How to pass vairable to get() in dicitonary in python?

-2

I am simply trying to solve the following question

You are given a date. Your task is to find what the day is on that date.
Sample imput : 08 10 2018

I came up with following solution:

days='0':'monday','1':'tuesday','2':'wed','3':'thurs','4':'friday','5':'sat','6':'sun'

user_input=datetime.datetime(2018, 11 ,6)

result=user_input.weekday()
print (days.get('result'))

Now it prints 'None' ,I was expecting this to return keys value.

Even print(result) returns value of 1 and type(result) returns int.

I want to know why I am not getting the expected output.
There must be a more pythonic way to do this but my major concern is the way get() is behaving.

asked Nov 13 '18 at 14:16

Rusty

1056

4

I think you mean days.get(result) not days.get('result'). The string 'result' is not in your dictionary. Though maybe the keys in your dictionary should be ints, not strings.

– khelwood
Nov 13 '18 at 14:18

try print (days.get(result)) without the quotes.

– Ev. Kounis
Nov 13 '18 at 14:18

days.get(result).

– Austin
Nov 13 '18 at 14:19

Either print(days[str(result)]) or change the dictionary keys to integers and then print(days[result])

– myrmica
Nov 13 '18 at 14:23

add a comment |

-2

I am simply trying to solve the following question

You are given a date. Your task is to find what the day is on that date.
Sample imput : 08 10 2018

I came up with following solution:

days='0':'monday','1':'tuesday','2':'wed','3':'thurs','4':'friday','5':'sat','6':'sun'

user_input=datetime.datetime(2018, 11 ,6)

result=user_input.weekday()
print (days.get('result'))

Now it prints 'None' ,I was expecting this to return keys value.

Even print(result) returns value of 1 and type(result) returns int.

I want to know why I am not getting the expected output.
There must be a more pythonic way to do this but my major concern is the way get() is behaving.

asked Nov 13 '18 at 14:16

Rusty

1056

4

I think you mean days.get(result) not days.get('result'). The string 'result' is not in your dictionary. Though maybe the keys in your dictionary should be ints, not strings.

– khelwood
Nov 13 '18 at 14:18

try print (days.get(result)) without the quotes.

– Ev. Kounis
Nov 13 '18 at 14:18

days.get(result).

– Austin
Nov 13 '18 at 14:19

Either print(days[str(result)]) or change the dictionary keys to integers and then print(days[result])

– myrmica
Nov 13 '18 at 14:23

add a comment |

-2

I am simply trying to solve the following question

You are given a date. Your task is to find what the day is on that date.
Sample imput : 08 10 2018

I came up with following solution:

days='0':'monday','1':'tuesday','2':'wed','3':'thurs','4':'friday','5':'sat','6':'sun'

user_input=datetime.datetime(2018, 11 ,6)

result=user_input.weekday()
print (days.get('result'))

Now it prints 'None' ,I was expecting this to return keys value.

Even print(result) returns value of 1 and type(result) returns int.

I want to know why I am not getting the expected output.
There must be a more pythonic way to do this but my major concern is the way get() is behaving.

asked Nov 13 '18 at 14:16

Rusty

1056

I am simply trying to solve the following question

You are given a date. Your task is to find what the day is on that date.
Sample imput : 08 10 2018

I came up with following solution:

days='0':'monday','1':'tuesday','2':'wed','3':'thurs','4':'friday','5':'sat','6':'sun'

user_input=datetime.datetime(2018, 11 ,6)

result=user_input.weekday()
print (days.get('result'))

Now it prints 'None' ,I was expecting this to return keys value.

Even print(result) returns value of 1 and type(result) returns int.

I want to know why I am not getting the expected output.
There must be a more pythonic way to do this but my major concern is the way get() is behaving.

python dictionary scripting

asked Nov 13 '18 at 14:16

Rusty

1056

asked Nov 13 '18 at 14:16

Rusty

1056

asked Nov 13 '18 at 14:16

Rusty

1056

asked Nov 13 '18 at 14:16

Rusty

1056

asked Nov 13 '18 at 14:16

Rusty

1056

4

I think you mean days.get(result) not days.get('result'). The string 'result' is not in your dictionary. Though maybe the keys in your dictionary should be ints, not strings.

– khelwood
Nov 13 '18 at 14:18

try print (days.get(result)) without the quotes.

– Ev. Kounis
Nov 13 '18 at 14:18

days.get(result).

– Austin
Nov 13 '18 at 14:19

Either print(days[str(result)]) or change the dictionary keys to integers and then print(days[result])

– myrmica
Nov 13 '18 at 14:23

add a comment |

4

I think you mean days.get(result) not days.get('result'). The string 'result' is not in your dictionary. Though maybe the keys in your dictionary should be ints, not strings.

– khelwood
Nov 13 '18 at 14:18

try print (days.get(result)) without the quotes.

– Ev. Kounis
Nov 13 '18 at 14:18

days.get(result).

– Austin
Nov 13 '18 at 14:19

Either print(days[str(result)]) or change the dictionary keys to integers and then print(days[result])

– myrmica
Nov 13 '18 at 14:23

I think you mean days.get(result) not days.get('result'). The string 'result' is not in your dictionary. Though maybe the keys in your dictionary should be ints, not strings.

– khelwood
Nov 13 '18 at 14:18

try print (days.get(result)) without the quotes.

– Ev. Kounis
Nov 13 '18 at 14:18

days.get(result).

– Austin
Nov 13 '18 at 14:19

Either print(days[str(result)]) or change the dictionary keys to integers and then print(days[result])

– myrmica
Nov 13 '18 at 14:23

add a comment |

1 Answer
1

active

oldest

votes

Firstly, days.get('result') is trying to look up the string 'result' in your dictionary, not the variable result.

Secondly user_input.weekday() returns an int, but the keys in your dictionary are strings, not ints.

This would have worked:

days = 0:'monday', 1:'tuesday', 2:'wed', 3:'thurs', 4:'friday', 5:'sat', 6:'sun'
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days.get(result)) # or simply print(days[result])

However, since the possible range of days is the numbers 0 to 6, a list would work just as well.

days = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days[result])

answered Nov 13 '18 at 14:25

khelwood

30.8k74263

I was not aware that I am looking for result as key itself. I was given this question in sys admin Interview scripting part and Idk why dictionary came in mind ,I should have used list. Thanks for the help mate.

– Rusty
Nov 13 '18 at 14:50

add a comment |

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1 Answer
1

active

oldest

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1 Answer
1

active

oldest

votes

Firstly, days.get('result') is trying to look up the string 'result' in your dictionary, not the variable result.

Secondly user_input.weekday() returns an int, but the keys in your dictionary are strings, not ints.

This would have worked:

days = 0:'monday', 1:'tuesday', 2:'wed', 3:'thurs', 4:'friday', 5:'sat', 6:'sun'
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days.get(result)) # or simply print(days[result])

However, since the possible range of days is the numbers 0 to 6, a list would work just as well.

days = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days[result])

answered Nov 13 '18 at 14:25

khelwood

30.8k74263

I was not aware that I am looking for result as key itself. I was given this question in sys admin Interview scripting part and Idk why dictionary came in mind ,I should have used list. Thanks for the help mate.

– Rusty
Nov 13 '18 at 14:50

add a comment |

Firstly, days.get('result') is trying to look up the string 'result' in your dictionary, not the variable result.

Secondly user_input.weekday() returns an int, but the keys in your dictionary are strings, not ints.

This would have worked:

days = 0:'monday', 1:'tuesday', 2:'wed', 3:'thurs', 4:'friday', 5:'sat', 6:'sun'
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days.get(result)) # or simply print(days[result])

However, since the possible range of days is the numbers 0 to 6, a list would work just as well.

days = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days[result])

answered Nov 13 '18 at 14:25

khelwood

30.8k74263

I was not aware that I am looking for result as key itself. I was given this question in sys admin Interview scripting part and Idk why dictionary came in mind ,I should have used list. Thanks for the help mate.

– Rusty
Nov 13 '18 at 14:50

add a comment |

Firstly, days.get('result') is trying to look up the string 'result' in your dictionary, not the variable result.

Secondly user_input.weekday() returns an int, but the keys in your dictionary are strings, not ints.

This would have worked:

days = 0:'monday', 1:'tuesday', 2:'wed', 3:'thurs', 4:'friday', 5:'sat', 6:'sun'
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days.get(result)) # or simply print(days[result])

However, since the possible range of days is the numbers 0 to 6, a list would work just as well.

days = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days[result])

answered Nov 13 '18 at 14:25

khelwood

30.8k74263

Firstly, days.get('result') is trying to look up the string 'result' in your dictionary, not the variable result.

Secondly user_input.weekday() returns an int, but the keys in your dictionary are strings, not ints.

This would have worked:

days = 0:'monday', 1:'tuesday', 2:'wed', 3:'thurs', 4:'friday', 5:'sat', 6:'sun'
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days.get(result)) # or simply print(days[result])

However, since the possible range of days is the numbers 0 to 6, a list would work just as well.

days = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']
user_input = datetime.datetime(2018, 11, 6)
result = user_input.weekday()
print(days[result])

answered Nov 13 '18 at 14:25

khelwood

30.8k74263

answered Nov 13 '18 at 14:25

khelwood

30.8k74263

answered Nov 13 '18 at 14:25

khelwood

30.8k74263

answered Nov 13 '18 at 14:25

khelwood

30.8k74263

I was not aware that I am looking for result as key itself. I was given this question in sys admin Interview scripting part and Idk why dictionary came in mind ,I should have used list. Thanks for the help mate.

– Rusty
Nov 13 '18 at 14:50

add a comment |

I was not aware that I am looking for result as key itself. I was given this question in sys admin Interview scripting part and Idk why dictionary came in mind ,I should have used list. Thanks for the help mate.

– Rusty
Nov 13 '18 at 14:50

I was not aware that I am looking for result as key itself. I was given this question in sys admin Interview scripting part and Idk why dictionary came in mind ,I should have used list. Thanks for the help mate.

– Rusty
Nov 13 '18 at 14:50

add a comment |

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