Odtnhj

I have a script that takes parameters such as:

script.sh 1 3

I want to then go through a text file and print out the first and third words from each line. I have simply no idea how to do this. If anyone could help I'd really appreciate it...

This is what I currently have:

counter=0
wordcounter=0

param=$(echo "$3" | tr , " ") 

words()
 for word in $1; do
 for col in $param; do
 if [ $wordcounter -eq $col ]; then
 echo $word
 fi
 done 
 done
 wordcounter=$((wordcounter + 1))


eachline() tr , " ")
 for word in $newline; do
 if [ $counter -gt 3 ]; then
 echo "$word"
 fi
 counter=$((counter + 1))
 done
 if [ $counter -gt 0 ]; then 
 words "$newline"
 fi
 counter=$((counter + 1))


while read line; do
 eachline $line
done < company/employee.txt

Use awk:

$ awk 'print $1 " " $3' file

for file:

1 2 3 4 5
6 7 8 9 0

Output is:

1 3
6 8

In bash script:

#!/bin/bash

awk_command="print";
for i in "$@"; do
 awk_command="$awk_command $$i " "";
done 
awk_command="$awk_command";
awk "$awk_command" file

With this script you can pass any number of indexes:

For 1 and 2:

$ ./script.sh 1 2
1 2 
6 7 

For 1, 2 and 5:

$ ./script.sh 1 2 5
1 2 5 
6 7 0