Multiply the rows with dates in aws athena
I'm new to aws athena.
Is there a way to get the expected output from this input?
INPUT (csv file has following input)
DATE (yyyymmdd) | ip | FINISHED ( 1:finished; 0: not finish)
2017-01-01 | 111 | 1
2017-01-01 | 222 | 1
2017-01-02 | 333 | 1
2017-01-03 | 444 | 1
EXPECTED OUTPUT
DATE (yyyymmdd) | ip | FINISHED ( 1:finished; 0: not finish)
2017-01-01 | 111 | 1
2017-01-01 | 222 | 1
2017-01-01 | 333 | 0
2017-01-01 | 444 | 0
2017-01-02 | 111 | 1
2017-01-02 | 222 | 1
2017-01-02 | 333 | 1
2017-01-02 | 444 | 0
2017-01-03 | 111 | 1
2017-01-03 | 222 | 1
2017-01-03 | 333 | 1
2017-01-03 | 444 | 1
amazon-athena
add a comment |
I'm new to aws athena.
Is there a way to get the expected output from this input?
INPUT (csv file has following input)
DATE (yyyymmdd) | ip | FINISHED ( 1:finished; 0: not finish)
2017-01-01 | 111 | 1
2017-01-01 | 222 | 1
2017-01-02 | 333 | 1
2017-01-03 | 444 | 1
EXPECTED OUTPUT
DATE (yyyymmdd) | ip | FINISHED ( 1:finished; 0: not finish)
2017-01-01 | 111 | 1
2017-01-01 | 222 | 1
2017-01-01 | 333 | 0
2017-01-01 | 444 | 0
2017-01-02 | 111 | 1
2017-01-02 | 222 | 1
2017-01-02 | 333 | 1
2017-01-02 | 444 | 0
2017-01-03 | 111 | 1
2017-01-03 | 222 | 1
2017-01-03 | 333 | 1
2017-01-03 | 444 | 1
amazon-athena
add a comment |
I'm new to aws athena.
Is there a way to get the expected output from this input?
INPUT (csv file has following input)
DATE (yyyymmdd) | ip | FINISHED ( 1:finished; 0: not finish)
2017-01-01 | 111 | 1
2017-01-01 | 222 | 1
2017-01-02 | 333 | 1
2017-01-03 | 444 | 1
EXPECTED OUTPUT
DATE (yyyymmdd) | ip | FINISHED ( 1:finished; 0: not finish)
2017-01-01 | 111 | 1
2017-01-01 | 222 | 1
2017-01-01 | 333 | 0
2017-01-01 | 444 | 0
2017-01-02 | 111 | 1
2017-01-02 | 222 | 1
2017-01-02 | 333 | 1
2017-01-02 | 444 | 0
2017-01-03 | 111 | 1
2017-01-03 | 222 | 1
2017-01-03 | 333 | 1
2017-01-03 | 444 | 1
amazon-athena
I'm new to aws athena.
Is there a way to get the expected output from this input?
INPUT (csv file has following input)
DATE (yyyymmdd) | ip | FINISHED ( 1:finished; 0: not finish)
2017-01-01 | 111 | 1
2017-01-01 | 222 | 1
2017-01-02 | 333 | 1
2017-01-03 | 444 | 1
EXPECTED OUTPUT
DATE (yyyymmdd) | ip | FINISHED ( 1:finished; 0: not finish)
2017-01-01 | 111 | 1
2017-01-01 | 222 | 1
2017-01-01 | 333 | 0
2017-01-01 | 444 | 0
2017-01-02 | 111 | 1
2017-01-02 | 222 | 1
2017-01-02 | 333 | 1
2017-01-02 | 444 | 0
2017-01-03 | 111 | 1
2017-01-03 | 222 | 1
2017-01-03 | 333 | 1
2017-01-03 | 444 | 1
amazon-athena
amazon-athena
edited Nov 21 '18 at 4:30
thang phi
asked Nov 14 '18 at 7:14
thang phithang phi
35
35
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add a comment |
1 Answer
1
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oldest
votes
This is example query how to do it:
select t1."DATE (yyyymmdd)",t2.ip from
(SELECT "DATE (yyyymmdd)" FROM tab1 group by "DATE (yyyymmdd)") t1,
(SELECT ip FROM tab2 group by ip) t2
In this "select" is used cartesian join, so you cannot apply this to big data set, because there will occur the performance issues.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This is example query how to do it:
select t1."DATE (yyyymmdd)",t2.ip from
(SELECT "DATE (yyyymmdd)" FROM tab1 group by "DATE (yyyymmdd)") t1,
(SELECT ip FROM tab2 group by ip) t2
In this "select" is used cartesian join, so you cannot apply this to big data set, because there will occur the performance issues.
add a comment |
This is example query how to do it:
select t1."DATE (yyyymmdd)",t2.ip from
(SELECT "DATE (yyyymmdd)" FROM tab1 group by "DATE (yyyymmdd)") t1,
(SELECT ip FROM tab2 group by ip) t2
In this "select" is used cartesian join, so you cannot apply this to big data set, because there will occur the performance issues.
add a comment |
This is example query how to do it:
select t1."DATE (yyyymmdd)",t2.ip from
(SELECT "DATE (yyyymmdd)" FROM tab1 group by "DATE (yyyymmdd)") t1,
(SELECT ip FROM tab2 group by ip) t2
In this "select" is used cartesian join, so you cannot apply this to big data set, because there will occur the performance issues.
This is example query how to do it:
select t1."DATE (yyyymmdd)",t2.ip from
(SELECT "DATE (yyyymmdd)" FROM tab1 group by "DATE (yyyymmdd)") t1,
(SELECT ip FROM tab2 group by ip) t2
In this "select" is used cartesian join, so you cannot apply this to big data set, because there will occur the performance issues.
answered Nov 24 '18 at 13:58
j.b.gorskij.b.gorski
666212
666212
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