Odtnhj

I wrote a function (asterisksDisplay) that displays a solid rectangle of asterisks whose sides are specified in the integer parameters as row and column, which are taken from the user. The program below works perfectly.

#include <stdio.h>

void asterisksDisplay (int row, int column);

int main (void)

 int a=0;
 int b=0;
 printf("Please enter sides of your shape: ");
 scanf("%d%d", &a, &b);
 printf("nYour shape is: n");
 asterisksDisplay(a, b);


void asterisksDisplay (int row, int column)

 for (int i = 1; i <= row; i++) 
 for (int p = 1; p <= column; p++) 
 printf("*");
 
 printf("n");
 
 

When I try to modify this function of asterisks to a function of a user given character display, somehow compiler skips displaying the character.

#include <stdio.h>

void asterisksDisplay (int row, int column, char character);
int main (void)

 int a=0;
 int b=0;
 char c;
 printf("Please enter sides of your shape: ");
 scanf("%d%d", &a, &b);
 printf("nplease enter the character to be filled: ");
 scanf("%s", &c);
 printf("n");
 asterisksDisplay(a, b, c);


void asterisksDisplay (int row, int column, char character)

 for (int i = 1; i <= row; i++) 
 for (int p = 1; p <= column; p++) 
 printf("%c", character);
 
 printf("n");
 

what is the solution for fixing this?

Change

 scanf("%s", &c);

to

 scanf(" %c", &c);
 ^^-----------------------(i)
 ^^------------------------- (ii)

• Change of the conversion specifier from %s to %c, as (i): because c is a char type.




• We need to escape the previously entered newline, so the extra whitespace before the conversion specifier, which matches and discards any leading whitespace input present in the buffer.