Type casting in OpenCL APIs (void *)&c_mem_obj
I have encountered a strange syntax inside armaments list of OpenCL host-code. However, I do not have any problem with my hostcode functionality but it is strange for me what does it mean at all and why it pass the arguments in this way.
clSetKernelArg(kernel, 0, sizeof(cl_mem), (void *)&c_mem_obj);
To the best of my knowledge, it is type cast. am i wrong ?
i believe it does not have any special purpose since the clSetKernelArg API already accept only pointer.
It is really helpful to have a more technical explanation.
thanks,
jimbo
opencl
asked Nov 14 '18 at 20:30
Mehdi Roozmeh mehdjimboMehdi Roozmeh mehdjimbo
1
add a comment |
I have encountered a strange syntax inside armaments list of OpenCL host-code. However, I do not have any problem with my hostcode functionality but it is strange for me what does it mean at all and why it pass the arguments in this way.
clSetKernelArg(kernel, 0, sizeof(cl_mem), (void *)&c_mem_obj);
To the best of my knowledge, it is type cast. am i wrong ?
i believe it does not have any special purpose since the clSetKernelArg API already accept only pointer.
It is really helpful to have a more technical explanation.
thanks,
jimbo
opencl
asked Nov 14 '18 at 20:30
Mehdi Roozmeh mehdjimboMehdi Roozmeh mehdjimbo
1
add a comment |
I have encountered a strange syntax inside armaments list of OpenCL host-code. However, I do not have any problem with my hostcode functionality but it is strange for me what does it mean at all and why it pass the arguments in this way.
clSetKernelArg(kernel, 0, sizeof(cl_mem), (void *)&c_mem_obj);
To the best of my knowledge, it is type cast. am i wrong ?
i believe it does not have any special purpose since the clSetKernelArg API already accept only pointer.
It is really helpful to have a more technical explanation.
thanks,
jimbo
opencl
asked Nov 14 '18 at 20:30
Mehdi Roozmeh mehdjimboMehdi Roozmeh mehdjimbo
1
I have encountered a strange syntax inside armaments list of OpenCL host-code. However, I do not have any problem with my hostcode functionality but it is strange for me what does it mean at all and why it pass the arguments in this way.
clSetKernelArg(kernel, 0, sizeof(cl_mem), (void *)&c_mem_obj);
To the best of my knowledge, it is type cast. am i wrong ?
i believe it does not have any special purpose since the clSetKernelArg API already accept only pointer.
It is really helpful to have a more technical explanation.
thanks,
jimbo
opencl
opencl
asked Nov 14 '18 at 20:30
Mehdi Roozmeh mehdjimboMehdi Roozmeh mehdjimbo
1
asked Nov 14 '18 at 20:30
Mehdi Roozmeh mehdjimboMehdi Roozmeh mehdjimbo
1
asked Nov 14 '18 at 20:30
Mehdi Roozmeh mehdjimboMehdi Roozmeh mehdjimbo
1
asked Nov 14 '18 at 20:30
Mehdi Roozmeh mehdjimboMehdi Roozmeh mehdjimbo
1
asked Nov 14 '18 at 20:30
Mehdi Roozmeh mehdjimboMehdi Roozmeh mehdjimbo
1
1
add a comment |
add a comment |
1 Answer
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You are right, it is a type cast. It is taking the address of your cl_mem object (which is type cl_mem *) and casting it to type void * (and since clSetKernelArg takes a const void * it's not even the best cast).
It is not required. You could also just write clSetKernelArg(kernel, 0, sizeof(cl_mem), &c_mem_obj) and it should compile (it does for our code, on Windows, Mac, and Linux).
answered Nov 15 '18 at 0:06
DithermasterDithermaster
5,5241817
Thanks!!! Yes you are right. it works without cast. I did not understood why they used this kind of syntax and since it was from NVIDIA benchmark it become more interesting for me.
– Mehdi Roozmeh mehdjimbo
Nov 15 '18 at 13:19
add a comment |
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1 Answer
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1 Answer
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You are right, it is a type cast. It is taking the address of your cl_mem object (which is type cl_mem *) and casting it to type void * (and since clSetKernelArg takes a const void * it's not even the best cast).
It is not required. You could also just write clSetKernelArg(kernel, 0, sizeof(cl_mem), &c_mem_obj) and it should compile (it does for our code, on Windows, Mac, and Linux).
answered Nov 15 '18 at 0:06
DithermasterDithermaster
5,5241817
Thanks!!! Yes you are right. it works without cast. I did not understood why they used this kind of syntax and since it was from NVIDIA benchmark it become more interesting for me.
– Mehdi Roozmeh mehdjimbo
Nov 15 '18 at 13:19
add a comment |
You are right, it is a type cast. It is taking the address of your cl_mem object (which is type cl_mem *) and casting it to type void * (and since clSetKernelArg takes a const void * it's not even the best cast).
It is not required. You could also just write clSetKernelArg(kernel, 0, sizeof(cl_mem), &c_mem_obj) and it should compile (it does for our code, on Windows, Mac, and Linux).
answered Nov 15 '18 at 0:06
DithermasterDithermaster
5,5241817
Thanks!!! Yes you are right. it works without cast. I did not understood why they used this kind of syntax and since it was from NVIDIA benchmark it become more interesting for me.
– Mehdi Roozmeh mehdjimbo
Nov 15 '18 at 13:19
add a comment |
You are right, it is a type cast. It is taking the address of your cl_mem object (which is type cl_mem *) and casting it to type void * (and since clSetKernelArg takes a const void * it's not even the best cast).
It is not required. You could also just write clSetKernelArg(kernel, 0, sizeof(cl_mem), &c_mem_obj) and it should compile (it does for our code, on Windows, Mac, and Linux).
answered Nov 15 '18 at 0:06
DithermasterDithermaster
5,5241817
You are right, it is a type cast. It is taking the address of your cl_mem object (which is type cl_mem *) and casting it to type void * (and since clSetKernelArg takes a const void * it's not even the best cast).
It is not required. You could also just write clSetKernelArg(kernel, 0, sizeof(cl_mem), &c_mem_obj) and it should compile (it does for our code, on Windows, Mac, and Linux).
answered Nov 15 '18 at 0:06
DithermasterDithermaster
5,5241817
answered Nov 15 '18 at 0:06
DithermasterDithermaster
5,5241817
answered Nov 15 '18 at 0:06
DithermasterDithermaster
5,5241817
answered Nov 15 '18 at 0:06
DithermasterDithermaster
5,5241817
5,5241817
Thanks!!! Yes you are right. it works without cast. I did not understood why they used this kind of syntax and since it was from NVIDIA benchmark it become more interesting for me.
– Mehdi Roozmeh mehdjimbo
Nov 15 '18 at 13:19
add a comment |
Thanks!!! Yes you are right. it works without cast. I did not understood why they used this kind of syntax and since it was from NVIDIA benchmark it become more interesting for me.
– Mehdi Roozmeh mehdjimbo
Nov 15 '18 at 13:19
Thanks!!! Yes you are right. it works without cast. I did not understood why they used this kind of syntax and since it was from NVIDIA benchmark it become more interesting for me.
– Mehdi Roozmeh mehdjimbo
Nov 15 '18 at 13:19
Thanks!!! Yes you are right. it works without cast. I did not understood why they used this kind of syntax and since it was from NVIDIA benchmark it become more interesting for me.
– Mehdi Roozmeh mehdjimbo
Nov 15 '18 at 13:19
add a comment |
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