Regex pattern including all special characters
I want to write a simple regular expression to check if in given string exist any special character. My regex works but I don't know why it also includes all numbers, so when I put some number it returns an error.
My code:
//pattern to find if there is any special character in string
Pattern regex = Pattern.compile("[$&+,:;=?@#|'<>.-^*()%!]");
//matcher to find if there is any special character in string
Matcher matcher = regex.matcher(searchQuery.getSearchFor());
if(matcher.find())
errors.rejectValue("searchFor", "wrong_pattern.SearchQuery.searchForSpecialCharacters","Special characters are not allowed!");
java regex
edited Nov 12 at 11:19
Suraj Rao
22.6k75469
asked Aug 5 '13 at 12:18
Piotr Sagalara
78511122
add a comment |
I want to write a simple regular expression to check if in given string exist any special character. My regex works but I don't know why it also includes all numbers, so when I put some number it returns an error.
My code:
//pattern to find if there is any special character in string
Pattern regex = Pattern.compile("[$&+,:;=?@#|'<>.-^*()%!]");
//matcher to find if there is any special character in string
Matcher matcher = regex.matcher(searchQuery.getSearchFor());
if(matcher.find())
errors.rejectValue("searchFor", "wrong_pattern.SearchQuery.searchForSpecialCharacters","Special characters are not allowed!");
java regex
edited Nov 12 at 11:19
Suraj Rao
22.6k75469
asked Aug 5 '13 at 12:18
Piotr Sagalara
78511122
4
the dash inshould be escaped, it has special meaning there.
– MightyPork
Aug 5 '13 at 12:21
7
¿¡ So you think that the only special characters that exist are the ones on your keyboard !? :-)
– xanatos
Aug 5 '13 at 12:22
2
Exactly. It would be better to define all "non-special" charactes and make that negative.
– NeplatnyUdaj
Aug 5 '13 at 12:22
yes maybe it would be wiser to assert the use of only those characters you want to allow.
– d'alar'cop
Aug 5 '13 at 12:23
14
Just like children, all characters are special, each in its own way. :)
– tchrist
Aug 5 '13 at 13:15
add a comment |
I want to write a simple regular expression to check if in given string exist any special character. My regex works but I don't know why it also includes all numbers, so when I put some number it returns an error.
My code:
//pattern to find if there is any special character in string
Pattern regex = Pattern.compile("[$&+,:;=?@#|'<>.-^*()%!]");
//matcher to find if there is any special character in string
Matcher matcher = regex.matcher(searchQuery.getSearchFor());
if(matcher.find())
errors.rejectValue("searchFor", "wrong_pattern.SearchQuery.searchForSpecialCharacters","Special characters are not allowed!");
java regex
edited Nov 12 at 11:19
Suraj Rao
22.6k75469
asked Aug 5 '13 at 12:18
Piotr Sagalara
78511122
I want to write a simple regular expression to check if in given string exist any special character. My regex works but I don't know why it also includes all numbers, so when I put some number it returns an error.
My code:
//pattern to find if there is any special character in string
Pattern regex = Pattern.compile("[$&+,:;=?@#|'<>.-^*()%!]");
//matcher to find if there is any special character in string
Matcher matcher = regex.matcher(searchQuery.getSearchFor());
if(matcher.find())
errors.rejectValue("searchFor", "wrong_pattern.SearchQuery.searchForSpecialCharacters","Special characters are not allowed!");
java regex
java regex
edited Nov 12 at 11:19
Suraj Rao
22.6k75469
asked Aug 5 '13 at 12:18
Piotr Sagalara
78511122
edited Nov 12 at 11:19
Suraj Rao
22.6k75469
asked Aug 5 '13 at 12:18
Piotr Sagalara
78511122
edited Nov 12 at 11:19
Suraj Rao
22.6k75469
edited Nov 12 at 11:19
Suraj Rao
22.6k75469
edited Nov 12 at 11:19
Suraj Rao
22.6k75469
22.6k75469
asked Aug 5 '13 at 12:18
Piotr Sagalara
78511122
asked Aug 5 '13 at 12:18
Piotr Sagalara
78511122
asked Aug 5 '13 at 12:18
Piotr Sagalara
78511122
78511122
4
the dash inshould be escaped, it has special meaning there.
– MightyPork
Aug 5 '13 at 12:21
7
¿¡ So you think that the only special characters that exist are the ones on your keyboard !? :-)
– xanatos
Aug 5 '13 at 12:22
2
Exactly. It would be better to define all "non-special" charactes and make that negative.
– NeplatnyUdaj
Aug 5 '13 at 12:22
yes maybe it would be wiser to assert the use of only those characters you want to allow.
– d'alar'cop
Aug 5 '13 at 12:23
14
Just like children, all characters are special, each in its own way. :)
– tchrist
Aug 5 '13 at 13:15
add a comment |
4
the dash inshould be escaped, it has special meaning there.
– MightyPork
Aug 5 '13 at 12:21
7
¿¡ So you think that the only special characters that exist are the ones on your keyboard !? :-)
– xanatos
Aug 5 '13 at 12:22
2
Exactly. It would be better to define all "non-special" charactes and make that negative.
– NeplatnyUdaj
Aug 5 '13 at 12:22
yes maybe it would be wiser to assert the use of only those characters you want to allow.
– d'alar'cop
Aug 5 '13 at 12:23
14
Just like children, all characters are special, each in its own way. :)
– tchrist
Aug 5 '13 at 13:15
4
4
the dash in
– MightyPork
Aug 5 '13 at 12:21
the dash in
– MightyPork
Aug 5 '13 at 12:21
7
7
¿¡ So you think that the only special characters that exist are the ones on your keyboard !? :-)
– xanatos
Aug 5 '13 at 12:22
¿¡ So you think that the only special characters that exist are the ones on your keyboard !? :-)
– xanatos
Aug 5 '13 at 12:22
2
2
Exactly. It would be better to define all "non-special" charactes and make that negative.
– NeplatnyUdaj
Aug 5 '13 at 12:22
Exactly. It would be better to define all "non-special" charactes and make that negative.
– NeplatnyUdaj
Aug 5 '13 at 12:22
yes maybe it would be wiser to assert the use of only those characters you want to allow.
– d'alar'cop
Aug 5 '13 at 12:23
yes maybe it would be wiser to assert the use of only those characters you want to allow.
– d'alar'cop
Aug 5 '13 at 12:23
14
14
Just like children, all characters are special, each in its own way. :)
– tchrist
Aug 5 '13 at 13:15
Just like children, all characters are special, each in its own way. :)
– tchrist
Aug 5 '13 at 13:15
add a comment |
13 Answers
13
active
oldest
votes
Please don't do that... little Unicode BABY ANGELs like this one 👼 are dying! ◕◡◕ (← these are not images) (nor is the arrow!)
☺
And you are killing 20 years of DOS :-) (the last smiley is called WHITE SMILING FACE... Now it's at 263A... But in ancient times it was ALT-1)and his friend
☻
BLACK SMILING FACE... Now it's at 263B... But in ancient times it was ALT-2Try a negative match:
Pattern regex = Pattern.compile("[^A-Za-z0-9]");
(this will ok only A-Z "standard" letters and "standard" digits.
answered Aug 5 '13 at 12:23
xanatos
88.6k7139196
3
Will this work for non-english characters? such as à 蔿
– Abdullah Shoaib
Dec 9 '13 at 12:44
2
@AbdullahShoaib Clearly not :) You'll need to do a full list of what you consider "special" and/or what you consider "good".
– xanatos
Mar 9 '15 at 9:58
I notice many people use[A-Za-z0-9]to represent any letter or digit, both lowercase and upper, but is it not better to just do[0-z]?
– Abraham Murciano Benzadon
Jun 25 '17 at 16:09
3
@AbrahamMurcianoBenzadon: The decimal digits, the upper case roman letters, and the lower case roman letters occupy three disjoint ranges of character code space.
– Solomon Slow
Jun 25 '17 at 17:31
1
@AbrahamMurcianoBenzadon You can see what James wrote in the handy screenshot of Character Map posted by Sina in another response: your regex would accept :;<=>?@^_` (other than 0-9, a-z, A-Z)
– xanatos
Jun 26 '17 at 6:15
|
show 3 more comments
You have a dash in the middle of the character class, which will mean a character range. Put the dash at the end of the class like so:
[$&+,:;=?@#|'<>.^*()%!-]
answered Aug 5 '13 at 12:22
Jerry
57.7k1067101
add a comment |
That's because your pattern contains a .-^ which is all characters between and including . and ^, which included digits and several other characters as shown below:
If by special characters, you mean punctuation and symbols use:
[pPpS]
which contains all unicode punctuation and symbols.
answered Aug 5 '13 at 12:31
Sina Iravanian
12.8k32241
add a comment |
SInce you don't have white-space and underscore in your character class I think following regex will be better for you:
Pattern regex = Pattern.compile("[^ws]");
Which means match everything other than [A-Za-z0-9s_]
Unicode version:
Pattern regex = Pattern.compile("[^pLds_]");
answered Aug 5 '13 at 12:27
anubhava
519k46315389
add a comment |
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class detectspecial
public int getSpecialCharacterCount(String s)
answered Jun 26 '14 at 8:23
Ashish Sharma
21224
this code always return 0
– En NuNYet de Can CalÇadA
May 7 '17 at 16:36
add a comment |
Try:
(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$
(?i)^(A)$: indicates that the regular expression A is case insensitive.
[a-z]: represents any alphabetic character from a to z.
[^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]: represents any alphabetic character except a to z, digits, and special characters i.e. accented characters.
[[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]: represents any alphabetic(accented or unaccented) character only characters.
*: one or more occurrence of the regex that precedes it.
edited Feb 17 '16 at 18:42
Alan Moore
60.5k978132
answered Feb 17 '16 at 11:26
cdaiga
3,75611222
This would be a better answer if it included an explanation along with the code.
– John Hascall
Feb 17 '16 at 17:04
@JohnHascall, I just added an explanation.
– cdaiga
Feb 17 '16 at 17:31
Inside a character class, none of those characters need to be escaped except` and-`. Many of them never need to be escaped at all. "Better safe than sorry" is a fine philosophy, but readability is important, too.
– Alan Moore
Feb 17 '16 at 18:46
add a comment |
If you only rely on ASCII characters, you can rely on using the hex ranges on the ASCII table. Here is a regex that will grab all special characters in the range of 33-47, 58-64, 91-96, 123-126
[x21-x2Fx3A-x40x5B-x60x7B-x7E]
However you can think of special characters as not normal characters. If we take that approach, you can simply do this
^[A-Za-z0-9s]+
Hower this will not catch _ ^ and probably others.
answered Feb 3 '16 at 22:06
Serguei Fedorov
4,17394379
I finally used(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$to match any character.
– cdaiga
Feb 17 '16 at 11:25
Whatever works best for you!
– Serguei Fedorov
Feb 17 '16 at 18:37
1
Never use[A-z]in a regex. It matches all uppercase and lowercase ASCII letters as you would expect. but it also matches several punctuation characters whose code points lie betweenZanda. Use[A-Za-z]instead, or[a-z]in case-insensitive mode.
– Alan Moore
Feb 17 '16 at 18:37
@AlanMoore, good to know! I'll make the change to the answer.
– Serguei Fedorov
Feb 17 '16 at 18:39
how about '.' dot character . It supporsed to match any character except new line. In python re.DOTALL matches all including newline. Check out the regular expression faq in the python tutorial docs.python.org/2/howto/regex.html
– Dr Deo
Sep 6 at 15:01
add a comment |
Use this regular expression pattern ("^[a-zA-Z0-9]*$") .It validates alphanumeric string excluding the special characters
answered Jul 4 '16 at 6:41
sam
438
add a comment |
Here is my regex variant of a special character:
String regExp = "^[^<>"/|;:.,~!?@#$%^=&*\]\\()\[¿§«»ω⊙¤°℃℉€¥£¢¡®©0-9_+]*$";
(Java code)
answered Mar 20 '17 at 14:52
Chuck
548711
2
you missed •☺○♣♥☻☺ and more..
– Aks4125
Dec 30 '17 at 4:58
add a comment |
Try using this for the same things - StringUtils.isAlphanumeric(value)
edited Dec 7 '16 at 23:54
Buddy
8,56952951
answered Dec 7 '16 at 23:52
Ash
28839
space/blank is also a special char if you use this method. Better to replace the space and tabs chars before calling this method.
– Deepu Sahni
Mar 21 at 1:14
add a comment |
Here is my regular expression, that I used for removing all the special characters from any string :
String regex = ("[ \\s@ [\"]\\[\\]\\\-9|^#%'*/<()>:`;,!& .?_$+-]+")
edited Nov 12 at 12:05
Jan Černý
8121622
answered Nov 12 at 10:56
Suchismita Barik
112
add a comment |
(^W$)
^ - start of the string,
W - match any non-word character [^a-zA-Z0-9_],
$ - end of the string
answered Aug 26 '16 at 9:18
Sareesh Krishnan
20626
add a comment |
We can achieve this using Pattern and Matcher as follows:
Pattern pattern = Pattern.compile("[^A-Za-z0-9 ]");
Matcher matcher = pattern.matcher(trString);
boolean hasSpecialChars = matcher.find();
answered Sep 20 at 12:18
KayV
3,65122054
add a comment |
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13 Answers
13
active
oldest
votes
13 Answers
13
active
oldest
votes
active
oldest
votes
active
oldest
votes
Please don't do that... little Unicode BABY ANGELs like this one 👼 are dying! ◕◡◕ (← these are not images) (nor is the arrow!)
☺
And you are killing 20 years of DOS :-) (the last smiley is called WHITE SMILING FACE... Now it's at 263A... But in ancient times it was ALT-1)and his friend
☻
BLACK SMILING FACE... Now it's at 263B... But in ancient times it was ALT-2Try a negative match:
Pattern regex = Pattern.compile("[^A-Za-z0-9]");
(this will ok only A-Z "standard" letters and "standard" digits.
answered Aug 5 '13 at 12:23
xanatos
88.6k7139196
3
Will this work for non-english characters? such as à 蔿
– Abdullah Shoaib
Dec 9 '13 at 12:44
2
@AbdullahShoaib Clearly not :) You'll need to do a full list of what you consider "special" and/or what you consider "good".
– xanatos
Mar 9 '15 at 9:58
I notice many people use[A-Za-z0-9]to represent any letter or digit, both lowercase and upper, but is it not better to just do[0-z]?
– Abraham Murciano Benzadon
Jun 25 '17 at 16:09
3
@AbrahamMurcianoBenzadon: The decimal digits, the upper case roman letters, and the lower case roman letters occupy three disjoint ranges of character code space.
– Solomon Slow
Jun 25 '17 at 17:31
1
@AbrahamMurcianoBenzadon You can see what James wrote in the handy screenshot of Character Map posted by Sina in another response: your regex would accept :;<=>?@^_` (other than 0-9, a-z, A-Z)
– xanatos
Jun 26 '17 at 6:15
|
show 3 more comments
Please don't do that... little Unicode BABY ANGELs like this one 👼 are dying! ◕◡◕ (← these are not images) (nor is the arrow!)
☺
And you are killing 20 years of DOS :-) (the last smiley is called WHITE SMILING FACE... Now it's at 263A... But in ancient times it was ALT-1)and his friend
☻
BLACK SMILING FACE... Now it's at 263B... But in ancient times it was ALT-2Try a negative match:
Pattern regex = Pattern.compile("[^A-Za-z0-9]");
(this will ok only A-Z "standard" letters and "standard" digits.
answered Aug 5 '13 at 12:23
xanatos
88.6k7139196
3
Will this work for non-english characters? such as à 蔿
– Abdullah Shoaib
Dec 9 '13 at 12:44
2
@AbdullahShoaib Clearly not :) You'll need to do a full list of what you consider "special" and/or what you consider "good".
– xanatos
Mar 9 '15 at 9:58
I notice many people use[A-Za-z0-9]to represent any letter or digit, both lowercase and upper, but is it not better to just do[0-z]?
– Abraham Murciano Benzadon
Jun 25 '17 at 16:09
3
@AbrahamMurcianoBenzadon: The decimal digits, the upper case roman letters, and the lower case roman letters occupy three disjoint ranges of character code space.
– Solomon Slow
Jun 25 '17 at 17:31
1
@AbrahamMurcianoBenzadon You can see what James wrote in the handy screenshot of Character Map posted by Sina in another response: your regex would accept :;<=>?@^_` (other than 0-9, a-z, A-Z)
– xanatos
Jun 26 '17 at 6:15
|
show 3 more comments
Please don't do that... little Unicode BABY ANGELs like this one 👼 are dying! ◕◡◕ (← these are not images) (nor is the arrow!)
☺
And you are killing 20 years of DOS :-) (the last smiley is called WHITE SMILING FACE... Now it's at 263A... But in ancient times it was ALT-1)and his friend
☻
BLACK SMILING FACE... Now it's at 263B... But in ancient times it was ALT-2Try a negative match:
Pattern regex = Pattern.compile("[^A-Za-z0-9]");
(this will ok only A-Z "standard" letters and "standard" digits.
answered Aug 5 '13 at 12:23
xanatos
88.6k7139196
Please don't do that... little Unicode BABY ANGELs like this one 👼 are dying! ◕◡◕ (← these are not images) (nor is the arrow!)
☺
And you are killing 20 years of DOS :-) (the last smiley is called WHITE SMILING FACE... Now it's at 263A... But in ancient times it was ALT-1)and his friend
☻
BLACK SMILING FACE... Now it's at 263B... But in ancient times it was ALT-2Try a negative match:
Pattern regex = Pattern.compile("[^A-Za-z0-9]");
(this will ok only A-Z "standard" letters and "standard" digits.
answered Aug 5 '13 at 12:23
xanatos
88.6k7139196
edited Oct 2 '15 at 12:05
answered Aug 5 '13 at 12:23
xanatos
88.6k7139196
answered Aug 5 '13 at 12:23
xanatos
88.6k7139196
answered Aug 5 '13 at 12:23
xanatos
88.6k7139196
88.6k7139196
3
Will this work for non-english characters? such as à 蔿
– Abdullah Shoaib
Dec 9 '13 at 12:44
2
@AbdullahShoaib Clearly not :) You'll need to do a full list of what you consider "special" and/or what you consider "good".
– xanatos
Mar 9 '15 at 9:58
I notice many people use[A-Za-z0-9]to represent any letter or digit, both lowercase and upper, but is it not better to just do[0-z]?
– Abraham Murciano Benzadon
Jun 25 '17 at 16:09
3
@AbrahamMurcianoBenzadon: The decimal digits, the upper case roman letters, and the lower case roman letters occupy three disjoint ranges of character code space.
– Solomon Slow
Jun 25 '17 at 17:31
1
@AbrahamMurcianoBenzadon You can see what James wrote in the handy screenshot of Character Map posted by Sina in another response: your regex would accept :;<=>?@^_` (other than 0-9, a-z, A-Z)
– xanatos
Jun 26 '17 at 6:15
|
show 3 more comments
3
Will this work for non-english characters? such as à 蔿
– Abdullah Shoaib
Dec 9 '13 at 12:44
2
@AbdullahShoaib Clearly not :) You'll need to do a full list of what you consider "special" and/or what you consider "good".
– xanatos
Mar 9 '15 at 9:58
I notice many people use[A-Za-z0-9]to represent any letter or digit, both lowercase and upper, but is it not better to just do[0-z]?
– Abraham Murciano Benzadon
Jun 25 '17 at 16:09
3
@AbrahamMurcianoBenzadon: The decimal digits, the upper case roman letters, and the lower case roman letters occupy three disjoint ranges of character code space.
– Solomon Slow
Jun 25 '17 at 17:31
1
@AbrahamMurcianoBenzadon You can see what James wrote in the handy screenshot of Character Map posted by Sina in another response: your regex would accept :;<=>?@^_` (other than 0-9, a-z, A-Z)
– xanatos
Jun 26 '17 at 6:15
3
3
Will this work for non-english characters? such as à 蔿
– Abdullah Shoaib
Dec 9 '13 at 12:44
Will this work for non-english characters? such as à 蔿
– Abdullah Shoaib
Dec 9 '13 at 12:44
2
2
@AbdullahShoaib Clearly not :) You'll need to do a full list of what you consider "special" and/or what you consider "good".
– xanatos
Mar 9 '15 at 9:58
@AbdullahShoaib Clearly not :) You'll need to do a full list of what you consider "special" and/or what you consider "good".
– xanatos
Mar 9 '15 at 9:58
I notice many people use
[A-Za-z0-9] to represent any letter or digit, both lowercase and upper, but is it not better to just do [0-z]?– Abraham Murciano Benzadon
Jun 25 '17 at 16:09
I notice many people use
[A-Za-z0-9] to represent any letter or digit, both lowercase and upper, but is it not better to just do [0-z]?– Abraham Murciano Benzadon
Jun 25 '17 at 16:09
3
3
@AbrahamMurcianoBenzadon: The decimal digits, the upper case roman letters, and the lower case roman letters occupy three disjoint ranges of character code space.
– Solomon Slow
Jun 25 '17 at 17:31
@AbrahamMurcianoBenzadon: The decimal digits, the upper case roman letters, and the lower case roman letters occupy three disjoint ranges of character code space.
– Solomon Slow
Jun 25 '17 at 17:31
1
1
@AbrahamMurcianoBenzadon You can see what James wrote in the handy screenshot of Character Map posted by Sina in another response: your regex would accept :;<=>?@^_` (other than 0-9, a-z, A-Z)
– xanatos
Jun 26 '17 at 6:15
@AbrahamMurcianoBenzadon You can see what James wrote in the handy screenshot of Character Map posted by Sina in another response: your regex would accept :;<=>?@^_` (other than 0-9, a-z, A-Z)
– xanatos
Jun 26 '17 at 6:15
|
show 3 more comments
You have a dash in the middle of the character class, which will mean a character range. Put the dash at the end of the class like so:
[$&+,:;=?@#|'<>.^*()%!-]
answered Aug 5 '13 at 12:22
Jerry
57.7k1067101
add a comment |
You have a dash in the middle of the character class, which will mean a character range. Put the dash at the end of the class like so:
[$&+,:;=?@#|'<>.^*()%!-]
answered Aug 5 '13 at 12:22
Jerry
57.7k1067101
add a comment |
You have a dash in the middle of the character class, which will mean a character range. Put the dash at the end of the class like so:
[$&+,:;=?@#|'<>.^*()%!-]
answered Aug 5 '13 at 12:22
Jerry
57.7k1067101
You have a dash in the middle of the character class, which will mean a character range. Put the dash at the end of the class like so:
[$&+,:;=?@#|'<>.^*()%!-]
answered Aug 5 '13 at 12:22
Jerry
57.7k1067101
answered Aug 5 '13 at 12:22
Jerry
57.7k1067101
answered Aug 5 '13 at 12:22
Jerry
57.7k1067101
answered Aug 5 '13 at 12:22
Jerry
57.7k1067101
57.7k1067101
add a comment |
add a comment |
That's because your pattern contains a .-^ which is all characters between and including . and ^, which included digits and several other characters as shown below:
If by special characters, you mean punctuation and symbols use:
[pPpS]
which contains all unicode punctuation and symbols.
answered Aug 5 '13 at 12:31
Sina Iravanian
12.8k32241
add a comment |
That's because your pattern contains a .-^ which is all characters between and including . and ^, which included digits and several other characters as shown below:
If by special characters, you mean punctuation and symbols use:
[pPpS]
which contains all unicode punctuation and symbols.
answered Aug 5 '13 at 12:31
Sina Iravanian
12.8k32241
add a comment |
That's because your pattern contains a .-^ which is all characters between and including . and ^, which included digits and several other characters as shown below:
If by special characters, you mean punctuation and symbols use:
[pPpS]
which contains all unicode punctuation and symbols.
answered Aug 5 '13 at 12:31
Sina Iravanian
12.8k32241
That's because your pattern contains a .-^ which is all characters between and including . and ^, which included digits and several other characters as shown below:
If by special characters, you mean punctuation and symbols use:
[pPpS]
which contains all unicode punctuation and symbols.
answered Aug 5 '13 at 12:31
Sina Iravanian
12.8k32241
answered Aug 5 '13 at 12:31
Sina Iravanian
12.8k32241
answered Aug 5 '13 at 12:31
Sina Iravanian
12.8k32241
answered Aug 5 '13 at 12:31
Sina Iravanian
12.8k32241
12.8k32241
add a comment |
add a comment |
SInce you don't have white-space and underscore in your character class I think following regex will be better for you:
Pattern regex = Pattern.compile("[^ws]");
Which means match everything other than [A-Za-z0-9s_]
Unicode version:
Pattern regex = Pattern.compile("[^pLds_]");
answered Aug 5 '13 at 12:27
anubhava
519k46315389
add a comment |
SInce you don't have white-space and underscore in your character class I think following regex will be better for you:
Pattern regex = Pattern.compile("[^ws]");
Which means match everything other than [A-Za-z0-9s_]
Unicode version:
Pattern regex = Pattern.compile("[^pLds_]");
answered Aug 5 '13 at 12:27
anubhava
519k46315389
add a comment |
SInce you don't have white-space and underscore in your character class I think following regex will be better for you:
Pattern regex = Pattern.compile("[^ws]");
Which means match everything other than [A-Za-z0-9s_]
Unicode version:
Pattern regex = Pattern.compile("[^pLds_]");
answered Aug 5 '13 at 12:27
anubhava
519k46315389
SInce you don't have white-space and underscore in your character class I think following regex will be better for you:
Pattern regex = Pattern.compile("[^ws]");
Which means match everything other than [A-Za-z0-9s_]
Unicode version:
Pattern regex = Pattern.compile("[^pLds_]");
answered Aug 5 '13 at 12:27
anubhava
519k46315389
answered Aug 5 '13 at 12:27
anubhava
519k46315389
answered Aug 5 '13 at 12:27
anubhava
519k46315389
answered Aug 5 '13 at 12:27
anubhava
519k46315389
519k46315389
add a comment |
add a comment |
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class detectspecial
public int getSpecialCharacterCount(String s)
answered Jun 26 '14 at 8:23
Ashish Sharma
21224
this code always return 0
– En NuNYet de Can CalÇadA
May 7 '17 at 16:36
add a comment |
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class detectspecial
public int getSpecialCharacterCount(String s)
answered Jun 26 '14 at 8:23
Ashish Sharma
21224
this code always return 0
– En NuNYet de Can CalÇadA
May 7 '17 at 16:36
add a comment |
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class detectspecial
public int getSpecialCharacterCount(String s)
answered Jun 26 '14 at 8:23
Ashish Sharma
21224
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class detectspecial
public int getSpecialCharacterCount(String s)
answered Jun 26 '14 at 8:23
Ashish Sharma
21224
answered Jun 26 '14 at 8:23
Ashish Sharma
21224
answered Jun 26 '14 at 8:23
Ashish Sharma
21224
answered Jun 26 '14 at 8:23
Ashish Sharma
21224
21224
this code always return 0
– En NuNYet de Can CalÇadA
May 7 '17 at 16:36
add a comment |
this code always return 0
– En NuNYet de Can CalÇadA
May 7 '17 at 16:36
this code always return 0
– En NuNYet de Can CalÇadA
May 7 '17 at 16:36
this code always return 0
– En NuNYet de Can CalÇadA
May 7 '17 at 16:36
add a comment |
Try:
(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$
(?i)^(A)$: indicates that the regular expression A is case insensitive.
[a-z]: represents any alphabetic character from a to z.
[^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]: represents any alphabetic character except a to z, digits, and special characters i.e. accented characters.
[[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]: represents any alphabetic(accented or unaccented) character only characters.
*: one or more occurrence of the regex that precedes it.
edited Feb 17 '16 at 18:42
Alan Moore
60.5k978132
answered Feb 17 '16 at 11:26
cdaiga
3,75611222
This would be a better answer if it included an explanation along with the code.
– John Hascall
Feb 17 '16 at 17:04
@JohnHascall, I just added an explanation.
– cdaiga
Feb 17 '16 at 17:31
Inside a character class, none of those characters need to be escaped except` and-`. Many of them never need to be escaped at all. "Better safe than sorry" is a fine philosophy, but readability is important, too.
– Alan Moore
Feb 17 '16 at 18:46
add a comment |
Try:
(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$
(?i)^(A)$: indicates that the regular expression A is case insensitive.
[a-z]: represents any alphabetic character from a to z.
[^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]: represents any alphabetic character except a to z, digits, and special characters i.e. accented characters.
[[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]: represents any alphabetic(accented or unaccented) character only characters.
*: one or more occurrence of the regex that precedes it.
edited Feb 17 '16 at 18:42
Alan Moore
60.5k978132
answered Feb 17 '16 at 11:26
cdaiga
3,75611222
This would be a better answer if it included an explanation along with the code.
– John Hascall
Feb 17 '16 at 17:04
@JohnHascall, I just added an explanation.
– cdaiga
Feb 17 '16 at 17:31
Inside a character class, none of those characters need to be escaped except` and-`. Many of them never need to be escaped at all. "Better safe than sorry" is a fine philosophy, but readability is important, too.
– Alan Moore
Feb 17 '16 at 18:46
add a comment |
Try:
(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$
(?i)^(A)$: indicates that the regular expression A is case insensitive.
[a-z]: represents any alphabetic character from a to z.
[^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]: represents any alphabetic character except a to z, digits, and special characters i.e. accented characters.
[[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]: represents any alphabetic(accented or unaccented) character only characters.
*: one or more occurrence of the regex that precedes it.
edited Feb 17 '16 at 18:42
Alan Moore
60.5k978132
answered Feb 17 '16 at 11:26
cdaiga
3,75611222
Try:
(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$
(?i)^(A)$: indicates that the regular expression A is case insensitive.
[a-z]: represents any alphabetic character from a to z.
[^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]: represents any alphabetic character except a to z, digits, and special characters i.e. accented characters.
[[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]: represents any alphabetic(accented or unaccented) character only characters.
*: one or more occurrence of the regex that precedes it.
edited Feb 17 '16 at 18:42
Alan Moore
60.5k978132
answered Feb 17 '16 at 11:26
cdaiga
3,75611222
edited Feb 17 '16 at 18:42
Alan Moore
60.5k978132
edited Feb 17 '16 at 18:42
Alan Moore
60.5k978132
edited Feb 17 '16 at 18:42
Alan Moore
60.5k978132
60.5k978132
answered Feb 17 '16 at 11:26
cdaiga
3,75611222
answered Feb 17 '16 at 11:26
cdaiga
3,75611222
answered Feb 17 '16 at 11:26
cdaiga
3,75611222
3,75611222
This would be a better answer if it included an explanation along with the code.
– John Hascall
Feb 17 '16 at 17:04
@JohnHascall, I just added an explanation.
– cdaiga
Feb 17 '16 at 17:31
Inside a character class, none of those characters need to be escaped except` and-`. Many of them never need to be escaped at all. "Better safe than sorry" is a fine philosophy, but readability is important, too.
– Alan Moore
Feb 17 '16 at 18:46
add a comment |
This would be a better answer if it included an explanation along with the code.
– John Hascall
Feb 17 '16 at 17:04
@JohnHascall, I just added an explanation.
– cdaiga
Feb 17 '16 at 17:31
Inside a character class, none of those characters need to be escaped except` and-`. Many of them never need to be escaped at all. "Better safe than sorry" is a fine philosophy, but readability is important, too.
– Alan Moore
Feb 17 '16 at 18:46
This would be a better answer if it included an explanation along with the code.
– John Hascall
Feb 17 '16 at 17:04
This would be a better answer if it included an explanation along with the code.
– John Hascall
Feb 17 '16 at 17:04
@JohnHascall, I just added an explanation.
– cdaiga
Feb 17 '16 at 17:31
@JohnHascall, I just added an explanation.
– cdaiga
Feb 17 '16 at 17:31
Inside a character class, none of those characters need to be escaped except
` and -`. Many of them never need to be escaped at all. "Better safe than sorry" is a fine philosophy, but readability is important, too.– Alan Moore
Feb 17 '16 at 18:46
Inside a character class, none of those characters need to be escaped except
` and -`. Many of them never need to be escaped at all. "Better safe than sorry" is a fine philosophy, but readability is important, too.– Alan Moore
Feb 17 '16 at 18:46
add a comment |
If you only rely on ASCII characters, you can rely on using the hex ranges on the ASCII table. Here is a regex that will grab all special characters in the range of 33-47, 58-64, 91-96, 123-126
[x21-x2Fx3A-x40x5B-x60x7B-x7E]
However you can think of special characters as not normal characters. If we take that approach, you can simply do this
^[A-Za-z0-9s]+
Hower this will not catch _ ^ and probably others.
answered Feb 3 '16 at 22:06
Serguei Fedorov
4,17394379
I finally used(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$to match any character.
– cdaiga
Feb 17 '16 at 11:25
Whatever works best for you!
– Serguei Fedorov
Feb 17 '16 at 18:37
1
Never use[A-z]in a regex. It matches all uppercase and lowercase ASCII letters as you would expect. but it also matches several punctuation characters whose code points lie betweenZanda. Use[A-Za-z]instead, or[a-z]in case-insensitive mode.
– Alan Moore
Feb 17 '16 at 18:37
@AlanMoore, good to know! I'll make the change to the answer.
– Serguei Fedorov
Feb 17 '16 at 18:39
how about '.' dot character . It supporsed to match any character except new line. In python re.DOTALL matches all including newline. Check out the regular expression faq in the python tutorial docs.python.org/2/howto/regex.html
– Dr Deo
Sep 6 at 15:01
add a comment |
If you only rely on ASCII characters, you can rely on using the hex ranges on the ASCII table. Here is a regex that will grab all special characters in the range of 33-47, 58-64, 91-96, 123-126
[x21-x2Fx3A-x40x5B-x60x7B-x7E]
However you can think of special characters as not normal characters. If we take that approach, you can simply do this
^[A-Za-z0-9s]+
Hower this will not catch _ ^ and probably others.
answered Feb 3 '16 at 22:06
Serguei Fedorov
4,17394379
I finally used(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$to match any character.
– cdaiga
Feb 17 '16 at 11:25
Whatever works best for you!
– Serguei Fedorov
Feb 17 '16 at 18:37
1
Never use[A-z]in a regex. It matches all uppercase and lowercase ASCII letters as you would expect. but it also matches several punctuation characters whose code points lie betweenZanda. Use[A-Za-z]instead, or[a-z]in case-insensitive mode.
– Alan Moore
Feb 17 '16 at 18:37
@AlanMoore, good to know! I'll make the change to the answer.
– Serguei Fedorov
Feb 17 '16 at 18:39
how about '.' dot character . It supporsed to match any character except new line. In python re.DOTALL matches all including newline. Check out the regular expression faq in the python tutorial docs.python.org/2/howto/regex.html
– Dr Deo
Sep 6 at 15:01
add a comment |
If you only rely on ASCII characters, you can rely on using the hex ranges on the ASCII table. Here is a regex that will grab all special characters in the range of 33-47, 58-64, 91-96, 123-126
[x21-x2Fx3A-x40x5B-x60x7B-x7E]
However you can think of special characters as not normal characters. If we take that approach, you can simply do this
^[A-Za-z0-9s]+
Hower this will not catch _ ^ and probably others.
answered Feb 3 '16 at 22:06
Serguei Fedorov
4,17394379
If you only rely on ASCII characters, you can rely on using the hex ranges on the ASCII table. Here is a regex that will grab all special characters in the range of 33-47, 58-64, 91-96, 123-126
[x21-x2Fx3A-x40x5B-x60x7B-x7E]
However you can think of special characters as not normal characters. If we take that approach, you can simply do this
^[A-Za-z0-9s]+
Hower this will not catch _ ^ and probably others.
answered Feb 3 '16 at 22:06
Serguei Fedorov
4,17394379
edited Feb 17 '16 at 18:40
answered Feb 3 '16 at 22:06
Serguei Fedorov
4,17394379
answered Feb 3 '16 at 22:06
Serguei Fedorov
4,17394379
answered Feb 3 '16 at 22:06
Serguei Fedorov
4,17394379
4,17394379
I finally used(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$to match any character.
– cdaiga
Feb 17 '16 at 11:25
Whatever works best for you!
– Serguei Fedorov
Feb 17 '16 at 18:37
1
Never use[A-z]in a regex. It matches all uppercase and lowercase ASCII letters as you would expect. but it also matches several punctuation characters whose code points lie betweenZanda. Use[A-Za-z]instead, or[a-z]in case-insensitive mode.
– Alan Moore
Feb 17 '16 at 18:37
@AlanMoore, good to know! I'll make the change to the answer.
– Serguei Fedorov
Feb 17 '16 at 18:39
how about '.' dot character . It supporsed to match any character except new line. In python re.DOTALL matches all including newline. Check out the regular expression faq in the python tutorial docs.python.org/2/howto/regex.html
– Dr Deo
Sep 6 at 15:01
add a comment |
I finally used(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$to match any character.
– cdaiga
Feb 17 '16 at 11:25
Whatever works best for you!
– Serguei Fedorov
Feb 17 '16 at 18:37
1
Never use[A-z]in a regex. It matches all uppercase and lowercase ASCII letters as you would expect. but it also matches several punctuation characters whose code points lie betweenZanda. Use[A-Za-z]instead, or[a-z]in case-insensitive mode.
– Alan Moore
Feb 17 '16 at 18:37
@AlanMoore, good to know! I'll make the change to the answer.
– Serguei Fedorov
Feb 17 '16 at 18:39
how about '.' dot character . It supporsed to match any character except new line. In python re.DOTALL matches all including newline. Check out the regular expression faq in the python tutorial docs.python.org/2/howto/regex.html
– Dr Deo
Sep 6 at 15:01
I finally used
(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$ to match any character.– cdaiga
Feb 17 '16 at 11:25
I finally used
(?i)^([[a-z][^a-z0-9\s\(\)\[\]\\\\^\$\|\?\*\+\.\<\>\-\=\!\_]]*)$ to match any character.– cdaiga
Feb 17 '16 at 11:25
Whatever works best for you!
– Serguei Fedorov
Feb 17 '16 at 18:37
Whatever works best for you!
– Serguei Fedorov
Feb 17 '16 at 18:37
1
1
Never use
[A-z] in a regex. It matches all uppercase and lowercase ASCII letters as you would expect. but it also matches several punctuation characters whose code points lie between Z and a. Use [A-Za-z] instead, or [a-z] in case-insensitive mode.– Alan Moore
Feb 17 '16 at 18:37
Never use
[A-z] in a regex. It matches all uppercase and lowercase ASCII letters as you would expect. but it also matches several punctuation characters whose code points lie between Z and a. Use [A-Za-z] instead, or [a-z] in case-insensitive mode.– Alan Moore
Feb 17 '16 at 18:37
@AlanMoore, good to know! I'll make the change to the answer.
– Serguei Fedorov
Feb 17 '16 at 18:39
@AlanMoore, good to know! I'll make the change to the answer.
– Serguei Fedorov
Feb 17 '16 at 18:39
how about '.' dot character . It supporsed to match any character except new line. In python re.DOTALL matches all including newline. Check out the regular expression faq in the python tutorial docs.python.org/2/howto/regex.html
– Dr Deo
Sep 6 at 15:01
how about '.' dot character . It supporsed to match any character except new line. In python re.DOTALL matches all including newline. Check out the regular expression faq in the python tutorial docs.python.org/2/howto/regex.html
– Dr Deo
Sep 6 at 15:01
add a comment |
Use this regular expression pattern ("^[a-zA-Z0-9]*$") .It validates alphanumeric string excluding the special characters
answered Jul 4 '16 at 6:41
sam
438
add a comment |
Use this regular expression pattern ("^[a-zA-Z0-9]*$") .It validates alphanumeric string excluding the special characters
answered Jul 4 '16 at 6:41
sam
438
add a comment |
Use this regular expression pattern ("^[a-zA-Z0-9]*$") .It validates alphanumeric string excluding the special characters
answered Jul 4 '16 at 6:41
sam
438
Use this regular expression pattern ("^[a-zA-Z0-9]*$") .It validates alphanumeric string excluding the special characters
answered Jul 4 '16 at 6:41
sam
438
answered Jul 4 '16 at 6:41
sam
438
answered Jul 4 '16 at 6:41
sam
438
answered Jul 4 '16 at 6:41
sam
438
438
add a comment |
add a comment |
Here is my regex variant of a special character:
String regExp = "^[^<>"/|;:.,~!?@#$%^=&*\]\\()\[¿§«»ω⊙¤°℃℉€¥£¢¡®©0-9_+]*$";
(Java code)
answered Mar 20 '17 at 14:52
Chuck
548711
2
you missed •☺○♣♥☻☺ and more..
– Aks4125
Dec 30 '17 at 4:58
add a comment |
Here is my regex variant of a special character:
String regExp = "^[^<>"/|;:.,~!?@#$%^=&*\]\\()\[¿§«»ω⊙¤°℃℉€¥£¢¡®©0-9_+]*$";
(Java code)
answered Mar 20 '17 at 14:52
Chuck
548711
2
you missed •☺○♣♥☻☺ and more..
– Aks4125
Dec 30 '17 at 4:58
add a comment |
Here is my regex variant of a special character:
String regExp = "^[^<>"/|;:.,~!?@#$%^=&*\]\\()\[¿§«»ω⊙¤°℃℉€¥£¢¡®©0-9_+]*$";
(Java code)
answered Mar 20 '17 at 14:52
Chuck
548711
Here is my regex variant of a special character:
String regExp = "^[^<>"/|;:.,~!?@#$%^=&*\]\\()\[¿§«»ω⊙¤°℃℉€¥£¢¡®©0-9_+]*$";
(Java code)
answered Mar 20 '17 at 14:52
Chuck
548711
answered Mar 20 '17 at 14:52
Chuck
548711
answered Mar 20 '17 at 14:52
Chuck
548711
answered Mar 20 '17 at 14:52
Chuck
548711
548711
2
you missed •☺○♣♥☻☺ and more..
– Aks4125
Dec 30 '17 at 4:58
add a comment |
2
you missed •☺○♣♥☻☺ and more..
– Aks4125
Dec 30 '17 at 4:58
2
2
you missed •☺○♣♥☻☺ and more..
– Aks4125
Dec 30 '17 at 4:58
you missed •☺○♣♥☻☺ and more..
– Aks4125
Dec 30 '17 at 4:58
add a comment |
Try using this for the same things - StringUtils.isAlphanumeric(value)
edited Dec 7 '16 at 23:54
Buddy
8,56952951
answered Dec 7 '16 at 23:52
Ash
28839
space/blank is also a special char if you use this method. Better to replace the space and tabs chars before calling this method.
– Deepu Sahni
Mar 21 at 1:14
add a comment |
Try using this for the same things - StringUtils.isAlphanumeric(value)
edited Dec 7 '16 at 23:54
Buddy
8,56952951
answered Dec 7 '16 at 23:52
Ash
28839
space/blank is also a special char if you use this method. Better to replace the space and tabs chars before calling this method.
– Deepu Sahni
Mar 21 at 1:14
add a comment |
Try using this for the same things - StringUtils.isAlphanumeric(value)
edited Dec 7 '16 at 23:54
Buddy
8,56952951
answered Dec 7 '16 at 23:52
Ash
28839
Try using this for the same things - StringUtils.isAlphanumeric(value)
edited Dec 7 '16 at 23:54
Buddy
8,56952951
answered Dec 7 '16 at 23:52
Ash
28839
edited Dec 7 '16 at 23:54
Buddy
8,56952951
edited Dec 7 '16 at 23:54
Buddy
8,56952951
edited Dec 7 '16 at 23:54
Buddy
8,56952951
8,56952951
answered Dec 7 '16 at 23:52
Ash
28839
answered Dec 7 '16 at 23:52
Ash
28839
answered Dec 7 '16 at 23:52
Ash
28839
28839
space/blank is also a special char if you use this method. Better to replace the space and tabs chars before calling this method.
– Deepu Sahni
Mar 21 at 1:14
add a comment |
space/blank is also a special char if you use this method. Better to replace the space and tabs chars before calling this method.
– Deepu Sahni
Mar 21 at 1:14
space/blank is also a special char if you use this method. Better to replace the space and tabs chars before calling this method.
– Deepu Sahni
Mar 21 at 1:14
space/blank is also a special char if you use this method. Better to replace the space and tabs chars before calling this method.
– Deepu Sahni
Mar 21 at 1:14
add a comment |
Here is my regular expression, that I used for removing all the special characters from any string :
String regex = ("[ \\s@ [\"]\\[\\]\\\-9|^#%'*/<()>:`;,!& .?_$+-]+")
edited Nov 12 at 12:05
Jan Černý
8121622
answered Nov 12 at 10:56
Suchismita Barik
112
add a comment |
Here is my regular expression, that I used for removing all the special characters from any string :
String regex = ("[ \\s@ [\"]\\[\\]\\\-9|^#%'*/<()>:`;,!& .?_$+-]+")
edited Nov 12 at 12:05
Jan Černý
8121622
answered Nov 12 at 10:56
Suchismita Barik
112
add a comment |
Here is my regular expression, that I used for removing all the special characters from any string :
String regex = ("[ \\s@ [\"]\\[\\]\\\-9|^#%'*/<()>:`;,!& .?_$+-]+")
edited Nov 12 at 12:05
Jan Černý
8121622
answered Nov 12 at 10:56
Suchismita Barik
112
Here is my regular expression, that I used for removing all the special characters from any string :
String regex = ("[ \\s@ [\"]\\[\\]\\\-9|^#%'*/<()>:`;,!& .?_$+-]+")
edited Nov 12 at 12:05
Jan Černý
8121622
answered Nov 12 at 10:56
Suchismita Barik
112
edited Nov 12 at 12:05
Jan Černý
8121622
edited Nov 12 at 12:05
Jan Černý
8121622
edited Nov 12 at 12:05
Jan Černý
8121622
8121622
answered Nov 12 at 10:56
Suchismita Barik
112
answered Nov 12 at 10:56
Suchismita Barik
112
answered Nov 12 at 10:56
Suchismita Barik
112
112
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(^W$)
^ - start of the string,
W - match any non-word character [^a-zA-Z0-9_],
$ - end of the string
answered Aug 26 '16 at 9:18
Sareesh Krishnan
20626
add a comment |
(^W$)
^ - start of the string,
W - match any non-word character [^a-zA-Z0-9_],
$ - end of the string
answered Aug 26 '16 at 9:18
Sareesh Krishnan
20626
add a comment |
(^W$)
^ - start of the string,
W - match any non-word character [^a-zA-Z0-9_],
$ - end of the string
answered Aug 26 '16 at 9:18
Sareesh Krishnan
20626
(^W$)
^ - start of the string,
W - match any non-word character [^a-zA-Z0-9_],
$ - end of the string
answered Aug 26 '16 at 9:18
Sareesh Krishnan
20626
answered Aug 26 '16 at 9:18
Sareesh Krishnan
20626
answered Aug 26 '16 at 9:18
Sareesh Krishnan
20626
answered Aug 26 '16 at 9:18
Sareesh Krishnan
20626
20626
add a comment |
add a comment |
We can achieve this using Pattern and Matcher as follows:
Pattern pattern = Pattern.compile("[^A-Za-z0-9 ]");
Matcher matcher = pattern.matcher(trString);
boolean hasSpecialChars = matcher.find();
answered Sep 20 at 12:18
KayV
3,65122054
add a comment |
We can achieve this using Pattern and Matcher as follows:
Pattern pattern = Pattern.compile("[^A-Za-z0-9 ]");
Matcher matcher = pattern.matcher(trString);
boolean hasSpecialChars = matcher.find();
answered Sep 20 at 12:18
KayV
3,65122054
add a comment |
We can achieve this using Pattern and Matcher as follows:
Pattern pattern = Pattern.compile("[^A-Za-z0-9 ]");
Matcher matcher = pattern.matcher(trString);
boolean hasSpecialChars = matcher.find();
answered Sep 20 at 12:18
KayV
3,65122054
We can achieve this using Pattern and Matcher as follows:
Pattern pattern = Pattern.compile("[^A-Za-z0-9 ]");
Matcher matcher = pattern.matcher(trString);
boolean hasSpecialChars = matcher.find();
answered Sep 20 at 12:18
KayV
3,65122054
answered Sep 20 at 12:18
KayV
3,65122054
answered Sep 20 at 12:18
KayV
3,65122054
answered Sep 20 at 12:18
KayV
3,65122054
3,65122054
add a comment |
add a comment |
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4
the dash in
should be escaped, it has special meaning there.– MightyPork
Aug 5 '13 at 12:21
7
¿¡ So you think that the only special characters that exist are the ones on your keyboard !? :-)
– xanatos
Aug 5 '13 at 12:22
2
Exactly. It would be better to define all "non-special" charactes and make that negative.
– NeplatnyUdaj
Aug 5 '13 at 12:22
yes maybe it would be wiser to assert the use of only those characters you want to allow.
– d'alar'cop
Aug 5 '13 at 12:23
14
Just like children, all characters are special, each in its own way. :)
– tchrist
Aug 5 '13 at 13:15