Iterating through list and comparing dicts inside of list
0
I have a list like this:
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson',
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
I want to iterate trough this list so that it compares these dicts to each other. Then I want to make own lists of the dicts that has the same date. How can I do this?
The outcome should be this:
List n
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson')]
List n+1
[(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson',
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
python list dictionary
edited Nov 13 '18 at 2:05
Cœur
17.5k9104145
asked May 13 '14 at 8:16
user3496563user3496563
681311
add a comment |
0
I have a list like this:
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson',
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
I want to iterate trough this list so that it compares these dicts to each other. Then I want to make own lists of the dicts that has the same date. How can I do this?
The outcome should be this:
List n
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson')]
List n+1
[(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson',
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
python list dictionary
edited Nov 13 '18 at 2:05
Cœur
17.5k9104145
asked May 13 '14 at 8:16
user3496563user3496563
681311
add a comment |
0
0
0
I have a list like this:
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson',
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
I want to iterate trough this list so that it compares these dicts to each other. Then I want to make own lists of the dicts that has the same date. How can I do this?
The outcome should be this:
List n
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson')]
List n+1
[(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson',
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
python list dictionary
edited Nov 13 '18 at 2:05
Cœur
17.5k9104145
asked May 13 '14 at 8:16
user3496563user3496563
681311
I have a list like this:
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson',
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
I want to iterate trough this list so that it compares these dicts to each other. Then I want to make own lists of the dicts that has the same date. How can I do this?
The outcome should be this:
List n
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson')]
List n+1
[(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson',
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
python list dictionary
python list dictionary
edited Nov 13 '18 at 2:05
Cœur
17.5k9104145
asked May 13 '14 at 8:16
user3496563user3496563
681311
edited Nov 13 '18 at 2:05
Cœur
17.5k9104145
asked May 13 '14 at 8:16
user3496563user3496563
681311
edited Nov 13 '18 at 2:05
Cœur
17.5k9104145
edited Nov 13 '18 at 2:05
Cœur
17.5k9104145
edited Nov 13 '18 at 2:05
Cœur
17.5k9104145
17.5k9104145
asked May 13 '14 at 8:16
user3496563user3496563
681311
asked May 13 '14 at 8:16
user3496563user3496563
681311
asked May 13 '14 at 8:16
user3496563user3496563
681311
681311
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
Given a is your list, this solution will work:
from itertools import groupby
for k, g in groupby(sorted(a, key=lambda x: x[0]), key=lambda x: x[0]):
print(list(g))
and produce this output
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson')]
[(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
answered May 13 '14 at 8:27
vaultahvaultah
27.1k974101
Thanks, this worked!
– user3496563
May 13 '14 at 9:38
add a comment |
1
There's a facility for this task called groupby. But it uses iterators and depends on the fact that items to be grouped together are already in order, so you might need to sort the input before applying it, depending on is "sortedness" of course.
from itertools import groupby
v = [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ]
v.sort() # to ensure that all equal datetimes are together in the list
result = [ list(i) for x, i in itertools.groupby(v, lambda a: a[0]) ]
result will then be this:
[ [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson') ],
[ (datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ] ]
Which is what you wanted.
answered May 13 '14 at 8:36
AlfeAlfe
31.6k1062102
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Given a is your list, this solution will work:
from itertools import groupby
for k, g in groupby(sorted(a, key=lambda x: x[0]), key=lambda x: x[0]):
print(list(g))
and produce this output
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson')]
[(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
answered May 13 '14 at 8:27
vaultahvaultah
27.1k974101
Thanks, this worked!
– user3496563
May 13 '14 at 9:38
add a comment |
1
Given a is your list, this solution will work:
from itertools import groupby
for k, g in groupby(sorted(a, key=lambda x: x[0]), key=lambda x: x[0]):
print(list(g))
and produce this output
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson')]
[(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
answered May 13 '14 at 8:27
vaultahvaultah
27.1k974101
Thanks, this worked!
– user3496563
May 13 '14 at 9:38
add a comment |
1
1
1
Given a is your list, this solution will work:
from itertools import groupby
for k, g in groupby(sorted(a, key=lambda x: x[0]), key=lambda x: x[0]):
print(list(g))
and produce this output
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson')]
[(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
answered May 13 '14 at 8:27
vaultahvaultah
27.1k974101
Given a is your list, this solution will work:
from itertools import groupby
for k, g in groupby(sorted(a, key=lambda x: x[0]), key=lambda x: x[0]):
print(list(g))
and produce this output
[(datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson')]
[(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson')]
answered May 13 '14 at 8:27
vaultahvaultah
27.1k974101
edited May 13 '14 at 8:34
answered May 13 '14 at 8:27
vaultahvaultah
27.1k974101
answered May 13 '14 at 8:27
vaultahvaultah
27.1k974101
answered May 13 '14 at 8:27
vaultahvaultah
27.1k974101
27.1k974101
Thanks, this worked!
– user3496563
May 13 '14 at 9:38
add a comment |
Thanks, this worked!
– user3496563
May 13 '14 at 9:38
Thanks, this worked!
– user3496563
May 13 '14 at 9:38
Thanks, this worked!
– user3496563
May 13 '14 at 9:38
add a comment |
1
There's a facility for this task called groupby. But it uses iterators and depends on the fact that items to be grouped together are already in order, so you might need to sort the input before applying it, depending on is "sortedness" of course.
from itertools import groupby
v = [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ]
v.sort() # to ensure that all equal datetimes are together in the list
result = [ list(i) for x, i in itertools.groupby(v, lambda a: a[0]) ]
result will then be this:
[ [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson') ],
[ (datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ] ]
Which is what you wanted.
answered May 13 '14 at 8:36
AlfeAlfe
31.6k1062102
add a comment |
1
There's a facility for this task called groupby. But it uses iterators and depends on the fact that items to be grouped together are already in order, so you might need to sort the input before applying it, depending on is "sortedness" of course.
from itertools import groupby
v = [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ]
v.sort() # to ensure that all equal datetimes are together in the list
result = [ list(i) for x, i in itertools.groupby(v, lambda a: a[0]) ]
result will then be this:
[ [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson') ],
[ (datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ] ]
Which is what you wanted.
answered May 13 '14 at 8:36
AlfeAlfe
31.6k1062102
add a comment |
1
1
1
There's a facility for this task called groupby. But it uses iterators and depends on the fact that items to be grouped together are already in order, so you might need to sort the input before applying it, depending on is "sortedness" of course.
from itertools import groupby
v = [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ]
v.sort() # to ensure that all equal datetimes are together in the list
result = [ list(i) for x, i in itertools.groupby(v, lambda a: a[0]) ]
result will then be this:
[ [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson') ],
[ (datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ] ]
Which is what you wanted.
answered May 13 '14 at 8:36
AlfeAlfe
31.6k1062102
There's a facility for this task called groupby. But it uses iterators and depends on the fact that items to be grouped together are already in order, so you might need to sort the input before applying it, depending on is "sortedness" of course.
from itertools import groupby
v = [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ]
v.sort() # to ensure that all equal datetimes are together in the list
result = [ list(i) for x, i in itertools.groupby(v, lambda a: a[0]) ]
result will then be this:
[ [ (datetime.date(2014, 4, 15), 'first_name': 'Mike', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 15), 'first_name': 'Hannah', 'last_name': 'Jackson') ],
[ (datetime.date(2014, 4, 16), 'first_name': 'Tom', 'last_name': 'Jackson'),
(datetime.date(2014, 4, 16), 'first_name': 'Macy', 'last_name': 'Jackson') ] ]
Which is what you wanted.
answered May 13 '14 at 8:36
AlfeAlfe
31.6k1062102
answered May 13 '14 at 8:36
AlfeAlfe
31.6k1062102
answered May 13 '14 at 8:36
AlfeAlfe
31.6k1062102
answered May 13 '14 at 8:36
AlfeAlfe
31.6k1062102
31.6k1062102
add a comment |
add a comment |
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