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I have a dictionaries inside a list like this:

sample_dict = [1: [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 
 [1, 2, 3, 4, 5], 
 [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]], 
 2: [[3, 4, 6, 7, 8, 9, 10, 11], [1, 2, 3, 6, 10], ]]

Now, I would like to check the key 1's first value in the list with key 2's first value.
something like this,

Compare Values (first value of list of lists of key 1)

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10] 

with (first value of list of lists of key 2)

[3, 4, 6, 7, 8, 9, 10, 11]

If they are a match I would like to append it to a new list matching_list, if not I would to append non-matching values into another list non_matching_list.

This is what I tried so far,

matching_list = 
non_matching_list = 

for each_dict in sample_dict:
 current_dict_values = 
 for key, value_list in each_dict.items():
 temp_dict_values = 

 for value in value_list:
 temp_dict_values.append(value)

 .... don't know how to keep track of key 1's first list of lists values.

I was thinking of creating a temporary list to keep track of key 1 list values, but I am stuck and not sure how to proceed.

My final output should be like this:

matching_list = [[3,4,6,7,8,9,10], [1,2,3], ]
non_matching_list = [[1,2,5,11],[4,5,6,10],[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]]

How can I achieve my output? Any ideas would be great.

This can be achieved by converting lists to sets to make operations like symmetric_difference() and intersection() for your non_matching_list and matching_list respectively.

Here is one of the solutions:

matching_list, non_matching_list = , 

for lists1, lists2 in zip(sample_dict[0].values(), sample_dict[1].values()):
 for l1, l2 in zip(lists1, lists2):
 matching_list.append(list(set(l1) & set(l2)))
 non_matching_list.append(list(set(l1).symmetric_difference(set(l2))))

Note that using set(l1) & set(l2) is same as set(l1).intersection(set(l2)), so basically it's an intersection operation here.

I'm also using builtin zip() function to aggregate elements from each of the iterables ( both lists ).