How to write kernelized version of Pearson Correlation without any inbuilt function?










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I want to compute kernelized version of Pearson correlation, so I have to write the code instead of using the corrcoef command, according to formula I have to write the cov and std separately, I used dot product trick for cov and when I am using it for std the result is not true (this trick)



Actually I font know exactly how to input kernel (for example Gaussian in std )



for i=1:p;
one_vector(1:size(Signalsi,1,1)) = 1;
mu = (one_vector * Signalsi,1) / size(Signalsi,1,1);
A_mean_subtract = Signalsi,1 - mu(one_vector, :);
for j=1:116
u=(A_mean_subtract(:,j));
for z=1:116;
v=(A_mean_subtract(:,z));
r=sqrt(sum((u-v).^2)); ---- cov in Gaussian form ( instead of u'*v) I put u and v in gaussian kernel formula
gamma=1/(2*100^2);
k=exp(-gamma*(r^2));
covB(j,z) = k / (size(Signalsi,1,1) - 1);---- it is correct
K_R(j,z)= covB(j,z)/sqrt((u'*u)*(v'*v);---- I know that I have to kernelized this part like above but before that the result is not correct in sipmle form (not kernelized) let alone kernel form
end
end









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    0















    I want to compute kernelized version of Pearson correlation, so I have to write the code instead of using the corrcoef command, according to formula I have to write the cov and std separately, I used dot product trick for cov and when I am using it for std the result is not true (this trick)



    Actually I font know exactly how to input kernel (for example Gaussian in std )



    for i=1:p;
    one_vector(1:size(Signalsi,1,1)) = 1;
    mu = (one_vector * Signalsi,1) / size(Signalsi,1,1);
    A_mean_subtract = Signalsi,1 - mu(one_vector, :);
    for j=1:116
    u=(A_mean_subtract(:,j));
    for z=1:116;
    v=(A_mean_subtract(:,z));
    r=sqrt(sum((u-v).^2)); ---- cov in Gaussian form ( instead of u'*v) I put u and v in gaussian kernel formula
    gamma=1/(2*100^2);
    k=exp(-gamma*(r^2));
    covB(j,z) = k / (size(Signalsi,1,1) - 1);---- it is correct
    K_R(j,z)= covB(j,z)/sqrt((u'*u)*(v'*v);---- I know that I have to kernelized this part like above but before that the result is not correct in sipmle form (not kernelized) let alone kernel form
    end
    end









    share|improve this question


























      0












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      0








      I want to compute kernelized version of Pearson correlation, so I have to write the code instead of using the corrcoef command, according to formula I have to write the cov and std separately, I used dot product trick for cov and when I am using it for std the result is not true (this trick)



      Actually I font know exactly how to input kernel (for example Gaussian in std )



      for i=1:p;
      one_vector(1:size(Signalsi,1,1)) = 1;
      mu = (one_vector * Signalsi,1) / size(Signalsi,1,1);
      A_mean_subtract = Signalsi,1 - mu(one_vector, :);
      for j=1:116
      u=(A_mean_subtract(:,j));
      for z=1:116;
      v=(A_mean_subtract(:,z));
      r=sqrt(sum((u-v).^2)); ---- cov in Gaussian form ( instead of u'*v) I put u and v in gaussian kernel formula
      gamma=1/(2*100^2);
      k=exp(-gamma*(r^2));
      covB(j,z) = k / (size(Signalsi,1,1) - 1);---- it is correct
      K_R(j,z)= covB(j,z)/sqrt((u'*u)*(v'*v);---- I know that I have to kernelized this part like above but before that the result is not correct in sipmle form (not kernelized) let alone kernel form
      end
      end









      share|improve this question
















      I want to compute kernelized version of Pearson correlation, so I have to write the code instead of using the corrcoef command, according to formula I have to write the cov and std separately, I used dot product trick for cov and when I am using it for std the result is not true (this trick)



      Actually I font know exactly how to input kernel (for example Gaussian in std )



      for i=1:p;
      one_vector(1:size(Signalsi,1,1)) = 1;
      mu = (one_vector * Signalsi,1) / size(Signalsi,1,1);
      A_mean_subtract = Signalsi,1 - mu(one_vector, :);
      for j=1:116
      u=(A_mean_subtract(:,j));
      for z=1:116;
      v=(A_mean_subtract(:,z));
      r=sqrt(sum((u-v).^2)); ---- cov in Gaussian form ( instead of u'*v) I put u and v in gaussian kernel formula
      gamma=1/(2*100^2);
      k=exp(-gamma*(r^2));
      covB(j,z) = k / (size(Signalsi,1,1) - 1);---- it is correct
      K_R(j,z)= covB(j,z)/sqrt((u'*u)*(v'*v);---- I know that I have to kernelized this part like above but before that the result is not correct in sipmle form (not kernelized) let alone kernel form
      end
      end






      kernel correlation






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      edited Nov 15 '18 at 9:11









      Sagar Zala

      2,38441337




      2,38441337










      asked Nov 15 '18 at 8:27









      Hessam AhmadiHessam Ahmadi

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