How to get an array of unique values of a specific key provided I only have an array of id's of that object using ES6
0
I have a store set up for a list of candidate objects like this
const candidatesStore = [
id: 1, status: active
id:2, status: inactive
id: 3 status: failed
id: 4 status:inactive
id: 5 status:failed
.
... and so on ]
I only have the list of id's in an array, ex: requiredArray = [2,3,4]
How to get a list of unique statuses by just using requiredArray using ES6 in the most efficient way
The result should be [inactive, failed]
I preferably want to use reduce to get unique value, and find to get the list of candidates from candidatesStore
javascript ecmascript-6
asked Nov 12 '18 at 19:53
Anand Dharne
62
add a comment |
0
I have a store set up for a list of candidate objects like this
const candidatesStore = [
id: 1, status: active
id:2, status: inactive
id: 3 status: failed
id: 4 status:inactive
id: 5 status:failed
.
... and so on ]
I only have the list of id's in an array, ex: requiredArray = [2,3,4]
How to get a list of unique statuses by just using requiredArray using ES6 in the most efficient way
The result should be [inactive, failed]
I preferably want to use reduce to get unique value, and find to get the list of candidates from candidatesStore
javascript ecmascript-6
asked Nov 12 '18 at 19:53
Anand Dharne
62
What's going on with thesecandidate1 =assignments in your array literal?
– Bergi
Nov 12 '18 at 19:59
How aboutArray.from(new Set(candidatesStore.filter(cand => requiredArray.includes(cand.id)).map(cand => cand.status)))? I don't see howreduceorfindcould be useful here.
– Bergi
Nov 12 '18 at 20:00
add a comment |
0
0
0
I have a store set up for a list of candidate objects like this
const candidatesStore = [
id: 1, status: active
id:2, status: inactive
id: 3 status: failed
id: 4 status:inactive
id: 5 status:failed
.
... and so on ]
I only have the list of id's in an array, ex: requiredArray = [2,3,4]
How to get a list of unique statuses by just using requiredArray using ES6 in the most efficient way
The result should be [inactive, failed]
I preferably want to use reduce to get unique value, and find to get the list of candidates from candidatesStore
javascript ecmascript-6
asked Nov 12 '18 at 19:53
Anand Dharne
62
I have a store set up for a list of candidate objects like this
const candidatesStore = [
id: 1, status: active
id:2, status: inactive
id: 3 status: failed
id: 4 status:inactive
id: 5 status:failed
.
... and so on ]
I only have the list of id's in an array, ex: requiredArray = [2,3,4]
How to get a list of unique statuses by just using requiredArray using ES6 in the most efficient way
The result should be [inactive, failed]
I preferably want to use reduce to get unique value, and find to get the list of candidates from candidatesStore
javascript ecmascript-6
javascript ecmascript-6
asked Nov 12 '18 at 19:53
Anand Dharne
62
asked Nov 12 '18 at 19:53
Anand Dharne
62
edited Nov 13 '18 at 22:23
asked Nov 12 '18 at 19:53
Anand Dharne
62
asked Nov 12 '18 at 19:53
Anand Dharne
62
asked Nov 12 '18 at 19:53
Anand Dharne
62
62
What's going on with thesecandidate1 =assignments in your array literal?
– Bergi
Nov 12 '18 at 19:59
How aboutArray.from(new Set(candidatesStore.filter(cand => requiredArray.includes(cand.id)).map(cand => cand.status)))? I don't see howreduceorfindcould be useful here.
– Bergi
Nov 12 '18 at 20:00
add a comment |
What's going on with thesecandidate1 =assignments in your array literal?
– Bergi
Nov 12 '18 at 19:59
How aboutArray.from(new Set(candidatesStore.filter(cand => requiredArray.includes(cand.id)).map(cand => cand.status)))? I don't see howreduceorfindcould be useful here.
– Bergi
Nov 12 '18 at 20:00
What's going on with these
candidate1 = assignments in your array literal?– Bergi
Nov 12 '18 at 19:59
What's going on with these
candidate1 = assignments in your array literal?– Bergi
Nov 12 '18 at 19:59
How about
Array.from(new Set(candidatesStore.filter(cand => requiredArray.includes(cand.id)).map(cand => cand.status)))? I don't see how reduce or find could be useful here.– Bergi
Nov 12 '18 at 20:00
How about
Array.from(new Set(candidatesStore.filter(cand => requiredArray.includes(cand.id)).map(cand => cand.status)))? I don't see how reduce or find could be useful here.– Bergi
Nov 12 '18 at 20:00
add a comment |
2 Answers
2
active
oldest
votes
1
You can use "reduce" as well as "filter" for this.
Note - I have to change your input object little bit as "candidate1 = ..." was not making much sense here.
const candidates = [
id: 1, status: 'active'
,id: 2, status: 'inactive'
,id: 3, status: 'failed'
,id: 4, status: 'inactive'
,id: 5, status: 'failed'
]
const requiredArray = [2,3,4]
let result = [...candidates.filter(( id ) => requiredArray.includes(id))
.reduce((s, d) => s.add(d.status) , new Set)
]
console.log(result)answered Nov 12 '18 at 20:01
Nitish Narang
2,938815
FWIW, you can also skip the.mapstep and do.reduce((s, d) => s.add(d.status) , new Set)
– Felix Kling
Nov 13 '18 at 1:44
Yeah Correct. Thank you for pointing Sir!! BTW been long time follower of your detailed answers, which has helped me understand JS better. Want to take this chance to Thank you for spreading knowledge!! 😊
– Nitish Narang
Nov 13 '18 at 3:57
1
I'm glad to hear that and you are very welcome :)
– Felix Kling
Nov 13 '18 at 17:13
add a comment |
0
Try this.
const candidates = [
id: 1, status: "active",
id: 2, status: "inactive",
id: 3, status: "failed",
id: 4, status: "inactive",
id: 5, status: "failed",
];
let requiredArray = [2,3,4];
let newArray = candidates.filter(x=>requiredArray.includes(x.id))
console.log(newArray);answered Nov 12 '18 at 20:04
eag845
878611
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can use "reduce" as well as "filter" for this.
Note - I have to change your input object little bit as "candidate1 = ..." was not making much sense here.
const candidates = [
id: 1, status: 'active'
,id: 2, status: 'inactive'
,id: 3, status: 'failed'
,id: 4, status: 'inactive'
,id: 5, status: 'failed'
]
const requiredArray = [2,3,4]
let result = [...candidates.filter(( id ) => requiredArray.includes(id))
.reduce((s, d) => s.add(d.status) , new Set)
]
console.log(result)answered Nov 12 '18 at 20:01
Nitish Narang
2,938815
FWIW, you can also skip the.mapstep and do.reduce((s, d) => s.add(d.status) , new Set)
– Felix Kling
Nov 13 '18 at 1:44
Yeah Correct. Thank you for pointing Sir!! BTW been long time follower of your detailed answers, which has helped me understand JS better. Want to take this chance to Thank you for spreading knowledge!! 😊
– Nitish Narang
Nov 13 '18 at 3:57
1
I'm glad to hear that and you are very welcome :)
– Felix Kling
Nov 13 '18 at 17:13
add a comment |
1
You can use "reduce" as well as "filter" for this.
Note - I have to change your input object little bit as "candidate1 = ..." was not making much sense here.
const candidates = [
id: 1, status: 'active'
,id: 2, status: 'inactive'
,id: 3, status: 'failed'
,id: 4, status: 'inactive'
,id: 5, status: 'failed'
]
const requiredArray = [2,3,4]
let result = [...candidates.filter(( id ) => requiredArray.includes(id))
.reduce((s, d) => s.add(d.status) , new Set)
]
console.log(result)answered Nov 12 '18 at 20:01
Nitish Narang
2,938815
FWIW, you can also skip the.mapstep and do.reduce((s, d) => s.add(d.status) , new Set)
– Felix Kling
Nov 13 '18 at 1:44
Yeah Correct. Thank you for pointing Sir!! BTW been long time follower of your detailed answers, which has helped me understand JS better. Want to take this chance to Thank you for spreading knowledge!! 😊
– Nitish Narang
Nov 13 '18 at 3:57
1
I'm glad to hear that and you are very welcome :)
– Felix Kling
Nov 13 '18 at 17:13
add a comment |
1
1
1
You can use "reduce" as well as "filter" for this.
Note - I have to change your input object little bit as "candidate1 = ..." was not making much sense here.
const candidates = [
id: 1, status: 'active'
,id: 2, status: 'inactive'
,id: 3, status: 'failed'
,id: 4, status: 'inactive'
,id: 5, status: 'failed'
]
const requiredArray = [2,3,4]
let result = [...candidates.filter(( id ) => requiredArray.includes(id))
.reduce((s, d) => s.add(d.status) , new Set)
]
console.log(result)answered Nov 12 '18 at 20:01
Nitish Narang
2,938815
You can use "reduce" as well as "filter" for this.
Note - I have to change your input object little bit as "candidate1 = ..." was not making much sense here.
const candidates = [
id: 1, status: 'active'
,id: 2, status: 'inactive'
,id: 3, status: 'failed'
,id: 4, status: 'inactive'
,id: 5, status: 'failed'
]
const requiredArray = [2,3,4]
let result = [...candidates.filter(( id ) => requiredArray.includes(id))
.reduce((s, d) => s.add(d.status) , new Set)
]
console.log(result)const candidates = [
id: 1, status: 'active'
,id: 2, status: 'inactive'
,id: 3, status: 'failed'
,id: 4, status: 'inactive'
,id: 5, status: 'failed'
]
const requiredArray = [2,3,4]
let result = [...candidates.filter(( id ) => requiredArray.includes(id))
.reduce((s, d) => s.add(d.status) , new Set)
]
console.log(result)const candidates = [
id: 1, status: 'active'
,id: 2, status: 'inactive'
,id: 3, status: 'failed'
,id: 4, status: 'inactive'
,id: 5, status: 'failed'
]
const requiredArray = [2,3,4]
let result = [...candidates.filter(( id ) => requiredArray.includes(id))
.reduce((s, d) => s.add(d.status) , new Set)
]
console.log(result)answered Nov 12 '18 at 20:01
Nitish Narang
2,938815
edited Nov 13 '18 at 6:38
answered Nov 12 '18 at 20:01
Nitish Narang
2,938815
answered Nov 12 '18 at 20:01
Nitish Narang
2,938815
answered Nov 12 '18 at 20:01
Nitish Narang
2,938815
2,938815
FWIW, you can also skip the.mapstep and do.reduce((s, d) => s.add(d.status) , new Set)
– Felix Kling
Nov 13 '18 at 1:44
Yeah Correct. Thank you for pointing Sir!! BTW been long time follower of your detailed answers, which has helped me understand JS better. Want to take this chance to Thank you for spreading knowledge!! 😊
– Nitish Narang
Nov 13 '18 at 3:57
1
I'm glad to hear that and you are very welcome :)
– Felix Kling
Nov 13 '18 at 17:13
add a comment |
FWIW, you can also skip the.mapstep and do.reduce((s, d) => s.add(d.status) , new Set)
– Felix Kling
Nov 13 '18 at 1:44
Yeah Correct. Thank you for pointing Sir!! BTW been long time follower of your detailed answers, which has helped me understand JS better. Want to take this chance to Thank you for spreading knowledge!! 😊
– Nitish Narang
Nov 13 '18 at 3:57
1
I'm glad to hear that and you are very welcome :)
– Felix Kling
Nov 13 '18 at 17:13
FWIW, you can also skip the
.map step and do .reduce((s, d) => s.add(d.status) , new Set)– Felix Kling
Nov 13 '18 at 1:44
FWIW, you can also skip the
.map step and do .reduce((s, d) => s.add(d.status) , new Set)– Felix Kling
Nov 13 '18 at 1:44
Yeah Correct. Thank you for pointing Sir!! BTW been long time follower of your detailed answers, which has helped me understand JS better. Want to take this chance to Thank you for spreading knowledge!! 😊
– Nitish Narang
Nov 13 '18 at 3:57
Yeah Correct. Thank you for pointing Sir!! BTW been long time follower of your detailed answers, which has helped me understand JS better. Want to take this chance to Thank you for spreading knowledge!! 😊
– Nitish Narang
Nov 13 '18 at 3:57
1
1
I'm glad to hear that and you are very welcome :)
– Felix Kling
Nov 13 '18 at 17:13
I'm glad to hear that and you are very welcome :)
– Felix Kling
Nov 13 '18 at 17:13
add a comment |
0
Try this.
const candidates = [
id: 1, status: "active",
id: 2, status: "inactive",
id: 3, status: "failed",
id: 4, status: "inactive",
id: 5, status: "failed",
];
let requiredArray = [2,3,4];
let newArray = candidates.filter(x=>requiredArray.includes(x.id))
console.log(newArray);answered Nov 12 '18 at 20:04
eag845
878611
add a comment |
0
Try this.
const candidates = [
id: 1, status: "active",
id: 2, status: "inactive",
id: 3, status: "failed",
id: 4, status: "inactive",
id: 5, status: "failed",
];
let requiredArray = [2,3,4];
let newArray = candidates.filter(x=>requiredArray.includes(x.id))
console.log(newArray);answered Nov 12 '18 at 20:04
eag845
878611
add a comment |
0
0
0
Try this.
const candidates = [
id: 1, status: "active",
id: 2, status: "inactive",
id: 3, status: "failed",
id: 4, status: "inactive",
id: 5, status: "failed",
];
let requiredArray = [2,3,4];
let newArray = candidates.filter(x=>requiredArray.includes(x.id))
console.log(newArray);answered Nov 12 '18 at 20:04
eag845
878611
Try this.
const candidates = [
id: 1, status: "active",
id: 2, status: "inactive",
id: 3, status: "failed",
id: 4, status: "inactive",
id: 5, status: "failed",
];
let requiredArray = [2,3,4];
let newArray = candidates.filter(x=>requiredArray.includes(x.id))
console.log(newArray);const candidates = [
id: 1, status: "active",
id: 2, status: "inactive",
id: 3, status: "failed",
id: 4, status: "inactive",
id: 5, status: "failed",
];
let requiredArray = [2,3,4];
let newArray = candidates.filter(x=>requiredArray.includes(x.id))
console.log(newArray);const candidates = [
id: 1, status: "active",
id: 2, status: "inactive",
id: 3, status: "failed",
id: 4, status: "inactive",
id: 5, status: "failed",
];
let requiredArray = [2,3,4];
let newArray = candidates.filter(x=>requiredArray.includes(x.id))
console.log(newArray);answered Nov 12 '18 at 20:04
eag845
878611
answered Nov 12 '18 at 20:04
eag845
878611
answered Nov 12 '18 at 20:04
eag845
878611
answered Nov 12 '18 at 20:04
eag845
878611
878611
add a comment |
add a comment |
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What's going on with these
candidate1 =assignments in your array literal?– Bergi
Nov 12 '18 at 19:59
How about
Array.from(new Set(candidatesStore.filter(cand => requiredArray.includes(cand.id)).map(cand => cand.status)))? I don't see howreduceorfindcould be useful here.– Bergi
Nov 12 '18 at 20:00