Looking for a regular expression to match following

string = '***All Done***, ***Execution Success 5664 for $**$ files***'

re pattern = ([w+].*[$**]$.*[w+]|[w+])

output i'm getting: 'All Done***, ***Execution Success for $**$ files'

expected output: All Done Execution Success 5664 for $**$ files

Should get only alpha numeric characters and $**$ . Rest all should be cleared. Any help would be appreciated. In case if $**$ is not found on string, then it should return: All Done Execution Success 5664 for files.

edited Nov 15 '18 at 11:56

fewlinesofcode

2,1071819

asked Nov 15 '18 at 11:11

rubenhardy

1

Try re.sub(r'*3(.*?)*3|[^ws]', r'1', string) (this is for Python 3.5+)

– Wiktor Stribiżew
Nov 15 '18 at 11:14

This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'

– rubenhardy
Nov 15 '18 at 11:19

Then use the r'($**$)|[^ws]' regex with the same code as above.

– Wiktor Stribiżew
Nov 15 '18 at 11:24

Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"

– rubenhardy
Nov 15 '18 at 11:32

So, your Python is older than 3.5. Use re.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)

– Wiktor Stribiżew
Nov 15 '18 at 11:33

|
show 4 more comments

string = '***All Done***, ***Execution Success 5664 for $**$ files***'

re pattern = ([w+].*[$**]$.*[w+]|[w+])

output i'm getting: 'All Done***, ***Execution Success for $**$ files'

expected output: All Done Execution Success 5664 for $**$ files

edited Nov 15 '18 at 11:56

fewlinesofcode

2,1071819

asked Nov 15 '18 at 11:11

rubenhardy

1

Try re.sub(r'*3(.*?)*3|[^ws]', r'1', string) (this is for Python 3.5+)

– Wiktor Stribiżew
Nov 15 '18 at 11:14

This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'

– rubenhardy
Nov 15 '18 at 11:19

Then use the r'($**$)|[^ws]' regex with the same code as above.

– Wiktor Stribiżew
Nov 15 '18 at 11:24

Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"

– rubenhardy
Nov 15 '18 at 11:32

So, your Python is older than 3.5. Use re.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)

– Wiktor Stribiżew
Nov 15 '18 at 11:33

|
show 4 more comments

string = '***All Done***, ***Execution Success 5664 for $**$ files***'

re pattern = ([w+].*[$**]$.*[w+]|[w+])

output i'm getting: 'All Done***, ***Execution Success for $**$ files'

expected output: All Done Execution Success 5664 for $**$ files

edited Nov 15 '18 at 11:56

fewlinesofcode

2,1071819

asked Nov 15 '18 at 11:11

rubenhardy

string = '***All Done***, ***Execution Success 5664 for $**$ files***'

re pattern = ([w+].*[$**]$.*[w+]|[w+])

output i'm getting: 'All Done***, ***Execution Success for $**$ files'

expected output: All Done Execution Success 5664 for $**$ files

python regex

edited Nov 15 '18 at 11:56

fewlinesofcode

2,1071819

asked Nov 15 '18 at 11:11

rubenhardy

edited Nov 15 '18 at 11:56

fewlinesofcode

2,1071819

asked Nov 15 '18 at 11:11

rubenhardy

edited Nov 15 '18 at 11:56

fewlinesofcode

2,1071819

edited Nov 15 '18 at 11:56

fewlinesofcode

2,1071819

edited Nov 15 '18 at 11:56

fewlinesofcode

2,1071819

asked Nov 15 '18 at 11:11

rubenhardy

asked Nov 15 '18 at 11:11

rubenhardy

asked Nov 15 '18 at 11:11

rubenhardy

1

Try re.sub(r'*3(.*?)*3|[^ws]', r'1', string) (this is for Python 3.5+)

– Wiktor Stribiżew
Nov 15 '18 at 11:14

This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'

– rubenhardy
Nov 15 '18 at 11:19

Then use the r'($**$)|[^ws]' regex with the same code as above.

– Wiktor Stribiżew
Nov 15 '18 at 11:24

Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"

– rubenhardy
Nov 15 '18 at 11:32

So, your Python is older than 3.5. Use re.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)

– Wiktor Stribiżew
Nov 15 '18 at 11:33

|
show 4 more comments

1

Try re.sub(r'*3(.*?)*3|[^ws]', r'1', string) (this is for Python 3.5+)

– Wiktor Stribiżew
Nov 15 '18 at 11:14

This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'

– rubenhardy
Nov 15 '18 at 11:19

Then use the r'($**$)|[^ws]' regex with the same code as above.

– Wiktor Stribiżew
Nov 15 '18 at 11:24

Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"

– rubenhardy
Nov 15 '18 at 11:32

So, your Python is older than 3.5. Use re.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)

– Wiktor Stribiżew
Nov 15 '18 at 11:33

Try re.sub(r'*3(.*?)*3|[^ws]', r'1', string) (this is for Python 3.5+)

– Wiktor Stribiżew
Nov 15 '18 at 11:14

This did not work for me. String i've provided is just an example. It is not necessary to start with '***'. It can be like 'Error not ** found. Restore $**$ again **'. In this case i'm expecting regex to return 'Error not found Restore $**$ again'

– rubenhardy
Nov 15 '18 at 11:19

Then use the r'($**$)|[^ws]' regex with the same code as above.

– Wiktor Stribiżew
Nov 15 '18 at 11:24

Tried this: 're.sub(r'($**$)|[^ws]', r'1', string)'. Got an exception: "raise error, "unmatched group" sre_constants.error: unmatched group"

– rubenhardy
Nov 15 '18 at 11:32

So, your Python is older than 3.5. Use re.sub(r'($**$)|[^ws]', lambda x: x.group(1) if x.group(1) else '', string)

– Wiktor Stribiżew
Nov 15 '18 at 11:33

|
show 4 more comments

1 Answer
1

active

oldest

votes

This seems to work for your provided examples (Python 3.6):

import re

strings = [
 '***All Done***, ***Execution Success 5664 for $**$ files***',
 'Error not ** found. Restore $**$ again **'
]

pattern = "w+|$**$"
cpattern = re.compile(pattern)

for string in strings:
 print(" ".join(cpattern.findall(string)))

Output:

 All Done Execution Success 5664 for $**$ files
 Error not found Restore $**$ again

edited Nov 15 '18 at 11:41

answered Nov 15 '18 at 11:34

dabismal

This worked excellently for my need. Thank you dabismal.

– rubenhardy
Nov 15 '18 at 11:43

add a comment |

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1 Answer
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1 Answer
1

active

oldest

votes

This seems to work for your provided examples (Python 3.6):

import re

strings = [
 '***All Done***, ***Execution Success 5664 for $**$ files***',
 'Error not ** found. Restore $**$ again **'
]

pattern = "w+|$**$"
cpattern = re.compile(pattern)

for string in strings:
 print(" ".join(cpattern.findall(string)))

Output:

 All Done Execution Success 5664 for $**$ files
 Error not found Restore $**$ again

edited Nov 15 '18 at 11:41

answered Nov 15 '18 at 11:34

dabismal

This worked excellently for my need. Thank you dabismal.

– rubenhardy
Nov 15 '18 at 11:43

add a comment |

This seems to work for your provided examples (Python 3.6):

import re

strings = [
 '***All Done***, ***Execution Success 5664 for $**$ files***',
 'Error not ** found. Restore $**$ again **'
]

pattern = "w+|$**$"
cpattern = re.compile(pattern)

for string in strings:
 print(" ".join(cpattern.findall(string)))

Output:

 All Done Execution Success 5664 for $**$ files
 Error not found Restore $**$ again

edited Nov 15 '18 at 11:41

answered Nov 15 '18 at 11:34

dabismal

This worked excellently for my need. Thank you dabismal.

– rubenhardy
Nov 15 '18 at 11:43

add a comment |

This seems to work for your provided examples (Python 3.6):

import re

strings = [
 '***All Done***, ***Execution Success 5664 for $**$ files***',
 'Error not ** found. Restore $**$ again **'
]

pattern = "w+|$**$"
cpattern = re.compile(pattern)

for string in strings:
 print(" ".join(cpattern.findall(string)))

Output:

 All Done Execution Success 5664 for $**$ files
 Error not found Restore $**$ again

edited Nov 15 '18 at 11:41

answered Nov 15 '18 at 11:34

dabismal

This seems to work for your provided examples (Python 3.6):

import re

strings = [
 '***All Done***, ***Execution Success 5664 for $**$ files***',
 'Error not ** found. Restore $**$ again **'
]

pattern = "w+|$**$"
cpattern = re.compile(pattern)

for string in strings:
 print(" ".join(cpattern.findall(string)))

Output:

 All Done Execution Success 5664 for $**$ files
 Error not found Restore $**$ again

edited Nov 15 '18 at 11:41

answered Nov 15 '18 at 11:34

dabismal

edited Nov 15 '18 at 11:41

answered Nov 15 '18 at 11:34

dabismal

answered Nov 15 '18 at 11:34

dabismal

answered Nov 15 '18 at 11:34

dabismal

This worked excellently for my need. Thank you dabismal.

– rubenhardy
Nov 15 '18 at 11:43

add a comment |

This worked excellently for my need. Thank you dabismal.

– rubenhardy
Nov 15 '18 at 11:43

This worked excellently for my need. Thank you dabismal.

– rubenhardy
Nov 15 '18 at 11:43

add a comment |

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