Odtnhj

I want to read below file line by line from a text file and print how I want in shell scripting

Text file content: 
zero#123456 
one#123 
two#12345678 

I want to print this as:

zero@1-6 
one@1-3 
two@1-8 

I tried the following:

file="readFile.txt" 
while IFS= read -r line 
do echo "$line" 
done <printf '%sn' "$file" 

Create a script like below: my_print.sh

file="readFile.txt" 

while IFS= read -r line
do
one=$(echo $line| awk -F'#' 'print $1') ## This splits the line based on '#' and picks the 1st value. So, we get zero from 'zero#123456 ' 
len=$(echo $line| awk -F'#' 'print $2'|wc -c) ## This takes the 2nd value which is 123456 and counts the number of characters
two=$(echo $line| awk -F'#' 'print $2'| cut -c 1) ## This picks the 1st character from '123456' which is 1
three=$(echo $line| awk -F'#' 'print $2'| cut -c $((len-1))) ## This picks the last character from '123456' which is 6
echo $one@$two-$three ## This is basically printing the output in the format you wanted 'zero@1-6'
done <"$file"

Run it like:

mayankp@mayank:~/$ sh my_print.sh 
mayankp@mayank:~/$ cat output.txt 
zero@1-6
one@1-3
two@1-8

Let me know of this helps.

It's no shell scripting (missed that first, sorry) but using perl with combined lookahead and lookbehind for a number:

$ perl -pe 's/(?<=[0-9]).*(?=[0-9])/-/' file
Text file content: 
zero#1-6 
one#1-3 
two#1-8 

Explained some:

• 
  s//-/ replace with a -
  


• 
  (?<=[0-9]) positive lookbehind, if preceeded by a number
  


• 
  (?=[0-9]) positive lookahead, if followed by a number
  

With sed:

sed -r 's/^(.+)#([0-9])[0-9]*([0-9])s*$/1@2-3/' readFile.txt

• 
  -r: using extented regular expressions (just to write some stuff without escaping them by a backslash)


• 
  s/expr1/expr2/: substitute expr1 by expr2
  


• 
  epxr1 is described by a regular expression, relevant matching patterns are caught by 3 capturing groups (parenthesized ones).


• 
  epxr2 retrieves captured strings (1, 2, 3) and insert them in a formatted output (the one you wanted).

Regular-Expressions.info seems to be interesting to start with them. Also you can check your own regexp with Regx101.com.

Update: Also you could do that with awk:

awk -F'#' ' 
 gsub(/s*/,"", $2) ; 
 print $1 "@" substr($2, 1, 1) "-" substr($2, length($2), 1) 
 ' < test.txt

I added a gsub() call because your file seems to have trailing blank characters.