Explode and Set if condition php










0














Array ( [0] => 1 [1] => 2 )


I'm trying to set an if condition based on user permission, the idea is to show menu based on given values, if it is 1, one menu will be displayed and 2 second menu will be displayed, if its both then all values will be displayed. So far for single values i have gotten it right but how to do it for array of values
This is my code



<?php
$userid = $this->phpsession->get("user_id");
$userrole = $this->phpsession->get("user_type");

$query = $this->db->select("role_empid,role_permissions")->from('hw_role')->where('role_empid', $userid)->get()->result();
$data = $query[0]->role_permissions;

if($data == 1)
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php else if($data == 2) ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php ?>
</ul>









share|improve this question























  • Look at in_array - php.net/manual/en/function.in-array.php
    – fubar
    Nov 12 at 6:07










  • ok @fubar can you share an example
    – Amal Joseph
    Nov 12 at 6:09










  • what is the value in "role_permissions" if it contain multiple value array or json?
    – Poonam Navapara
    Nov 12 at 6:11










  • Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
    – Amal Joseph
    Nov 12 at 6:15










  • What is the issue with your current condition?
    – Sachin
    Nov 12 at 6:27















0














Array ( [0] => 1 [1] => 2 )


I'm trying to set an if condition based on user permission, the idea is to show menu based on given values, if it is 1, one menu will be displayed and 2 second menu will be displayed, if its both then all values will be displayed. So far for single values i have gotten it right but how to do it for array of values
This is my code



<?php
$userid = $this->phpsession->get("user_id");
$userrole = $this->phpsession->get("user_type");

$query = $this->db->select("role_empid,role_permissions")->from('hw_role')->where('role_empid', $userid)->get()->result();
$data = $query[0]->role_permissions;

if($data == 1)
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php else if($data == 2) ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php ?>
</ul>









share|improve this question























  • Look at in_array - php.net/manual/en/function.in-array.php
    – fubar
    Nov 12 at 6:07










  • ok @fubar can you share an example
    – Amal Joseph
    Nov 12 at 6:09










  • what is the value in "role_permissions" if it contain multiple value array or json?
    – Poonam Navapara
    Nov 12 at 6:11










  • Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
    – Amal Joseph
    Nov 12 at 6:15










  • What is the issue with your current condition?
    – Sachin
    Nov 12 at 6:27













0












0








0







Array ( [0] => 1 [1] => 2 )


I'm trying to set an if condition based on user permission, the idea is to show menu based on given values, if it is 1, one menu will be displayed and 2 second menu will be displayed, if its both then all values will be displayed. So far for single values i have gotten it right but how to do it for array of values
This is my code



<?php
$userid = $this->phpsession->get("user_id");
$userrole = $this->phpsession->get("user_type");

$query = $this->db->select("role_empid,role_permissions")->from('hw_role')->where('role_empid', $userid)->get()->result();
$data = $query[0]->role_permissions;

if($data == 1)
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php else if($data == 2) ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php ?>
</ul>









share|improve this question















Array ( [0] => 1 [1] => 2 )


I'm trying to set an if condition based on user permission, the idea is to show menu based on given values, if it is 1, one menu will be displayed and 2 second menu will be displayed, if its both then all values will be displayed. So far for single values i have gotten it right but how to do it for array of values
This is my code



<?php
$userid = $this->phpsession->get("user_id");
$userrole = $this->phpsession->get("user_type");

$query = $this->db->select("role_empid,role_permissions")->from('hw_role')->where('role_empid', $userid)->get()->result();
$data = $query[0]->role_permissions;

if($data == 1)
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php else if($data == 2) ?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php ?>
</ul>






php codeigniter






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share|improve this question













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share|improve this question








edited Nov 12 at 6:21









ariefbayu

17k85581




17k85581










asked Nov 12 at 6:06









Amal Joseph

115




115











  • Look at in_array - php.net/manual/en/function.in-array.php
    – fubar
    Nov 12 at 6:07










  • ok @fubar can you share an example
    – Amal Joseph
    Nov 12 at 6:09










  • what is the value in "role_permissions" if it contain multiple value array or json?
    – Poonam Navapara
    Nov 12 at 6:11










  • Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
    – Amal Joseph
    Nov 12 at 6:15










  • What is the issue with your current condition?
    – Sachin
    Nov 12 at 6:27
















  • Look at in_array - php.net/manual/en/function.in-array.php
    – fubar
    Nov 12 at 6:07










  • ok @fubar can you share an example
    – Amal Joseph
    Nov 12 at 6:09










  • what is the value in "role_permissions" if it contain multiple value array or json?
    – Poonam Navapara
    Nov 12 at 6:11










  • Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
    – Amal Joseph
    Nov 12 at 6:15










  • What is the issue with your current condition?
    – Sachin
    Nov 12 at 6:27















Look at in_array - php.net/manual/en/function.in-array.php
– fubar
Nov 12 at 6:07




Look at in_array - php.net/manual/en/function.in-array.php
– fubar
Nov 12 at 6:07












ok @fubar can you share an example
– Amal Joseph
Nov 12 at 6:09




ok @fubar can you share an example
– Amal Joseph
Nov 12 at 6:09












what is the value in "role_permissions" if it contain multiple value array or json?
– Poonam Navapara
Nov 12 at 6:11




what is the value in "role_permissions" if it contain multiple value array or json?
– Poonam Navapara
Nov 12 at 6:11












Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
– Amal Joseph
Nov 12 at 6:15




Array ( [0] => 1 [1] => 2 ) value of role permission @PoonamNavapara
– Amal Joseph
Nov 12 at 6:15












What is the issue with your current condition?
– Sachin
Nov 12 at 6:27




What is the issue with your current condition?
– Sachin
Nov 12 at 6:27












3 Answers
3






active

oldest

votes


















0














if role_permission contain json object that first convert it into the array like



$data = $query[0]->role_permissions;
$data=json_decode($data);


otherwise direct check the condition for



$data = $query[0]->role_permissions;

if(in_array(1,$data) && in_array(2,$data))


else if(in_array(1,$data))


else if(in_array(2,$data))







share|improve this answer




















  • ok let me check if it works ,thanks for your time
    – Amal Joseph
    Nov 12 at 6:18










  • A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
    – Amal Joseph
    Nov 12 at 6:21










  • Yes, $data must be contain array value
    – Poonam Navapara
    Nov 12 at 6:23










  • what should i do then?
    – Amal Joseph
    Nov 12 at 6:26










  • i exploded the value now it works
    – Amal Joseph
    Nov 12 at 6:27


















0














If $query[0]->role_permissions is an array that has distinct value, then you can try :



 <ul>
<?php for($i = 0; $i<count($data);$i++)
if($data[$i] == 1) ?>

<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>

<?php
if($data[$i] == 2) ?>

<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>

<?php ?>
</ul>





share|improve this answer






















  • when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
    – Amal Joseph
    Nov 12 at 6:25










  • updated my answer @AmalJoseph, just remove else
    – arisalsaila
    Nov 12 at 6:28










  • ok let me check @arisalsaila thanks
    – Amal Joseph
    Nov 12 at 6:36


















0














Try This



<?php
if(in_array(1,$data))
?>
<li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
<li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
<?php
if(in_array(2,$data))
?>
<li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
<?php ?>





share|improve this answer




















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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    if role_permission contain json object that first convert it into the array like



    $data = $query[0]->role_permissions;
    $data=json_decode($data);


    otherwise direct check the condition for



    $data = $query[0]->role_permissions;

    if(in_array(1,$data) && in_array(2,$data))


    else if(in_array(1,$data))


    else if(in_array(2,$data))







    share|improve this answer




















    • ok let me check if it works ,thanks for your time
      – Amal Joseph
      Nov 12 at 6:18










    • A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
      – Amal Joseph
      Nov 12 at 6:21










    • Yes, $data must be contain array value
      – Poonam Navapara
      Nov 12 at 6:23










    • what should i do then?
      – Amal Joseph
      Nov 12 at 6:26










    • i exploded the value now it works
      – Amal Joseph
      Nov 12 at 6:27















    0














    if role_permission contain json object that first convert it into the array like



    $data = $query[0]->role_permissions;
    $data=json_decode($data);


    otherwise direct check the condition for



    $data = $query[0]->role_permissions;

    if(in_array(1,$data) && in_array(2,$data))


    else if(in_array(1,$data))


    else if(in_array(2,$data))







    share|improve this answer




















    • ok let me check if it works ,thanks for your time
      – Amal Joseph
      Nov 12 at 6:18










    • A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
      – Amal Joseph
      Nov 12 at 6:21










    • Yes, $data must be contain array value
      – Poonam Navapara
      Nov 12 at 6:23










    • what should i do then?
      – Amal Joseph
      Nov 12 at 6:26










    • i exploded the value now it works
      – Amal Joseph
      Nov 12 at 6:27













    0












    0








    0






    if role_permission contain json object that first convert it into the array like



    $data = $query[0]->role_permissions;
    $data=json_decode($data);


    otherwise direct check the condition for



    $data = $query[0]->role_permissions;

    if(in_array(1,$data) && in_array(2,$data))


    else if(in_array(1,$data))


    else if(in_array(2,$data))







    share|improve this answer












    if role_permission contain json object that first convert it into the array like



    $data = $query[0]->role_permissions;
    $data=json_decode($data);


    otherwise direct check the condition for



    $data = $query[0]->role_permissions;

    if(in_array(1,$data) && in_array(2,$data))


    else if(in_array(1,$data))


    else if(in_array(2,$data))








    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 12 at 6:17









    Poonam Navapara

    18618




    18618











    • ok let me check if it works ,thanks for your time
      – Amal Joseph
      Nov 12 at 6:18










    • A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
      – Amal Joseph
      Nov 12 at 6:21










    • Yes, $data must be contain array value
      – Poonam Navapara
      Nov 12 at 6:23










    • what should i do then?
      – Amal Joseph
      Nov 12 at 6:26










    • i exploded the value now it works
      – Amal Joseph
      Nov 12 at 6:27
















    • ok let me check if it works ,thanks for your time
      – Amal Joseph
      Nov 12 at 6:18










    • A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
      – Amal Joseph
      Nov 12 at 6:21










    • Yes, $data must be contain array value
      – Poonam Navapara
      Nov 12 at 6:23










    • what should i do then?
      – Amal Joseph
      Nov 12 at 6:26










    • i exploded the value now it works
      – Amal Joseph
      Nov 12 at 6:27















    ok let me check if it works ,thanks for your time
    – Amal Joseph
    Nov 12 at 6:18




    ok let me check if it works ,thanks for your time
    – Amal Joseph
    Nov 12 at 6:18












    A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
    – Amal Joseph
    Nov 12 at 6:21




    A PHP Error was encountered Severity: Warning Message: in_array() expects parameter 2 to be array, string given
    – Amal Joseph
    Nov 12 at 6:21












    Yes, $data must be contain array value
    – Poonam Navapara
    Nov 12 at 6:23




    Yes, $data must be contain array value
    – Poonam Navapara
    Nov 12 at 6:23












    what should i do then?
    – Amal Joseph
    Nov 12 at 6:26




    what should i do then?
    – Amal Joseph
    Nov 12 at 6:26












    i exploded the value now it works
    – Amal Joseph
    Nov 12 at 6:27




    i exploded the value now it works
    – Amal Joseph
    Nov 12 at 6:27













    0














    If $query[0]->role_permissions is an array that has distinct value, then you can try :



     <ul>
    <?php for($i = 0; $i<count($data);$i++)
    if($data[$i] == 1) ?>

    <li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
    <li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>

    <?php
    if($data[$i] == 2) ?>

    <li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>

    <?php ?>
    </ul>





    share|improve this answer






















    • when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
      – Amal Joseph
      Nov 12 at 6:25










    • updated my answer @AmalJoseph, just remove else
      – arisalsaila
      Nov 12 at 6:28










    • ok let me check @arisalsaila thanks
      – Amal Joseph
      Nov 12 at 6:36















    0














    If $query[0]->role_permissions is an array that has distinct value, then you can try :



     <ul>
    <?php for($i = 0; $i<count($data);$i++)
    if($data[$i] == 1) ?>

    <li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
    <li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>

    <?php
    if($data[$i] == 2) ?>

    <li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>

    <?php ?>
    </ul>





    share|improve this answer






















    • when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
      – Amal Joseph
      Nov 12 at 6:25










    • updated my answer @AmalJoseph, just remove else
      – arisalsaila
      Nov 12 at 6:28










    • ok let me check @arisalsaila thanks
      – Amal Joseph
      Nov 12 at 6:36













    0












    0








    0






    If $query[0]->role_permissions is an array that has distinct value, then you can try :



     <ul>
    <?php for($i = 0; $i<count($data);$i++)
    if($data[$i] == 1) ?>

    <li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
    <li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>

    <?php
    if($data[$i] == 2) ?>

    <li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>

    <?php ?>
    </ul>





    share|improve this answer














    If $query[0]->role_permissions is an array that has distinct value, then you can try :



     <ul>
    <?php for($i = 0; $i<count($data);$i++)
    if($data[$i] == 1) ?>

    <li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
    <li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>

    <?php
    if($data[$i] == 2) ?>

    <li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>

    <?php ?>
    </ul>






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 12 at 6:27

























    answered Nov 12 at 6:21









    arisalsaila

    37416




    37416











    • when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
      – Amal Joseph
      Nov 12 at 6:25










    • updated my answer @AmalJoseph, just remove else
      – arisalsaila
      Nov 12 at 6:28










    • ok let me check @arisalsaila thanks
      – Amal Joseph
      Nov 12 at 6:36
















    • when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
      – Amal Joseph
      Nov 12 at 6:25










    • updated my answer @AmalJoseph, just remove else
      – arisalsaila
      Nov 12 at 6:28










    • ok let me check @arisalsaila thanks
      – Amal Joseph
      Nov 12 at 6:36















    when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
    – Amal Joseph
    Nov 12 at 6:25




    when it have array value of Array ( [0] => 1 [1] => 2 ) only enquiry list is shown, i need both menu to be shown when it contains 1 and 2
    – Amal Joseph
    Nov 12 at 6:25












    updated my answer @AmalJoseph, just remove else
    – arisalsaila
    Nov 12 at 6:28




    updated my answer @AmalJoseph, just remove else
    – arisalsaila
    Nov 12 at 6:28












    ok let me check @arisalsaila thanks
    – Amal Joseph
    Nov 12 at 6:36




    ok let me check @arisalsaila thanks
    – Amal Joseph
    Nov 12 at 6:36











    0














    Try This



    <?php
    if(in_array(1,$data))
    ?>
    <li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
    <li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
    <?php
    if(in_array(2,$data))
    ?>
    <li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
    <?php ?>





    share|improve this answer

























      0














      Try This



      <?php
      if(in_array(1,$data))
      ?>
      <li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
      <li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
      <?php
      if(in_array(2,$data))
      ?>
      <li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
      <?php ?>





      share|improve this answer























        0












        0








        0






        Try This



        <?php
        if(in_array(1,$data))
        ?>
        <li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
        <li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
        <?php
        if(in_array(2,$data))
        ?>
        <li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
        <?php ?>





        share|improve this answer












        Try This



        <?php
        if(in_array(1,$data))
        ?>
        <li><a href="<?php echo base_url("enquiry/addEnquiry"); ?>">Add Enquiry</a></li>
        <li><a href="<?php echo base_url("enquiry"); ?>">Enquiry List</a></li>
        <?php
        if(in_array(2,$data))
        ?>
        <li><a href="<?php echo base_url("enquiry/proposalList"); ?>">Request For Proposal</a></li>
        <?php ?>






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 at 6:44









        Sachin

        620411




        620411



























            draft saved

            draft discarded
















































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