Dynamically access object property using variable










539














I'm trying to access a property of an object using a dynamic name. Is this possible?



const something = bar: "Foobar!" ;
const foo = 'bar';
something.foo; // The idea is to access something.bar, getting "Foobar!"









share|improve this question



















  • 3




    See also property access: dot notation vs. brackets? and How do I add a property to an object using a variable as the name?
    – Bergi
    Nov 18 '14 at 6:11















539














I'm trying to access a property of an object using a dynamic name. Is this possible?



const something = bar: "Foobar!" ;
const foo = 'bar';
something.foo; // The idea is to access something.bar, getting "Foobar!"









share|improve this question



















  • 3




    See also property access: dot notation vs. brackets? and How do I add a property to an object using a variable as the name?
    – Bergi
    Nov 18 '14 at 6:11













539












539








539


119





I'm trying to access a property of an object using a dynamic name. Is this possible?



const something = bar: "Foobar!" ;
const foo = 'bar';
something.foo; // The idea is to access something.bar, getting "Foobar!"









share|improve this question















I'm trying to access a property of an object using a dynamic name. Is this possible?



const something = bar: "Foobar!" ;
const foo = 'bar';
something.foo; // The idea is to access something.bar, getting "Foobar!"






javascript object properties






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 22 '17 at 16:12









Taryn

188k46286351




188k46286351










asked Nov 22 '10 at 11:23









RichW

3,25141729




3,25141729







  • 3




    See also property access: dot notation vs. brackets? and How do I add a property to an object using a variable as the name?
    – Bergi
    Nov 18 '14 at 6:11












  • 3




    See also property access: dot notation vs. brackets? and How do I add a property to an object using a variable as the name?
    – Bergi
    Nov 18 '14 at 6:11







3




3




See also property access: dot notation vs. brackets? and How do I add a property to an object using a variable as the name?
– Bergi
Nov 18 '14 at 6:11




See also property access: dot notation vs. brackets? and How do I add a property to an object using a variable as the name?
– Bergi
Nov 18 '14 at 6:11












11 Answers
11






active

oldest

votes


















713














There are two ways to access properties of an object:



  • Dot notation: something.bar

  • Bracket notation: something['bar']

The value between the brackets can be any expression. Therefore, if the property name is stored in a variable, you have to use bracket notation:



var foo = 'bar';
something[foo];
// both x = something[foo] and something[foo] = x work as expected





share|improve this answer


















  • 22




    careful with this: javascript compilers will error here since they dont rename strings but they do rename object properties
    – chacham15
    Dec 6 '11 at 8:40






  • 4




    Some more info on why this is possible: JS objects are associative arrays, that's why. Further Reading: quirksmode.org/js/associative.html stackoverflow.com/questions/14031368/…
    – dotnetguy
    Jun 3 '14 at 9:00










  • @dotnetguy No they are not. Arrays are objects that inherit from the plain JS object prototype and therefore you can add properties a go-go like any plain object. The 'associative' behaviour is more object-like than array like. You can't iterate the 'associative' version by simple index so it is not displaying array-like behaviour. You can define your 'associative' array as or and treat it the same in either case as far as random property access is concerned.
    – Vanquished Wombat
    Jan 3 '17 at 16:01






  • 2




    @VanquishedWombat Not sure what your objection pertains to? I did not say that JS Objects are arrays?
    – dotnetguy
    Jan 6 '17 at 0:30










  • as a reference to the correct answer , Reference
    – youhana
    Jun 8 '17 at 21:23



















46














This is my solution:



function resolve(path, obj) self)



Usage examples:



resolve("document.body.style.width")
// or
resolve("style.width", document.body)
// or even use array indexes
// (someObject has been defined in the question)
resolve("part.0.size", someObject)
// returns null when intermediate properties are not defined:
resolve('properties.that.do.not.exist', hello:'world')





share|improve this answer


















  • 4




    This is similar to lodash get
    – Moby Disk
    Dec 15 '17 at 14:06



















26














In javascript we can access with:



  • dot notation - foo.bar

  • square brackets - foo[someVar] or foo["string"]

But only second case allows to access properties dynamically:



var foo = pName1 : 1, pName2 : [1, foo : bar , 3] , ...

var name = "pName"
var num = 1;

foo[name + num]; // 1

// --

var a = 2;
var b = 1;
var c = "foo";

foo[name + a][b][c]; // bar





share|improve this answer
















  • 1




    I'm staring at 2,000 lines of if statements because the previous dev didn't use square brackets, and statically accessed object properties by dot notation. It's for an approval process app that has 7 different approvers and the steps are all the same. /rip
    – Chad
    Jun 7 '18 at 14:28



















16














Following is an ES6 example of how you can access the property of an object using a property name that has been dynamically generated by concatenating two strings.



var suffix = " name";

var person =
["first" + suffix]: "Nicholas",
["last" + suffix]: "Zakas"
;

console.log(person["first name"]); // "Nicholas"
console.log(person["last name"]); // "Zakas"


This is called computed property names






share|improve this answer






























    12














    You can achieve this in quite a few different ways.



    let foo = 
    bar: 'Hello World'
    ;

    foo.bar;
    foo['bar'];


    The bracket notation is specially powerful as it let's you access a property based on a variable:



    let foo = 
    bar: 'Hello World'
    ;

    let prop = 'bar';

    foo[prop];


    This can be extended to looping over every property of an object. This can be seem redundant due to newer JavaScript constructs such as for ... of ..., but helps illustrate a use case:



    let foo = 
    bar: 'Hello World',
    baz: 'How are you doing?',
    last: 'Quite alright'
    ;

    for (let prop in foo.getOwnPropertyNames())
    console.log(foo[prop]);



    Both dot and bracket notation also work as expected for nested objects:



    let foo = 
    bar:
    baz: 'Hello World'

    ;

    foo.bar.baz;
    foo['bar']['baz'];
    foo.bar['baz'];
    foo['bar'].baz;


    Object destructuring



    We could also consider object destructuring as a means to access a property in an object, but as follows:



    let foo = 
    bar: 'Hello World',
    baz: 'How are you doing?',
    last: 'Quite alright'
    ;

    let prop = 'last';
    let bar, baz, [prop]: customName = foo;

    // bar = 'Hello World'
    // baz = 'How are you doing?'
    // customName = 'Quite alright'





    share|improve this answer






























      4














      UPDATED



      I have take comments below into consideration and agreed. Eval is to be avoided.



      Accessing root properties in object is easily achieved with obj[variable], but getting nested complicates thing. Not to write already written code I suggest to use lodash.get.



      Example



      // Accessing root property
      var rootProp = 'rootPropert';
      _.get(object, rootProp, defaultValue);

      // Accessing nested property
      var listOfNestedProperties = [var1, var2];
      _.get(object, listOfNestedProperties);


      Lodash get can be used on different ways, here is link to the documentation lodash.get






      share|improve this answer


















      • 4




        It's best to avoid using eval whenever possible. stackoverflow.com/questions/86513/…
        – Luke
        Jun 23 '15 at 18:07






      • 7




        Using eval for something as trivial as accessing properties is plain overkill and hardly advisable under any circumstance. What's "trouble"? obj['nested']['test'] works very well and doesn't require you to embed code in strings.
        – Paul Stenne
        Oct 23 '15 at 10:14






      • 3




        eval is three times slower or more, I wouldn't recommend this to newbies because it might teach them bad habits. I use obj['nested']['value'] - remember kids, eval is evil!
        – jaggedsoft
        Nov 26 '15 at 1:25







      • 1




        @Luke He's now the only want to bring Lodash _.get to the table. I think this answer deserves now upvotes instead of downvotes. It may be overkill, but it's good to know it exists.
        – Emile Bergeron
        Dec 20 '16 at 21:42






      • 1




        Thank you for introducing lodash for this. I came here by google looking for a method to set a value deep in an object, and used their _.set method (which is identical to above but with the extra arguement for the value to set).
        – TPHughes
        Jul 3 '18 at 9:03


















      2














      Whenever you need to access property dynamically you have to use square bracket for accessing property not "." operator

      Syntax: object[propery}






      const something = bar: "Foobar!" ;
      const foo = 'bar';
      // something.foo; -- not correct way at it is expecting foo as proprty in something= foo: "value";
      // correct way is something[foo]
      alert( something[foo])








      share|improve this answer






























        2














        You can do it like this using Lodash get



        _.get(object, 'a[0].b.c');





        share|improve this answer






























          1














          It gets interesting when you have to pass parameters to this function as well.



          Code jsfiddle



          var obj = method:function(p1,p2,p3)console.log("method:",arguments)

          var str = "method('p1', 'p2', 'p3');"

          var match = str.match(/^s*(S+)((.*));s*$/);

          var func = match[1]
          var parameters = match[2].split(',');
          for(var i = 0; i < parameters.length; ++i)
          // clean up param begninning
          parameters[i] = parameters[i].replace(/^s*['"]?/,'');
          // clean up param end
          parameters[i] = parameters[i].replace(/['"]?s*$/,'');


          obj[func](parameters); // sends parameters as array
          obj[func].apply(this, parameters); // sends parameters as individual values





          share|improve this answer




























            -3














            You should use JSON.parse, take a look at https://www.w3schools.com/js/js_json_parse.asp



            const obj = JSON.parse(' "name":"John", "age":30, "city":"New York"')
            console.log(obj.name)
            console.log(obj.age)





            share|improve this answer




























              -4














              const something = bar: "Foobar!" ;
              const foo = 'bar';

              something[`$foo`];





              share|improve this answer


















              • 7




                Why on earth would you do that? Your foo is already a string, so `$foo` is exactly the same as foo. (Also, your code seems to have some extra backslashes that don't belong there. But it would still be pointless even if you fixed that syntax error.)
                – Ilmari Karonen
                Sep 19 '17 at 18:49










              protected by Samuel Liew Oct 5 '15 at 9:00



              Thank you for your interest in this question.
              Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).



              Would you like to answer one of these unanswered questions instead?














              11 Answers
              11






              active

              oldest

              votes








              11 Answers
              11






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              713














              There are two ways to access properties of an object:



              • Dot notation: something.bar

              • Bracket notation: something['bar']

              The value between the brackets can be any expression. Therefore, if the property name is stored in a variable, you have to use bracket notation:



              var foo = 'bar';
              something[foo];
              // both x = something[foo] and something[foo] = x work as expected





              share|improve this answer


















              • 22




                careful with this: javascript compilers will error here since they dont rename strings but they do rename object properties
                – chacham15
                Dec 6 '11 at 8:40






              • 4




                Some more info on why this is possible: JS objects are associative arrays, that's why. Further Reading: quirksmode.org/js/associative.html stackoverflow.com/questions/14031368/…
                – dotnetguy
                Jun 3 '14 at 9:00










              • @dotnetguy No they are not. Arrays are objects that inherit from the plain JS object prototype and therefore you can add properties a go-go like any plain object. The 'associative' behaviour is more object-like than array like. You can't iterate the 'associative' version by simple index so it is not displaying array-like behaviour. You can define your 'associative' array as or and treat it the same in either case as far as random property access is concerned.
                – Vanquished Wombat
                Jan 3 '17 at 16:01






              • 2




                @VanquishedWombat Not sure what your objection pertains to? I did not say that JS Objects are arrays?
                – dotnetguy
                Jan 6 '17 at 0:30










              • as a reference to the correct answer , Reference
                – youhana
                Jun 8 '17 at 21:23
















              713














              There are two ways to access properties of an object:



              • Dot notation: something.bar

              • Bracket notation: something['bar']

              The value between the brackets can be any expression. Therefore, if the property name is stored in a variable, you have to use bracket notation:



              var foo = 'bar';
              something[foo];
              // both x = something[foo] and something[foo] = x work as expected





              share|improve this answer


















              • 22




                careful with this: javascript compilers will error here since they dont rename strings but they do rename object properties
                – chacham15
                Dec 6 '11 at 8:40






              • 4




                Some more info on why this is possible: JS objects are associative arrays, that's why. Further Reading: quirksmode.org/js/associative.html stackoverflow.com/questions/14031368/…
                – dotnetguy
                Jun 3 '14 at 9:00










              • @dotnetguy No they are not. Arrays are objects that inherit from the plain JS object prototype and therefore you can add properties a go-go like any plain object. The 'associative' behaviour is more object-like than array like. You can't iterate the 'associative' version by simple index so it is not displaying array-like behaviour. You can define your 'associative' array as or and treat it the same in either case as far as random property access is concerned.
                – Vanquished Wombat
                Jan 3 '17 at 16:01






              • 2




                @VanquishedWombat Not sure what your objection pertains to? I did not say that JS Objects are arrays?
                – dotnetguy
                Jan 6 '17 at 0:30










              • as a reference to the correct answer , Reference
                – youhana
                Jun 8 '17 at 21:23














              713












              713








              713






              There are two ways to access properties of an object:



              • Dot notation: something.bar

              • Bracket notation: something['bar']

              The value between the brackets can be any expression. Therefore, if the property name is stored in a variable, you have to use bracket notation:



              var foo = 'bar';
              something[foo];
              // both x = something[foo] and something[foo] = x work as expected





              share|improve this answer














              There are two ways to access properties of an object:



              • Dot notation: something.bar

              • Bracket notation: something['bar']

              The value between the brackets can be any expression. Therefore, if the property name is stored in a variable, you have to use bracket notation:



              var foo = 'bar';
              something[foo];
              // both x = something[foo] and something[foo] = x work as expected






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Jan 2 '18 at 18:05









              Salman A

              175k66336424




              175k66336424










              answered Nov 22 '10 at 11:25









              Jan Hančič

              40.8k138189




              40.8k138189







              • 22




                careful with this: javascript compilers will error here since they dont rename strings but they do rename object properties
                – chacham15
                Dec 6 '11 at 8:40






              • 4




                Some more info on why this is possible: JS objects are associative arrays, that's why. Further Reading: quirksmode.org/js/associative.html stackoverflow.com/questions/14031368/…
                – dotnetguy
                Jun 3 '14 at 9:00










              • @dotnetguy No they are not. Arrays are objects that inherit from the plain JS object prototype and therefore you can add properties a go-go like any plain object. The 'associative' behaviour is more object-like than array like. You can't iterate the 'associative' version by simple index so it is not displaying array-like behaviour. You can define your 'associative' array as or and treat it the same in either case as far as random property access is concerned.
                – Vanquished Wombat
                Jan 3 '17 at 16:01






              • 2




                @VanquishedWombat Not sure what your objection pertains to? I did not say that JS Objects are arrays?
                – dotnetguy
                Jan 6 '17 at 0:30










              • as a reference to the correct answer , Reference
                – youhana
                Jun 8 '17 at 21:23













              • 22




                careful with this: javascript compilers will error here since they dont rename strings but they do rename object properties
                – chacham15
                Dec 6 '11 at 8:40






              • 4




                Some more info on why this is possible: JS objects are associative arrays, that's why. Further Reading: quirksmode.org/js/associative.html stackoverflow.com/questions/14031368/…
                – dotnetguy
                Jun 3 '14 at 9:00










              • @dotnetguy No they are not. Arrays are objects that inherit from the plain JS object prototype and therefore you can add properties a go-go like any plain object. The 'associative' behaviour is more object-like than array like. You can't iterate the 'associative' version by simple index so it is not displaying array-like behaviour. You can define your 'associative' array as or and treat it the same in either case as far as random property access is concerned.
                – Vanquished Wombat
                Jan 3 '17 at 16:01






              • 2




                @VanquishedWombat Not sure what your objection pertains to? I did not say that JS Objects are arrays?
                – dotnetguy
                Jan 6 '17 at 0:30










              • as a reference to the correct answer , Reference
                – youhana
                Jun 8 '17 at 21:23








              22




              22




              careful with this: javascript compilers will error here since they dont rename strings but they do rename object properties
              – chacham15
              Dec 6 '11 at 8:40




              careful with this: javascript compilers will error here since they dont rename strings but they do rename object properties
              – chacham15
              Dec 6 '11 at 8:40




              4




              4




              Some more info on why this is possible: JS objects are associative arrays, that's why. Further Reading: quirksmode.org/js/associative.html stackoverflow.com/questions/14031368/…
              – dotnetguy
              Jun 3 '14 at 9:00




              Some more info on why this is possible: JS objects are associative arrays, that's why. Further Reading: quirksmode.org/js/associative.html stackoverflow.com/questions/14031368/…
              – dotnetguy
              Jun 3 '14 at 9:00












              @dotnetguy No they are not. Arrays are objects that inherit from the plain JS object prototype and therefore you can add properties a go-go like any plain object. The 'associative' behaviour is more object-like than array like. You can't iterate the 'associative' version by simple index so it is not displaying array-like behaviour. You can define your 'associative' array as or and treat it the same in either case as far as random property access is concerned.
              – Vanquished Wombat
              Jan 3 '17 at 16:01




              @dotnetguy No they are not. Arrays are objects that inherit from the plain JS object prototype and therefore you can add properties a go-go like any plain object. The 'associative' behaviour is more object-like than array like. You can't iterate the 'associative' version by simple index so it is not displaying array-like behaviour. You can define your 'associative' array as or and treat it the same in either case as far as random property access is concerned.
              – Vanquished Wombat
              Jan 3 '17 at 16:01




              2




              2




              @VanquishedWombat Not sure what your objection pertains to? I did not say that JS Objects are arrays?
              – dotnetguy
              Jan 6 '17 at 0:30




              @VanquishedWombat Not sure what your objection pertains to? I did not say that JS Objects are arrays?
              – dotnetguy
              Jan 6 '17 at 0:30












              as a reference to the correct answer , Reference
              – youhana
              Jun 8 '17 at 21:23





              as a reference to the correct answer , Reference
              – youhana
              Jun 8 '17 at 21:23














              46














              This is my solution:



              function resolve(path, obj) self)



              Usage examples:



              resolve("document.body.style.width")
              // or
              resolve("style.width", document.body)
              // or even use array indexes
              // (someObject has been defined in the question)
              resolve("part.0.size", someObject)
              // returns null when intermediate properties are not defined:
              resolve('properties.that.do.not.exist', hello:'world')





              share|improve this answer


















              • 4




                This is similar to lodash get
                – Moby Disk
                Dec 15 '17 at 14:06
















              46














              This is my solution:



              function resolve(path, obj) self)



              Usage examples:



              resolve("document.body.style.width")
              // or
              resolve("style.width", document.body)
              // or even use array indexes
              // (someObject has been defined in the question)
              resolve("part.0.size", someObject)
              // returns null when intermediate properties are not defined:
              resolve('properties.that.do.not.exist', hello:'world')





              share|improve this answer


















              • 4




                This is similar to lodash get
                – Moby Disk
                Dec 15 '17 at 14:06














              46












              46








              46






              This is my solution:



              function resolve(path, obj) self)



              Usage examples:



              resolve("document.body.style.width")
              // or
              resolve("style.width", document.body)
              // or even use array indexes
              // (someObject has been defined in the question)
              resolve("part.0.size", someObject)
              // returns null when intermediate properties are not defined:
              resolve('properties.that.do.not.exist', hello:'world')





              share|improve this answer














              This is my solution:



              function resolve(path, obj) self)



              Usage examples:



              resolve("document.body.style.width")
              // or
              resolve("style.width", document.body)
              // or even use array indexes
              // (someObject has been defined in the question)
              resolve("part.0.size", someObject)
              // returns null when intermediate properties are not defined:
              resolve('properties.that.do.not.exist', hello:'world')






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Sep 23 '17 at 14:45









              GeekyDeaks

              500511




              500511










              answered Jul 26 '17 at 8:57









              abahet

              3,13111819




              3,13111819







              • 4




                This is similar to lodash get
                – Moby Disk
                Dec 15 '17 at 14:06













              • 4




                This is similar to lodash get
                – Moby Disk
                Dec 15 '17 at 14:06








              4




              4




              This is similar to lodash get
              – Moby Disk
              Dec 15 '17 at 14:06





              This is similar to lodash get
              – Moby Disk
              Dec 15 '17 at 14:06












              26














              In javascript we can access with:



              • dot notation - foo.bar

              • square brackets - foo[someVar] or foo["string"]

              But only second case allows to access properties dynamically:



              var foo = pName1 : 1, pName2 : [1, foo : bar , 3] , ...

              var name = "pName"
              var num = 1;

              foo[name + num]; // 1

              // --

              var a = 2;
              var b = 1;
              var c = "foo";

              foo[name + a][b][c]; // bar





              share|improve this answer
















              • 1




                I'm staring at 2,000 lines of if statements because the previous dev didn't use square brackets, and statically accessed object properties by dot notation. It's for an approval process app that has 7 different approvers and the steps are all the same. /rip
                – Chad
                Jun 7 '18 at 14:28
















              26














              In javascript we can access with:



              • dot notation - foo.bar

              • square brackets - foo[someVar] or foo["string"]

              But only second case allows to access properties dynamically:



              var foo = pName1 : 1, pName2 : [1, foo : bar , 3] , ...

              var name = "pName"
              var num = 1;

              foo[name + num]; // 1

              // --

              var a = 2;
              var b = 1;
              var c = "foo";

              foo[name + a][b][c]; // bar





              share|improve this answer
















              • 1




                I'm staring at 2,000 lines of if statements because the previous dev didn't use square brackets, and statically accessed object properties by dot notation. It's for an approval process app that has 7 different approvers and the steps are all the same. /rip
                – Chad
                Jun 7 '18 at 14:28














              26












              26








              26






              In javascript we can access with:



              • dot notation - foo.bar

              • square brackets - foo[someVar] or foo["string"]

              But only second case allows to access properties dynamically:



              var foo = pName1 : 1, pName2 : [1, foo : bar , 3] , ...

              var name = "pName"
              var num = 1;

              foo[name + num]; // 1

              // --

              var a = 2;
              var b = 1;
              var c = "foo";

              foo[name + a][b][c]; // bar





              share|improve this answer












              In javascript we can access with:



              • dot notation - foo.bar

              • square brackets - foo[someVar] or foo["string"]

              But only second case allows to access properties dynamically:



              var foo = pName1 : 1, pName2 : [1, foo : bar , 3] , ...

              var name = "pName"
              var num = 1;

              foo[name + num]; // 1

              // --

              var a = 2;
              var b = 1;
              var c = "foo";

              foo[name + a][b][c]; // bar






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Jul 1 '14 at 15:40









              Sonique

              2,36042540




              2,36042540







              • 1




                I'm staring at 2,000 lines of if statements because the previous dev didn't use square brackets, and statically accessed object properties by dot notation. It's for an approval process app that has 7 different approvers and the steps are all the same. /rip
                – Chad
                Jun 7 '18 at 14:28













              • 1




                I'm staring at 2,000 lines of if statements because the previous dev didn't use square brackets, and statically accessed object properties by dot notation. It's for an approval process app that has 7 different approvers and the steps are all the same. /rip
                – Chad
                Jun 7 '18 at 14:28








              1




              1




              I'm staring at 2,000 lines of if statements because the previous dev didn't use square brackets, and statically accessed object properties by dot notation. It's for an approval process app that has 7 different approvers and the steps are all the same. /rip
              – Chad
              Jun 7 '18 at 14:28





              I'm staring at 2,000 lines of if statements because the previous dev didn't use square brackets, and statically accessed object properties by dot notation. It's for an approval process app that has 7 different approvers and the steps are all the same. /rip
              – Chad
              Jun 7 '18 at 14:28












              16














              Following is an ES6 example of how you can access the property of an object using a property name that has been dynamically generated by concatenating two strings.



              var suffix = " name";

              var person =
              ["first" + suffix]: "Nicholas",
              ["last" + suffix]: "Zakas"
              ;

              console.log(person["first name"]); // "Nicholas"
              console.log(person["last name"]); // "Zakas"


              This is called computed property names






              share|improve this answer



























                16














                Following is an ES6 example of how you can access the property of an object using a property name that has been dynamically generated by concatenating two strings.



                var suffix = " name";

                var person =
                ["first" + suffix]: "Nicholas",
                ["last" + suffix]: "Zakas"
                ;

                console.log(person["first name"]); // "Nicholas"
                console.log(person["last name"]); // "Zakas"


                This is called computed property names






                share|improve this answer

























                  16












                  16








                  16






                  Following is an ES6 example of how you can access the property of an object using a property name that has been dynamically generated by concatenating two strings.



                  var suffix = " name";

                  var person =
                  ["first" + suffix]: "Nicholas",
                  ["last" + suffix]: "Zakas"
                  ;

                  console.log(person["first name"]); // "Nicholas"
                  console.log(person["last name"]); // "Zakas"


                  This is called computed property names






                  share|improve this answer














                  Following is an ES6 example of how you can access the property of an object using a property name that has been dynamically generated by concatenating two strings.



                  var suffix = " name";

                  var person =
                  ["first" + suffix]: "Nicholas",
                  ["last" + suffix]: "Zakas"
                  ;

                  console.log(person["first name"]); // "Nicholas"
                  console.log(person["last name"]); // "Zakas"


                  This is called computed property names







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Jul 10 '17 at 6:11









                  try-catch-finally

                  4,75342451




                  4,75342451










                  answered Aug 2 '16 at 19:46









                  zloctb

                  4,69834148




                  4,69834148





















                      12














                      You can achieve this in quite a few different ways.



                      let foo = 
                      bar: 'Hello World'
                      ;

                      foo.bar;
                      foo['bar'];


                      The bracket notation is specially powerful as it let's you access a property based on a variable:



                      let foo = 
                      bar: 'Hello World'
                      ;

                      let prop = 'bar';

                      foo[prop];


                      This can be extended to looping over every property of an object. This can be seem redundant due to newer JavaScript constructs such as for ... of ..., but helps illustrate a use case:



                      let foo = 
                      bar: 'Hello World',
                      baz: 'How are you doing?',
                      last: 'Quite alright'
                      ;

                      for (let prop in foo.getOwnPropertyNames())
                      console.log(foo[prop]);



                      Both dot and bracket notation also work as expected for nested objects:



                      let foo = 
                      bar:
                      baz: 'Hello World'

                      ;

                      foo.bar.baz;
                      foo['bar']['baz'];
                      foo.bar['baz'];
                      foo['bar'].baz;


                      Object destructuring



                      We could also consider object destructuring as a means to access a property in an object, but as follows:



                      let foo = 
                      bar: 'Hello World',
                      baz: 'How are you doing?',
                      last: 'Quite alright'
                      ;

                      let prop = 'last';
                      let bar, baz, [prop]: customName = foo;

                      // bar = 'Hello World'
                      // baz = 'How are you doing?'
                      // customName = 'Quite alright'





                      share|improve this answer



























                        12














                        You can achieve this in quite a few different ways.



                        let foo = 
                        bar: 'Hello World'
                        ;

                        foo.bar;
                        foo['bar'];


                        The bracket notation is specially powerful as it let's you access a property based on a variable:



                        let foo = 
                        bar: 'Hello World'
                        ;

                        let prop = 'bar';

                        foo[prop];


                        This can be extended to looping over every property of an object. This can be seem redundant due to newer JavaScript constructs such as for ... of ..., but helps illustrate a use case:



                        let foo = 
                        bar: 'Hello World',
                        baz: 'How are you doing?',
                        last: 'Quite alright'
                        ;

                        for (let prop in foo.getOwnPropertyNames())
                        console.log(foo[prop]);



                        Both dot and bracket notation also work as expected for nested objects:



                        let foo = 
                        bar:
                        baz: 'Hello World'

                        ;

                        foo.bar.baz;
                        foo['bar']['baz'];
                        foo.bar['baz'];
                        foo['bar'].baz;


                        Object destructuring



                        We could also consider object destructuring as a means to access a property in an object, but as follows:



                        let foo = 
                        bar: 'Hello World',
                        baz: 'How are you doing?',
                        last: 'Quite alright'
                        ;

                        let prop = 'last';
                        let bar, baz, [prop]: customName = foo;

                        // bar = 'Hello World'
                        // baz = 'How are you doing?'
                        // customName = 'Quite alright'





                        share|improve this answer

























                          12












                          12








                          12






                          You can achieve this in quite a few different ways.



                          let foo = 
                          bar: 'Hello World'
                          ;

                          foo.bar;
                          foo['bar'];


                          The bracket notation is specially powerful as it let's you access a property based on a variable:



                          let foo = 
                          bar: 'Hello World'
                          ;

                          let prop = 'bar';

                          foo[prop];


                          This can be extended to looping over every property of an object. This can be seem redundant due to newer JavaScript constructs such as for ... of ..., but helps illustrate a use case:



                          let foo = 
                          bar: 'Hello World',
                          baz: 'How are you doing?',
                          last: 'Quite alright'
                          ;

                          for (let prop in foo.getOwnPropertyNames())
                          console.log(foo[prop]);



                          Both dot and bracket notation also work as expected for nested objects:



                          let foo = 
                          bar:
                          baz: 'Hello World'

                          ;

                          foo.bar.baz;
                          foo['bar']['baz'];
                          foo.bar['baz'];
                          foo['bar'].baz;


                          Object destructuring



                          We could also consider object destructuring as a means to access a property in an object, but as follows:



                          let foo = 
                          bar: 'Hello World',
                          baz: 'How are you doing?',
                          last: 'Quite alright'
                          ;

                          let prop = 'last';
                          let bar, baz, [prop]: customName = foo;

                          // bar = 'Hello World'
                          // baz = 'How are you doing?'
                          // customName = 'Quite alright'





                          share|improve this answer














                          You can achieve this in quite a few different ways.



                          let foo = 
                          bar: 'Hello World'
                          ;

                          foo.bar;
                          foo['bar'];


                          The bracket notation is specially powerful as it let's you access a property based on a variable:



                          let foo = 
                          bar: 'Hello World'
                          ;

                          let prop = 'bar';

                          foo[prop];


                          This can be extended to looping over every property of an object. This can be seem redundant due to newer JavaScript constructs such as for ... of ..., but helps illustrate a use case:



                          let foo = 
                          bar: 'Hello World',
                          baz: 'How are you doing?',
                          last: 'Quite alright'
                          ;

                          for (let prop in foo.getOwnPropertyNames())
                          console.log(foo[prop]);



                          Both dot and bracket notation also work as expected for nested objects:



                          let foo = 
                          bar:
                          baz: 'Hello World'

                          ;

                          foo.bar.baz;
                          foo['bar']['baz'];
                          foo.bar['baz'];
                          foo['bar'].baz;


                          Object destructuring



                          We could also consider object destructuring as a means to access a property in an object, but as follows:



                          let foo = 
                          bar: 'Hello World',
                          baz: 'How are you doing?',
                          last: 'Quite alright'
                          ;

                          let prop = 'last';
                          let bar, baz, [prop]: customName = foo;

                          // bar = 'Hello World'
                          // baz = 'How are you doing?'
                          // customName = 'Quite alright'






                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Dec 13 '17 at 8:06

























                          answered Mar 8 '17 at 11:30









                          Gorka Hernandez

                          2,317823




                          2,317823





















                              4














                              UPDATED



                              I have take comments below into consideration and agreed. Eval is to be avoided.



                              Accessing root properties in object is easily achieved with obj[variable], but getting nested complicates thing. Not to write already written code I suggest to use lodash.get.



                              Example



                              // Accessing root property
                              var rootProp = 'rootPropert';
                              _.get(object, rootProp, defaultValue);

                              // Accessing nested property
                              var listOfNestedProperties = [var1, var2];
                              _.get(object, listOfNestedProperties);


                              Lodash get can be used on different ways, here is link to the documentation lodash.get






                              share|improve this answer


















                              • 4




                                It's best to avoid using eval whenever possible. stackoverflow.com/questions/86513/…
                                – Luke
                                Jun 23 '15 at 18:07






                              • 7




                                Using eval for something as trivial as accessing properties is plain overkill and hardly advisable under any circumstance. What's "trouble"? obj['nested']['test'] works very well and doesn't require you to embed code in strings.
                                – Paul Stenne
                                Oct 23 '15 at 10:14






                              • 3




                                eval is three times slower or more, I wouldn't recommend this to newbies because it might teach them bad habits. I use obj['nested']['value'] - remember kids, eval is evil!
                                – jaggedsoft
                                Nov 26 '15 at 1:25







                              • 1




                                @Luke He's now the only want to bring Lodash _.get to the table. I think this answer deserves now upvotes instead of downvotes. It may be overkill, but it's good to know it exists.
                                – Emile Bergeron
                                Dec 20 '16 at 21:42






                              • 1




                                Thank you for introducing lodash for this. I came here by google looking for a method to set a value deep in an object, and used their _.set method (which is identical to above but with the extra arguement for the value to set).
                                – TPHughes
                                Jul 3 '18 at 9:03















                              4














                              UPDATED



                              I have take comments below into consideration and agreed. Eval is to be avoided.



                              Accessing root properties in object is easily achieved with obj[variable], but getting nested complicates thing. Not to write already written code I suggest to use lodash.get.



                              Example



                              // Accessing root property
                              var rootProp = 'rootPropert';
                              _.get(object, rootProp, defaultValue);

                              // Accessing nested property
                              var listOfNestedProperties = [var1, var2];
                              _.get(object, listOfNestedProperties);


                              Lodash get can be used on different ways, here is link to the documentation lodash.get






                              share|improve this answer


















                              • 4




                                It's best to avoid using eval whenever possible. stackoverflow.com/questions/86513/…
                                – Luke
                                Jun 23 '15 at 18:07






                              • 7




                                Using eval for something as trivial as accessing properties is plain overkill and hardly advisable under any circumstance. What's "trouble"? obj['nested']['test'] works very well and doesn't require you to embed code in strings.
                                – Paul Stenne
                                Oct 23 '15 at 10:14






                              • 3




                                eval is three times slower or more, I wouldn't recommend this to newbies because it might teach them bad habits. I use obj['nested']['value'] - remember kids, eval is evil!
                                – jaggedsoft
                                Nov 26 '15 at 1:25







                              • 1




                                @Luke He's now the only want to bring Lodash _.get to the table. I think this answer deserves now upvotes instead of downvotes. It may be overkill, but it's good to know it exists.
                                – Emile Bergeron
                                Dec 20 '16 at 21:42






                              • 1




                                Thank you for introducing lodash for this. I came here by google looking for a method to set a value deep in an object, and used their _.set method (which is identical to above but with the extra arguement for the value to set).
                                – TPHughes
                                Jul 3 '18 at 9:03













                              4












                              4








                              4






                              UPDATED



                              I have take comments below into consideration and agreed. Eval is to be avoided.



                              Accessing root properties in object is easily achieved with obj[variable], but getting nested complicates thing. Not to write already written code I suggest to use lodash.get.



                              Example



                              // Accessing root property
                              var rootProp = 'rootPropert';
                              _.get(object, rootProp, defaultValue);

                              // Accessing nested property
                              var listOfNestedProperties = [var1, var2];
                              _.get(object, listOfNestedProperties);


                              Lodash get can be used on different ways, here is link to the documentation lodash.get






                              share|improve this answer














                              UPDATED



                              I have take comments below into consideration and agreed. Eval is to be avoided.



                              Accessing root properties in object is easily achieved with obj[variable], but getting nested complicates thing. Not to write already written code I suggest to use lodash.get.



                              Example



                              // Accessing root property
                              var rootProp = 'rootPropert';
                              _.get(object, rootProp, defaultValue);

                              // Accessing nested property
                              var listOfNestedProperties = [var1, var2];
                              _.get(object, listOfNestedProperties);


                              Lodash get can be used on different ways, here is link to the documentation lodash.get







                              share|improve this answer














                              share|improve this answer



                              share|improve this answer








                              edited Jun 19 '18 at 9:29

























                              answered Jun 22 '15 at 8:10









                              Mr Br

                              1,519916




                              1,519916







                              • 4




                                It's best to avoid using eval whenever possible. stackoverflow.com/questions/86513/…
                                – Luke
                                Jun 23 '15 at 18:07






                              • 7




                                Using eval for something as trivial as accessing properties is plain overkill and hardly advisable under any circumstance. What's "trouble"? obj['nested']['test'] works very well and doesn't require you to embed code in strings.
                                – Paul Stenne
                                Oct 23 '15 at 10:14






                              • 3




                                eval is three times slower or more, I wouldn't recommend this to newbies because it might teach them bad habits. I use obj['nested']['value'] - remember kids, eval is evil!
                                – jaggedsoft
                                Nov 26 '15 at 1:25







                              • 1




                                @Luke He's now the only want to bring Lodash _.get to the table. I think this answer deserves now upvotes instead of downvotes. It may be overkill, but it's good to know it exists.
                                – Emile Bergeron
                                Dec 20 '16 at 21:42






                              • 1




                                Thank you for introducing lodash for this. I came here by google looking for a method to set a value deep in an object, and used their _.set method (which is identical to above but with the extra arguement for the value to set).
                                – TPHughes
                                Jul 3 '18 at 9:03












                              • 4




                                It's best to avoid using eval whenever possible. stackoverflow.com/questions/86513/…
                                – Luke
                                Jun 23 '15 at 18:07






                              • 7




                                Using eval for something as trivial as accessing properties is plain overkill and hardly advisable under any circumstance. What's "trouble"? obj['nested']['test'] works very well and doesn't require you to embed code in strings.
                                – Paul Stenne
                                Oct 23 '15 at 10:14






                              • 3




                                eval is three times slower or more, I wouldn't recommend this to newbies because it might teach them bad habits. I use obj['nested']['value'] - remember kids, eval is evil!
                                – jaggedsoft
                                Nov 26 '15 at 1:25







                              • 1




                                @Luke He's now the only want to bring Lodash _.get to the table. I think this answer deserves now upvotes instead of downvotes. It may be overkill, but it's good to know it exists.
                                – Emile Bergeron
                                Dec 20 '16 at 21:42






                              • 1




                                Thank you for introducing lodash for this. I came here by google looking for a method to set a value deep in an object, and used their _.set method (which is identical to above but with the extra arguement for the value to set).
                                – TPHughes
                                Jul 3 '18 at 9:03







                              4




                              4




                              It's best to avoid using eval whenever possible. stackoverflow.com/questions/86513/…
                              – Luke
                              Jun 23 '15 at 18:07




                              It's best to avoid using eval whenever possible. stackoverflow.com/questions/86513/…
                              – Luke
                              Jun 23 '15 at 18:07




                              7




                              7




                              Using eval for something as trivial as accessing properties is plain overkill and hardly advisable under any circumstance. What's "trouble"? obj['nested']['test'] works very well and doesn't require you to embed code in strings.
                              – Paul Stenne
                              Oct 23 '15 at 10:14




                              Using eval for something as trivial as accessing properties is plain overkill and hardly advisable under any circumstance. What's "trouble"? obj['nested']['test'] works very well and doesn't require you to embed code in strings.
                              – Paul Stenne
                              Oct 23 '15 at 10:14




                              3




                              3




                              eval is three times slower or more, I wouldn't recommend this to newbies because it might teach them bad habits. I use obj['nested']['value'] - remember kids, eval is evil!
                              – jaggedsoft
                              Nov 26 '15 at 1:25





                              eval is three times slower or more, I wouldn't recommend this to newbies because it might teach them bad habits. I use obj['nested']['value'] - remember kids, eval is evil!
                              – jaggedsoft
                              Nov 26 '15 at 1:25





                              1




                              1




                              @Luke He's now the only want to bring Lodash _.get to the table. I think this answer deserves now upvotes instead of downvotes. It may be overkill, but it's good to know it exists.
                              – Emile Bergeron
                              Dec 20 '16 at 21:42




                              @Luke He's now the only want to bring Lodash _.get to the table. I think this answer deserves now upvotes instead of downvotes. It may be overkill, but it's good to know it exists.
                              – Emile Bergeron
                              Dec 20 '16 at 21:42




                              1




                              1




                              Thank you for introducing lodash for this. I came here by google looking for a method to set a value deep in an object, and used their _.set method (which is identical to above but with the extra arguement for the value to set).
                              – TPHughes
                              Jul 3 '18 at 9:03




                              Thank you for introducing lodash for this. I came here by google looking for a method to set a value deep in an object, and used their _.set method (which is identical to above but with the extra arguement for the value to set).
                              – TPHughes
                              Jul 3 '18 at 9:03











                              2














                              Whenever you need to access property dynamically you have to use square bracket for accessing property not "." operator

                              Syntax: object[propery}






                              const something = bar: "Foobar!" ;
                              const foo = 'bar';
                              // something.foo; -- not correct way at it is expecting foo as proprty in something= foo: "value";
                              // correct way is something[foo]
                              alert( something[foo])








                              share|improve this answer



























                                2














                                Whenever you need to access property dynamically you have to use square bracket for accessing property not "." operator

                                Syntax: object[propery}






                                const something = bar: "Foobar!" ;
                                const foo = 'bar';
                                // something.foo; -- not correct way at it is expecting foo as proprty in something= foo: "value";
                                // correct way is something[foo]
                                alert( something[foo])








                                share|improve this answer

























                                  2












                                  2








                                  2






                                  Whenever you need to access property dynamically you have to use square bracket for accessing property not "." operator

                                  Syntax: object[propery}






                                  const something = bar: "Foobar!" ;
                                  const foo = 'bar';
                                  // something.foo; -- not correct way at it is expecting foo as proprty in something= foo: "value";
                                  // correct way is something[foo]
                                  alert( something[foo])








                                  share|improve this answer














                                  Whenever you need to access property dynamically you have to use square bracket for accessing property not "." operator

                                  Syntax: object[propery}






                                  const something = bar: "Foobar!" ;
                                  const foo = 'bar';
                                  // something.foo; -- not correct way at it is expecting foo as proprty in something= foo: "value";
                                  // correct way is something[foo]
                                  alert( something[foo])








                                  const something = bar: "Foobar!" ;
                                  const foo = 'bar';
                                  // something.foo; -- not correct way at it is expecting foo as proprty in something= foo: "value";
                                  // correct way is something[foo]
                                  alert( something[foo])





                                  const something = bar: "Foobar!" ;
                                  const foo = 'bar';
                                  // something.foo; -- not correct way at it is expecting foo as proprty in something= foo: "value";
                                  // correct way is something[foo]
                                  alert( something[foo])






                                  share|improve this answer














                                  share|improve this answer



                                  share|improve this answer








                                  edited Jul 31 '18 at 8:25









                                  Manasi

                                  434314




                                  434314










                                  answered Jul 31 '18 at 8:24









                                  Rupesh Agrawal

                                  607419




                                  607419





















                                      2














                                      You can do it like this using Lodash get



                                      _.get(object, 'a[0].b.c');





                                      share|improve this answer



























                                        2














                                        You can do it like this using Lodash get



                                        _.get(object, 'a[0].b.c');





                                        share|improve this answer

























                                          2












                                          2








                                          2






                                          You can do it like this using Lodash get



                                          _.get(object, 'a[0].b.c');





                                          share|improve this answer














                                          You can do it like this using Lodash get



                                          _.get(object, 'a[0].b.c');






                                          share|improve this answer














                                          share|improve this answer



                                          share|improve this answer








                                          edited Sep 6 '18 at 15:57









                                          JJJ

                                          29k147591




                                          29k147591










                                          answered Sep 6 '18 at 6:36









                                          shalonteoh

                                          2551311




                                          2551311





















                                              1














                                              It gets interesting when you have to pass parameters to this function as well.



                                              Code jsfiddle



                                              var obj = method:function(p1,p2,p3)console.log("method:",arguments)

                                              var str = "method('p1', 'p2', 'p3');"

                                              var match = str.match(/^s*(S+)((.*));s*$/);

                                              var func = match[1]
                                              var parameters = match[2].split(',');
                                              for(var i = 0; i < parameters.length; ++i)
                                              // clean up param begninning
                                              parameters[i] = parameters[i].replace(/^s*['"]?/,'');
                                              // clean up param end
                                              parameters[i] = parameters[i].replace(/['"]?s*$/,'');


                                              obj[func](parameters); // sends parameters as array
                                              obj[func].apply(this, parameters); // sends parameters as individual values





                                              share|improve this answer

























                                                1














                                                It gets interesting when you have to pass parameters to this function as well.



                                                Code jsfiddle



                                                var obj = method:function(p1,p2,p3)console.log("method:",arguments)

                                                var str = "method('p1', 'p2', 'p3');"

                                                var match = str.match(/^s*(S+)((.*));s*$/);

                                                var func = match[1]
                                                var parameters = match[2].split(',');
                                                for(var i = 0; i < parameters.length; ++i)
                                                // clean up param begninning
                                                parameters[i] = parameters[i].replace(/^s*['"]?/,'');
                                                // clean up param end
                                                parameters[i] = parameters[i].replace(/['"]?s*$/,'');


                                                obj[func](parameters); // sends parameters as array
                                                obj[func].apply(this, parameters); // sends parameters as individual values





                                                share|improve this answer























                                                  1












                                                  1








                                                  1






                                                  It gets interesting when you have to pass parameters to this function as well.



                                                  Code jsfiddle



                                                  var obj = method:function(p1,p2,p3)console.log("method:",arguments)

                                                  var str = "method('p1', 'p2', 'p3');"

                                                  var match = str.match(/^s*(S+)((.*));s*$/);

                                                  var func = match[1]
                                                  var parameters = match[2].split(',');
                                                  for(var i = 0; i < parameters.length; ++i)
                                                  // clean up param begninning
                                                  parameters[i] = parameters[i].replace(/^s*['"]?/,'');
                                                  // clean up param end
                                                  parameters[i] = parameters[i].replace(/['"]?s*$/,'');


                                                  obj[func](parameters); // sends parameters as array
                                                  obj[func].apply(this, parameters); // sends parameters as individual values





                                                  share|improve this answer












                                                  It gets interesting when you have to pass parameters to this function as well.



                                                  Code jsfiddle



                                                  var obj = method:function(p1,p2,p3)console.log("method:",arguments)

                                                  var str = "method('p1', 'p2', 'p3');"

                                                  var match = str.match(/^s*(S+)((.*));s*$/);

                                                  var func = match[1]
                                                  var parameters = match[2].split(',');
                                                  for(var i = 0; i < parameters.length; ++i)
                                                  // clean up param begninning
                                                  parameters[i] = parameters[i].replace(/^s*['"]?/,'');
                                                  // clean up param end
                                                  parameters[i] = parameters[i].replace(/['"]?s*$/,'');


                                                  obj[func](parameters); // sends parameters as array
                                                  obj[func].apply(this, parameters); // sends parameters as individual values






                                                  share|improve this answer












                                                  share|improve this answer



                                                  share|improve this answer










                                                  answered Nov 13 '16 at 17:37









                                                  Jacksonkr

                                                  17.7k34137234




                                                  17.7k34137234





















                                                      -3














                                                      You should use JSON.parse, take a look at https://www.w3schools.com/js/js_json_parse.asp



                                                      const obj = JSON.parse(' "name":"John", "age":30, "city":"New York"')
                                                      console.log(obj.name)
                                                      console.log(obj.age)





                                                      share|improve this answer

























                                                        -3














                                                        You should use JSON.parse, take a look at https://www.w3schools.com/js/js_json_parse.asp



                                                        const obj = JSON.parse(' "name":"John", "age":30, "city":"New York"')
                                                        console.log(obj.name)
                                                        console.log(obj.age)





                                                        share|improve this answer























                                                          -3












                                                          -3








                                                          -3






                                                          You should use JSON.parse, take a look at https://www.w3schools.com/js/js_json_parse.asp



                                                          const obj = JSON.parse(' "name":"John", "age":30, "city":"New York"')
                                                          console.log(obj.name)
                                                          console.log(obj.age)





                                                          share|improve this answer












                                                          You should use JSON.parse, take a look at https://www.w3schools.com/js/js_json_parse.asp



                                                          const obj = JSON.parse(' "name":"John", "age":30, "city":"New York"')
                                                          console.log(obj.name)
                                                          console.log(obj.age)






                                                          share|improve this answer












                                                          share|improve this answer



                                                          share|improve this answer










                                                          answered Jun 14 '17 at 21:42









                                                          onmyway133

                                                          24.4k14157190




                                                          24.4k14157190





















                                                              -4














                                                              const something = bar: "Foobar!" ;
                                                              const foo = 'bar';

                                                              something[`$foo`];





                                                              share|improve this answer


















                                                              • 7




                                                                Why on earth would you do that? Your foo is already a string, so `$foo` is exactly the same as foo. (Also, your code seems to have some extra backslashes that don't belong there. But it would still be pointless even if you fixed that syntax error.)
                                                                – Ilmari Karonen
                                                                Sep 19 '17 at 18:49
















                                                              -4














                                                              const something = bar: "Foobar!" ;
                                                              const foo = 'bar';

                                                              something[`$foo`];





                                                              share|improve this answer


















                                                              • 7




                                                                Why on earth would you do that? Your foo is already a string, so `$foo` is exactly the same as foo. (Also, your code seems to have some extra backslashes that don't belong there. But it would still be pointless even if you fixed that syntax error.)
                                                                – Ilmari Karonen
                                                                Sep 19 '17 at 18:49














                                                              -4












                                                              -4








                                                              -4






                                                              const something = bar: "Foobar!" ;
                                                              const foo = 'bar';

                                                              something[`$foo`];





                                                              share|improve this answer














                                                              const something = bar: "Foobar!" ;
                                                              const foo = 'bar';

                                                              something[`$foo`];






                                                              share|improve this answer














                                                              share|improve this answer



                                                              share|improve this answer








                                                              edited Sep 19 '17 at 17:12









                                                              Cody Gray

                                                              191k34373461




                                                              191k34373461










                                                              answered Jul 2 '17 at 19:04









                                                              Sergey

                                                              984




                                                              984







                                                              • 7




                                                                Why on earth would you do that? Your foo is already a string, so `$foo` is exactly the same as foo. (Also, your code seems to have some extra backslashes that don't belong there. But it would still be pointless even if you fixed that syntax error.)
                                                                – Ilmari Karonen
                                                                Sep 19 '17 at 18:49













                                                              • 7




                                                                Why on earth would you do that? Your foo is already a string, so `$foo` is exactly the same as foo. (Also, your code seems to have some extra backslashes that don't belong there. But it would still be pointless even if you fixed that syntax error.)
                                                                – Ilmari Karonen
                                                                Sep 19 '17 at 18:49








                                                              7




                                                              7




                                                              Why on earth would you do that? Your foo is already a string, so `$foo` is exactly the same as foo. (Also, your code seems to have some extra backslashes that don't belong there. But it would still be pointless even if you fixed that syntax error.)
                                                              – Ilmari Karonen
                                                              Sep 19 '17 at 18:49





                                                              Why on earth would you do that? Your foo is already a string, so `$foo` is exactly the same as foo. (Also, your code seems to have some extra backslashes that don't belong there. But it would still be pointless even if you fixed that syntax error.)
                                                              – Ilmari Karonen
                                                              Sep 19 '17 at 18:49






                                                              protected by Samuel Liew Oct 5 '15 at 9:00



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