SQL Division Operator and implementation in Mysql










0















In a database i have some cars that are rented by customers. I want to find the cars that were rented by All Customers, and display their PlateNr. In other words i want to make SQL Division in MySql.
My Database is like this:



Customer



ID,Name
1 , John
2 , Scott



Car



PlateNr,Colour
1111 , red
2222 , black



Rents



ID , PlateNr , Date
1, 1111, 2010-01-01
1, 1111, 2010-02-01
2, 1111, 2010-03-02
2, 2222, 2010-01-02



Following some instructions i have the following query, but it doesn't work to find the car that was rented by all customers (correct result should be Platenr=1111). What is wrong with the query?



SELECT PlateNr
FROM rents as R1
WHERE NOT EXISTS
(SELECT car.PlateNr
FROM car
WHERE NOT EXISTS
(SELECT rents.PlateNr
FROM rents
WHERE rents.PlateNr=R1.PlateNr));









share|improve this question


























    0















    In a database i have some cars that are rented by customers. I want to find the cars that were rented by All Customers, and display their PlateNr. In other words i want to make SQL Division in MySql.
    My Database is like this:



    Customer



    ID,Name
    1 , John
    2 , Scott



    Car



    PlateNr,Colour
    1111 , red
    2222 , black



    Rents



    ID , PlateNr , Date
    1, 1111, 2010-01-01
    1, 1111, 2010-02-01
    2, 1111, 2010-03-02
    2, 2222, 2010-01-02



    Following some instructions i have the following query, but it doesn't work to find the car that was rented by all customers (correct result should be Platenr=1111). What is wrong with the query?



    SELECT PlateNr
    FROM rents as R1
    WHERE NOT EXISTS
    (SELECT car.PlateNr
    FROM car
    WHERE NOT EXISTS
    (SELECT rents.PlateNr
    FROM rents
    WHERE rents.PlateNr=R1.PlateNr));









    share|improve this question
























      0












      0








      0








      In a database i have some cars that are rented by customers. I want to find the cars that were rented by All Customers, and display their PlateNr. In other words i want to make SQL Division in MySql.
      My Database is like this:



      Customer



      ID,Name
      1 , John
      2 , Scott



      Car



      PlateNr,Colour
      1111 , red
      2222 , black



      Rents



      ID , PlateNr , Date
      1, 1111, 2010-01-01
      1, 1111, 2010-02-01
      2, 1111, 2010-03-02
      2, 2222, 2010-01-02



      Following some instructions i have the following query, but it doesn't work to find the car that was rented by all customers (correct result should be Platenr=1111). What is wrong with the query?



      SELECT PlateNr
      FROM rents as R1
      WHERE NOT EXISTS
      (SELECT car.PlateNr
      FROM car
      WHERE NOT EXISTS
      (SELECT rents.PlateNr
      FROM rents
      WHERE rents.PlateNr=R1.PlateNr));









      share|improve this question














      In a database i have some cars that are rented by customers. I want to find the cars that were rented by All Customers, and display their PlateNr. In other words i want to make SQL Division in MySql.
      My Database is like this:



      Customer



      ID,Name
      1 , John
      2 , Scott



      Car



      PlateNr,Colour
      1111 , red
      2222 , black



      Rents



      ID , PlateNr , Date
      1, 1111, 2010-01-01
      1, 1111, 2010-02-01
      2, 1111, 2010-03-02
      2, 2222, 2010-01-02



      Following some instructions i have the following query, but it doesn't work to find the car that was rented by all customers (correct result should be Platenr=1111). What is wrong with the query?



      SELECT PlateNr
      FROM rents as R1
      WHERE NOT EXISTS
      (SELECT car.PlateNr
      FROM car
      WHERE NOT EXISTS
      (SELECT rents.PlateNr
      FROM rents
      WHERE rents.PlateNr=R1.PlateNr));






      mysql






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 14 '18 at 7:17









      ritgeoritgeo

      416




      416






















          2 Answers
          2






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          1














          I would write this query as:



          SELECT PlateNr
          FROM Rents
          GROUP BY PlateNr
          HAVING COUNT(DISTINCT ID) = (SELECT COUNT(*) FROM Customer);


          In plain English, this says to find all plates whose distinct count of renting customers matches the total number of customers. I assume here that ID is a unique column in the Customers table.






          share|improve this answer






























            0














            With this query you can see which customer rented which car and how many times, ıf you can ask something else you can add a comment



            Select Customer.Name,Car.PlateNr,count(*) as Count
            from Customer inner join Rents On Rents.ID=Customer.ID
            inner join Car On Car.PlateNr=Rents.PlateNr
            group by Customer.Name,Car.PlateNr
            having count(*)>1





            share|improve this answer

























            • Thanks Yusuf. It doesnt work, bu if i replace Car,PlateNr with Car.PlateNr it works as you describe.

              – ritgeo
              Nov 14 '18 at 7:52











            • Yes I corrected it,

              – yusuf hayırsever
              Nov 14 '18 at 7:53










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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            I would write this query as:



            SELECT PlateNr
            FROM Rents
            GROUP BY PlateNr
            HAVING COUNT(DISTINCT ID) = (SELECT COUNT(*) FROM Customer);


            In plain English, this says to find all plates whose distinct count of renting customers matches the total number of customers. I assume here that ID is a unique column in the Customers table.






            share|improve this answer



























              1














              I would write this query as:



              SELECT PlateNr
              FROM Rents
              GROUP BY PlateNr
              HAVING COUNT(DISTINCT ID) = (SELECT COUNT(*) FROM Customer);


              In plain English, this says to find all plates whose distinct count of renting customers matches the total number of customers. I assume here that ID is a unique column in the Customers table.






              share|improve this answer

























                1












                1








                1







                I would write this query as:



                SELECT PlateNr
                FROM Rents
                GROUP BY PlateNr
                HAVING COUNT(DISTINCT ID) = (SELECT COUNT(*) FROM Customer);


                In plain English, this says to find all plates whose distinct count of renting customers matches the total number of customers. I assume here that ID is a unique column in the Customers table.






                share|improve this answer













                I would write this query as:



                SELECT PlateNr
                FROM Rents
                GROUP BY PlateNr
                HAVING COUNT(DISTINCT ID) = (SELECT COUNT(*) FROM Customer);


                In plain English, this says to find all plates whose distinct count of renting customers matches the total number of customers. I assume here that ID is a unique column in the Customers table.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 14 '18 at 7:26









                Tim BiegeleisenTim Biegeleisen

                225k1391143




                225k1391143























                    0














                    With this query you can see which customer rented which car and how many times, ıf you can ask something else you can add a comment



                    Select Customer.Name,Car.PlateNr,count(*) as Count
                    from Customer inner join Rents On Rents.ID=Customer.ID
                    inner join Car On Car.PlateNr=Rents.PlateNr
                    group by Customer.Name,Car.PlateNr
                    having count(*)>1





                    share|improve this answer

























                    • Thanks Yusuf. It doesnt work, bu if i replace Car,PlateNr with Car.PlateNr it works as you describe.

                      – ritgeo
                      Nov 14 '18 at 7:52











                    • Yes I corrected it,

                      – yusuf hayırsever
                      Nov 14 '18 at 7:53















                    0














                    With this query you can see which customer rented which car and how many times, ıf you can ask something else you can add a comment



                    Select Customer.Name,Car.PlateNr,count(*) as Count
                    from Customer inner join Rents On Rents.ID=Customer.ID
                    inner join Car On Car.PlateNr=Rents.PlateNr
                    group by Customer.Name,Car.PlateNr
                    having count(*)>1





                    share|improve this answer

























                    • Thanks Yusuf. It doesnt work, bu if i replace Car,PlateNr with Car.PlateNr it works as you describe.

                      – ritgeo
                      Nov 14 '18 at 7:52











                    • Yes I corrected it,

                      – yusuf hayırsever
                      Nov 14 '18 at 7:53













                    0












                    0








                    0







                    With this query you can see which customer rented which car and how many times, ıf you can ask something else you can add a comment



                    Select Customer.Name,Car.PlateNr,count(*) as Count
                    from Customer inner join Rents On Rents.ID=Customer.ID
                    inner join Car On Car.PlateNr=Rents.PlateNr
                    group by Customer.Name,Car.PlateNr
                    having count(*)>1





                    share|improve this answer















                    With this query you can see which customer rented which car and how many times, ıf you can ask something else you can add a comment



                    Select Customer.Name,Car.PlateNr,count(*) as Count
                    from Customer inner join Rents On Rents.ID=Customer.ID
                    inner join Car On Car.PlateNr=Rents.PlateNr
                    group by Customer.Name,Car.PlateNr
                    having count(*)>1






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Nov 14 '18 at 7:53

























                    answered Nov 14 '18 at 7:38









                    yusuf hayırseveryusuf hayırsever

                    1877




                    1877












                    • Thanks Yusuf. It doesnt work, bu if i replace Car,PlateNr with Car.PlateNr it works as you describe.

                      – ritgeo
                      Nov 14 '18 at 7:52











                    • Yes I corrected it,

                      – yusuf hayırsever
                      Nov 14 '18 at 7:53

















                    • Thanks Yusuf. It doesnt work, bu if i replace Car,PlateNr with Car.PlateNr it works as you describe.

                      – ritgeo
                      Nov 14 '18 at 7:52











                    • Yes I corrected it,

                      – yusuf hayırsever
                      Nov 14 '18 at 7:53
















                    Thanks Yusuf. It doesnt work, bu if i replace Car,PlateNr with Car.PlateNr it works as you describe.

                    – ritgeo
                    Nov 14 '18 at 7:52





                    Thanks Yusuf. It doesnt work, bu if i replace Car,PlateNr with Car.PlateNr it works as you describe.

                    – ritgeo
                    Nov 14 '18 at 7:52













                    Yes I corrected it,

                    – yusuf hayırsever
                    Nov 14 '18 at 7:53





                    Yes I corrected it,

                    – yusuf hayırsever
                    Nov 14 '18 at 7:53

















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