document.body.removeEventListener removes ALL click event listeners (not the specified function) why?










1















document.body.removeEventListener("click", delElm);


removes all "onclick" events for the entire page. why? Am I not clearly specifying what function I want removed from the document.body?



document.body.innerHTML += "<div id='dynamicLinkCheckOutput'></div>";
var dynamicLinkCheckOutput = document.getElementById('dynamicLinkCheckOutput');

function delElm(e)
var dynamicLinkCheckOutput = document.getElementById('dynamicLinkCheckOutput');
dynamicLinkCheckOutput.parentNode.removeChild(dynamicLinkCheckOutput);
//document.body.removeEventListener("click", delElm); //moved for clairity

setTimeout(function()
dynamicLinkCheckOutput.onclick = function(e)
e.stopPropagation();
;
document.body.addEventListener("click", delElm);
document.body.removeEventListener("click", delElm); //ALL click events from ALL elements have been removed the moment this line executes.
, 0);









share|improve this question


























    1















    document.body.removeEventListener("click", delElm);


    removes all "onclick" events for the entire page. why? Am I not clearly specifying what function I want removed from the document.body?



    document.body.innerHTML += "<div id='dynamicLinkCheckOutput'></div>";
    var dynamicLinkCheckOutput = document.getElementById('dynamicLinkCheckOutput');

    function delElm(e)
    var dynamicLinkCheckOutput = document.getElementById('dynamicLinkCheckOutput');
    dynamicLinkCheckOutput.parentNode.removeChild(dynamicLinkCheckOutput);
    //document.body.removeEventListener("click", delElm); //moved for clairity

    setTimeout(function()
    dynamicLinkCheckOutput.onclick = function(e)
    e.stopPropagation();
    ;
    document.body.addEventListener("click", delElm);
    document.body.removeEventListener("click", delElm); //ALL click events from ALL elements have been removed the moment this line executes.
    , 0);









    share|improve this question
























      1












      1








      1








      document.body.removeEventListener("click", delElm);


      removes all "onclick" events for the entire page. why? Am I not clearly specifying what function I want removed from the document.body?



      document.body.innerHTML += "<div id='dynamicLinkCheckOutput'></div>";
      var dynamicLinkCheckOutput = document.getElementById('dynamicLinkCheckOutput');

      function delElm(e)
      var dynamicLinkCheckOutput = document.getElementById('dynamicLinkCheckOutput');
      dynamicLinkCheckOutput.parentNode.removeChild(dynamicLinkCheckOutput);
      //document.body.removeEventListener("click", delElm); //moved for clairity

      setTimeout(function()
      dynamicLinkCheckOutput.onclick = function(e)
      e.stopPropagation();
      ;
      document.body.addEventListener("click", delElm);
      document.body.removeEventListener("click", delElm); //ALL click events from ALL elements have been removed the moment this line executes.
      , 0);









      share|improve this question














      document.body.removeEventListener("click", delElm);


      removes all "onclick" events for the entire page. why? Am I not clearly specifying what function I want removed from the document.body?



      document.body.innerHTML += "<div id='dynamicLinkCheckOutput'></div>";
      var dynamicLinkCheckOutput = document.getElementById('dynamicLinkCheckOutput');

      function delElm(e)
      var dynamicLinkCheckOutput = document.getElementById('dynamicLinkCheckOutput');
      dynamicLinkCheckOutput.parentNode.removeChild(dynamicLinkCheckOutput);
      //document.body.removeEventListener("click", delElm); //moved for clairity

      setTimeout(function()
      dynamicLinkCheckOutput.onclick = function(e)
      e.stopPropagation();
      ;
      document.body.addEventListener("click", delElm);
      document.body.removeEventListener("click", delElm); //ALL click events from ALL elements have been removed the moment this line executes.
      , 0);






      javascript dom






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 13 '18 at 19:19









      SamSam

      246




      246






















          1 Answer
          1






          active

          oldest

          votes


















          2















          document.body.removeEventListener("click", delElm);


          removes all "onclick" events for the entire page




          No, it doesn't. But this does:



          document.body.innerHTML += "<div id='dynamicLinkCheckOutput'></div>";


          Using += on innerHTML forces the browser to:



          • Spin through all of the elements inside body building an HTML string for them.

          • Return that string to the JavaScript layer, which then adds on the string on the right-hand side.

          • Parse the string assigned back to innerHTML by the JavaScript layer, wipe out all elements within body (thus losing their event handlers and most other state), and create new, replacement elements for them from the parsed HTML.

          If you want to append to body (or any other element), don't use innerHTML += x, use:




          • insertAdjacentHTML:



            document.body.insertAdjacentHTML("beforeend", "<div id='dynamicLinkCheckOutput'></div>");


            or




          • createElement and appendChild:



            var div = document.createElement("div");
            div.id = "dynamicLinkCheckOutput";
            document.body.appendChild(div);


            or



          • Various other DOM methods. More to explore: DOM on MDN.






          share|improve this answer


















          • 1





            serves me right for cutting corners 🤦. Thanks TJ!

            – Sam
            Nov 13 '18 at 19:38












          • @Sam - A pleasure. Happy coding! :-)

            – T.J. Crowder
            Nov 13 '18 at 19:46










          Your Answer






          StackExchange.ifUsing("editor", function ()
          StackExchange.using("externalEditor", function ()
          StackExchange.using("snippets", function ()
          StackExchange.snippets.init();
          );
          );
          , "code-snippets");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "1"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );













          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53288090%2fdocument-body-removeeventlistener-removes-all-click-event-listeners-not-the-spe%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2















          document.body.removeEventListener("click", delElm);


          removes all "onclick" events for the entire page




          No, it doesn't. But this does:



          document.body.innerHTML += "<div id='dynamicLinkCheckOutput'></div>";


          Using += on innerHTML forces the browser to:



          • Spin through all of the elements inside body building an HTML string for them.

          • Return that string to the JavaScript layer, which then adds on the string on the right-hand side.

          • Parse the string assigned back to innerHTML by the JavaScript layer, wipe out all elements within body (thus losing their event handlers and most other state), and create new, replacement elements for them from the parsed HTML.

          If you want to append to body (or any other element), don't use innerHTML += x, use:




          • insertAdjacentHTML:



            document.body.insertAdjacentHTML("beforeend", "<div id='dynamicLinkCheckOutput'></div>");


            or




          • createElement and appendChild:



            var div = document.createElement("div");
            div.id = "dynamicLinkCheckOutput";
            document.body.appendChild(div);


            or



          • Various other DOM methods. More to explore: DOM on MDN.






          share|improve this answer


















          • 1





            serves me right for cutting corners 🤦. Thanks TJ!

            – Sam
            Nov 13 '18 at 19:38












          • @Sam - A pleasure. Happy coding! :-)

            – T.J. Crowder
            Nov 13 '18 at 19:46















          2















          document.body.removeEventListener("click", delElm);


          removes all "onclick" events for the entire page




          No, it doesn't. But this does:



          document.body.innerHTML += "<div id='dynamicLinkCheckOutput'></div>";


          Using += on innerHTML forces the browser to:



          • Spin through all of the elements inside body building an HTML string for them.

          • Return that string to the JavaScript layer, which then adds on the string on the right-hand side.

          • Parse the string assigned back to innerHTML by the JavaScript layer, wipe out all elements within body (thus losing their event handlers and most other state), and create new, replacement elements for them from the parsed HTML.

          If you want to append to body (or any other element), don't use innerHTML += x, use:




          • insertAdjacentHTML:



            document.body.insertAdjacentHTML("beforeend", "<div id='dynamicLinkCheckOutput'></div>");


            or




          • createElement and appendChild:



            var div = document.createElement("div");
            div.id = "dynamicLinkCheckOutput";
            document.body.appendChild(div);


            or



          • Various other DOM methods. More to explore: DOM on MDN.






          share|improve this answer


















          • 1





            serves me right for cutting corners 🤦. Thanks TJ!

            – Sam
            Nov 13 '18 at 19:38












          • @Sam - A pleasure. Happy coding! :-)

            – T.J. Crowder
            Nov 13 '18 at 19:46













          2












          2








          2








          document.body.removeEventListener("click", delElm);


          removes all "onclick" events for the entire page




          No, it doesn't. But this does:



          document.body.innerHTML += "<div id='dynamicLinkCheckOutput'></div>";


          Using += on innerHTML forces the browser to:



          • Spin through all of the elements inside body building an HTML string for them.

          • Return that string to the JavaScript layer, which then adds on the string on the right-hand side.

          • Parse the string assigned back to innerHTML by the JavaScript layer, wipe out all elements within body (thus losing their event handlers and most other state), and create new, replacement elements for them from the parsed HTML.

          If you want to append to body (or any other element), don't use innerHTML += x, use:




          • insertAdjacentHTML:



            document.body.insertAdjacentHTML("beforeend", "<div id='dynamicLinkCheckOutput'></div>");


            or




          • createElement and appendChild:



            var div = document.createElement("div");
            div.id = "dynamicLinkCheckOutput";
            document.body.appendChild(div);


            or



          • Various other DOM methods. More to explore: DOM on MDN.






          share|improve this answer














          document.body.removeEventListener("click", delElm);


          removes all "onclick" events for the entire page




          No, it doesn't. But this does:



          document.body.innerHTML += "<div id='dynamicLinkCheckOutput'></div>";


          Using += on innerHTML forces the browser to:



          • Spin through all of the elements inside body building an HTML string for them.

          • Return that string to the JavaScript layer, which then adds on the string on the right-hand side.

          • Parse the string assigned back to innerHTML by the JavaScript layer, wipe out all elements within body (thus losing their event handlers and most other state), and create new, replacement elements for them from the parsed HTML.

          If you want to append to body (or any other element), don't use innerHTML += x, use:




          • insertAdjacentHTML:



            document.body.insertAdjacentHTML("beforeend", "<div id='dynamicLinkCheckOutput'></div>");


            or




          • createElement and appendChild:



            var div = document.createElement("div");
            div.id = "dynamicLinkCheckOutput";
            document.body.appendChild(div);


            or



          • Various other DOM methods. More to explore: DOM on MDN.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 19:23









          T.J. CrowderT.J. Crowder

          683k12112121306




          683k12112121306







          • 1





            serves me right for cutting corners 🤦. Thanks TJ!

            – Sam
            Nov 13 '18 at 19:38












          • @Sam - A pleasure. Happy coding! :-)

            – T.J. Crowder
            Nov 13 '18 at 19:46












          • 1





            serves me right for cutting corners 🤦. Thanks TJ!

            – Sam
            Nov 13 '18 at 19:38












          • @Sam - A pleasure. Happy coding! :-)

            – T.J. Crowder
            Nov 13 '18 at 19:46







          1




          1





          serves me right for cutting corners 🤦. Thanks TJ!

          – Sam
          Nov 13 '18 at 19:38






          serves me right for cutting corners 🤦. Thanks TJ!

          – Sam
          Nov 13 '18 at 19:38














          @Sam - A pleasure. Happy coding! :-)

          – T.J. Crowder
          Nov 13 '18 at 19:46





          @Sam - A pleasure. Happy coding! :-)

          – T.J. Crowder
          Nov 13 '18 at 19:46

















          draft saved

          draft discarded
















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53288090%2fdocument-body-removeeventlistener-removes-all-click-event-listeners-not-the-spe%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          這個網誌中的熱門文章

          How to read a connectionString WITH PROVIDER in .NET Core?

          Node.js Script on GitHub Pages or Amazon S3

          Museum of Modern and Contemporary Art of Trento and Rovereto