Meaning of * operator when used with classes










-1















I've been trying to follow a video tutorial on Python and cannot understand one operation the developer performs.



class Polynomial():

def __init__(self, *coeffs):
self.coeffs = coeffs # (3,4,3)

def __repr__(self):
return 'Polynomial(*!r)'.format(self.coeffs)

def __add__(self, other):
print(self.coeffs)
print(other.coeffs)
z = (x + y for x, y in zip(self.coeffs, other.coeffs))
print(z)
return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs)))

p1 = Polynomial(1, 2, 3) # x^2 + 2x + 3
p2 = Polynomial(3, 4, 3) # 3x^2 + 4x + 3
#print(p2) # Polynomial(*(3, 4, 3))
print(p1 + p2) # Polynomial(*(4, 6, 6))


The above example will print



<generator object Polynomial.__add__.<locals>.<genexpr> at 0x030D0390>


as the return value of z, I cannot understand why because I am performing a zip operation of two tuples?



Alongside that problem, I do not understand why removing the * during the return of __add__ causes a problem i.e return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs))) to return Polynomial((x + y for x, y in zip(self.coeffs, other.coeffs)))



What is the * operator doing, and why is z an object of Polynomial?



The _add__ method does not contain a parameter containing a * or ** and is therefore a different situation.










share|improve this question



















  • 2





    Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

    – Norrius
    Nov 15 '18 at 9:19















-1















I've been trying to follow a video tutorial on Python and cannot understand one operation the developer performs.



class Polynomial():

def __init__(self, *coeffs):
self.coeffs = coeffs # (3,4,3)

def __repr__(self):
return 'Polynomial(*!r)'.format(self.coeffs)

def __add__(self, other):
print(self.coeffs)
print(other.coeffs)
z = (x + y for x, y in zip(self.coeffs, other.coeffs))
print(z)
return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs)))

p1 = Polynomial(1, 2, 3) # x^2 + 2x + 3
p2 = Polynomial(3, 4, 3) # 3x^2 + 4x + 3
#print(p2) # Polynomial(*(3, 4, 3))
print(p1 + p2) # Polynomial(*(4, 6, 6))


The above example will print



<generator object Polynomial.__add__.<locals>.<genexpr> at 0x030D0390>


as the return value of z, I cannot understand why because I am performing a zip operation of two tuples?



Alongside that problem, I do not understand why removing the * during the return of __add__ causes a problem i.e return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs))) to return Polynomial((x + y for x, y in zip(self.coeffs, other.coeffs)))



What is the * operator doing, and why is z an object of Polynomial?



The _add__ method does not contain a parameter containing a * or ** and is therefore a different situation.










share|improve this question



















  • 2





    Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

    – Norrius
    Nov 15 '18 at 9:19













-1












-1








-1








I've been trying to follow a video tutorial on Python and cannot understand one operation the developer performs.



class Polynomial():

def __init__(self, *coeffs):
self.coeffs = coeffs # (3,4,3)

def __repr__(self):
return 'Polynomial(*!r)'.format(self.coeffs)

def __add__(self, other):
print(self.coeffs)
print(other.coeffs)
z = (x + y for x, y in zip(self.coeffs, other.coeffs))
print(z)
return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs)))

p1 = Polynomial(1, 2, 3) # x^2 + 2x + 3
p2 = Polynomial(3, 4, 3) # 3x^2 + 4x + 3
#print(p2) # Polynomial(*(3, 4, 3))
print(p1 + p2) # Polynomial(*(4, 6, 6))


The above example will print



<generator object Polynomial.__add__.<locals>.<genexpr> at 0x030D0390>


as the return value of z, I cannot understand why because I am performing a zip operation of two tuples?



Alongside that problem, I do not understand why removing the * during the return of __add__ causes a problem i.e return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs))) to return Polynomial((x + y for x, y in zip(self.coeffs, other.coeffs)))



What is the * operator doing, and why is z an object of Polynomial?



The _add__ method does not contain a parameter containing a * or ** and is therefore a different situation.










share|improve this question
















I've been trying to follow a video tutorial on Python and cannot understand one operation the developer performs.



class Polynomial():

def __init__(self, *coeffs):
self.coeffs = coeffs # (3,4,3)

def __repr__(self):
return 'Polynomial(*!r)'.format(self.coeffs)

def __add__(self, other):
print(self.coeffs)
print(other.coeffs)
z = (x + y for x, y in zip(self.coeffs, other.coeffs))
print(z)
return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs)))

p1 = Polynomial(1, 2, 3) # x^2 + 2x + 3
p2 = Polynomial(3, 4, 3) # 3x^2 + 4x + 3
#print(p2) # Polynomial(*(3, 4, 3))
print(p1 + p2) # Polynomial(*(4, 6, 6))


The above example will print



<generator object Polynomial.__add__.<locals>.<genexpr> at 0x030D0390>


as the return value of z, I cannot understand why because I am performing a zip operation of two tuples?



Alongside that problem, I do not understand why removing the * during the return of __add__ causes a problem i.e return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs))) to return Polynomial((x + y for x, y in zip(self.coeffs, other.coeffs)))



What is the * operator doing, and why is z an object of Polynomial?



The _add__ method does not contain a parameter containing a * or ** and is therefore a different situation.







python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 9:21







J.doe

















asked Nov 15 '18 at 9:13









J.doeJ.doe

233




233







  • 2





    Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

    – Norrius
    Nov 15 '18 at 9:19












  • 2





    Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

    – Norrius
    Nov 15 '18 at 9:19







2




2





Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

– Norrius
Nov 15 '18 at 9:19





Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

– Norrius
Nov 15 '18 at 9:19












3 Answers
3






active

oldest

votes


















1














So first.



Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



Or you can use your generator, so print:



print([el for el in z])


Second, the *.



It will simply pass iterable as separated args, so:



SomeClass(*args)


Will do:



SomeClass(args[0], args[1], args[2], ...)


You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
And here (double asterisk):
https://docs.python.org/3/reference/expressions.html#dictionary-displays






share|improve this answer


















  • 1





    or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

    – buran
    Nov 15 '18 at 9:22



















0














When in a function declaration, * is list of args send.



For exemple:



def my_function(a, *b, **c):
print(a)
print(b)
print(c)

my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


output :



1st args
["other arg", "other arg again", 2]
"arg_type": "kwargs"



And when is not in function declaration, it's for unpack the list.



For exemple:



list_of_arguments = ['a', 'b', 'z']
my_str = "the first letter of alphabet is , the second is and the last is "
print(my_str.format(*list_of_arguments))





or other exemple



 def my_second_func(a, b, c):
print(a)
print(b)

my_list = [1, 2, 3]
my_second_func(a, b, c)


will output:



 1
2





share|improve this answer

























  • but add does not have a parameter with a *

    – J.doe
    Nov 15 '18 at 9:18











  • i edited my post, in your code * is used for unpack the list returned by the zip() function

    – iElden
    Nov 15 '18 at 9:22


















0














Consider this easy example:



a = [1, 2, 3]
b = [4, 5, 6]

gen = (x + y for x, y in zip(a, b))

print(gen) ## this will print <generator object <genexpr> at 0x...>


In this case, the asterisk evaluates the generator expression. So when doing



print(*gen) ## this will print 5 7 9


you evaluate the generator expression.






share|improve this answer






















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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    So first.



    Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



    Or you can use your generator, so print:



    print([el for el in z])


    Second, the *.



    It will simply pass iterable as separated args, so:



    SomeClass(*args)


    Will do:



    SomeClass(args[0], args[1], args[2], ...)


    You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
    And here (double asterisk):
    https://docs.python.org/3/reference/expressions.html#dictionary-displays






    share|improve this answer


















    • 1





      or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

      – buran
      Nov 15 '18 at 9:22
















    1














    So first.



    Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



    Or you can use your generator, so print:



    print([el for el in z])


    Second, the *.



    It will simply pass iterable as separated args, so:



    SomeClass(*args)


    Will do:



    SomeClass(args[0], args[1], args[2], ...)


    You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
    And here (double asterisk):
    https://docs.python.org/3/reference/expressions.html#dictionary-displays






    share|improve this answer


















    • 1





      or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

      – buran
      Nov 15 '18 at 9:22














    1












    1








    1







    So first.



    Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



    Or you can use your generator, so print:



    print([el for el in z])


    Second, the *.



    It will simply pass iterable as separated args, so:



    SomeClass(*args)


    Will do:



    SomeClass(args[0], args[1], args[2], ...)


    You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
    And here (double asterisk):
    https://docs.python.org/3/reference/expressions.html#dictionary-displays






    share|improve this answer













    So first.



    Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



    Or you can use your generator, so print:



    print([el for el in z])


    Second, the *.



    It will simply pass iterable as separated args, so:



    SomeClass(*args)


    Will do:



    SomeClass(args[0], args[1], args[2], ...)


    You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
    And here (double asterisk):
    https://docs.python.org/3/reference/expressions.html#dictionary-displays







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 15 '18 at 9:21









    opalczynskiopalczynski

    1,045810




    1,045810







    • 1





      or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

      – buran
      Nov 15 '18 at 9:22













    • 1





      or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

      – buran
      Nov 15 '18 at 9:22








    1




    1





    or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

    – buran
    Nov 15 '18 at 9:22






    or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

    – buran
    Nov 15 '18 at 9:22














    0














    When in a function declaration, * is list of args send.



    For exemple:



    def my_function(a, *b, **c):
    print(a)
    print(b)
    print(c)

    my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


    output :



    1st args
    ["other arg", "other arg again", 2]
    "arg_type": "kwargs"



    And when is not in function declaration, it's for unpack the list.



    For exemple:



    list_of_arguments = ['a', 'b', 'z']
    my_str = "the first letter of alphabet is , the second is and the last is "
    print(my_str.format(*list_of_arguments))





    or other exemple



     def my_second_func(a, b, c):
    print(a)
    print(b)

    my_list = [1, 2, 3]
    my_second_func(a, b, c)


    will output:



     1
    2





    share|improve this answer

























    • but add does not have a parameter with a *

      – J.doe
      Nov 15 '18 at 9:18











    • i edited my post, in your code * is used for unpack the list returned by the zip() function

      – iElden
      Nov 15 '18 at 9:22















    0














    When in a function declaration, * is list of args send.



    For exemple:



    def my_function(a, *b, **c):
    print(a)
    print(b)
    print(c)

    my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


    output :



    1st args
    ["other arg", "other arg again", 2]
    "arg_type": "kwargs"



    And when is not in function declaration, it's for unpack the list.



    For exemple:



    list_of_arguments = ['a', 'b', 'z']
    my_str = "the first letter of alphabet is , the second is and the last is "
    print(my_str.format(*list_of_arguments))





    or other exemple



     def my_second_func(a, b, c):
    print(a)
    print(b)

    my_list = [1, 2, 3]
    my_second_func(a, b, c)


    will output:



     1
    2





    share|improve this answer

























    • but add does not have a parameter with a *

      – J.doe
      Nov 15 '18 at 9:18











    • i edited my post, in your code * is used for unpack the list returned by the zip() function

      – iElden
      Nov 15 '18 at 9:22













    0












    0








    0







    When in a function declaration, * is list of args send.



    For exemple:



    def my_function(a, *b, **c):
    print(a)
    print(b)
    print(c)

    my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


    output :



    1st args
    ["other arg", "other arg again", 2]
    "arg_type": "kwargs"



    And when is not in function declaration, it's for unpack the list.



    For exemple:



    list_of_arguments = ['a', 'b', 'z']
    my_str = "the first letter of alphabet is , the second is and the last is "
    print(my_str.format(*list_of_arguments))





    or other exemple



     def my_second_func(a, b, c):
    print(a)
    print(b)

    my_list = [1, 2, 3]
    my_second_func(a, b, c)


    will output:



     1
    2





    share|improve this answer















    When in a function declaration, * is list of args send.



    For exemple:



    def my_function(a, *b, **c):
    print(a)
    print(b)
    print(c)

    my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


    output :



    1st args
    ["other arg", "other arg again", 2]
    "arg_type": "kwargs"



    And when is not in function declaration, it's for unpack the list.



    For exemple:



    list_of_arguments = ['a', 'b', 'z']
    my_str = "the first letter of alphabet is , the second is and the last is "
    print(my_str.format(*list_of_arguments))





    or other exemple



     def my_second_func(a, b, c):
    print(a)
    print(b)

    my_list = [1, 2, 3]
    my_second_func(a, b, c)


    will output:



     1
    2






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 15 '18 at 9:18

























    answered Nov 15 '18 at 9:16









    iEldeniElden

    692518




    692518












    • but add does not have a parameter with a *

      – J.doe
      Nov 15 '18 at 9:18











    • i edited my post, in your code * is used for unpack the list returned by the zip() function

      – iElden
      Nov 15 '18 at 9:22

















    • but add does not have a parameter with a *

      – J.doe
      Nov 15 '18 at 9:18











    • i edited my post, in your code * is used for unpack the list returned by the zip() function

      – iElden
      Nov 15 '18 at 9:22
















    but add does not have a parameter with a *

    – J.doe
    Nov 15 '18 at 9:18





    but add does not have a parameter with a *

    – J.doe
    Nov 15 '18 at 9:18













    i edited my post, in your code * is used for unpack the list returned by the zip() function

    – iElden
    Nov 15 '18 at 9:22





    i edited my post, in your code * is used for unpack the list returned by the zip() function

    – iElden
    Nov 15 '18 at 9:22











    0














    Consider this easy example:



    a = [1, 2, 3]
    b = [4, 5, 6]

    gen = (x + y for x, y in zip(a, b))

    print(gen) ## this will print <generator object <genexpr> at 0x...>


    In this case, the asterisk evaluates the generator expression. So when doing



    print(*gen) ## this will print 5 7 9


    you evaluate the generator expression.






    share|improve this answer



























      0














      Consider this easy example:



      a = [1, 2, 3]
      b = [4, 5, 6]

      gen = (x + y for x, y in zip(a, b))

      print(gen) ## this will print <generator object <genexpr> at 0x...>


      In this case, the asterisk evaluates the generator expression. So when doing



      print(*gen) ## this will print 5 7 9


      you evaluate the generator expression.






      share|improve this answer

























        0












        0








        0







        Consider this easy example:



        a = [1, 2, 3]
        b = [4, 5, 6]

        gen = (x + y for x, y in zip(a, b))

        print(gen) ## this will print <generator object <genexpr> at 0x...>


        In this case, the asterisk evaluates the generator expression. So when doing



        print(*gen) ## this will print 5 7 9


        you evaluate the generator expression.






        share|improve this answer













        Consider this easy example:



        a = [1, 2, 3]
        b = [4, 5, 6]

        gen = (x + y for x, y in zip(a, b))

        print(gen) ## this will print <generator object <genexpr> at 0x...>


        In this case, the asterisk evaluates the generator expression. So when doing



        print(*gen) ## this will print 5 7 9


        you evaluate the generator expression.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 9:27









        DocDrivenDocDriven

        1,2302621




        1,2302621



























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