validate google docs and office 365 url

I am using regex for validating if the provided url is valid or not. To test validity(either google docs url or office 365 docs), I did the following but it's not working

var url = "https://hello-my.sharepoint.com/:w:/r/personal/;
var urlRegx = new RegExp('^(docs.google.com|(http|https)://[A-Za-z]-.my.sharepoint.com)', 'i');
console.log(urlRegx.test(url));

This is giving me false when i have the sharepoint url but true when i have the `url = "docs.google.com/document/"

asked Nov 15 '18 at 9:12

milan

810929

Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

– Wiktor Stribiżew
Nov 15 '18 at 9:14

add a comment |

I am using regex for validating if the provided url is valid or not. To test validity(either google docs url or office 365 docs), I did the following but it's not working

var url = "https://hello-my.sharepoint.com/:w:/r/personal/;
var urlRegx = new RegExp('^(docs.google.com|(http|https)://[A-Za-z]-.my.sharepoint.com)', 'i');
console.log(urlRegx.test(url));

This is giving me false when i have the sharepoint url but true when i have the `url = "docs.google.com/document/"

asked Nov 15 '18 at 9:12

milan

810929

Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

– Wiktor Stribiżew
Nov 15 '18 at 9:14

add a comment |

I am using regex for validating if the provided url is valid or not. To test validity(either google docs url or office 365 docs), I did the following but it's not working

var url = "https://hello-my.sharepoint.com/:w:/r/personal/;
var urlRegx = new RegExp('^(docs.google.com|(http|https)://[A-Za-z]-.my.sharepoint.com)', 'i');
console.log(urlRegx.test(url));

This is giving me false when i have the sharepoint url but true when i have the `url = "docs.google.com/document/"

asked Nov 15 '18 at 9:12

milan

810929

I am using regex for validating if the provided url is valid or not. To test validity(either google docs url or office 365 docs), I did the following but it's not working

var url = "https://hello-my.sharepoint.com/:w:/r/personal/;
var urlRegx = new RegExp('^(docs.google.com|(http|https)://[A-Za-z]-.my.sharepoint.com)', 'i');
console.log(urlRegx.test(url));

This is giving me false when i have the sharepoint url but true when i have the `url = "docs.google.com/document/"

javascript regex

asked Nov 15 '18 at 9:12

milan

810929

asked Nov 15 '18 at 9:12

milan

810929

asked Nov 15 '18 at 9:12

milan

810929

asked Nov 15 '18 at 9:12

milan

810929

asked Nov 15 '18 at 9:12

milan

810929

Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

– Wiktor Stribiżew
Nov 15 '18 at 9:14

add a comment |

Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

– Wiktor Stribiżew
Nov 15 '18 at 9:14

Try var urlRegx = /^(?:docs.google.com|https?)://[A-Za-z]+-my.sharepoint.com/i;. See the regex demo.

– Wiktor Stribiżew
Nov 15 '18 at 9:14

add a comment |

1 Answer
1

active

oldest

votes

You've got an additional closing bracket ) at the end of your expression which you should remove.

You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).

Here is a working example:

var url = "https://hello-my.sharepoint.com/:w:/r/personal/";
var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');
console.log(urlRegx.test(url));

Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:

var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;

edited Nov 19 '18 at 4:46

answered Nov 15 '18 at 9:22

Nick Parsons

9,5462826

You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

– Wiktor Stribiżew
Nov 15 '18 at 9:25

@WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

– Nick Parsons
Nov 15 '18 at 9:36

if you try to validate the url 'docs.google.com' it gives you false as an output

– milan
Nov 19 '18 at 4:40

@milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

– Nick Parsons
Nov 19 '18 at 4:46

add a comment |

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1 Answer
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1 Answer
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oldest

votes

You've got an additional closing bracket ) at the end of your expression which you should remove.

You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).

Here is a working example:

var url = "https://hello-my.sharepoint.com/:w:/r/personal/";
var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');
console.log(urlRegx.test(url));

Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:

var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;

edited Nov 19 '18 at 4:46

answered Nov 15 '18 at 9:22

Nick Parsons

9,5462826

You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

– Wiktor Stribiżew
Nov 15 '18 at 9:25

@WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

– Nick Parsons
Nov 15 '18 at 9:36

if you try to validate the url 'docs.google.com' it gives you false as an output

– milan
Nov 19 '18 at 4:40

@milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

– Nick Parsons
Nov 19 '18 at 4:46

add a comment |

You've got an additional closing bracket ) at the end of your expression which you should remove.

You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).

Here is a working example:

var url = "https://hello-my.sharepoint.com/:w:/r/personal/";
var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');
console.log(urlRegx.test(url));

Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:

var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;

edited Nov 19 '18 at 4:46

answered Nov 15 '18 at 9:22

Nick Parsons

9,5462826

You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

– Wiktor Stribiżew
Nov 15 '18 at 9:25

@WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

– Nick Parsons
Nov 15 '18 at 9:36

if you try to validate the url 'docs.google.com' it gives you false as an output

– milan
Nov 19 '18 at 4:40

@milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

– Nick Parsons
Nov 19 '18 at 4:46

add a comment |

You've got an additional closing bracket ) at the end of your expression which you should remove.

You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).

Here is a working example:

var url = "https://hello-my.sharepoint.com/:w:/r/personal/";
var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');
console.log(urlRegx.test(url));

Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:

var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;

edited Nov 19 '18 at 4:46

answered Nov 15 '18 at 9:22

Nick Parsons

9,5462826

You've got an additional closing bracket ) at the end of your expression which you should remove.

You are also missing a + after [A-Za-z] (as without the plus you are only matching a single character).

Here is a working example:

var url = "https://hello-my.sharepoint.com/:w:/r/personal/";
var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');
console.log(urlRegx.test(url));

Note: When using the RegExp constructor you do not need to escape the special characters. Thus, if you don't use the RegExp constructor you must escape your special characters like so:

var urlRegx = /(docs.google.com|(http|https))://[A-Za-z]+-my.sharepoint.com/i;

var url = "https://hello-my.sharepoint.com/:w:/r/personal/";
var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');
console.log(urlRegx.test(url));

var url = "https://hello-my.sharepoint.com/:w:/r/personal/";
var urlRegx = new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i');
console.log(urlRegx.test(url));

edited Nov 19 '18 at 4:46

answered Nov 15 '18 at 9:22

Nick Parsons

9,5462826

edited Nov 19 '18 at 4:46

answered Nov 15 '18 at 9:22

Nick Parsons

9,5462826

answered Nov 15 '18 at 9:22

Nick Parsons

9,5462826

answered Nov 15 '18 at 9:22

Nick Parsons

9,5462826

You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

– Wiktor Stribiżew
Nov 15 '18 at 9:25

@WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

– Nick Parsons
Nov 15 '18 at 9:36

if you try to validate the url 'docs.google.com' it gives you false as an output

– milan
Nov 19 '18 at 4:40

@milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

– Nick Parsons
Nov 19 '18 at 4:46

add a comment |

You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

– Wiktor Stribiżew
Nov 15 '18 at 9:25

@WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

– Nick Parsons
Nov 15 '18 at 9:36

if you try to validate the url 'docs.google.com' it gives you false as an output

– milan
Nov 19 '18 at 4:40

@milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

– Nick Parsons
Nov 19 '18 at 4:46

You still did not escape dots. See console.log('.'). There is no need escaping / in a regex pattern built with RegExp constructor, / is not a special regex metacharacter.

– Wiktor Stribiżew
Nov 15 '18 at 9:25

@WiktorStribiżew Ah yes, you right. Thanks for pointing this out. I've updated my answer

– Nick Parsons
Nov 15 '18 at 9:36

if you try to validate the url 'docs.google.com' it gives you false as an output

– milan
Nov 19 '18 at 4:40

@milan try new RegExp('(docs.google.com|(http|https))(://[A-Za-z]+-my.sharepoint.com)?', 'i'); instead

– Nick Parsons
Nov 19 '18 at 4:46

add a comment |

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