Null values in json Twitter Search API Php









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I try parse Search Twitter API results. ID,Nick name, status message etc. - with this all stuff are all ok. But when i try echo hastags or media url i catch null value but in in json i have a data.
My working code:
$twitter = new TwitterAPIExchange($settings);



$string = json_decode($twitter->setGetfield($getfield)
->buildOauth($url, $requestMethod)
->performRequest(),true);

foreach($string['statuses'] as $tweets) {
$time = $tweets['created_at'];
$id = $tweets['id'];
$source = $tweets['source'];
$tweet = $tweets['full_text'];
$name = $tweets['user']['name'];
$user = $tweets['user']['screen_name'];
$profile_image = $tweets['user']['profile_image_url'];
$followers = $tweets['user']['followers_count'];
$friends = $tweets['user']['friends_count'];
$listed = $tweets['user']['listed_count'];
$hashtag = $tweets['media']['media_url'];
echo "Time and Date of Tweet: " . $time ."<br />";
echo "ID of Tweet: " . $id . "<br />";
echo "Source of Tweet: " . $source . "<br />";
echo "Tweet: ". $tweet ."<br />";
echo "Tweeted by: ". $name ."<br />";
echo "Screen name: ". $user ."<br />";
echo "<a href="http://twitter.com/$user">@$user</a><br />";
echo "<img src="".$profile_image."" width="100px" height="100px" /><br />";
echo "Followers: ". $followers ."<br />";
echo "Friends: ". $friends ."<br />";
echo "Listed: ". $listed ."<br /><hr />";


here piace of json output (var_dump $string)



 string(46) "http://pbs.twimg.com/media/DrvSmRIWkAEDLMv.jpg"
["media_url_https"]=>
string(47) "https://pbs.twimg.com/media/DrvSmRIWkAEDLMv.jpg"
["url"]=>
string(23) "https://"
["display_url"]=>
string(26) "pic.twitter.com/r7nAHcjEpA"
["expanded_url"]=>
string(65) "https://twitter.com/KolaSokol1/status/1061673709738565634/photo/1"
["type"]=>
string(5) "photo"
["sizes"]=>


As i see i have data at media_url, but when i try



$hashtag = $tweets['media']['media_url'];
echo "hashtags: ". $hashtags ."<br /><hr />";


I get nothing.



Also when i try do



echo "<pre>";
echo var_dump($tweets['media']['media_url']);
echo "</pre>";


I get NULL.
I am really bad in php, please give me advise, what i'am missing? Thank you for advice.










share|improve this question





















  • Can you try $tweets['media'][0]['media_url']?
    – Nigel Ren
    Nov 11 at 21:52










  • I try but the same => NULL
    – Николай Соколовский
    Nov 11 at 22:15










  • Oh i get it. works fine if like this echo var_dump($tweets['entities']['media']['0']['media_url']);
    – Николай Соколовский
    Nov 12 at 22:23















up vote
0
down vote

favorite












I try parse Search Twitter API results. ID,Nick name, status message etc. - with this all stuff are all ok. But when i try echo hastags or media url i catch null value but in in json i have a data.
My working code:
$twitter = new TwitterAPIExchange($settings);



$string = json_decode($twitter->setGetfield($getfield)
->buildOauth($url, $requestMethod)
->performRequest(),true);

foreach($string['statuses'] as $tweets) {
$time = $tweets['created_at'];
$id = $tweets['id'];
$source = $tweets['source'];
$tweet = $tweets['full_text'];
$name = $tweets['user']['name'];
$user = $tweets['user']['screen_name'];
$profile_image = $tweets['user']['profile_image_url'];
$followers = $tweets['user']['followers_count'];
$friends = $tweets['user']['friends_count'];
$listed = $tweets['user']['listed_count'];
$hashtag = $tweets['media']['media_url'];
echo "Time and Date of Tweet: " . $time ."<br />";
echo "ID of Tweet: " . $id . "<br />";
echo "Source of Tweet: " . $source . "<br />";
echo "Tweet: ". $tweet ."<br />";
echo "Tweeted by: ". $name ."<br />";
echo "Screen name: ". $user ."<br />";
echo "<a href="http://twitter.com/$user">@$user</a><br />";
echo "<img src="".$profile_image."" width="100px" height="100px" /><br />";
echo "Followers: ". $followers ."<br />";
echo "Friends: ". $friends ."<br />";
echo "Listed: ". $listed ."<br /><hr />";


here piace of json output (var_dump $string)



 string(46) "http://pbs.twimg.com/media/DrvSmRIWkAEDLMv.jpg"
["media_url_https"]=>
string(47) "https://pbs.twimg.com/media/DrvSmRIWkAEDLMv.jpg"
["url"]=>
string(23) "https://"
["display_url"]=>
string(26) "pic.twitter.com/r7nAHcjEpA"
["expanded_url"]=>
string(65) "https://twitter.com/KolaSokol1/status/1061673709738565634/photo/1"
["type"]=>
string(5) "photo"
["sizes"]=>


As i see i have data at media_url, but when i try



$hashtag = $tweets['media']['media_url'];
echo "hashtags: ". $hashtags ."<br /><hr />";


I get nothing.



Also when i try do



echo "<pre>";
echo var_dump($tweets['media']['media_url']);
echo "</pre>";


I get NULL.
I am really bad in php, please give me advise, what i'am missing? Thank you for advice.










share|improve this question





















  • Can you try $tweets['media'][0]['media_url']?
    – Nigel Ren
    Nov 11 at 21:52










  • I try but the same => NULL
    – Николай Соколовский
    Nov 11 at 22:15










  • Oh i get it. works fine if like this echo var_dump($tweets['entities']['media']['0']['media_url']);
    – Николай Соколовский
    Nov 12 at 22:23













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I try parse Search Twitter API results. ID,Nick name, status message etc. - with this all stuff are all ok. But when i try echo hastags or media url i catch null value but in in json i have a data.
My working code:
$twitter = new TwitterAPIExchange($settings);



$string = json_decode($twitter->setGetfield($getfield)
->buildOauth($url, $requestMethod)
->performRequest(),true);

foreach($string['statuses'] as $tweets) {
$time = $tweets['created_at'];
$id = $tweets['id'];
$source = $tweets['source'];
$tweet = $tweets['full_text'];
$name = $tweets['user']['name'];
$user = $tweets['user']['screen_name'];
$profile_image = $tweets['user']['profile_image_url'];
$followers = $tweets['user']['followers_count'];
$friends = $tweets['user']['friends_count'];
$listed = $tweets['user']['listed_count'];
$hashtag = $tweets['media']['media_url'];
echo "Time and Date of Tweet: " . $time ."<br />";
echo "ID of Tweet: " . $id . "<br />";
echo "Source of Tweet: " . $source . "<br />";
echo "Tweet: ". $tweet ."<br />";
echo "Tweeted by: ". $name ."<br />";
echo "Screen name: ". $user ."<br />";
echo "<a href="http://twitter.com/$user">@$user</a><br />";
echo "<img src="".$profile_image."" width="100px" height="100px" /><br />";
echo "Followers: ". $followers ."<br />";
echo "Friends: ". $friends ."<br />";
echo "Listed: ". $listed ."<br /><hr />";


here piace of json output (var_dump $string)



 string(46) "http://pbs.twimg.com/media/DrvSmRIWkAEDLMv.jpg"
["media_url_https"]=>
string(47) "https://pbs.twimg.com/media/DrvSmRIWkAEDLMv.jpg"
["url"]=>
string(23) "https://"
["display_url"]=>
string(26) "pic.twitter.com/r7nAHcjEpA"
["expanded_url"]=>
string(65) "https://twitter.com/KolaSokol1/status/1061673709738565634/photo/1"
["type"]=>
string(5) "photo"
["sizes"]=>


As i see i have data at media_url, but when i try



$hashtag = $tweets['media']['media_url'];
echo "hashtags: ". $hashtags ."<br /><hr />";


I get nothing.



Also when i try do



echo "<pre>";
echo var_dump($tweets['media']['media_url']);
echo "</pre>";


I get NULL.
I am really bad in php, please give me advise, what i'am missing? Thank you for advice.










share|improve this question













I try parse Search Twitter API results. ID,Nick name, status message etc. - with this all stuff are all ok. But when i try echo hastags or media url i catch null value but in in json i have a data.
My working code:
$twitter = new TwitterAPIExchange($settings);



$string = json_decode($twitter->setGetfield($getfield)
->buildOauth($url, $requestMethod)
->performRequest(),true);

foreach($string['statuses'] as $tweets) {
$time = $tweets['created_at'];
$id = $tweets['id'];
$source = $tweets['source'];
$tweet = $tweets['full_text'];
$name = $tweets['user']['name'];
$user = $tweets['user']['screen_name'];
$profile_image = $tweets['user']['profile_image_url'];
$followers = $tweets['user']['followers_count'];
$friends = $tweets['user']['friends_count'];
$listed = $tweets['user']['listed_count'];
$hashtag = $tweets['media']['media_url'];
echo "Time and Date of Tweet: " . $time ."<br />";
echo "ID of Tweet: " . $id . "<br />";
echo "Source of Tweet: " . $source . "<br />";
echo "Tweet: ". $tweet ."<br />";
echo "Tweeted by: ". $name ."<br />";
echo "Screen name: ". $user ."<br />";
echo "<a href="http://twitter.com/$user">@$user</a><br />";
echo "<img src="".$profile_image."" width="100px" height="100px" /><br />";
echo "Followers: ". $followers ."<br />";
echo "Friends: ". $friends ."<br />";
echo "Listed: ". $listed ."<br /><hr />";


here piace of json output (var_dump $string)



 string(46) "http://pbs.twimg.com/media/DrvSmRIWkAEDLMv.jpg"
["media_url_https"]=>
string(47) "https://pbs.twimg.com/media/DrvSmRIWkAEDLMv.jpg"
["url"]=>
string(23) "https://"
["display_url"]=>
string(26) "pic.twitter.com/r7nAHcjEpA"
["expanded_url"]=>
string(65) "https://twitter.com/KolaSokol1/status/1061673709738565634/photo/1"
["type"]=>
string(5) "photo"
["sizes"]=>


As i see i have data at media_url, but when i try



$hashtag = $tweets['media']['media_url'];
echo "hashtags: ". $hashtags ."<br /><hr />";


I get nothing.



Also when i try do



echo "<pre>";
echo var_dump($tweets['media']['media_url']);
echo "</pre>";


I get NULL.
I am really bad in php, please give me advise, what i'am missing? Thank you for advice.







php json api twitter






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share|improve this question











share|improve this question




share|improve this question










asked Nov 11 at 21:08









Николай Соколовский

12




12











  • Can you try $tweets['media'][0]['media_url']?
    – Nigel Ren
    Nov 11 at 21:52










  • I try but the same => NULL
    – Николай Соколовский
    Nov 11 at 22:15










  • Oh i get it. works fine if like this echo var_dump($tweets['entities']['media']['0']['media_url']);
    – Николай Соколовский
    Nov 12 at 22:23

















  • Can you try $tweets['media'][0]['media_url']?
    – Nigel Ren
    Nov 11 at 21:52










  • I try but the same => NULL
    – Николай Соколовский
    Nov 11 at 22:15










  • Oh i get it. works fine if like this echo var_dump($tweets['entities']['media']['0']['media_url']);
    – Николай Соколовский
    Nov 12 at 22:23
















Can you try $tweets['media'][0]['media_url']?
– Nigel Ren
Nov 11 at 21:52




Can you try $tweets['media'][0]['media_url']?
– Nigel Ren
Nov 11 at 21:52












I try but the same => NULL
– Николай Соколовский
Nov 11 at 22:15




I try but the same => NULL
– Николай Соколовский
Nov 11 at 22:15












Oh i get it. works fine if like this echo var_dump($tweets['entities']['media']['0']['media_url']);
– Николай Соколовский
Nov 12 at 22:23





Oh i get it. works fine if like this echo var_dump($tweets['entities']['media']['0']['media_url']);
– Николай Соколовский
Nov 12 at 22:23













1 Answer
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up vote
0
down vote













Its work if do parse like this



 foreach ($string['statuses'] as $tweets) 
echo $tweets['entities']['hashtags']['0']['text']."<hr />";






share|improve this answer




















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    Its work if do parse like this



     foreach ($string['statuses'] as $tweets) 
    echo $tweets['entities']['hashtags']['0']['text']."<hr />";






    share|improve this answer
























      up vote
      0
      down vote













      Its work if do parse like this



       foreach ($string['statuses'] as $tweets) 
      echo $tweets['entities']['hashtags']['0']['text']."<hr />";






      share|improve this answer






















        up vote
        0
        down vote










        up vote
        0
        down vote









        Its work if do parse like this



         foreach ($string['statuses'] as $tweets) 
        echo $tweets['entities']['hashtags']['0']['text']."<hr />";






        share|improve this answer












        Its work if do parse like this



         foreach ($string['statuses'] as $tweets) 
        echo $tweets['entities']['hashtags']['0']['text']."<hr />";







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 at 22:28









        Николай Соколовский

        12




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