Integration in SymPy raises “no attribute '_eval_power'” error










0














Why does integral_0^1 log(x)/(x^2 - 1) dx not work in SymPy?




AttributeError: 'Not' object has no attribute '_eval_power'




http://www.ms.u-tokyo.ac.jp/kyoumu/a20170524.pdf#page=4



(OK)
Wolfram|Alpha Examples:



https://www.wolframalpha.com/input/?i=∫%5B0,1%5D+log(x)%2F(x%5E2-1)+dx



integral_0^1 log(x)/(x^2 - 1) dx = π^2/8?



1.2337



(??)
sympy



from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x^2-1)
print(integrate(f,(x, 0, 1)))
print(float(integrate(f,(x, 0, 1))))
# AttributeError: 'Not' object has no attribute '_eval_power'









share|improve this question























  • ^ is not the power operator in Python. Have you tried x**2?
    – user8408080
    Nov 12 at 12:52















0














Why does integral_0^1 log(x)/(x^2 - 1) dx not work in SymPy?




AttributeError: 'Not' object has no attribute '_eval_power'




http://www.ms.u-tokyo.ac.jp/kyoumu/a20170524.pdf#page=4



(OK)
Wolfram|Alpha Examples:



https://www.wolframalpha.com/input/?i=∫%5B0,1%5D+log(x)%2F(x%5E2-1)+dx



integral_0^1 log(x)/(x^2 - 1) dx = π^2/8?



1.2337



(??)
sympy



from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x^2-1)
print(integrate(f,(x, 0, 1)))
print(float(integrate(f,(x, 0, 1))))
# AttributeError: 'Not' object has no attribute '_eval_power'









share|improve this question























  • ^ is not the power operator in Python. Have you tried x**2?
    – user8408080
    Nov 12 at 12:52













0












0








0







Why does integral_0^1 log(x)/(x^2 - 1) dx not work in SymPy?




AttributeError: 'Not' object has no attribute '_eval_power'




http://www.ms.u-tokyo.ac.jp/kyoumu/a20170524.pdf#page=4



(OK)
Wolfram|Alpha Examples:



https://www.wolframalpha.com/input/?i=∫%5B0,1%5D+log(x)%2F(x%5E2-1)+dx



integral_0^1 log(x)/(x^2 - 1) dx = π^2/8?



1.2337



(??)
sympy



from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x^2-1)
print(integrate(f,(x, 0, 1)))
print(float(integrate(f,(x, 0, 1))))
# AttributeError: 'Not' object has no attribute '_eval_power'









share|improve this question















Why does integral_0^1 log(x)/(x^2 - 1) dx not work in SymPy?




AttributeError: 'Not' object has no attribute '_eval_power'




http://www.ms.u-tokyo.ac.jp/kyoumu/a20170524.pdf#page=4



(OK)
Wolfram|Alpha Examples:



https://www.wolframalpha.com/input/?i=∫%5B0,1%5D+log(x)%2F(x%5E2-1)+dx



integral_0^1 log(x)/(x^2 - 1) dx = π^2/8?



1.2337



(??)
sympy



from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x^2-1)
print(integrate(f,(x, 0, 1)))
print(float(integrate(f,(x, 0, 1))))
# AttributeError: 'Not' object has no attribute '_eval_power'






python sympy






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share|improve this question













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edited Nov 12 at 12:47







user6655984

















asked Nov 12 at 12:01









mrrclb48z

376




376











  • ^ is not the power operator in Python. Have you tried x**2?
    – user8408080
    Nov 12 at 12:52
















  • ^ is not the power operator in Python. Have you tried x**2?
    – user8408080
    Nov 12 at 12:52















^ is not the power operator in Python. Have you tried x**2?
– user8408080
Nov 12 at 12:52




^ is not the power operator in Python. Have you tried x**2?
– user8408080
Nov 12 at 12:52












2 Answers
2






active

oldest

votes


















1














Write f = log(x)/(x**2-1) because in Python, powers are denoted by ** (and ^ is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.



If you are okay with a floating point answer, then use numerical integration:



print(Integral(f,(x, 0, 1)).evalf())


which returns 1.23370055013617...



A thing worth trying with such integrals is nsimplify, which finds a symbolic answer than matches the outcome of numeric integration.



>>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
pi**2/8


Here the list [pi, E] includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma).






share|improve this answer






























    1














    In python, the power symbol is not ^ but **.



    Use this:



    from sympy import *
    # var("x")
    x = symbols('x', positive=True)
    f=log(x)/(x**2-1)
    print(integrate(f,(x, 0, 1)))


    Results:



    Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))





    share|improve this answer




















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      Write f = log(x)/(x**2-1) because in Python, powers are denoted by ** (and ^ is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.



      If you are okay with a floating point answer, then use numerical integration:



      print(Integral(f,(x, 0, 1)).evalf())


      which returns 1.23370055013617...



      A thing worth trying with such integrals is nsimplify, which finds a symbolic answer than matches the outcome of numeric integration.



      >>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
      pi**2/8


      Here the list [pi, E] includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma).






      share|improve this answer



























        1














        Write f = log(x)/(x**2-1) because in Python, powers are denoted by ** (and ^ is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.



        If you are okay with a floating point answer, then use numerical integration:



        print(Integral(f,(x, 0, 1)).evalf())


        which returns 1.23370055013617...



        A thing worth trying with such integrals is nsimplify, which finds a symbolic answer than matches the outcome of numeric integration.



        >>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
        pi**2/8


        Here the list [pi, E] includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma).






        share|improve this answer

























          1












          1








          1






          Write f = log(x)/(x**2-1) because in Python, powers are denoted by ** (and ^ is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.



          If you are okay with a floating point answer, then use numerical integration:



          print(Integral(f,(x, 0, 1)).evalf())


          which returns 1.23370055013617...



          A thing worth trying with such integrals is nsimplify, which finds a symbolic answer than matches the outcome of numeric integration.



          >>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
          pi**2/8


          Here the list [pi, E] includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma).






          share|improve this answer














          Write f = log(x)/(x**2-1) because in Python, powers are denoted by ** (and ^ is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.



          If you are okay with a floating point answer, then use numerical integration:



          print(Integral(f,(x, 0, 1)).evalf())


          which returns 1.23370055013617...



          A thing worth trying with such integrals is nsimplify, which finds a symbolic answer than matches the outcome of numeric integration.



          >>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
          pi**2/8


          Here the list [pi, E] includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma).







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 13 at 3:31

























          answered Nov 12 at 12:54







          user6655984






























              1














              In python, the power symbol is not ^ but **.



              Use this:



              from sympy import *
              # var("x")
              x = symbols('x', positive=True)
              f=log(x)/(x**2-1)
              print(integrate(f,(x, 0, 1)))


              Results:



              Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))





              share|improve this answer

























                1














                In python, the power symbol is not ^ but **.



                Use this:



                from sympy import *
                # var("x")
                x = symbols('x', positive=True)
                f=log(x)/(x**2-1)
                print(integrate(f,(x, 0, 1)))


                Results:



                Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))





                share|improve this answer























                  1












                  1








                  1






                  In python, the power symbol is not ^ but **.



                  Use this:



                  from sympy import *
                  # var("x")
                  x = symbols('x', positive=True)
                  f=log(x)/(x**2-1)
                  print(integrate(f,(x, 0, 1)))


                  Results:



                  Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))





                  share|improve this answer












                  In python, the power symbol is not ^ but **.



                  Use this:



                  from sympy import *
                  # var("x")
                  x = symbols('x', positive=True)
                  f=log(x)/(x**2-1)
                  print(integrate(f,(x, 0, 1)))


                  Results:



                  Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 12 at 12:53









                  seralouk

                  5,62522338




                  5,62522338



























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