How to know if a module is being compiled through worker-loader










0















My aim is to use the new DefinePlugin.runtimeValue() feature to conditionally define 'typeof window' to 'undefined' in the worker and 'object' outside the worker (web target)



currently, my unsatisfying code is:



new webpack.DefinePlugin(
'typeof window': webpack.DefinePlugin.runtimeValue(function( module )

const isWorker = module.nameForCondition && /.worker./.test(module.nameForCondition());
return JSON.stringify(isWorker ? 'undefined' : 'object');
)
),


and I wondering if I can detect worker-loader through the module object.










share|improve this question


























    0















    My aim is to use the new DefinePlugin.runtimeValue() feature to conditionally define 'typeof window' to 'undefined' in the worker and 'object' outside the worker (web target)



    currently, my unsatisfying code is:



    new webpack.DefinePlugin(
    'typeof window': webpack.DefinePlugin.runtimeValue(function( module )

    const isWorker = module.nameForCondition && /.worker./.test(module.nameForCondition());
    return JSON.stringify(isWorker ? 'undefined' : 'object');
    )
    ),


    and I wondering if I can detect worker-loader through the module object.










    share|improve this question
























      0












      0








      0








      My aim is to use the new DefinePlugin.runtimeValue() feature to conditionally define 'typeof window' to 'undefined' in the worker and 'object' outside the worker (web target)



      currently, my unsatisfying code is:



      new webpack.DefinePlugin(
      'typeof window': webpack.DefinePlugin.runtimeValue(function( module )

      const isWorker = module.nameForCondition && /.worker./.test(module.nameForCondition());
      return JSON.stringify(isWorker ? 'undefined' : 'object');
      )
      ),


      and I wondering if I can detect worker-loader through the module object.










      share|improve this question














      My aim is to use the new DefinePlugin.runtimeValue() feature to conditionally define 'typeof window' to 'undefined' in the worker and 'object' outside the worker (web target)



      currently, my unsatisfying code is:



      new webpack.DefinePlugin(
      'typeof window': webpack.DefinePlugin.runtimeValue(function( module )

      const isWorker = module.nameForCondition && /.worker./.test(module.nameForCondition());
      return JSON.stringify(isWorker ? 'undefined' : 'object');
      )
      ),


      and I wondering if I can detect worker-loader through the module object.







      webpack worker-loader






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 15 '18 at 9:11









      Franck FreiburgerFranck Freiburger

      8,819165174




      8,819165174






















          1 Answer
          1






          active

          oldest

          votes


















          0














          sorry for the noise, I found the answer by myself:



          const isWorker = module.parser.state.compilation.compiler.name === 'worker';





          share|improve this answer






















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            1 Answer
            1






            active

            oldest

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            sorry for the noise, I found the answer by myself:



            const isWorker = module.parser.state.compilation.compiler.name === 'worker';





            share|improve this answer



























              0














              sorry for the noise, I found the answer by myself:



              const isWorker = module.parser.state.compilation.compiler.name === 'worker';





              share|improve this answer

























                0












                0








                0







                sorry for the noise, I found the answer by myself:



                const isWorker = module.parser.state.compilation.compiler.name === 'worker';





                share|improve this answer













                sorry for the noise, I found the answer by myself:



                const isWorker = module.parser.state.compilation.compiler.name === 'worker';






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 15 '18 at 9:20









                Franck FreiburgerFranck Freiburger

                8,819165174




                8,819165174





























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