AJAX JSP displaying output data in a table










0















trying to display data from server in the page in a table. but unfortunately it is not working. I can display it using out.println. Code samples are attached. Thank you very much.



ajax1 handles the ajax part and ajax2 is the file for java code.



...



 Ajax1.jsp
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
<script>
$(document).ready(function()
$("#users").change(function()
var value = $(this).val();
$.get("ajax2.jsp",q:value,function(data)
$("#javaquery").html(data);
);
);
);
</script>
</head>
<body>
<select id = "users">
<option value="">Select Account ID</option>
<option value="calicut">calicut</option>
<option value="kochi">kochi</option>
<option value="Admin">Admin</option>

</select>
<br />
<div id="javaquery"><b>Name will be displayed here</b></div>
</body>
</html>


Ajax2.jsp

<%@page import="java.text.SimpleDateFormat"%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@page import="java.util.*,java.sql.*,java.io.*" %>
<%@page import="javax.servlet.*" %>
<%@page import="javax.servlet.http.*" %>
<%@ page import="java.sql.*" %>
<%@ page import="java.util.*" %>
<%@ page import="java.io.*" %>
<%@ page import="javax.sql.*" %>
<%@ page import="javax.naming.*,javax.swing.*,java.sql.Date.*,java.text.SimpleDateFormat.*,java.util.Date.*" %>
<html> <head> <meta http-equiv="Content-Type"
content="text/html; charset=UTF-8"> <title></title> </head>
<body>


<%

InitialContext ctx;
DataSource ds;
Connection conn;
ResultSet rs;
Statement stmt;

String name = "";
String ename="";

try

ctx=new InitialContext();
ds=(DataSource) ctx.lookup("java:app/jdbc/SalesDB");
conn=ds.getConnection();







String q = request.getParameter("q");

stmt = conn.createStatement(); //Create Statement to interact
rs = stmt.executeQuery("select * from employees where Username='"+q+"'");
while (rs.next())
name = rs.getString("Role_")+rs.getString("username");
ename=rs.getString("username");

rs.close();
stmt.close();
conn.close();
catch (Exception e)
e.printStackTrace();

%>
Name:<%out.print(name);%>
eName:<%out.print(ename);%>

</body> </html>


.............................................
.................................................










share|improve this question






















  • It's not working because you're not writing anything to the response. Also you're supposed to do this with a servlet.

    – Jonathan Laliberte
    Nov 14 '18 at 13:54











  • Can you kinldy provide some examples :(

    – Javanewbie
    Nov 15 '18 at 6:02















0















trying to display data from server in the page in a table. but unfortunately it is not working. I can display it using out.println. Code samples are attached. Thank you very much.



ajax1 handles the ajax part and ajax2 is the file for java code.



...



 Ajax1.jsp
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
<script>
$(document).ready(function()
$("#users").change(function()
var value = $(this).val();
$.get("ajax2.jsp",q:value,function(data)
$("#javaquery").html(data);
);
);
);
</script>
</head>
<body>
<select id = "users">
<option value="">Select Account ID</option>
<option value="calicut">calicut</option>
<option value="kochi">kochi</option>
<option value="Admin">Admin</option>

</select>
<br />
<div id="javaquery"><b>Name will be displayed here</b></div>
</body>
</html>


Ajax2.jsp

<%@page import="java.text.SimpleDateFormat"%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@page import="java.util.*,java.sql.*,java.io.*" %>
<%@page import="javax.servlet.*" %>
<%@page import="javax.servlet.http.*" %>
<%@ page import="java.sql.*" %>
<%@ page import="java.util.*" %>
<%@ page import="java.io.*" %>
<%@ page import="javax.sql.*" %>
<%@ page import="javax.naming.*,javax.swing.*,java.sql.Date.*,java.text.SimpleDateFormat.*,java.util.Date.*" %>
<html> <head> <meta http-equiv="Content-Type"
content="text/html; charset=UTF-8"> <title></title> </head>
<body>


<%

InitialContext ctx;
DataSource ds;
Connection conn;
ResultSet rs;
Statement stmt;

String name = "";
String ename="";

try

ctx=new InitialContext();
ds=(DataSource) ctx.lookup("java:app/jdbc/SalesDB");
conn=ds.getConnection();







String q = request.getParameter("q");

stmt = conn.createStatement(); //Create Statement to interact
rs = stmt.executeQuery("select * from employees where Username='"+q+"'");
while (rs.next())
name = rs.getString("Role_")+rs.getString("username");
ename=rs.getString("username");

rs.close();
stmt.close();
conn.close();
catch (Exception e)
e.printStackTrace();

%>
Name:<%out.print(name);%>
eName:<%out.print(ename);%>

</body> </html>


.............................................
.................................................










share|improve this question






















  • It's not working because you're not writing anything to the response. Also you're supposed to do this with a servlet.

    – Jonathan Laliberte
    Nov 14 '18 at 13:54











  • Can you kinldy provide some examples :(

    – Javanewbie
    Nov 15 '18 at 6:02













0












0








0








trying to display data from server in the page in a table. but unfortunately it is not working. I can display it using out.println. Code samples are attached. Thank you very much.



ajax1 handles the ajax part and ajax2 is the file for java code.



...



 Ajax1.jsp
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
<script>
$(document).ready(function()
$("#users").change(function()
var value = $(this).val();
$.get("ajax2.jsp",q:value,function(data)
$("#javaquery").html(data);
);
);
);
</script>
</head>
<body>
<select id = "users">
<option value="">Select Account ID</option>
<option value="calicut">calicut</option>
<option value="kochi">kochi</option>
<option value="Admin">Admin</option>

</select>
<br />
<div id="javaquery"><b>Name will be displayed here</b></div>
</body>
</html>


Ajax2.jsp

<%@page import="java.text.SimpleDateFormat"%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@page import="java.util.*,java.sql.*,java.io.*" %>
<%@page import="javax.servlet.*" %>
<%@page import="javax.servlet.http.*" %>
<%@ page import="java.sql.*" %>
<%@ page import="java.util.*" %>
<%@ page import="java.io.*" %>
<%@ page import="javax.sql.*" %>
<%@ page import="javax.naming.*,javax.swing.*,java.sql.Date.*,java.text.SimpleDateFormat.*,java.util.Date.*" %>
<html> <head> <meta http-equiv="Content-Type"
content="text/html; charset=UTF-8"> <title></title> </head>
<body>


<%

InitialContext ctx;
DataSource ds;
Connection conn;
ResultSet rs;
Statement stmt;

String name = "";
String ename="";

try

ctx=new InitialContext();
ds=(DataSource) ctx.lookup("java:app/jdbc/SalesDB");
conn=ds.getConnection();







String q = request.getParameter("q");

stmt = conn.createStatement(); //Create Statement to interact
rs = stmt.executeQuery("select * from employees where Username='"+q+"'");
while (rs.next())
name = rs.getString("Role_")+rs.getString("username");
ename=rs.getString("username");

rs.close();
stmt.close();
conn.close();
catch (Exception e)
e.printStackTrace();

%>
Name:<%out.print(name);%>
eName:<%out.print(ename);%>

</body> </html>


.............................................
.................................................










share|improve this question














trying to display data from server in the page in a table. but unfortunately it is not working. I can display it using out.println. Code samples are attached. Thank you very much.



ajax1 handles the ajax part and ajax2 is the file for java code.



...



 Ajax1.jsp
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
<script>
$(document).ready(function()
$("#users").change(function()
var value = $(this).val();
$.get("ajax2.jsp",q:value,function(data)
$("#javaquery").html(data);
);
);
);
</script>
</head>
<body>
<select id = "users">
<option value="">Select Account ID</option>
<option value="calicut">calicut</option>
<option value="kochi">kochi</option>
<option value="Admin">Admin</option>

</select>
<br />
<div id="javaquery"><b>Name will be displayed here</b></div>
</body>
</html>


Ajax2.jsp

<%@page import="java.text.SimpleDateFormat"%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@page import="java.util.*,java.sql.*,java.io.*" %>
<%@page import="javax.servlet.*" %>
<%@page import="javax.servlet.http.*" %>
<%@ page import="java.sql.*" %>
<%@ page import="java.util.*" %>
<%@ page import="java.io.*" %>
<%@ page import="javax.sql.*" %>
<%@ page import="javax.naming.*,javax.swing.*,java.sql.Date.*,java.text.SimpleDateFormat.*,java.util.Date.*" %>
<html> <head> <meta http-equiv="Content-Type"
content="text/html; charset=UTF-8"> <title></title> </head>
<body>


<%

InitialContext ctx;
DataSource ds;
Connection conn;
ResultSet rs;
Statement stmt;

String name = "";
String ename="";

try

ctx=new InitialContext();
ds=(DataSource) ctx.lookup("java:app/jdbc/SalesDB");
conn=ds.getConnection();







String q = request.getParameter("q");

stmt = conn.createStatement(); //Create Statement to interact
rs = stmt.executeQuery("select * from employees where Username='"+q+"'");
while (rs.next())
name = rs.getString("Role_")+rs.getString("username");
ename=rs.getString("username");

rs.close();
stmt.close();
conn.close();
catch (Exception e)
e.printStackTrace();

%>
Name:<%out.print(name);%>
eName:<%out.print(ename);%>

</body> </html>


.............................................
.................................................







html ajax jsp






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 14 '18 at 12:46









JavanewbieJavanewbie

166




166












  • It's not working because you're not writing anything to the response. Also you're supposed to do this with a servlet.

    – Jonathan Laliberte
    Nov 14 '18 at 13:54











  • Can you kinldy provide some examples :(

    – Javanewbie
    Nov 15 '18 at 6:02

















  • It's not working because you're not writing anything to the response. Also you're supposed to do this with a servlet.

    – Jonathan Laliberte
    Nov 14 '18 at 13:54











  • Can you kinldy provide some examples :(

    – Javanewbie
    Nov 15 '18 at 6:02
















It's not working because you're not writing anything to the response. Also you're supposed to do this with a servlet.

– Jonathan Laliberte
Nov 14 '18 at 13:54





It's not working because you're not writing anything to the response. Also you're supposed to do this with a servlet.

– Jonathan Laliberte
Nov 14 '18 at 13:54













Can you kinldy provide some examples :(

– Javanewbie
Nov 15 '18 at 6:02





Can you kinldy provide some examples :(

– Javanewbie
Nov 15 '18 at 6:02












1 Answer
1






active

oldest

votes


















1














 <script>
$(document).ready(function()
$("#users").change(function()
var value = $(this).val();
$.get("AjaxServlet",q:value,function(data)
$("#javaquery").html(data);
);
);
);
</script>


Remove java code from 2nd jsp and add it to a servlet called "AjaxServlet" with url mapping "/AjaxServlet"



AjaxServlet:



 @Override
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
String q = request.getParameter("q"); //q value



InitialContext ctx;
DataSource ds;
Connection conn;
ResultSet rs;
Statement stmt;

String name = "blank name";
String ename="";

try

ctx=new InitialContext();
ds=(DataSource) ctx.lookup("java:app/jdbc/SalesDB");
conn=ds.getConnection();







String q = request.getParameter("q");

stmt = conn.createStatement(); //Create Statement to interact
rs = stmt.executeQuery("select * from employees where Username='"+q+"'");
while (rs.next())
name = rs.getString("Role_")+rs.getString("username");
ename=rs.getString("username");

rs.close();
stmt.close();
conn.close();
catch (Exception e)
e.printStackTrace();




response.setContentType("text/plain"); // Set content type of the response so that jQuery knows what it can expect.
response.setCharacterEncoding("UTF-8"); // You want world domination, huh?
response.getWriter().write(name); // Write response body.



More info on how to do ajax with servlets here:
How to use Servlets and Ajax?






share|improve this answer






















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     <script>
    $(document).ready(function()
    $("#users").change(function()
    var value = $(this).val();
    $.get("AjaxServlet",q:value,function(data)
    $("#javaquery").html(data);
    );
    );
    );
    </script>


    Remove java code from 2nd jsp and add it to a servlet called "AjaxServlet" with url mapping "/AjaxServlet"



    AjaxServlet:



     @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
    String q = request.getParameter("q"); //q value



    InitialContext ctx;
    DataSource ds;
    Connection conn;
    ResultSet rs;
    Statement stmt;

    String name = "blank name";
    String ename="";

    try

    ctx=new InitialContext();
    ds=(DataSource) ctx.lookup("java:app/jdbc/SalesDB");
    conn=ds.getConnection();







    String q = request.getParameter("q");

    stmt = conn.createStatement(); //Create Statement to interact
    rs = stmt.executeQuery("select * from employees where Username='"+q+"'");
    while (rs.next())
    name = rs.getString("Role_")+rs.getString("username");
    ename=rs.getString("username");

    rs.close();
    stmt.close();
    conn.close();
    catch (Exception e)
    e.printStackTrace();




    response.setContentType("text/plain"); // Set content type of the response so that jQuery knows what it can expect.
    response.setCharacterEncoding("UTF-8"); // You want world domination, huh?
    response.getWriter().write(name); // Write response body.



    More info on how to do ajax with servlets here:
    How to use Servlets and Ajax?






    share|improve this answer



























      1














       <script>
      $(document).ready(function()
      $("#users").change(function()
      var value = $(this).val();
      $.get("AjaxServlet",q:value,function(data)
      $("#javaquery").html(data);
      );
      );
      );
      </script>


      Remove java code from 2nd jsp and add it to a servlet called "AjaxServlet" with url mapping "/AjaxServlet"



      AjaxServlet:



       @Override
      protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
      String q = request.getParameter("q"); //q value



      InitialContext ctx;
      DataSource ds;
      Connection conn;
      ResultSet rs;
      Statement stmt;

      String name = "blank name";
      String ename="";

      try

      ctx=new InitialContext();
      ds=(DataSource) ctx.lookup("java:app/jdbc/SalesDB");
      conn=ds.getConnection();







      String q = request.getParameter("q");

      stmt = conn.createStatement(); //Create Statement to interact
      rs = stmt.executeQuery("select * from employees where Username='"+q+"'");
      while (rs.next())
      name = rs.getString("Role_")+rs.getString("username");
      ename=rs.getString("username");

      rs.close();
      stmt.close();
      conn.close();
      catch (Exception e)
      e.printStackTrace();




      response.setContentType("text/plain"); // Set content type of the response so that jQuery knows what it can expect.
      response.setCharacterEncoding("UTF-8"); // You want world domination, huh?
      response.getWriter().write(name); // Write response body.



      More info on how to do ajax with servlets here:
      How to use Servlets and Ajax?






      share|improve this answer

























        1












        1








        1







         <script>
        $(document).ready(function()
        $("#users").change(function()
        var value = $(this).val();
        $.get("AjaxServlet",q:value,function(data)
        $("#javaquery").html(data);
        );
        );
        );
        </script>


        Remove java code from 2nd jsp and add it to a servlet called "AjaxServlet" with url mapping "/AjaxServlet"



        AjaxServlet:



         @Override
        protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
        String q = request.getParameter("q"); //q value



        InitialContext ctx;
        DataSource ds;
        Connection conn;
        ResultSet rs;
        Statement stmt;

        String name = "blank name";
        String ename="";

        try

        ctx=new InitialContext();
        ds=(DataSource) ctx.lookup("java:app/jdbc/SalesDB");
        conn=ds.getConnection();







        String q = request.getParameter("q");

        stmt = conn.createStatement(); //Create Statement to interact
        rs = stmt.executeQuery("select * from employees where Username='"+q+"'");
        while (rs.next())
        name = rs.getString("Role_")+rs.getString("username");
        ename=rs.getString("username");

        rs.close();
        stmt.close();
        conn.close();
        catch (Exception e)
        e.printStackTrace();




        response.setContentType("text/plain"); // Set content type of the response so that jQuery knows what it can expect.
        response.setCharacterEncoding("UTF-8"); // You want world domination, huh?
        response.getWriter().write(name); // Write response body.



        More info on how to do ajax with servlets here:
        How to use Servlets and Ajax?






        share|improve this answer













         <script>
        $(document).ready(function()
        $("#users").change(function()
        var value = $(this).val();
        $.get("AjaxServlet",q:value,function(data)
        $("#javaquery").html(data);
        );
        );
        );
        </script>


        Remove java code from 2nd jsp and add it to a servlet called "AjaxServlet" with url mapping "/AjaxServlet"



        AjaxServlet:



         @Override
        protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
        String q = request.getParameter("q"); //q value



        InitialContext ctx;
        DataSource ds;
        Connection conn;
        ResultSet rs;
        Statement stmt;

        String name = "blank name";
        String ename="";

        try

        ctx=new InitialContext();
        ds=(DataSource) ctx.lookup("java:app/jdbc/SalesDB");
        conn=ds.getConnection();







        String q = request.getParameter("q");

        stmt = conn.createStatement(); //Create Statement to interact
        rs = stmt.executeQuery("select * from employees where Username='"+q+"'");
        while (rs.next())
        name = rs.getString("Role_")+rs.getString("username");
        ename=rs.getString("username");

        rs.close();
        stmt.close();
        conn.close();
        catch (Exception e)
        e.printStackTrace();




        response.setContentType("text/plain"); // Set content type of the response so that jQuery knows what it can expect.
        response.setCharacterEncoding("UTF-8"); // You want world domination, huh?
        response.getWriter().write(name); // Write response body.



        More info on how to do ajax with servlets here:
        How to use Servlets and Ajax?







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 10:28









        Jonathan LaliberteJonathan Laliberte

        1,6342825




        1,6342825





























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