combining split functions and count occurrences in python










1















I create a list with:



import os
files=[f for f in os.listdir(source) if f.endswith('.tif')]


sometimes this gives a result like:



files=['file_1263_1-001.tif', 'file_1263_2-002.tif', 'file_1263_3-003.tif']

for f in files:
l1 = f.split("_")
print( l1[2].split("-") )


returns:



['1', '001.tif']
['2', '002.tif']
['3', '003.tif']


but sometimes I get this result:



files=['file_0563_74-001.tif', 'file_0563_74-002.tif', 'file_0563_74-003.tif']

for f in files:
l1 = f.split("_")
print( l1[2].split("-") )


returns:



['74', '001.tif']
['74', '002.tif']
['74', '003.tif']


I would like to create a flow control that if the first column (e.a. 74) has the same values, do someting else than when it contains different values (e.a. 1, 2, 3).

How do I accomplish that?










share|improve this question
























  • By using an if statement?

    – SilverSlash
    Nov 15 '18 at 9:18











  • I guess if is the best to do so

    – Rene
    Nov 15 '18 at 10:05















1















I create a list with:



import os
files=[f for f in os.listdir(source) if f.endswith('.tif')]


sometimes this gives a result like:



files=['file_1263_1-001.tif', 'file_1263_2-002.tif', 'file_1263_3-003.tif']

for f in files:
l1 = f.split("_")
print( l1[2].split("-") )


returns:



['1', '001.tif']
['2', '002.tif']
['3', '003.tif']


but sometimes I get this result:



files=['file_0563_74-001.tif', 'file_0563_74-002.tif', 'file_0563_74-003.tif']

for f in files:
l1 = f.split("_")
print( l1[2].split("-") )


returns:



['74', '001.tif']
['74', '002.tif']
['74', '003.tif']


I would like to create a flow control that if the first column (e.a. 74) has the same values, do someting else than when it contains different values (e.a. 1, 2, 3).

How do I accomplish that?










share|improve this question
























  • By using an if statement?

    – SilverSlash
    Nov 15 '18 at 9:18











  • I guess if is the best to do so

    – Rene
    Nov 15 '18 at 10:05













1












1








1








I create a list with:



import os
files=[f for f in os.listdir(source) if f.endswith('.tif')]


sometimes this gives a result like:



files=['file_1263_1-001.tif', 'file_1263_2-002.tif', 'file_1263_3-003.tif']

for f in files:
l1 = f.split("_")
print( l1[2].split("-") )


returns:



['1', '001.tif']
['2', '002.tif']
['3', '003.tif']


but sometimes I get this result:



files=['file_0563_74-001.tif', 'file_0563_74-002.tif', 'file_0563_74-003.tif']

for f in files:
l1 = f.split("_")
print( l1[2].split("-") )


returns:



['74', '001.tif']
['74', '002.tif']
['74', '003.tif']


I would like to create a flow control that if the first column (e.a. 74) has the same values, do someting else than when it contains different values (e.a. 1, 2, 3).

How do I accomplish that?










share|improve this question
















I create a list with:



import os
files=[f for f in os.listdir(source) if f.endswith('.tif')]


sometimes this gives a result like:



files=['file_1263_1-001.tif', 'file_1263_2-002.tif', 'file_1263_3-003.tif']

for f in files:
l1 = f.split("_")
print( l1[2].split("-") )


returns:



['1', '001.tif']
['2', '002.tif']
['3', '003.tif']


but sometimes I get this result:



files=['file_0563_74-001.tif', 'file_0563_74-002.tif', 'file_0563_74-003.tif']

for f in files:
l1 = f.split("_")
print( l1[2].split("-") )


returns:



['74', '001.tif']
['74', '002.tif']
['74', '003.tif']


I would like to create a flow control that if the first column (e.a. 74) has the same values, do someting else than when it contains different values (e.a. 1, 2, 3).

How do I accomplish that?







python string list split






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share|improve this question








edited Nov 15 '18 at 9:19









jpp

102k2164115




102k2164115










asked Nov 15 '18 at 9:14









ReneRene

627




627












  • By using an if statement?

    – SilverSlash
    Nov 15 '18 at 9:18











  • I guess if is the best to do so

    – Rene
    Nov 15 '18 at 10:05

















  • By using an if statement?

    – SilverSlash
    Nov 15 '18 at 9:18











  • I guess if is the best to do so

    – Rene
    Nov 15 '18 at 10:05
















By using an if statement?

– SilverSlash
Nov 15 '18 at 9:18





By using an if statement?

– SilverSlash
Nov 15 '18 at 9:18













I guess if is the best to do so

– Rene
Nov 15 '18 at 10:05





I guess if is the best to do so

– Rene
Nov 15 '18 at 10:05












2 Answers
2






active

oldest

votes


















0














You can use a set comprehension to extract unique types. Then use an if / else construct to apply logic depending on whether you have only one such type.



files = ['file_1263_1-001.tif', 'file_1263_2-002.tif', 'file_1263_3-003.tif']

file_types = fn.split('-')[0].rsplit('_')[-1] for fn in files

if len(file_types) == 1:
# do something
else:
# do something else





share|improve this answer
































    0














    Do in this way:



    files = [f.split('_')[2].split('-') for f in files]
    files
    Output: [['1', '001.tif'], ['2', '002.tif'], ['3', '003.tif']]


    Check if all first elements are same. If same then length of unique elements will be 1



    if len(set([x[1] for x in files])) == 1: # checks first elements are same
    # do something
    else:
    # do something





    share|improve this answer






















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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

      votes









      active

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      active

      oldest

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      0














      You can use a set comprehension to extract unique types. Then use an if / else construct to apply logic depending on whether you have only one such type.



      files = ['file_1263_1-001.tif', 'file_1263_2-002.tif', 'file_1263_3-003.tif']

      file_types = fn.split('-')[0].rsplit('_')[-1] for fn in files

      if len(file_types) == 1:
      # do something
      else:
      # do something else





      share|improve this answer





























        0














        You can use a set comprehension to extract unique types. Then use an if / else construct to apply logic depending on whether you have only one such type.



        files = ['file_1263_1-001.tif', 'file_1263_2-002.tif', 'file_1263_3-003.tif']

        file_types = fn.split('-')[0].rsplit('_')[-1] for fn in files

        if len(file_types) == 1:
        # do something
        else:
        # do something else





        share|improve this answer



























          0












          0








          0







          You can use a set comprehension to extract unique types. Then use an if / else construct to apply logic depending on whether you have only one such type.



          files = ['file_1263_1-001.tif', 'file_1263_2-002.tif', 'file_1263_3-003.tif']

          file_types = fn.split('-')[0].rsplit('_')[-1] for fn in files

          if len(file_types) == 1:
          # do something
          else:
          # do something else





          share|improve this answer















          You can use a set comprehension to extract unique types. Then use an if / else construct to apply logic depending on whether you have only one such type.



          files = ['file_1263_1-001.tif', 'file_1263_2-002.tif', 'file_1263_3-003.tif']

          file_types = fn.split('-')[0].rsplit('_')[-1] for fn in files

          if len(file_types) == 1:
          # do something
          else:
          # do something else






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 15 '18 at 13:44

























          answered Nov 15 '18 at 9:18









          jppjpp

          102k2164115




          102k2164115























              0














              Do in this way:



              files = [f.split('_')[2].split('-') for f in files]
              files
              Output: [['1', '001.tif'], ['2', '002.tif'], ['3', '003.tif']]


              Check if all first elements are same. If same then length of unique elements will be 1



              if len(set([x[1] for x in files])) == 1: # checks first elements are same
              # do something
              else:
              # do something





              share|improve this answer



























                0














                Do in this way:



                files = [f.split('_')[2].split('-') for f in files]
                files
                Output: [['1', '001.tif'], ['2', '002.tif'], ['3', '003.tif']]


                Check if all first elements are same. If same then length of unique elements will be 1



                if len(set([x[1] for x in files])) == 1: # checks first elements are same
                # do something
                else:
                # do something





                share|improve this answer

























                  0












                  0








                  0







                  Do in this way:



                  files = [f.split('_')[2].split('-') for f in files]
                  files
                  Output: [['1', '001.tif'], ['2', '002.tif'], ['3', '003.tif']]


                  Check if all first elements are same. If same then length of unique elements will be 1



                  if len(set([x[1] for x in files])) == 1: # checks first elements are same
                  # do something
                  else:
                  # do something





                  share|improve this answer













                  Do in this way:



                  files = [f.split('_')[2].split('-') for f in files]
                  files
                  Output: [['1', '001.tif'], ['2', '002.tif'], ['3', '003.tif']]


                  Check if all first elements are same. If same then length of unique elements will be 1



                  if len(set([x[1] for x in files])) == 1: # checks first elements are same
                  # do something
                  else:
                  # do something






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 15 '18 at 10:13









                  Abdul QuddusAbdul Quddus

                  317




                  317



























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