– mx0
Nov 12 '18 at 17:26
From the question code: "all 256 ASCII characters". ASCII does not have 256 characters, it has about 95 displayable characters.
– zaph
Nov 12 '18 at 18:01
it is actually the expanded AScII which is 256
– Engr Arome
Nov 12 '18 at 21:09
Consider: Is 0x00 an ASCII character? 0x08?
– zaph
Nov 13 '18 at 7:26
add a comment |
1
Possible duplicate of Java converting int to hex and back again
– mx0
Nov 12 '18 at 17:26
From the question code: "all 256 ASCII characters". ASCII does not have 256 characters, it has about 95 displayable characters.
– zaph
Nov 12 '18 at 18:01
it is actually the expanded AScII which is 256
– Engr Arome
Nov 12 '18 at 21:09
Consider: Is 0x00 an ASCII character? 0x08?
– zaph
Nov 13 '18 at 7:26
1
1
Possible duplicate of Java converting int to hex and back again
– mx0
Nov 12 '18 at 17:26
Possible duplicate of Java converting int to hex and back again
– mx0
Nov 12 '18 at 17:26
From the question code: "all 256 ASCII characters". ASCII does not have 256 characters, it has about 95 displayable characters.
– zaph
Nov 12 '18 at 18:01
From the question code: "all 256 ASCII characters". ASCII does not have 256 characters, it has about 95 displayable characters.
– zaph
Nov 12 '18 at 18:01
it is actually the expanded AScII which is 256
– Engr Arome
Nov 12 '18 at 21:09
it is actually the expanded AScII which is 256
– Engr Arome
Nov 12 '18 at 21:09
Consider: Is 0x00 an ASCII character? 0x08?
– zaph
Nov 13 '18 at 7:26
Consider: Is 0x00 an ASCII character? 0x08?
– zaph
Nov 13 '18 at 7:26
add a comment |
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1
Possible duplicate of Java converting int to hex and back again
– mx0
Nov 12 '18 at 17:26
From the question code: "all 256 ASCII characters". ASCII does not have 256 characters, it has about 95 displayable characters.
– zaph
Nov 12 '18 at 18:01
it is actually the expanded AScII which is 256
– Engr Arome
Nov 12 '18 at 21:09
Consider: Is 0x00 an ASCII character? 0x08?
– zaph
Nov 13 '18 at 7:26