Looking for a regular expression to match following
0
string = '***All Done***, ***Execution Success 5664 for $**$ files***'
re pattern = ([w+].*[$**]$.*[w+]|[w+])
output i'm getting: 'All Done***, ***Execution Success for $**$ files'
expected output: All Done Execution Success 5664 for $**$ files
Should get only alpha numeric characters and $**$. Rest all should be cleared. Any help would be appreciated. In case if $**$ is not found on string, then it should return: All Done Execution Success 5664 for files.
python regex
edited Nov 15 '18 at 11:56
fewlinesofcode
2,1071819
asked Nov 15 '18 at 11:11
rubenhardyrubenhardy
92
|
show 4 more comments
0
string = '***All Done***, ***Execution Success 5664 for $**$ files***'
re pattern = ([w+].*[$**]$.*[w+]|[w+])
output i'm getting: 'All Done***, ***Execution Success for $**$ files'
expected output: All Done Execution Success 5664 for $**$ files
Should get only alpha numeric characters and $**$. Rest all should be cleared. Any help would be appreciated. In case if $**$ is not found on string, then it should return: All Done Execution Success 5664 for files.
python regex
edited Nov 15 '18 at 11:56
fewlinesofcode
2,1071819
asked Nov 15 '18 at 11:11
rubenhardyrubenhardy
92
1
Tryre.sub(r'*3(.*?)*3|[^ws]', r'1', string)(this is for Python 3.5+)
– Wiktor Stribiżew
Nov 15 '18 at 11:14
This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'
– rubenhardy
Nov 15 '18 at 11:19
Then use ther'($**$)|[^ws]'regex with the same code as above.
– Wiktor Stribiżew
Nov 15 '18 at 11:24
Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"
– rubenhardy
Nov 15 '18 at 11:32
So, your Python is older than 3.5. Usere.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)
– Wiktor Stribiżew
Nov 15 '18 at 11:33
|
show 4 more comments
0
0
0
string = '***All Done***, ***Execution Success 5664 for $**$ files***'
re pattern = ([w+].*[$**]$.*[w+]|[w+])
output i'm getting: 'All Done***, ***Execution Success for $**$ files'
expected output: All Done Execution Success 5664 for $**$ files
Should get only alpha numeric characters and $**$. Rest all should be cleared. Any help would be appreciated. In case if $**$ is not found on string, then it should return: All Done Execution Success 5664 for files.
python regex
edited Nov 15 '18 at 11:56
fewlinesofcode
2,1071819
asked Nov 15 '18 at 11:11
rubenhardyrubenhardy
92
string = '***All Done***, ***Execution Success 5664 for $**$ files***'
re pattern = ([w+].*[$**]$.*[w+]|[w+])
output i'm getting: 'All Done***, ***Execution Success for $**$ files'
expected output: All Done Execution Success 5664 for $**$ files
Should get only alpha numeric characters and $**$. Rest all should be cleared. Any help would be appreciated. In case if $**$ is not found on string, then it should return: All Done Execution Success 5664 for files.
python regex
python regex
edited Nov 15 '18 at 11:56
fewlinesofcode
2,1071819
asked Nov 15 '18 at 11:11
rubenhardyrubenhardy
92
edited Nov 15 '18 at 11:56
fewlinesofcode
2,1071819
asked Nov 15 '18 at 11:11
rubenhardyrubenhardy
92
edited Nov 15 '18 at 11:56
fewlinesofcode
2,1071819
edited Nov 15 '18 at 11:56
fewlinesofcode
2,1071819
edited Nov 15 '18 at 11:56
fewlinesofcode
2,1071819
2,1071819
asked Nov 15 '18 at 11:11
rubenhardyrubenhardy
92
asked Nov 15 '18 at 11:11
rubenhardyrubenhardy
92
asked Nov 15 '18 at 11:11
rubenhardyrubenhardy
92
92
1
Tryre.sub(r'*3(.*?)*3|[^ws]', r'1', string)(this is for Python 3.5+)
– Wiktor Stribiżew
Nov 15 '18 at 11:14
This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'
– rubenhardy
Nov 15 '18 at 11:19
Then use ther'($**$)|[^ws]'regex with the same code as above.
– Wiktor Stribiżew
Nov 15 '18 at 11:24
Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"
– rubenhardy
Nov 15 '18 at 11:32
So, your Python is older than 3.5. Usere.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)
– Wiktor Stribiżew
Nov 15 '18 at 11:33
|
show 4 more comments
1
Tryre.sub(r'*3(.*?)*3|[^ws]', r'1', string)(this is for Python 3.5+)
– Wiktor Stribiżew
Nov 15 '18 at 11:14
This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'
– rubenhardy
Nov 15 '18 at 11:19
Then use ther'($**$)|[^ws]'regex with the same code as above.
– Wiktor Stribiżew
Nov 15 '18 at 11:24
Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"
– rubenhardy
Nov 15 '18 at 11:32
So, your Python is older than 3.5. Usere.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)
– Wiktor Stribiżew
Nov 15 '18 at 11:33
1
1
Try
re.sub(r'*3(.*?)*3|[^ws]', r'1', string) (this is for Python 3.5+)– Wiktor Stribiżew
Nov 15 '18 at 11:14
Try
re.sub(r'*3(.*?)*3|[^ws]', r'1', string) (this is for Python 3.5+)– Wiktor Stribiżew
Nov 15 '18 at 11:14
This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'
– rubenhardy
Nov 15 '18 at 11:19
This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'
– rubenhardy
Nov 15 '18 at 11:19
Then use the
r'($**$)|[^ws]' regex with the same code as above.– Wiktor Stribiżew
Nov 15 '18 at 11:24
Then use the
r'($**$)|[^ws]' regex with the same code as above.– Wiktor Stribiżew
Nov 15 '18 at 11:24
Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"
– rubenhardy
Nov 15 '18 at 11:32
Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"
– rubenhardy
Nov 15 '18 at 11:32
So, your Python is older than 3.5. Use
re.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)– Wiktor Stribiżew
Nov 15 '18 at 11:33
So, your Python is older than 3.5. Use
re.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)– Wiktor Stribiżew
Nov 15 '18 at 11:33
|
show 4 more comments
1 Answer
1
active
oldest
votes
0
This seems to work for your provided examples (Python 3.6):
import re
strings = [
'***All Done***, ***Execution Success 5664 for $**$ files***',
'Error not ** found. Restore $**$ again **'
]
pattern = "w+|$**$"
cpattern = re.compile(pattern)
for string in strings:
print(" ".join(cpattern.findall(string)))
Output:
All Done Execution Success 5664 for $**$ files
Error not found Restore $**$ again
answered Nov 15 '18 at 11:34
dabismaldabismal
12
This worked excellently for my need. Thank you dabismal.
– rubenhardy
Nov 15 '18 at 11:43
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
This seems to work for your provided examples (Python 3.6):
import re
strings = [
'***All Done***, ***Execution Success 5664 for $**$ files***',
'Error not ** found. Restore $**$ again **'
]
pattern = "w+|$**$"
cpattern = re.compile(pattern)
for string in strings:
print(" ".join(cpattern.findall(string)))
Output:
All Done Execution Success 5664 for $**$ files
Error not found Restore $**$ again
answered Nov 15 '18 at 11:34
dabismaldabismal
12
This worked excellently for my need. Thank you dabismal.
– rubenhardy
Nov 15 '18 at 11:43
add a comment |
0
This seems to work for your provided examples (Python 3.6):
import re
strings = [
'***All Done***, ***Execution Success 5664 for $**$ files***',
'Error not ** found. Restore $**$ again **'
]
pattern = "w+|$**$"
cpattern = re.compile(pattern)
for string in strings:
print(" ".join(cpattern.findall(string)))
Output:
All Done Execution Success 5664 for $**$ files
Error not found Restore $**$ again
answered Nov 15 '18 at 11:34
dabismaldabismal
12
This worked excellently for my need. Thank you dabismal.
– rubenhardy
Nov 15 '18 at 11:43
add a comment |
0
0
0
This seems to work for your provided examples (Python 3.6):
import re
strings = [
'***All Done***, ***Execution Success 5664 for $**$ files***',
'Error not ** found. Restore $**$ again **'
]
pattern = "w+|$**$"
cpattern = re.compile(pattern)
for string in strings:
print(" ".join(cpattern.findall(string)))
Output:
All Done Execution Success 5664 for $**$ files
Error not found Restore $**$ again
answered Nov 15 '18 at 11:34
dabismaldabismal
12
This seems to work for your provided examples (Python 3.6):
import re
strings = [
'***All Done***, ***Execution Success 5664 for $**$ files***',
'Error not ** found. Restore $**$ again **'
]
pattern = "w+|$**$"
cpattern = re.compile(pattern)
for string in strings:
print(" ".join(cpattern.findall(string)))
Output:
All Done Execution Success 5664 for $**$ files
Error not found Restore $**$ again
answered Nov 15 '18 at 11:34
dabismaldabismal
12
edited Nov 15 '18 at 11:41
answered Nov 15 '18 at 11:34
dabismaldabismal
12
answered Nov 15 '18 at 11:34
dabismaldabismal
12
answered Nov 15 '18 at 11:34
dabismaldabismal
12
12
This worked excellently for my need. Thank you dabismal.
– rubenhardy
Nov 15 '18 at 11:43
add a comment |
This worked excellently for my need. Thank you dabismal.
– rubenhardy
Nov 15 '18 at 11:43
This worked excellently for my need. Thank you dabismal.
– rubenhardy
Nov 15 '18 at 11:43
This worked excellently for my need. Thank you dabismal.
– rubenhardy
Nov 15 '18 at 11:43
add a comment |
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1
Try
re.sub(r'*3(.*?)*3|[^ws]', r'1', string)(this is for Python 3.5+)– Wiktor Stribiżew
Nov 15 '18 at 11:14
This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'
– rubenhardy
Nov 15 '18 at 11:19
Then use the
r'($**$)|[^ws]'regex with the same code as above.– Wiktor Stribiżew
Nov 15 '18 at 11:24
Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"
– rubenhardy
Nov 15 '18 at 11:32
So, your Python is older than 3.5. Use
re.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)– Wiktor Stribiżew
Nov 15 '18 at 11:33