SQL Reset row_number when column value changed










0















I've been trying to solve this but failed to do so. I need to get the duration of how long does a server has been unavailable. Here is the following data



Date | Time | Address | Status
11-14 | 6:32 | 1.1.1.1 | Down --- Count Start
11-14 | 6:34 | 1.1.1.1 | Down
11-14 | 6:54 | 1.1.1.1 | UP
11-14 | 7:20 | 1.1.1.1 | Down --- Reset Count to 1
11-14 | 7:25 | 1.1.1.1 | Down
11-14 | 7:30 | 1.1.1.1 | Up
11-14 | 7:40 | 1.1.1.1 | Down --- Reset Count to 1
11-14 | 6:35 | 2.2.2.2 | Down --- Now this is a different counter cause of different IP


I have this query



SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
,COALESCE(lag([Status]) over(order by [time]),'--') [Row]
INTO #temp
FROM
(
SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,CASE WHEN [status] = 'Success' THEN 'UP' ELSE 'DOWN' END [Status]
FROM [ESPS].[dbo].[Ping History] p
INNER JOIN [SuperDashboard].[dbo].[IP_Mapping] i ON i.[IP] = p.address
WHERE [Date] = CONVERT(Date,GETDATE())
) a

SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
FROM
(
SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
,CASE WHEN [Status] != [Row] THEN 1 ELSE 0 END [row]
FROM #temp
) a WHERE [row] = 1
DROP TABLE #temp


but this is only applicable with only one address as things get mixed up when I try to add 2.2.2.2. The ideal output of this is to get the duration of downtime of a server everytime it encounters a downtime. I hope someone can help me with this or point me to the right direction atleast.



Edit 1: Expected output should be



Date | Start DownTime | End DownTime | Address
11-14 | 6:32 | 6:54 | 1.1.1.1
11-14 | 7:20 | 7:30 | 1.1.1.1
11-14 | 7:40 | | 1.1.1.1
11-14 | 6:35 | | 2.2.2.2









share|improve this question
























  • can you show your expected result based on your above source data?

    – jap_jap
    Nov 14 '18 at 8:42











  • @im_one question has been updated sir.

    – Ordiz Imbano
    Nov 14 '18 at 11:00















0















I've been trying to solve this but failed to do so. I need to get the duration of how long does a server has been unavailable. Here is the following data



Date | Time | Address | Status
11-14 | 6:32 | 1.1.1.1 | Down --- Count Start
11-14 | 6:34 | 1.1.1.1 | Down
11-14 | 6:54 | 1.1.1.1 | UP
11-14 | 7:20 | 1.1.1.1 | Down --- Reset Count to 1
11-14 | 7:25 | 1.1.1.1 | Down
11-14 | 7:30 | 1.1.1.1 | Up
11-14 | 7:40 | 1.1.1.1 | Down --- Reset Count to 1
11-14 | 6:35 | 2.2.2.2 | Down --- Now this is a different counter cause of different IP


I have this query



SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
,COALESCE(lag([Status]) over(order by [time]),'--') [Row]
INTO #temp
FROM
(
SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,CASE WHEN [status] = 'Success' THEN 'UP' ELSE 'DOWN' END [Status]
FROM [ESPS].[dbo].[Ping History] p
INNER JOIN [SuperDashboard].[dbo].[IP_Mapping] i ON i.[IP] = p.address
WHERE [Date] = CONVERT(Date,GETDATE())
) a

SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
FROM
(
SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
,CASE WHEN [Status] != [Row] THEN 1 ELSE 0 END [row]
FROM #temp
) a WHERE [row] = 1
DROP TABLE #temp


but this is only applicable with only one address as things get mixed up when I try to add 2.2.2.2. The ideal output of this is to get the duration of downtime of a server everytime it encounters a downtime. I hope someone can help me with this or point me to the right direction atleast.



Edit 1: Expected output should be



Date | Start DownTime | End DownTime | Address
11-14 | 6:32 | 6:54 | 1.1.1.1
11-14 | 7:20 | 7:30 | 1.1.1.1
11-14 | 7:40 | | 1.1.1.1
11-14 | 6:35 | | 2.2.2.2









share|improve this question
























  • can you show your expected result based on your above source data?

    – jap_jap
    Nov 14 '18 at 8:42











  • @im_one question has been updated sir.

    – Ordiz Imbano
    Nov 14 '18 at 11:00













0












0








0


2






I've been trying to solve this but failed to do so. I need to get the duration of how long does a server has been unavailable. Here is the following data



Date | Time | Address | Status
11-14 | 6:32 | 1.1.1.1 | Down --- Count Start
11-14 | 6:34 | 1.1.1.1 | Down
11-14 | 6:54 | 1.1.1.1 | UP
11-14 | 7:20 | 1.1.1.1 | Down --- Reset Count to 1
11-14 | 7:25 | 1.1.1.1 | Down
11-14 | 7:30 | 1.1.1.1 | Up
11-14 | 7:40 | 1.1.1.1 | Down --- Reset Count to 1
11-14 | 6:35 | 2.2.2.2 | Down --- Now this is a different counter cause of different IP


I have this query



SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
,COALESCE(lag([Status]) over(order by [time]),'--') [Row]
INTO #temp
FROM
(
SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,CASE WHEN [status] = 'Success' THEN 'UP' ELSE 'DOWN' END [Status]
FROM [ESPS].[dbo].[Ping History] p
INNER JOIN [SuperDashboard].[dbo].[IP_Mapping] i ON i.[IP] = p.address
WHERE [Date] = CONVERT(Date,GETDATE())
) a

SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
FROM
(
SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
,CASE WHEN [Status] != [Row] THEN 1 ELSE 0 END [row]
FROM #temp
) a WHERE [row] = 1
DROP TABLE #temp


but this is only applicable with only one address as things get mixed up when I try to add 2.2.2.2. The ideal output of this is to get the duration of downtime of a server everytime it encounters a downtime. I hope someone can help me with this or point me to the right direction atleast.



Edit 1: Expected output should be



Date | Start DownTime | End DownTime | Address
11-14 | 6:32 | 6:54 | 1.1.1.1
11-14 | 7:20 | 7:30 | 1.1.1.1
11-14 | 7:40 | | 1.1.1.1
11-14 | 6:35 | | 2.2.2.2









share|improve this question
















I've been trying to solve this but failed to do so. I need to get the duration of how long does a server has been unavailable. Here is the following data



Date | Time | Address | Status
11-14 | 6:32 | 1.1.1.1 | Down --- Count Start
11-14 | 6:34 | 1.1.1.1 | Down
11-14 | 6:54 | 1.1.1.1 | UP
11-14 | 7:20 | 1.1.1.1 | Down --- Reset Count to 1
11-14 | 7:25 | 1.1.1.1 | Down
11-14 | 7:30 | 1.1.1.1 | Up
11-14 | 7:40 | 1.1.1.1 | Down --- Reset Count to 1
11-14 | 6:35 | 2.2.2.2 | Down --- Now this is a different counter cause of different IP


I have this query



SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
,COALESCE(lag([Status]) over(order by [time]),'--') [Row]
INTO #temp
FROM
(
SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,CASE WHEN [status] = 'Success' THEN 'UP' ELSE 'DOWN' END [Status]
FROM [ESPS].[dbo].[Ping History] p
INNER JOIN [SuperDashboard].[dbo].[IP_Mapping] i ON i.[IP] = p.address
WHERE [Date] = CONVERT(Date,GETDATE())
) a

SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
FROM
(
SELECT [date]
,[time]
,[address]
,[ms]
,[bytes]
,[ttl]
,[Status]
,CASE WHEN [Status] != [Row] THEN 1 ELSE 0 END [row]
FROM #temp
) a WHERE [row] = 1
DROP TABLE #temp


but this is only applicable with only one address as things get mixed up when I try to add 2.2.2.2. The ideal output of this is to get the duration of downtime of a server everytime it encounters a downtime. I hope someone can help me with this or point me to the right direction atleast.



Edit 1: Expected output should be



Date | Start DownTime | End DownTime | Address
11-14 | 6:32 | 6:54 | 1.1.1.1
11-14 | 7:20 | 7:30 | 1.1.1.1
11-14 | 7:40 | | 1.1.1.1
11-14 | 6:35 | | 2.2.2.2






sql sql-server-2017






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 10:59







Ordiz Imbano

















asked Nov 14 '18 at 7:12









Ordiz ImbanoOrdiz Imbano

117




117












  • can you show your expected result based on your above source data?

    – jap_jap
    Nov 14 '18 at 8:42











  • @im_one question has been updated sir.

    – Ordiz Imbano
    Nov 14 '18 at 11:00

















  • can you show your expected result based on your above source data?

    – jap_jap
    Nov 14 '18 at 8:42











  • @im_one question has been updated sir.

    – Ordiz Imbano
    Nov 14 '18 at 11:00
















can you show your expected result based on your above source data?

– jap_jap
Nov 14 '18 at 8:42





can you show your expected result based on your above source data?

– jap_jap
Nov 14 '18 at 8:42













@im_one question has been updated sir.

– Ordiz Imbano
Nov 14 '18 at 11:00





@im_one question has been updated sir.

– Ordiz Imbano
Nov 14 '18 at 11:00












2 Answers
2






active

oldest

votes


















0














This is a type of "group-and-islands" problem. If you can combine all the downs and following up (if any) into a single group, then the rest is just aggregation.



And, you can do this by counting the number of UPs that occur on or after each record. This is a simple cumulative sum, and then the rest is aggregation:



select address, date, grp,
min(case when status = 'DOWN' then time end) as startDown,
max(case when status = 'UP' then time end) as endUp
from (select t.*,
sum(case when status = 'UP' then 1 else 0 end) over (partition by address, date order by time desc) as grp
from t
) t
group by address, date, grp;





share|improve this answer






























    0














    Use lag() function



    DEMO



    select *,case when stat='Down' and (prevval='Up' or prevval is null) then 1 else 0 end as val from
    (
    select *,lag(stat) over(partition by address order by address) as prevval
    from #temp
    )A


    OUTPUT:



    address stat prevval val
    1.1.1.1 Down 1
    1.1.1.1 Up Down 0
    1.1.1.1 Down Up 1
    1.1.1.1 Down Down 0
    1.1.1.1 Up Down 0
    1.1.1.1 Down Up 1
    1.1.1.1 Down Down 0
    2.2.2.2 Down 1





    share|improve this answer

























    • hi sir I added the final expected output can you check it out?

      – Ordiz Imbano
      Nov 14 '18 at 11:02










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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    This is a type of "group-and-islands" problem. If you can combine all the downs and following up (if any) into a single group, then the rest is just aggregation.



    And, you can do this by counting the number of UPs that occur on or after each record. This is a simple cumulative sum, and then the rest is aggregation:



    select address, date, grp,
    min(case when status = 'DOWN' then time end) as startDown,
    max(case when status = 'UP' then time end) as endUp
    from (select t.*,
    sum(case when status = 'UP' then 1 else 0 end) over (partition by address, date order by time desc) as grp
    from t
    ) t
    group by address, date, grp;





    share|improve this answer



























      0














      This is a type of "group-and-islands" problem. If you can combine all the downs and following up (if any) into a single group, then the rest is just aggregation.



      And, you can do this by counting the number of UPs that occur on or after each record. This is a simple cumulative sum, and then the rest is aggregation:



      select address, date, grp,
      min(case when status = 'DOWN' then time end) as startDown,
      max(case when status = 'UP' then time end) as endUp
      from (select t.*,
      sum(case when status = 'UP' then 1 else 0 end) over (partition by address, date order by time desc) as grp
      from t
      ) t
      group by address, date, grp;





      share|improve this answer

























        0












        0








        0







        This is a type of "group-and-islands" problem. If you can combine all the downs and following up (if any) into a single group, then the rest is just aggregation.



        And, you can do this by counting the number of UPs that occur on or after each record. This is a simple cumulative sum, and then the rest is aggregation:



        select address, date, grp,
        min(case when status = 'DOWN' then time end) as startDown,
        max(case when status = 'UP' then time end) as endUp
        from (select t.*,
        sum(case when status = 'UP' then 1 else 0 end) over (partition by address, date order by time desc) as grp
        from t
        ) t
        group by address, date, grp;





        share|improve this answer













        This is a type of "group-and-islands" problem. If you can combine all the downs and following up (if any) into a single group, then the rest is just aggregation.



        And, you can do this by counting the number of UPs that occur on or after each record. This is a simple cumulative sum, and then the rest is aggregation:



        select address, date, grp,
        min(case when status = 'DOWN' then time end) as startDown,
        max(case when status = 'UP' then time end) as endUp
        from (select t.*,
        sum(case when status = 'UP' then 1 else 0 end) over (partition by address, date order by time desc) as grp
        from t
        ) t
        group by address, date, grp;






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 14 '18 at 12:43









        Gordon LinoffGordon Linoff

        773k35306408




        773k35306408























            0














            Use lag() function



            DEMO



            select *,case when stat='Down' and (prevval='Up' or prevval is null) then 1 else 0 end as val from
            (
            select *,lag(stat) over(partition by address order by address) as prevval
            from #temp
            )A


            OUTPUT:



            address stat prevval val
            1.1.1.1 Down 1
            1.1.1.1 Up Down 0
            1.1.1.1 Down Up 1
            1.1.1.1 Down Down 0
            1.1.1.1 Up Down 0
            1.1.1.1 Down Up 1
            1.1.1.1 Down Down 0
            2.2.2.2 Down 1





            share|improve this answer

























            • hi sir I added the final expected output can you check it out?

              – Ordiz Imbano
              Nov 14 '18 at 11:02















            0














            Use lag() function



            DEMO



            select *,case when stat='Down' and (prevval='Up' or prevval is null) then 1 else 0 end as val from
            (
            select *,lag(stat) over(partition by address order by address) as prevval
            from #temp
            )A


            OUTPUT:



            address stat prevval val
            1.1.1.1 Down 1
            1.1.1.1 Up Down 0
            1.1.1.1 Down Up 1
            1.1.1.1 Down Down 0
            1.1.1.1 Up Down 0
            1.1.1.1 Down Up 1
            1.1.1.1 Down Down 0
            2.2.2.2 Down 1





            share|improve this answer

























            • hi sir I added the final expected output can you check it out?

              – Ordiz Imbano
              Nov 14 '18 at 11:02













            0












            0








            0







            Use lag() function



            DEMO



            select *,case when stat='Down' and (prevval='Up' or prevval is null) then 1 else 0 end as val from
            (
            select *,lag(stat) over(partition by address order by address) as prevval
            from #temp
            )A


            OUTPUT:



            address stat prevval val
            1.1.1.1 Down 1
            1.1.1.1 Up Down 0
            1.1.1.1 Down Up 1
            1.1.1.1 Down Down 0
            1.1.1.1 Up Down 0
            1.1.1.1 Down Up 1
            1.1.1.1 Down Down 0
            2.2.2.2 Down 1





            share|improve this answer















            Use lag() function



            DEMO



            select *,case when stat='Down' and (prevval='Up' or prevval is null) then 1 else 0 end as val from
            (
            select *,lag(stat) over(partition by address order by address) as prevval
            from #temp
            )A


            OUTPUT:



            address stat prevval val
            1.1.1.1 Down 1
            1.1.1.1 Up Down 0
            1.1.1.1 Down Up 1
            1.1.1.1 Down Down 0
            1.1.1.1 Up Down 0
            1.1.1.1 Down Up 1
            1.1.1.1 Down Down 0
            2.2.2.2 Down 1






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 14 '18 at 7:25

























            answered Nov 14 '18 at 7:16









            fa06fa06

            13.2k2917




            13.2k2917












            • hi sir I added the final expected output can you check it out?

              – Ordiz Imbano
              Nov 14 '18 at 11:02

















            • hi sir I added the final expected output can you check it out?

              – Ordiz Imbano
              Nov 14 '18 at 11:02
















            hi sir I added the final expected output can you check it out?

            – Ordiz Imbano
            Nov 14 '18 at 11:02





            hi sir I added the final expected output can you check it out?

            – Ordiz Imbano
            Nov 14 '18 at 11:02

















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