Trying to do a simple sed substitution but I'm confused about what needs to be escaped
I have this string: '$'nwnwnwnnn
And want to change it to: bitset<9>(0bnwnwnwnnn), '$',
I've looked at many similar questions for different shells using their methods but nothing has worked. I'm generally in zsh but I can use bash or another shell.
The general form I've been trying is this:
sed -E -i new s/('.')([nw]+)/ bitset<9>(0b2), 1,/g thing.txt
It should work for any character other than $ and any sequence of n or w.
I'm generally confused as to what I need to escape here. Some answers on this site said to escape the parenthesis in the first part of the substitution.
Am I using -i incorrectly?
regex shell sed
edited Nov 15 '18 at 0:07
Barmar
429k36253352
asked Nov 15 '18 at 0:05
alsozatchalsozatch
111
add a comment |
I have this string: '$'nwnwnwnnn
And want to change it to: bitset<9>(0bnwnwnwnnn), '$',
I've looked at many similar questions for different shells using their methods but nothing has worked. I'm generally in zsh but I can use bash or another shell.
The general form I've been trying is this:
sed -E -i new s/('.')([nw]+)/ bitset<9>(0b2), 1,/g thing.txt
It should work for any character other than $ and any sequence of n or w.
I'm generally confused as to what I need to escape here. Some answers on this site said to escape the parenthesis in the first part of the substitution.
Am I using -i incorrectly?
regex shell sed
edited Nov 15 '18 at 0:07
Barmar
429k36253352
asked Nov 15 '18 at 0:05
alsozatchalsozatch
111
add a comment |
I have this string: '$'nwnwnwnnn
And want to change it to: bitset<9>(0bnwnwnwnnn), '$',
I've looked at many similar questions for different shells using their methods but nothing has worked. I'm generally in zsh but I can use bash or another shell.
The general form I've been trying is this:
sed -E -i new s/('.')([nw]+)/ bitset<9>(0b2), 1,/g thing.txt
It should work for any character other than $ and any sequence of n or w.
I'm generally confused as to what I need to escape here. Some answers on this site said to escape the parenthesis in the first part of the substitution.
Am I using -i incorrectly?
regex shell sed
edited Nov 15 '18 at 0:07
Barmar
429k36253352
asked Nov 15 '18 at 0:05
alsozatchalsozatch
111
I have this string: '$'nwnwnwnnn
And want to change it to: bitset<9>(0bnwnwnwnnn), '$',
I've looked at many similar questions for different shells using their methods but nothing has worked. I'm generally in zsh but I can use bash or another shell.
The general form I've been trying is this:
sed -E -i new s/('.')([nw]+)/ bitset<9>(0b2), 1,/g thing.txt
It should work for any character other than $ and any sequence of n or w.
I'm generally confused as to what I need to escape here. Some answers on this site said to escape the parenthesis in the first part of the substitution.
Am I using -i incorrectly?
regex shell sed
regex shell sed
edited Nov 15 '18 at 0:07
Barmar
429k36253352
asked Nov 15 '18 at 0:05
alsozatchalsozatch
111
edited Nov 15 '18 at 0:07
Barmar
429k36253352
asked Nov 15 '18 at 0:05
alsozatchalsozatch
111
edited Nov 15 '18 at 0:07
Barmar
429k36253352
edited Nov 15 '18 at 0:07
Barmar
429k36253352
edited Nov 15 '18 at 0:07
Barmar
429k36253352
429k36253352
asked Nov 15 '18 at 0:05
alsozatchalsozatch
111
asked Nov 15 '18 at 0:05
alsozatchalsozatch
111
asked Nov 15 '18 at 0:05
alsozatchalsozatch
111
111
add a comment |
add a comment |
1 Answer
1
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oldest
votes
You need to escape the parentheses to create a capture group if you're using basic regexp, you don't escape them if you're using extended regexp. The -E option to GNU sed, and the -r option to standard sed, enable extended regexp, so you don't need to escape them.
If you only want to match $ rather than allow any character in the quotes, you need an escaped $.
You need to put the entire s/// command inside quotes, as it must be a single argument to the sed command.
When using -i, it's conventional to put a . before the suffix. Also, the suffix is put on the saved copy of the original file, not the new file that you're creating with the changes, so new is a poor suffix.
sed -E -i .bak "s/('$')([nw]+)/ bitset<9>(0b2), 1,/g" thing.txt
answered Nov 15 '18 at 0:13
BarmarBarmar
429k36253352
This worked for me but only when I used double quotes instead of single quotes around the regex command and stopped escaping the single quotes. Thanks
– alsozatch
Nov 15 '18 at 0:24
I always forget which shell quotes allow escaping quotes inside them :)
– Barmar
Nov 15 '18 at 0:26
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You need to escape the parentheses to create a capture group if you're using basic regexp, you don't escape them if you're using extended regexp. The -E option to GNU sed, and the -r option to standard sed, enable extended regexp, so you don't need to escape them.
If you only want to match $ rather than allow any character in the quotes, you need an escaped $.
You need to put the entire s/// command inside quotes, as it must be a single argument to the sed command.
When using -i, it's conventional to put a . before the suffix. Also, the suffix is put on the saved copy of the original file, not the new file that you're creating with the changes, so new is a poor suffix.
sed -E -i .bak "s/('$')([nw]+)/ bitset<9>(0b2), 1,/g" thing.txt
answered Nov 15 '18 at 0:13
BarmarBarmar
429k36253352
This worked for me but only when I used double quotes instead of single quotes around the regex command and stopped escaping the single quotes. Thanks
– alsozatch
Nov 15 '18 at 0:24
I always forget which shell quotes allow escaping quotes inside them :)
– Barmar
Nov 15 '18 at 0:26
add a comment |
You need to escape the parentheses to create a capture group if you're using basic regexp, you don't escape them if you're using extended regexp. The -E option to GNU sed, and the -r option to standard sed, enable extended regexp, so you don't need to escape them.
If you only want to match $ rather than allow any character in the quotes, you need an escaped $.
You need to put the entire s/// command inside quotes, as it must be a single argument to the sed command.
When using -i, it's conventional to put a . before the suffix. Also, the suffix is put on the saved copy of the original file, not the new file that you're creating with the changes, so new is a poor suffix.
sed -E -i .bak "s/('$')([nw]+)/ bitset<9>(0b2), 1,/g" thing.txt
answered Nov 15 '18 at 0:13
BarmarBarmar
429k36253352
This worked for me but only when I used double quotes instead of single quotes around the regex command and stopped escaping the single quotes. Thanks
– alsozatch
Nov 15 '18 at 0:24
I always forget which shell quotes allow escaping quotes inside them :)
– Barmar
Nov 15 '18 at 0:26
add a comment |
You need to escape the parentheses to create a capture group if you're using basic regexp, you don't escape them if you're using extended regexp. The -E option to GNU sed, and the -r option to standard sed, enable extended regexp, so you don't need to escape them.
If you only want to match $ rather than allow any character in the quotes, you need an escaped $.
You need to put the entire s/// command inside quotes, as it must be a single argument to the sed command.
When using -i, it's conventional to put a . before the suffix. Also, the suffix is put on the saved copy of the original file, not the new file that you're creating with the changes, so new is a poor suffix.
sed -E -i .bak "s/('$')([nw]+)/ bitset<9>(0b2), 1,/g" thing.txt
answered Nov 15 '18 at 0:13
BarmarBarmar
429k36253352
You need to escape the parentheses to create a capture group if you're using basic regexp, you don't escape them if you're using extended regexp. The -E option to GNU sed, and the -r option to standard sed, enable extended regexp, so you don't need to escape them.
If you only want to match $ rather than allow any character in the quotes, you need an escaped $.
You need to put the entire s/// command inside quotes, as it must be a single argument to the sed command.
When using -i, it's conventional to put a . before the suffix. Also, the suffix is put on the saved copy of the original file, not the new file that you're creating with the changes, so new is a poor suffix.
sed -E -i .bak "s/('$')([nw]+)/ bitset<9>(0b2), 1,/g" thing.txt
answered Nov 15 '18 at 0:13
BarmarBarmar
429k36253352
edited Nov 15 '18 at 0:25
answered Nov 15 '18 at 0:13
BarmarBarmar
429k36253352
answered Nov 15 '18 at 0:13
BarmarBarmar
429k36253352
answered Nov 15 '18 at 0:13
BarmarBarmar
429k36253352
429k36253352
This worked for me but only when I used double quotes instead of single quotes around the regex command and stopped escaping the single quotes. Thanks
– alsozatch
Nov 15 '18 at 0:24
I always forget which shell quotes allow escaping quotes inside them :)
– Barmar
Nov 15 '18 at 0:26
add a comment |
This worked for me but only when I used double quotes instead of single quotes around the regex command and stopped escaping the single quotes. Thanks
– alsozatch
Nov 15 '18 at 0:24
I always forget which shell quotes allow escaping quotes inside them :)
– Barmar
Nov 15 '18 at 0:26
This worked for me but only when I used double quotes instead of single quotes around the regex command and stopped escaping the single quotes. Thanks
– alsozatch
Nov 15 '18 at 0:24
This worked for me but only when I used double quotes instead of single quotes around the regex command and stopped escaping the single quotes. Thanks
– alsozatch
Nov 15 '18 at 0:24
I always forget which shell quotes allow escaping quotes inside them :)
– Barmar
Nov 15 '18 at 0:26
I always forget which shell quotes allow escaping quotes inside them :)
– Barmar
Nov 15 '18 at 0:26
add a comment |
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