Integration in SymPy raises “no attribute '_eval_power'” error
Why does integral_0^1 log(x)/(x^2 - 1) dx not work in SymPy?
AttributeError: 'Not' object has no attribute '_eval_power'
http://www.ms.u-tokyo.ac.jp/kyoumu/a20170524.pdf#page=4
(OK)
Wolfram|Alpha Examples:
https://www.wolframalpha.com/input/?i=∫%5B0,1%5D+log(x)%2F(x%5E2-1)+dx
integral_0^1 log(x)/(x^2 - 1) dx = π^2/8?
1.2337
(??)
sympy
from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x^2-1)
print(integrate(f,(x, 0, 1)))
print(float(integrate(f,(x, 0, 1))))
# AttributeError: 'Not' object has no attribute '_eval_power'
python sympy
add a comment |
Why does integral_0^1 log(x)/(x^2 - 1) dx not work in SymPy?
AttributeError: 'Not' object has no attribute '_eval_power'
http://www.ms.u-tokyo.ac.jp/kyoumu/a20170524.pdf#page=4
(OK)
Wolfram|Alpha Examples:
https://www.wolframalpha.com/input/?i=∫%5B0,1%5D+log(x)%2F(x%5E2-1)+dx
integral_0^1 log(x)/(x^2 - 1) dx = π^2/8?
1.2337
(??)
sympy
from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x^2-1)
print(integrate(f,(x, 0, 1)))
print(float(integrate(f,(x, 0, 1))))
# AttributeError: 'Not' object has no attribute '_eval_power'
python sympy
^
is not the power operator in Python. Have you triedx**2
?
– user8408080
Nov 12 at 12:52
add a comment |
Why does integral_0^1 log(x)/(x^2 - 1) dx not work in SymPy?
AttributeError: 'Not' object has no attribute '_eval_power'
http://www.ms.u-tokyo.ac.jp/kyoumu/a20170524.pdf#page=4
(OK)
Wolfram|Alpha Examples:
https://www.wolframalpha.com/input/?i=∫%5B0,1%5D+log(x)%2F(x%5E2-1)+dx
integral_0^1 log(x)/(x^2 - 1) dx = π^2/8?
1.2337
(??)
sympy
from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x^2-1)
print(integrate(f,(x, 0, 1)))
print(float(integrate(f,(x, 0, 1))))
# AttributeError: 'Not' object has no attribute '_eval_power'
python sympy
Why does integral_0^1 log(x)/(x^2 - 1) dx not work in SymPy?
AttributeError: 'Not' object has no attribute '_eval_power'
http://www.ms.u-tokyo.ac.jp/kyoumu/a20170524.pdf#page=4
(OK)
Wolfram|Alpha Examples:
https://www.wolframalpha.com/input/?i=∫%5B0,1%5D+log(x)%2F(x%5E2-1)+dx
integral_0^1 log(x)/(x^2 - 1) dx = π^2/8?
1.2337
(??)
sympy
from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x^2-1)
print(integrate(f,(x, 0, 1)))
print(float(integrate(f,(x, 0, 1))))
# AttributeError: 'Not' object has no attribute '_eval_power'
python sympy
python sympy
edited Nov 12 at 12:47
user6655984
asked Nov 12 at 12:01
mrrclb48z
376
376
^
is not the power operator in Python. Have you triedx**2
?
– user8408080
Nov 12 at 12:52
add a comment |
^
is not the power operator in Python. Have you triedx**2
?
– user8408080
Nov 12 at 12:52
^
is not the power operator in Python. Have you tried x**2
?– user8408080
Nov 12 at 12:52
^
is not the power operator in Python. Have you tried x**2
?– user8408080
Nov 12 at 12:52
add a comment |
2 Answers
2
active
oldest
votes
Write f = log(x)/(x**2-1)
because in Python, powers are denoted by **
(and ^
is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.
If you are okay with a floating point answer, then use numerical integration:
print(Integral(f,(x, 0, 1)).evalf())
which returns 1.23370055013617
...
A thing worth trying with such integrals is nsimplify
, which finds a symbolic answer than matches the outcome of numeric integration.
>>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
pi**2/8
Here the list [pi, E]
includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma
).
add a comment |
In python, the power symbol is not ^
but **
.
Use this:
from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x**2-1)
print(integrate(f,(x, 0, 1)))
Results:
Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Write f = log(x)/(x**2-1)
because in Python, powers are denoted by **
(and ^
is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.
If you are okay with a floating point answer, then use numerical integration:
print(Integral(f,(x, 0, 1)).evalf())
which returns 1.23370055013617
...
A thing worth trying with such integrals is nsimplify
, which finds a symbolic answer than matches the outcome of numeric integration.
>>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
pi**2/8
Here the list [pi, E]
includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma
).
add a comment |
Write f = log(x)/(x**2-1)
because in Python, powers are denoted by **
(and ^
is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.
If you are okay with a floating point answer, then use numerical integration:
print(Integral(f,(x, 0, 1)).evalf())
which returns 1.23370055013617
...
A thing worth trying with such integrals is nsimplify
, which finds a symbolic answer than matches the outcome of numeric integration.
>>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
pi**2/8
Here the list [pi, E]
includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma
).
add a comment |
Write f = log(x)/(x**2-1)
because in Python, powers are denoted by **
(and ^
is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.
If you are okay with a floating point answer, then use numerical integration:
print(Integral(f,(x, 0, 1)).evalf())
which returns 1.23370055013617
...
A thing worth trying with such integrals is nsimplify
, which finds a symbolic answer than matches the outcome of numeric integration.
>>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
pi**2/8
Here the list [pi, E]
includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma
).
Write f = log(x)/(x**2-1)
because in Python, powers are denoted by **
(and ^
is XOR). This is why the error is thrown. However, SymPy is still unable to integrate that function: the integral returns unevaluated. These polylog-type nonelementary integrals give a lot of trouble to SymPy.
If you are okay with a floating point answer, then use numerical integration:
print(Integral(f,(x, 0, 1)).evalf())
which returns 1.23370055013617
...
A thing worth trying with such integrals is nsimplify
, which finds a symbolic answer than matches the outcome of numeric integration.
>>> nsimplify(Integral(f, (x, 0, 1)), [pi, E])
pi**2/8
Here the list [pi, E]
includes the two most famous math constants, which are likely to appear in integrals. (Another constant that shows up often is EulerGamma
).
edited Nov 13 at 3:31
answered Nov 12 at 12:54
user6655984
add a comment |
add a comment |
In python, the power symbol is not ^
but **
.
Use this:
from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x**2-1)
print(integrate(f,(x, 0, 1)))
Results:
Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))
add a comment |
In python, the power symbol is not ^
but **
.
Use this:
from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x**2-1)
print(integrate(f,(x, 0, 1)))
Results:
Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))
add a comment |
In python, the power symbol is not ^
but **
.
Use this:
from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x**2-1)
print(integrate(f,(x, 0, 1)))
Results:
Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))
In python, the power symbol is not ^
but **
.
Use this:
from sympy import *
# var("x")
x = symbols('x', positive=True)
f=log(x)/(x**2-1)
print(integrate(f,(x, 0, 1)))
Results:
Integral(log(x)/((x - 1)*(x + 1)), (x, 0, 1))
answered Nov 12 at 12:53
seralouk
5,62522338
5,62522338
add a comment |
add a comment |
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^
is not the power operator in Python. Have you triedx**2
?– user8408080
Nov 12 at 12:52