PIMPL idiom for a pointer to a class in C++










1















I have a working interface for two programs (ProgramA and ProgramB) that I would like to improve decoupling both programs as much as possible. The case that I want to cover is making a call from ProgramA to a class from ProgramB (Compute_Prop) that can only be initialized with some arguments which I do not now in advance. Hence, I use a pointer in the header. Currently, I have something like this:



interface.h



#include "programB.h" // loads Compute_Prop

class Compute
public:
Compute();
Compute(targ1 arg1, targ2 arg2);
~Compute();
// some methods ...
private:
Compute_Prop* compute;
;


interface.cpp



#include "programB.h"
#include "interface.h"

#include "programA.h"

Compute::Compute() = default;

Compute::~Compute()
delete compute;


Compute::Compute(arg1, arg2)

// do something ... to get data

compute = new Compute_Prop( &data, arg2 );



Then, I try to imitate the PIMPL idiom with the following



interface.h



#include "programB.h" // loads Compute_Prop

class Compute
public:
Compute();
Compute(targ1 arg1, targ2 arg2);
~Compute();
// some methods ...
private:
class PIMPL;
PIMPL* compute;
;


interface.cpp



#include "programB.h"
#include "interface.h"

#include "programA.h"

Compute::PIMPL = Compute_Prop;

Compute::Compute() = default;

Compute::~Compute()
delete compute;


Compute::Compute(arg1, arg2)

// do something ... to get data

compute = new Compute_Prop( &data, arg2 );



but the compiler says:



error: expected unqualified-id
Compute::PIMPL = Compute_Prop;
^


I guess that it has something to do with Compute_Prop not having
an empty constructor. I can't come up with something that works. What should I do? Something like a pointer to a pointer, maybe? As a restriction, I cannot modify programB.



Note: As it is probably already clear from above, my understanding of low level C++/C is scarce.



EDIT: I introduced the corrections suggested by @n.m. and @Matthieu Brucher










share|improve this question



















  • 1





    Your member declaration syntax is wrong throughout. You are not supposed to repeat the class name inside the class. So no Compute::Compute(), just Compute(). I have no idea why some compilers accept the syntax you are using, it's totally illegal.

    – n.m.
    Nov 13 '18 at 19:37







  • 3





    You cannot assign types in C++. Once you declare class PIMPL; it expects that there will be a class named PIMPL. Pointer declared as PIMPL* ptr; will always have the type PIMPL of that promised class. Compute::PIMPL = Compute_Prop; is not possible, because PIMPL and Compute_Prop are both immutable types. It won't convert all PIMPLs into Compute_Props.

    – Quimby
    Nov 13 '18 at 19:57







  • 1





    if ( compute != nullptr ) delete compute; compute = nullptr; No!! just delete it, or even better, use std::unique_ptr!!

    – Matthieu Brucher
    Nov 13 '18 at 20:09






  • 1





    Compute::PIMPL is a type, you cannot have this type = value syntax. You need a name. Something like Compute::compute perhaps. Compute::PIMPL Compute::compute = ....

    – n.m.
    Nov 13 '18 at 20:28







  • 1





    yes, delete already does the check, it's a useless redundancy. And if you have problems with using unique_ptr, then it means that you have other things to fix as well, ceuase that's how the pimlp should be handled.

    – Matthieu Brucher
    Nov 14 '18 at 14:00















1















I have a working interface for two programs (ProgramA and ProgramB) that I would like to improve decoupling both programs as much as possible. The case that I want to cover is making a call from ProgramA to a class from ProgramB (Compute_Prop) that can only be initialized with some arguments which I do not now in advance. Hence, I use a pointer in the header. Currently, I have something like this:



interface.h



#include "programB.h" // loads Compute_Prop

class Compute
public:
Compute();
Compute(targ1 arg1, targ2 arg2);
~Compute();
// some methods ...
private:
Compute_Prop* compute;
;


interface.cpp



#include "programB.h"
#include "interface.h"

#include "programA.h"

Compute::Compute() = default;

Compute::~Compute()
delete compute;


Compute::Compute(arg1, arg2)

// do something ... to get data

compute = new Compute_Prop( &data, arg2 );



Then, I try to imitate the PIMPL idiom with the following



interface.h



#include "programB.h" // loads Compute_Prop

class Compute
public:
Compute();
Compute(targ1 arg1, targ2 arg2);
~Compute();
// some methods ...
private:
class PIMPL;
PIMPL* compute;
;


interface.cpp



#include "programB.h"
#include "interface.h"

#include "programA.h"

Compute::PIMPL = Compute_Prop;

Compute::Compute() = default;

Compute::~Compute()
delete compute;


Compute::Compute(arg1, arg2)

// do something ... to get data

compute = new Compute_Prop( &data, arg2 );



but the compiler says:



error: expected unqualified-id
Compute::PIMPL = Compute_Prop;
^


I guess that it has something to do with Compute_Prop not having
an empty constructor. I can't come up with something that works. What should I do? Something like a pointer to a pointer, maybe? As a restriction, I cannot modify programB.



Note: As it is probably already clear from above, my understanding of low level C++/C is scarce.



EDIT: I introduced the corrections suggested by @n.m. and @Matthieu Brucher










share|improve this question



















  • 1





    Your member declaration syntax is wrong throughout. You are not supposed to repeat the class name inside the class. So no Compute::Compute(), just Compute(). I have no idea why some compilers accept the syntax you are using, it's totally illegal.

    – n.m.
    Nov 13 '18 at 19:37







  • 3





    You cannot assign types in C++. Once you declare class PIMPL; it expects that there will be a class named PIMPL. Pointer declared as PIMPL* ptr; will always have the type PIMPL of that promised class. Compute::PIMPL = Compute_Prop; is not possible, because PIMPL and Compute_Prop are both immutable types. It won't convert all PIMPLs into Compute_Props.

    – Quimby
    Nov 13 '18 at 19:57







  • 1





    if ( compute != nullptr ) delete compute; compute = nullptr; No!! just delete it, or even better, use std::unique_ptr!!

    – Matthieu Brucher
    Nov 13 '18 at 20:09






  • 1





    Compute::PIMPL is a type, you cannot have this type = value syntax. You need a name. Something like Compute::compute perhaps. Compute::PIMPL Compute::compute = ....

    – n.m.
    Nov 13 '18 at 20:28







  • 1





    yes, delete already does the check, it's a useless redundancy. And if you have problems with using unique_ptr, then it means that you have other things to fix as well, ceuase that's how the pimlp should be handled.

    – Matthieu Brucher
    Nov 14 '18 at 14:00













1












1








1








I have a working interface for two programs (ProgramA and ProgramB) that I would like to improve decoupling both programs as much as possible. The case that I want to cover is making a call from ProgramA to a class from ProgramB (Compute_Prop) that can only be initialized with some arguments which I do not now in advance. Hence, I use a pointer in the header. Currently, I have something like this:



interface.h



#include "programB.h" // loads Compute_Prop

class Compute
public:
Compute();
Compute(targ1 arg1, targ2 arg2);
~Compute();
// some methods ...
private:
Compute_Prop* compute;
;


interface.cpp



#include "programB.h"
#include "interface.h"

#include "programA.h"

Compute::Compute() = default;

Compute::~Compute()
delete compute;


Compute::Compute(arg1, arg2)

// do something ... to get data

compute = new Compute_Prop( &data, arg2 );



Then, I try to imitate the PIMPL idiom with the following



interface.h



#include "programB.h" // loads Compute_Prop

class Compute
public:
Compute();
Compute(targ1 arg1, targ2 arg2);
~Compute();
// some methods ...
private:
class PIMPL;
PIMPL* compute;
;


interface.cpp



#include "programB.h"
#include "interface.h"

#include "programA.h"

Compute::PIMPL = Compute_Prop;

Compute::Compute() = default;

Compute::~Compute()
delete compute;


Compute::Compute(arg1, arg2)

// do something ... to get data

compute = new Compute_Prop( &data, arg2 );



but the compiler says:



error: expected unqualified-id
Compute::PIMPL = Compute_Prop;
^


I guess that it has something to do with Compute_Prop not having
an empty constructor. I can't come up with something that works. What should I do? Something like a pointer to a pointer, maybe? As a restriction, I cannot modify programB.



Note: As it is probably already clear from above, my understanding of low level C++/C is scarce.



EDIT: I introduced the corrections suggested by @n.m. and @Matthieu Brucher










share|improve this question
















I have a working interface for two programs (ProgramA and ProgramB) that I would like to improve decoupling both programs as much as possible. The case that I want to cover is making a call from ProgramA to a class from ProgramB (Compute_Prop) that can only be initialized with some arguments which I do not now in advance. Hence, I use a pointer in the header. Currently, I have something like this:



interface.h



#include "programB.h" // loads Compute_Prop

class Compute
public:
Compute();
Compute(targ1 arg1, targ2 arg2);
~Compute();
// some methods ...
private:
Compute_Prop* compute;
;


interface.cpp



#include "programB.h"
#include "interface.h"

#include "programA.h"

Compute::Compute() = default;

Compute::~Compute()
delete compute;


Compute::Compute(arg1, arg2)

// do something ... to get data

compute = new Compute_Prop( &data, arg2 );



Then, I try to imitate the PIMPL idiom with the following



interface.h



#include "programB.h" // loads Compute_Prop

class Compute
public:
Compute();
Compute(targ1 arg1, targ2 arg2);
~Compute();
// some methods ...
private:
class PIMPL;
PIMPL* compute;
;


interface.cpp



#include "programB.h"
#include "interface.h"

#include "programA.h"

Compute::PIMPL = Compute_Prop;

Compute::Compute() = default;

Compute::~Compute()
delete compute;


Compute::Compute(arg1, arg2)

// do something ... to get data

compute = new Compute_Prop( &data, arg2 );



but the compiler says:



error: expected unqualified-id
Compute::PIMPL = Compute_Prop;
^


I guess that it has something to do with Compute_Prop not having
an empty constructor. I can't come up with something that works. What should I do? Something like a pointer to a pointer, maybe? As a restriction, I cannot modify programB.



Note: As it is probably already clear from above, my understanding of low level C++/C is scarce.



EDIT: I introduced the corrections suggested by @n.m. and @Matthieu Brucher







c++ c++11 pointers pimpl-idiom






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 18 '18 at 21:46







Zythos

















asked Nov 13 '18 at 19:26









ZythosZythos

16118




16118







  • 1





    Your member declaration syntax is wrong throughout. You are not supposed to repeat the class name inside the class. So no Compute::Compute(), just Compute(). I have no idea why some compilers accept the syntax you are using, it's totally illegal.

    – n.m.
    Nov 13 '18 at 19:37







  • 3





    You cannot assign types in C++. Once you declare class PIMPL; it expects that there will be a class named PIMPL. Pointer declared as PIMPL* ptr; will always have the type PIMPL of that promised class. Compute::PIMPL = Compute_Prop; is not possible, because PIMPL and Compute_Prop are both immutable types. It won't convert all PIMPLs into Compute_Props.

    – Quimby
    Nov 13 '18 at 19:57







  • 1





    if ( compute != nullptr ) delete compute; compute = nullptr; No!! just delete it, or even better, use std::unique_ptr!!

    – Matthieu Brucher
    Nov 13 '18 at 20:09






  • 1





    Compute::PIMPL is a type, you cannot have this type = value syntax. You need a name. Something like Compute::compute perhaps. Compute::PIMPL Compute::compute = ....

    – n.m.
    Nov 13 '18 at 20:28







  • 1





    yes, delete already does the check, it's a useless redundancy. And if you have problems with using unique_ptr, then it means that you have other things to fix as well, ceuase that's how the pimlp should be handled.

    – Matthieu Brucher
    Nov 14 '18 at 14:00












  • 1





    Your member declaration syntax is wrong throughout. You are not supposed to repeat the class name inside the class. So no Compute::Compute(), just Compute(). I have no idea why some compilers accept the syntax you are using, it's totally illegal.

    – n.m.
    Nov 13 '18 at 19:37







  • 3





    You cannot assign types in C++. Once you declare class PIMPL; it expects that there will be a class named PIMPL. Pointer declared as PIMPL* ptr; will always have the type PIMPL of that promised class. Compute::PIMPL = Compute_Prop; is not possible, because PIMPL and Compute_Prop are both immutable types. It won't convert all PIMPLs into Compute_Props.

    – Quimby
    Nov 13 '18 at 19:57







  • 1





    if ( compute != nullptr ) delete compute; compute = nullptr; No!! just delete it, or even better, use std::unique_ptr!!

    – Matthieu Brucher
    Nov 13 '18 at 20:09






  • 1





    Compute::PIMPL is a type, you cannot have this type = value syntax. You need a name. Something like Compute::compute perhaps. Compute::PIMPL Compute::compute = ....

    – n.m.
    Nov 13 '18 at 20:28







  • 1





    yes, delete already does the check, it's a useless redundancy. And if you have problems with using unique_ptr, then it means that you have other things to fix as well, ceuase that's how the pimlp should be handled.

    – Matthieu Brucher
    Nov 14 '18 at 14:00







1




1





Your member declaration syntax is wrong throughout. You are not supposed to repeat the class name inside the class. So no Compute::Compute(), just Compute(). I have no idea why some compilers accept the syntax you are using, it's totally illegal.

– n.m.
Nov 13 '18 at 19:37






Your member declaration syntax is wrong throughout. You are not supposed to repeat the class name inside the class. So no Compute::Compute(), just Compute(). I have no idea why some compilers accept the syntax you are using, it's totally illegal.

– n.m.
Nov 13 '18 at 19:37





3




3





You cannot assign types in C++. Once you declare class PIMPL; it expects that there will be a class named PIMPL. Pointer declared as PIMPL* ptr; will always have the type PIMPL of that promised class. Compute::PIMPL = Compute_Prop; is not possible, because PIMPL and Compute_Prop are both immutable types. It won't convert all PIMPLs into Compute_Props.

– Quimby
Nov 13 '18 at 19:57






You cannot assign types in C++. Once you declare class PIMPL; it expects that there will be a class named PIMPL. Pointer declared as PIMPL* ptr; will always have the type PIMPL of that promised class. Compute::PIMPL = Compute_Prop; is not possible, because PIMPL and Compute_Prop are both immutable types. It won't convert all PIMPLs into Compute_Props.

– Quimby
Nov 13 '18 at 19:57





1




1





if ( compute != nullptr ) delete compute; compute = nullptr; No!! just delete it, or even better, use std::unique_ptr!!

– Matthieu Brucher
Nov 13 '18 at 20:09





if ( compute != nullptr ) delete compute; compute = nullptr; No!! just delete it, or even better, use std::unique_ptr!!

– Matthieu Brucher
Nov 13 '18 at 20:09




1




1





Compute::PIMPL is a type, you cannot have this type = value syntax. You need a name. Something like Compute::compute perhaps. Compute::PIMPL Compute::compute = ....

– n.m.
Nov 13 '18 at 20:28






Compute::PIMPL is a type, you cannot have this type = value syntax. You need a name. Something like Compute::compute perhaps. Compute::PIMPL Compute::compute = ....

– n.m.
Nov 13 '18 at 20:28





1




1





yes, delete already does the check, it's a useless redundancy. And if you have problems with using unique_ptr, then it means that you have other things to fix as well, ceuase that's how the pimlp should be handled.

– Matthieu Brucher
Nov 14 '18 at 14:00





yes, delete already does the check, it's a useless redundancy. And if you have problems with using unique_ptr, then it means that you have other things to fix as well, ceuase that's how the pimlp should be handled.

– Matthieu Brucher
Nov 14 '18 at 14:00












2 Answers
2






active

oldest

votes


















1














Your implementation should use an interface (or in fact a class with only abstract methods) as a base class.
You cannot assign types in C++. You can only create typedefs and aliases, like that:



using PIMPLType = Compute_Prop;


However this won't work in your case.
This is how it should be implemented (also with possibility of multiple implementations):



class IImplementation

public:
virtual void saySomething() = 0;
;

class ImplementationA : public IImplementation

public:
virtual void saySomething() override
std::cout << "A";

;
class ImplementationB : public IImplementation

public:
virtual void saySomething() override
std::cout << "B";

;

class Foo
IImplementation *pimpl;
public:
Foo()
: pimpl(new ImplementationA)


~Foo() delete pimpl;

void saySomething()
pimpl->saySomething();

;





share|improve this answer























  • I will investigate how to materialize it. Also, a point of concern is speed, methods of Compute are called millions of times and can take either milliseconds or minutes, hours.

    – Zythos
    Nov 14 '18 at 14:02



















0














I may have come across a simple solution. I post it here so you can judge if it is adequate, or even if it can be improved --- sure. I am convinced that runtime polymorphism is not needed, not even polymorphism. The member variable compute is going to be a pointer to a Compute_Prop type anyway. Then, given that performance is critical here: why running the extra overhead of virtual member functions?



The point here is to reach an implementation that hides the inclusion of Compute_Prop without loosing performance. How? This particular solution uses a templated class and then explicit instantiation. The point is that instantiation can be done in the implementation. Got it from a Fluent C++ blog post. Also, this post has hints for how the implementation should be done. A prototype would be:



interface.h



template <typename T>
class Compute
public:
Compute();
Compute(targ1 arg1, targ2 arg2);
~Compute();
// some methods ...
private:
T* compute; // No need to state that is going to be T:=Compute_Prop
;


interface_impl.h



#include "interface.h" 
#include "programA.h"

template <typename T>
Compute::Compute() = default;

template <typename T>
Compute::~Compute()
delete compute;


template <typename T>
Compute::Compute(arg1, arg2)

// do something ... to get data

compute = new T( &data, arg2 );



interface.cpp



 #include "interface.h"
#include "interface_impl.h"
#include "programA.h"
#include "programB.h" // loads Compute_Prop

int main(int argc, char** argv)

template class Compute<Compute_Prop>;




Another related question that might be useful for those with the same dilemma.






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    2 Answers
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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Your implementation should use an interface (or in fact a class with only abstract methods) as a base class.
    You cannot assign types in C++. You can only create typedefs and aliases, like that:



    using PIMPLType = Compute_Prop;


    However this won't work in your case.
    This is how it should be implemented (also with possibility of multiple implementations):



    class IImplementation

    public:
    virtual void saySomething() = 0;
    ;

    class ImplementationA : public IImplementation

    public:
    virtual void saySomething() override
    std::cout << "A";

    ;
    class ImplementationB : public IImplementation

    public:
    virtual void saySomething() override
    std::cout << "B";

    ;

    class Foo
    IImplementation *pimpl;
    public:
    Foo()
    : pimpl(new ImplementationA)


    ~Foo() delete pimpl;

    void saySomething()
    pimpl->saySomething();

    ;





    share|improve this answer























    • I will investigate how to materialize it. Also, a point of concern is speed, methods of Compute are called millions of times and can take either milliseconds or minutes, hours.

      – Zythos
      Nov 14 '18 at 14:02
















    1














    Your implementation should use an interface (or in fact a class with only abstract methods) as a base class.
    You cannot assign types in C++. You can only create typedefs and aliases, like that:



    using PIMPLType = Compute_Prop;


    However this won't work in your case.
    This is how it should be implemented (also with possibility of multiple implementations):



    class IImplementation

    public:
    virtual void saySomething() = 0;
    ;

    class ImplementationA : public IImplementation

    public:
    virtual void saySomething() override
    std::cout << "A";

    ;
    class ImplementationB : public IImplementation

    public:
    virtual void saySomething() override
    std::cout << "B";

    ;

    class Foo
    IImplementation *pimpl;
    public:
    Foo()
    : pimpl(new ImplementationA)


    ~Foo() delete pimpl;

    void saySomething()
    pimpl->saySomething();

    ;





    share|improve this answer























    • I will investigate how to materialize it. Also, a point of concern is speed, methods of Compute are called millions of times and can take either milliseconds or minutes, hours.

      – Zythos
      Nov 14 '18 at 14:02














    1












    1








    1







    Your implementation should use an interface (or in fact a class with only abstract methods) as a base class.
    You cannot assign types in C++. You can only create typedefs and aliases, like that:



    using PIMPLType = Compute_Prop;


    However this won't work in your case.
    This is how it should be implemented (also with possibility of multiple implementations):



    class IImplementation

    public:
    virtual void saySomething() = 0;
    ;

    class ImplementationA : public IImplementation

    public:
    virtual void saySomething() override
    std::cout << "A";

    ;
    class ImplementationB : public IImplementation

    public:
    virtual void saySomething() override
    std::cout << "B";

    ;

    class Foo
    IImplementation *pimpl;
    public:
    Foo()
    : pimpl(new ImplementationA)


    ~Foo() delete pimpl;

    void saySomething()
    pimpl->saySomething();

    ;





    share|improve this answer













    Your implementation should use an interface (or in fact a class with only abstract methods) as a base class.
    You cannot assign types in C++. You can only create typedefs and aliases, like that:



    using PIMPLType = Compute_Prop;


    However this won't work in your case.
    This is how it should be implemented (also with possibility of multiple implementations):



    class IImplementation

    public:
    virtual void saySomething() = 0;
    ;

    class ImplementationA : public IImplementation

    public:
    virtual void saySomething() override
    std::cout << "A";

    ;
    class ImplementationB : public IImplementation

    public:
    virtual void saySomething() override
    std::cout << "B";

    ;

    class Foo
    IImplementation *pimpl;
    public:
    Foo()
    : pimpl(new ImplementationA)


    ~Foo() delete pimpl;

    void saySomething()
    pimpl->saySomething();

    ;






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 13 '18 at 20:06









    Poeta KoduPoeta Kodu

    633311




    633311












    • I will investigate how to materialize it. Also, a point of concern is speed, methods of Compute are called millions of times and can take either milliseconds or minutes, hours.

      – Zythos
      Nov 14 '18 at 14:02


















    • I will investigate how to materialize it. Also, a point of concern is speed, methods of Compute are called millions of times and can take either milliseconds or minutes, hours.

      – Zythos
      Nov 14 '18 at 14:02

















    I will investigate how to materialize it. Also, a point of concern is speed, methods of Compute are called millions of times and can take either milliseconds or minutes, hours.

    – Zythos
    Nov 14 '18 at 14:02






    I will investigate how to materialize it. Also, a point of concern is speed, methods of Compute are called millions of times and can take either milliseconds or minutes, hours.

    – Zythos
    Nov 14 '18 at 14:02














    0














    I may have come across a simple solution. I post it here so you can judge if it is adequate, or even if it can be improved --- sure. I am convinced that runtime polymorphism is not needed, not even polymorphism. The member variable compute is going to be a pointer to a Compute_Prop type anyway. Then, given that performance is critical here: why running the extra overhead of virtual member functions?



    The point here is to reach an implementation that hides the inclusion of Compute_Prop without loosing performance. How? This particular solution uses a templated class and then explicit instantiation. The point is that instantiation can be done in the implementation. Got it from a Fluent C++ blog post. Also, this post has hints for how the implementation should be done. A prototype would be:



    interface.h



    template <typename T>
    class Compute
    public:
    Compute();
    Compute(targ1 arg1, targ2 arg2);
    ~Compute();
    // some methods ...
    private:
    T* compute; // No need to state that is going to be T:=Compute_Prop
    ;


    interface_impl.h



    #include "interface.h" 
    #include "programA.h"

    template <typename T>
    Compute::Compute() = default;

    template <typename T>
    Compute::~Compute()
    delete compute;


    template <typename T>
    Compute::Compute(arg1, arg2)

    // do something ... to get data

    compute = new T( &data, arg2 );



    interface.cpp



     #include "interface.h"
    #include "interface_impl.h"
    #include "programA.h"
    #include "programB.h" // loads Compute_Prop

    int main(int argc, char** argv)

    template class Compute<Compute_Prop>;




    Another related question that might be useful for those with the same dilemma.






    share|improve this answer





























      0














      I may have come across a simple solution. I post it here so you can judge if it is adequate, or even if it can be improved --- sure. I am convinced that runtime polymorphism is not needed, not even polymorphism. The member variable compute is going to be a pointer to a Compute_Prop type anyway. Then, given that performance is critical here: why running the extra overhead of virtual member functions?



      The point here is to reach an implementation that hides the inclusion of Compute_Prop without loosing performance. How? This particular solution uses a templated class and then explicit instantiation. The point is that instantiation can be done in the implementation. Got it from a Fluent C++ blog post. Also, this post has hints for how the implementation should be done. A prototype would be:



      interface.h



      template <typename T>
      class Compute
      public:
      Compute();
      Compute(targ1 arg1, targ2 arg2);
      ~Compute();
      // some methods ...
      private:
      T* compute; // No need to state that is going to be T:=Compute_Prop
      ;


      interface_impl.h



      #include "interface.h" 
      #include "programA.h"

      template <typename T>
      Compute::Compute() = default;

      template <typename T>
      Compute::~Compute()
      delete compute;


      template <typename T>
      Compute::Compute(arg1, arg2)

      // do something ... to get data

      compute = new T( &data, arg2 );



      interface.cpp



       #include "interface.h"
      #include "interface_impl.h"
      #include "programA.h"
      #include "programB.h" // loads Compute_Prop

      int main(int argc, char** argv)

      template class Compute<Compute_Prop>;




      Another related question that might be useful for those with the same dilemma.






      share|improve this answer



























        0












        0








        0







        I may have come across a simple solution. I post it here so you can judge if it is adequate, or even if it can be improved --- sure. I am convinced that runtime polymorphism is not needed, not even polymorphism. The member variable compute is going to be a pointer to a Compute_Prop type anyway. Then, given that performance is critical here: why running the extra overhead of virtual member functions?



        The point here is to reach an implementation that hides the inclusion of Compute_Prop without loosing performance. How? This particular solution uses a templated class and then explicit instantiation. The point is that instantiation can be done in the implementation. Got it from a Fluent C++ blog post. Also, this post has hints for how the implementation should be done. A prototype would be:



        interface.h



        template <typename T>
        class Compute
        public:
        Compute();
        Compute(targ1 arg1, targ2 arg2);
        ~Compute();
        // some methods ...
        private:
        T* compute; // No need to state that is going to be T:=Compute_Prop
        ;


        interface_impl.h



        #include "interface.h" 
        #include "programA.h"

        template <typename T>
        Compute::Compute() = default;

        template <typename T>
        Compute::~Compute()
        delete compute;


        template <typename T>
        Compute::Compute(arg1, arg2)

        // do something ... to get data

        compute = new T( &data, arg2 );



        interface.cpp



         #include "interface.h"
        #include "interface_impl.h"
        #include "programA.h"
        #include "programB.h" // loads Compute_Prop

        int main(int argc, char** argv)

        template class Compute<Compute_Prop>;




        Another related question that might be useful for those with the same dilemma.






        share|improve this answer















        I may have come across a simple solution. I post it here so you can judge if it is adequate, or even if it can be improved --- sure. I am convinced that runtime polymorphism is not needed, not even polymorphism. The member variable compute is going to be a pointer to a Compute_Prop type anyway. Then, given that performance is critical here: why running the extra overhead of virtual member functions?



        The point here is to reach an implementation that hides the inclusion of Compute_Prop without loosing performance. How? This particular solution uses a templated class and then explicit instantiation. The point is that instantiation can be done in the implementation. Got it from a Fluent C++ blog post. Also, this post has hints for how the implementation should be done. A prototype would be:



        interface.h



        template <typename T>
        class Compute
        public:
        Compute();
        Compute(targ1 arg1, targ2 arg2);
        ~Compute();
        // some methods ...
        private:
        T* compute; // No need to state that is going to be T:=Compute_Prop
        ;


        interface_impl.h



        #include "interface.h" 
        #include "programA.h"

        template <typename T>
        Compute::Compute() = default;

        template <typename T>
        Compute::~Compute()
        delete compute;


        template <typename T>
        Compute::Compute(arg1, arg2)

        // do something ... to get data

        compute = new T( &data, arg2 );



        interface.cpp



         #include "interface.h"
        #include "interface_impl.h"
        #include "programA.h"
        #include "programB.h" // loads Compute_Prop

        int main(int argc, char** argv)

        template class Compute<Compute_Prop>;




        Another related question that might be useful for those with the same dilemma.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 18 '18 at 11:06

























        answered Nov 18 '18 at 1:07









        ZythosZythos

        16118




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