RxJava parallel emit once
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i try to get an array of flowable get executed in parallel with FlowableFromArray
and emit the FlowableFromArray when all flowables are done.
But I'm missing the method to emit on last/latest.
I could only manage to make it work to emit onNext @see below
val results = FlowableFromArray(flowableArray).parallel()
.runOn(Schedulers.io())
.sequential()
.zipWith(r, BiFunction t1: Flowable<String>, t2: Int
->
t1
.subscribeOn(Schedulers.io())
.map i -> parseYoutubeTrack(i)
.observeOn(AndroidSchedulers.mainThread())
.subscribe next -> TLog.i(TAG, "_NEXT_ $next.videoId")
)
.subscribe()
android rx-java rx-java2 asked Nov 10 at 21:07
Plagueis
63
add a comment |
up vote
0
down vote
favorite
i try to get an array of flowable get executed in parallel with FlowableFromArray
and emit the FlowableFromArray when all flowables are done.
But I'm missing the method to emit on last/latest.
I could only manage to make it work to emit onNext @see below
val results = FlowableFromArray(flowableArray).parallel()
.runOn(Schedulers.io())
.sequential()
.zipWith(r, BiFunction t1: Flowable<String>, t2: Int
->
t1
.subscribeOn(Schedulers.io())
.map i -> parseYoutubeTrack(i)
.observeOn(AndroidSchedulers.mainThread())
.subscribe next -> TLog.i(TAG, "_NEXT_ $next.videoId")
)
.subscribe()
asked Nov 10 at 21:07
Plagueis
63
This makes no sense; you go parallel to then go back to sequential, then you subscribe in the zip handler. And also what isr?
– akarnokd
Nov 11 at 10:32
Made it work like so return FlowableFromArray(flowableArray) .parallel() .runOn(Schedulers.computation()) .map f -> parseYoutubeTrack(f.blockingFirst()) .sequential() .blockingLatest().toMutableList()
– Plagueis
Nov 18 at 17:05
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
i try to get an array of flowable get executed in parallel with FlowableFromArray
and emit the FlowableFromArray when all flowables are done.
But I'm missing the method to emit on last/latest.
I could only manage to make it work to emit onNext @see below
val results = FlowableFromArray(flowableArray).parallel()
.runOn(Schedulers.io())
.sequential()
.zipWith(r, BiFunction t1: Flowable<String>, t2: Int
->
t1
.subscribeOn(Schedulers.io())
.map i -> parseYoutubeTrack(i)
.observeOn(AndroidSchedulers.mainThread())
.subscribe next -> TLog.i(TAG, "_NEXT_ $next.videoId")
)
.subscribe()
asked Nov 10 at 21:07
Plagueis
63
i try to get an array of flowable get executed in parallel with FlowableFromArray
and emit the FlowableFromArray when all flowables are done.
But I'm missing the method to emit on last/latest.
I could only manage to make it work to emit onNext @see below
val results = FlowableFromArray(flowableArray).parallel()
.runOn(Schedulers.io())
.sequential()
.zipWith(r, BiFunction t1: Flowable<String>, t2: Int
->
t1
.subscribeOn(Schedulers.io())
.map i -> parseYoutubeTrack(i)
.observeOn(AndroidSchedulers.mainThread())
.subscribe next -> TLog.i(TAG, "_NEXT_ $next.videoId")
)
.subscribe()
asked Nov 10 at 21:07
Plagueis
63
asked Nov 10 at 21:07
Plagueis
63
asked Nov 10 at 21:07
Plagueis
63
asked Nov 10 at 21:07
Plagueis
63
asked Nov 10 at 21:07
Plagueis
63
63
This makes no sense; you go parallel to then go back to sequential, then you subscribe in the zip handler. And also what isr?
– akarnokd
Nov 11 at 10:32
Made it work like so return FlowableFromArray(flowableArray) .parallel() .runOn(Schedulers.computation()) .map f -> parseYoutubeTrack(f.blockingFirst()) .sequential() .blockingLatest().toMutableList()
– Plagueis
Nov 18 at 17:05
add a comment |
This makes no sense; you go parallel to then go back to sequential, then you subscribe in the zip handler. And also what isr?
– akarnokd
Nov 11 at 10:32
Made it work like so return FlowableFromArray(flowableArray) .parallel() .runOn(Schedulers.computation()) .map f -> parseYoutubeTrack(f.blockingFirst()) .sequential() .blockingLatest().toMutableList()
– Plagueis
Nov 18 at 17:05
This makes no sense; you go parallel to then go back to sequential, then you subscribe in the zip handler. And also what is
r?– akarnokd
Nov 11 at 10:32
This makes no sense; you go parallel to then go back to sequential, then you subscribe in the zip handler. And also what is
r?– akarnokd
Nov 11 at 10:32
Made it work like so return FlowableFromArray(flowableArray) .parallel() .runOn(Schedulers.computation()) .map f -> parseYoutubeTrack(f.blockingFirst()) .sequential() .blockingLatest().toMutableList()
– Plagueis
Nov 18 at 17:05
Made it work like so return FlowableFromArray(flowableArray) .parallel() .runOn(Schedulers.computation()) .map f -> parseYoutubeTrack(f.blockingFirst()) .sequential() .blockingLatest().toMutableList()
– Plagueis
Nov 18 at 17:05
add a comment |
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This makes no sense; you go parallel to then go back to sequential, then you subscribe in the zip handler. And also what is
r?– akarnokd
Nov 11 at 10:32
Made it work like so return FlowableFromArray(flowableArray) .parallel() .runOn(Schedulers.computation()) .map f -> parseYoutubeTrack(f.blockingFirst()) .sequential() .blockingLatest().toMutableList()
– Plagueis
Nov 18 at 17:05