How to apply scipy.signal.filtfilt() on incomplete data










0














I want to plot incomplete data (some values are None). In addition I want to apply a butter function on the dataset and show both graphs, incomplete and smoothened. The filter function seems to not work with incomplete data.



Data File: data.csv



import matplotlib.pyplot as plt
import pandas as pd
import numpy as np
from scipy import signal

data = np.genfromtxt('data.csv', delimiter = ',')
df = pd.DataFrame(data)
df.set_index(0, inplace = True)

b, a = signal.butter(5, 0.1)
y = signal.filtfilt(b,a, df[1].values)
df2 = pd.DataFrame(y, index=df.index)

df.plot()
df2.plot()

plt.show()


enter image description hereenter image description here










share|improve this question


























    0














    I want to plot incomplete data (some values are None). In addition I want to apply a butter function on the dataset and show both graphs, incomplete and smoothened. The filter function seems to not work with incomplete data.



    Data File: data.csv



    import matplotlib.pyplot as plt
    import pandas as pd
    import numpy as np
    from scipy import signal

    data = np.genfromtxt('data.csv', delimiter = ',')
    df = pd.DataFrame(data)
    df.set_index(0, inplace = True)

    b, a = signal.butter(5, 0.1)
    y = signal.filtfilt(b,a, df[1].values)
    df2 = pd.DataFrame(y, index=df.index)

    df.plot()
    df2.plot()

    plt.show()


    enter image description hereenter image description here










    share|improve this question
























      0












      0








      0







      I want to plot incomplete data (some values are None). In addition I want to apply a butter function on the dataset and show both graphs, incomplete and smoothened. The filter function seems to not work with incomplete data.



      Data File: data.csv



      import matplotlib.pyplot as plt
      import pandas as pd
      import numpy as np
      from scipy import signal

      data = np.genfromtxt('data.csv', delimiter = ',')
      df = pd.DataFrame(data)
      df.set_index(0, inplace = True)

      b, a = signal.butter(5, 0.1)
      y = signal.filtfilt(b,a, df[1].values)
      df2 = pd.DataFrame(y, index=df.index)

      df.plot()
      df2.plot()

      plt.show()


      enter image description hereenter image description here










      share|improve this question













      I want to plot incomplete data (some values are None). In addition I want to apply a butter function on the dataset and show both graphs, incomplete and smoothened. The filter function seems to not work with incomplete data.



      Data File: data.csv



      import matplotlib.pyplot as plt
      import pandas as pd
      import numpy as np
      from scipy import signal

      data = np.genfromtxt('data.csv', delimiter = ',')
      df = pd.DataFrame(data)
      df.set_index(0, inplace = True)

      b, a = signal.butter(5, 0.1)
      y = signal.filtfilt(b,a, df[1].values)
      df2 = pd.DataFrame(y, index=df.index)

      df.plot()
      df2.plot()

      plt.show()


      enter image description hereenter image description here







      python pandas numpy matplotlib scipy






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 12 at 12:16









      Artur Müller Romanov

      373212




      373212






















          1 Answer
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          1














          The documentation page does not mention anything related to NaN. You may have to first remove the NaN from your list of values. Here is a way to do it using Numpy isnan function:



          y = signal.filtfilt(b, a, df[1].values[~np.isnan(df[1].values)])
          df2 = pd.DataFrame(y, index=df.index[~np.isnan(df[1].values)])





          share|improve this answer


















          • 1




            That might be a reasonable solution. But the filter functions in scipy.signal assume the data is sampled at regular intervals. If you discard the nan values, the sample periods of the remaining data are no longer consistent, and that may invalidate the filter results.
            – Warren Weckesser
            Nov 12 at 14:00










          • In this case one would have to first manually resample the data at a lower frequency to match the removal of NaN values ?
            – Patol75
            Nov 12 at 14:39










          Your Answer






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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          The documentation page does not mention anything related to NaN. You may have to first remove the NaN from your list of values. Here is a way to do it using Numpy isnan function:



          y = signal.filtfilt(b, a, df[1].values[~np.isnan(df[1].values)])
          df2 = pd.DataFrame(y, index=df.index[~np.isnan(df[1].values)])





          share|improve this answer


















          • 1




            That might be a reasonable solution. But the filter functions in scipy.signal assume the data is sampled at regular intervals. If you discard the nan values, the sample periods of the remaining data are no longer consistent, and that may invalidate the filter results.
            – Warren Weckesser
            Nov 12 at 14:00










          • In this case one would have to first manually resample the data at a lower frequency to match the removal of NaN values ?
            – Patol75
            Nov 12 at 14:39















          1














          The documentation page does not mention anything related to NaN. You may have to first remove the NaN from your list of values. Here is a way to do it using Numpy isnan function:



          y = signal.filtfilt(b, a, df[1].values[~np.isnan(df[1].values)])
          df2 = pd.DataFrame(y, index=df.index[~np.isnan(df[1].values)])





          share|improve this answer


















          • 1




            That might be a reasonable solution. But the filter functions in scipy.signal assume the data is sampled at regular intervals. If you discard the nan values, the sample periods of the remaining data are no longer consistent, and that may invalidate the filter results.
            – Warren Weckesser
            Nov 12 at 14:00










          • In this case one would have to first manually resample the data at a lower frequency to match the removal of NaN values ?
            – Patol75
            Nov 12 at 14:39













          1












          1








          1






          The documentation page does not mention anything related to NaN. You may have to first remove the NaN from your list of values. Here is a way to do it using Numpy isnan function:



          y = signal.filtfilt(b, a, df[1].values[~np.isnan(df[1].values)])
          df2 = pd.DataFrame(y, index=df.index[~np.isnan(df[1].values)])





          share|improve this answer














          The documentation page does not mention anything related to NaN. You may have to first remove the NaN from your list of values. Here is a way to do it using Numpy isnan function:



          y = signal.filtfilt(b, a, df[1].values[~np.isnan(df[1].values)])
          df2 = pd.DataFrame(y, index=df.index[~np.isnan(df[1].values)])






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 12 at 12:54

























          answered Nov 12 at 12:33









          Patol75

          6136




          6136







          • 1




            That might be a reasonable solution. But the filter functions in scipy.signal assume the data is sampled at regular intervals. If you discard the nan values, the sample periods of the remaining data are no longer consistent, and that may invalidate the filter results.
            – Warren Weckesser
            Nov 12 at 14:00










          • In this case one would have to first manually resample the data at a lower frequency to match the removal of NaN values ?
            – Patol75
            Nov 12 at 14:39












          • 1




            That might be a reasonable solution. But the filter functions in scipy.signal assume the data is sampled at regular intervals. If you discard the nan values, the sample periods of the remaining data are no longer consistent, and that may invalidate the filter results.
            – Warren Weckesser
            Nov 12 at 14:00










          • In this case one would have to first manually resample the data at a lower frequency to match the removal of NaN values ?
            – Patol75
            Nov 12 at 14:39







          1




          1




          That might be a reasonable solution. But the filter functions in scipy.signal assume the data is sampled at regular intervals. If you discard the nan values, the sample periods of the remaining data are no longer consistent, and that may invalidate the filter results.
          – Warren Weckesser
          Nov 12 at 14:00




          That might be a reasonable solution. But the filter functions in scipy.signal assume the data is sampled at regular intervals. If you discard the nan values, the sample periods of the remaining data are no longer consistent, and that may invalidate the filter results.
          – Warren Weckesser
          Nov 12 at 14:00












          In this case one would have to first manually resample the data at a lower frequency to match the removal of NaN values ?
          – Patol75
          Nov 12 at 14:39




          In this case one would have to first manually resample the data at a lower frequency to match the removal of NaN values ?
          – Patol75
          Nov 12 at 14:39

















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