pymongo - Search collection for documents that contain with $and operator case insensitive [duplicate]









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  • How to AND and NOT in MongoDB $text search

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I am trying to search a collection which contains documents, collection looking like this:



['description':'Fast and Dangerous',
'colour':'blue',
'make':'ford',
'description':'slow and dangerous',
'colour':'red',
'make':'lexus']


I am trying to build a search query that will return all the documents which contain Red and Dangerous (case insensitive)



I started off with:



find("$text": "$search": "red dangerous")


However, this is certainly case insensitive, but it is an OR rather than AND.



I have read through https://docs.mongodb.com/manual/reference/operator/query/and/#op._S_and - but it means you have to refer to specific fields which could contain Red or Dangerous, rather than the entire document. What's the best way to go about this? I want my code to be professional, and I feel whatever hack I come up with really won't be. Any pointers?










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marked as duplicate by Neil Lunn mongodb
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Nov 12 at 8:23


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • Use $meta aggregation with the $sort stage. Something like db.collection.aggregate( [ $match: $text: "$search": "red Dangerous" , $addFields: score: $meta: "textScore" , $sort: score: 1 ] ). The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.
    – Anthony Winzlet
    Nov 11 at 15:00










  • That's a really interesting answer. Certainly highlighted some features I wasn't aware of. I'll put it in. It feels like my request should have a definite answer though, as in all of the requirements of the search have been met
    – rlou
    Nov 11 at 15:45














up vote
0
down vote

favorite













This question already has an answer here:



  • How to AND and NOT in MongoDB $text search

    1 answer



I am trying to search a collection which contains documents, collection looking like this:



['description':'Fast and Dangerous',
'colour':'blue',
'make':'ford',
'description':'slow and dangerous',
'colour':'red',
'make':'lexus']


I am trying to build a search query that will return all the documents which contain Red and Dangerous (case insensitive)



I started off with:



find("$text": "$search": "red dangerous")


However, this is certainly case insensitive, but it is an OR rather than AND.



I have read through https://docs.mongodb.com/manual/reference/operator/query/and/#op._S_and - but it means you have to refer to specific fields which could contain Red or Dangerous, rather than the entire document. What's the best way to go about this? I want my code to be professional, and I feel whatever hack I come up with really won't be. Any pointers?










share|improve this question















marked as duplicate by Neil Lunn mongodb
Users with the  mongodb badge can single-handedly close mongodb questions as duplicates and reopen them as needed.

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Nov 12 at 8:23


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • Use $meta aggregation with the $sort stage. Something like db.collection.aggregate( [ $match: $text: "$search": "red Dangerous" , $addFields: score: $meta: "textScore" , $sort: score: 1 ] ). The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.
    – Anthony Winzlet
    Nov 11 at 15:00










  • That's a really interesting answer. Certainly highlighted some features I wasn't aware of. I'll put it in. It feels like my request should have a definite answer though, as in all of the requirements of the search have been met
    – rlou
    Nov 11 at 15:45












up vote
0
down vote

favorite









up vote
0
down vote

favorite












This question already has an answer here:



  • How to AND and NOT in MongoDB $text search

    1 answer



I am trying to search a collection which contains documents, collection looking like this:



['description':'Fast and Dangerous',
'colour':'blue',
'make':'ford',
'description':'slow and dangerous',
'colour':'red',
'make':'lexus']


I am trying to build a search query that will return all the documents which contain Red and Dangerous (case insensitive)



I started off with:



find("$text": "$search": "red dangerous")


However, this is certainly case insensitive, but it is an OR rather than AND.



I have read through https://docs.mongodb.com/manual/reference/operator/query/and/#op._S_and - but it means you have to refer to specific fields which could contain Red or Dangerous, rather than the entire document. What's the best way to go about this? I want my code to be professional, and I feel whatever hack I come up with really won't be. Any pointers?










share|improve this question
















This question already has an answer here:



  • How to AND and NOT in MongoDB $text search

    1 answer



I am trying to search a collection which contains documents, collection looking like this:



['description':'Fast and Dangerous',
'colour':'blue',
'make':'ford',
'description':'slow and dangerous',
'colour':'red',
'make':'lexus']


I am trying to build a search query that will return all the documents which contain Red and Dangerous (case insensitive)



I started off with:



find("$text": "$search": "red dangerous")


However, this is certainly case insensitive, but it is an OR rather than AND.



I have read through https://docs.mongodb.com/manual/reference/operator/query/and/#op._S_and - but it means you have to refer to specific fields which could contain Red or Dangerous, rather than the entire document. What's the best way to go about this? I want my code to be professional, and I feel whatever hack I come up with really won't be. Any pointers?





This question already has an answer here:



  • How to AND and NOT in MongoDB $text search

    1 answer







python python-3.x mongodb pymongo






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edited Nov 11 at 14:17

























asked Nov 11 at 14:01









rlou

485




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marked as duplicate by Neil Lunn mongodb
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Nov 12 at 8:23


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by Neil Lunn mongodb
Users with the  mongodb badge can single-handedly close mongodb questions as duplicates and reopen them as needed.

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Nov 12 at 8:23


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.













  • Use $meta aggregation with the $sort stage. Something like db.collection.aggregate( [ $match: $text: "$search": "red Dangerous" , $addFields: score: $meta: "textScore" , $sort: score: 1 ] ). The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.
    – Anthony Winzlet
    Nov 11 at 15:00










  • That's a really interesting answer. Certainly highlighted some features I wasn't aware of. I'll put it in. It feels like my request should have a definite answer though, as in all of the requirements of the search have been met
    – rlou
    Nov 11 at 15:45
















  • Use $meta aggregation with the $sort stage. Something like db.collection.aggregate( [ $match: $text: "$search": "red Dangerous" , $addFields: score: $meta: "textScore" , $sort: score: 1 ] ). The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.
    – Anthony Winzlet
    Nov 11 at 15:00










  • That's a really interesting answer. Certainly highlighted some features I wasn't aware of. I'll put it in. It feels like my request should have a definite answer though, as in all of the requirements of the search have been met
    – rlou
    Nov 11 at 15:45















Use $meta aggregation with the $sort stage. Something like db.collection.aggregate( [ $match: $text: "$search": "red Dangerous" , $addFields: score: $meta: "textScore" , $sort: score: 1 ] ). The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.
– Anthony Winzlet
Nov 11 at 15:00




Use $meta aggregation with the $sort stage. Something like db.collection.aggregate( [ $match: $text: "$search": "red Dangerous" , $addFields: score: $meta: "textScore" , $sort: score: 1 ] ). The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.
– Anthony Winzlet
Nov 11 at 15:00












That's a really interesting answer. Certainly highlighted some features I wasn't aware of. I'll put it in. It feels like my request should have a definite answer though, as in all of the requirements of the search have been met
– rlou
Nov 11 at 15:45




That's a really interesting answer. Certainly highlighted some features I wasn't aware of. I'll put it in. It feels like my request should have a definite answer though, as in all of the requirements of the search have been met
– rlou
Nov 11 at 15:45












1 Answer
1






active

oldest

votes

















up vote
0
down vote













You can use $meta aggregation with the $sort stage. Something like



db.collection.aggregate([
"$match": "$text": "$search": "red Dangerous" ,
"$addFields": "score": "$meta": "textScore" ,
"$sort": "score": 1
])


The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.






share|improve this answer



























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    You can use $meta aggregation with the $sort stage. Something like



    db.collection.aggregate([
    "$match": "$text": "$search": "red Dangerous" ,
    "$addFields": "score": "$meta": "textScore" ,
    "$sort": "score": 1
    ])


    The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.






    share|improve this answer
























      up vote
      0
      down vote













      You can use $meta aggregation with the $sort stage. Something like



      db.collection.aggregate([
      "$match": "$text": "$search": "red Dangerous" ,
      "$addFields": "score": "$meta": "textScore" ,
      "$sort": "score": 1
      ])


      The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.






      share|improve this answer






















        up vote
        0
        down vote










        up vote
        0
        down vote









        You can use $meta aggregation with the $sort stage. Something like



        db.collection.aggregate([
        "$match": "$text": "$search": "red Dangerous" ,
        "$addFields": "score": "$meta": "textScore" ,
        "$sort": "score": 1
        ])


        The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.






        share|improve this answer












        You can use $meta aggregation with the $sort stage. Something like



        db.collection.aggregate([
        "$match": "$text": "$search": "red Dangerous" ,
        "$addFields": "score": "$meta": "textScore" ,
        "$sort": "score": 1
        ])


        The text score signifies how well the document matched the search term or terms. So the best matched documents will always come on the top.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 11 at 16:52









        Anthony Winzlet

        12.2k41038




        12.2k41038













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