Angular 6 extract value from decoded string base 64
1
I've decoded a string in Base64 with xml2js library and i got this value :
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>
i cut the encode value because it's to long
I'm blocked for getting the value of xlink:href, is there any technics or library for getting the attribute ?
I mean i want to get this value only : data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=
Thank's
angular typescript base64 asked Nov 15 '18 at 15:23
Stephanie JoyceStephanie Joyce
315
add a comment |
1
I've decoded a string in Base64 with xml2js library and i got this value :
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>
i cut the encode value because it's to long
I'm blocked for getting the value of xlink:href, is there any technics or library for getting the attribute ?
I mean i want to get this value only : data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=
Thank's
angular typescript base64 asked Nov 15 '18 at 15:23
Stephanie JoyceStephanie Joyce
315
You could try using a regex to match only that part of the string. Something like/xlink:href="([^"]*)"/
– Alex K
Nov 15 '18 at 15:46
1
It's a svg you can parse it using DOMParser
– JEY
Nov 15 '18 at 15:59
@JEY that's probably the most robust solution :)
– Alex K
Nov 15 '18 at 16:03
add a comment |
1
1
1
I've decoded a string in Base64 with xml2js library and i got this value :
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>
i cut the encode value because it's to long
I'm blocked for getting the value of xlink:href, is there any technics or library for getting the attribute ?
I mean i want to get this value only : data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=
Thank's
angular typescript base64 asked Nov 15 '18 at 15:23
Stephanie JoyceStephanie Joyce
315
I've decoded a string in Base64 with xml2js library and i got this value :
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>
i cut the encode value because it's to long
I'm blocked for getting the value of xlink:href, is there any technics or library for getting the attribute ?
I mean i want to get this value only : data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=
Thank's
angular typescript base64 angular typescript base64 asked Nov 15 '18 at 15:23
Stephanie JoyceStephanie Joyce
315
asked Nov 15 '18 at 15:23
Stephanie JoyceStephanie Joyce
315
asked Nov 15 '18 at 15:23
Stephanie JoyceStephanie Joyce
315
asked Nov 15 '18 at 15:23
Stephanie JoyceStephanie Joyce
315
asked Nov 15 '18 at 15:23
Stephanie JoyceStephanie Joyce
315
315
You could try using a regex to match only that part of the string. Something like/xlink:href="([^"]*)"/
– Alex K
Nov 15 '18 at 15:46
1
It's a svg you can parse it using DOMParser
– JEY
Nov 15 '18 at 15:59
@JEY that's probably the most robust solution :)
– Alex K
Nov 15 '18 at 16:03
add a comment |
You could try using a regex to match only that part of the string. Something like/xlink:href="([^"]*)"/
– Alex K
Nov 15 '18 at 15:46
1
It's a svg you can parse it using DOMParser
– JEY
Nov 15 '18 at 15:59
@JEY that's probably the most robust solution :)
– Alex K
Nov 15 '18 at 16:03
You could try using a regex to match only that part of the string. Something like
/xlink:href="([^"]*)"/– Alex K
Nov 15 '18 at 15:46
You could try using a regex to match only that part of the string. Something like
/xlink:href="([^"]*)"/– Alex K
Nov 15 '18 at 15:46
1
1
It's a svg you can parse it using DOMParser
– JEY
Nov 15 '18 at 15:59
It's a svg you can parse it using DOMParser
– JEY
Nov 15 '18 at 15:59
@JEY that's probably the most robust solution :)
– Alex K
Nov 15 '18 at 16:03
@JEY that's probably the most robust solution :)
– Alex K
Nov 15 '18 at 16:03
add a comment |
1 Answer
1
active
oldest
votes
2
You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:
const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;
const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);answered Nov 15 '18 at 16:01
Alex KAlex K
1,195610
just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn
– JEY
Nov 15 '18 at 16:04
@JEY looks like that works well too!
– Alex K
Nov 15 '18 at 16:10
I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions
– Stephanie Joyce
Nov 15 '18 at 16:11
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53322630%2fangular-6-extract-value-from-decoded-string-base-64%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:
const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;
const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);answered Nov 15 '18 at 16:01
Alex KAlex K
1,195610
just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn
– JEY
Nov 15 '18 at 16:04
@JEY looks like that works well too!
– Alex K
Nov 15 '18 at 16:10
I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions
– Stephanie Joyce
Nov 15 '18 at 16:11
add a comment |
2
You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:
const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;
const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);answered Nov 15 '18 at 16:01
Alex KAlex K
1,195610
just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn
– JEY
Nov 15 '18 at 16:04
@JEY looks like that works well too!
– Alex K
Nov 15 '18 at 16:10
I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions
– Stephanie Joyce
Nov 15 '18 at 16:11
add a comment |
2
2
2
You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:
const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;
const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);answered Nov 15 '18 at 16:01
Alex KAlex K
1,195610
You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:
const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;
const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;
const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;
const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);answered Nov 15 '18 at 16:01
Alex KAlex K
1,195610
answered Nov 15 '18 at 16:01
Alex KAlex K
1,195610
answered Nov 15 '18 at 16:01
Alex KAlex K
1,195610
answered Nov 15 '18 at 16:01
Alex KAlex K
1,195610
1,195610
just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn
– JEY
Nov 15 '18 at 16:04
@JEY looks like that works well too!
– Alex K
Nov 15 '18 at 16:10
I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions
– Stephanie Joyce
Nov 15 '18 at 16:11
add a comment |
just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn
– JEY
Nov 15 '18 at 16:04
@JEY looks like that works well too!
– Alex K
Nov 15 '18 at 16:10
I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions
– Stephanie Joyce
Nov 15 '18 at 16:11
just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn
– JEY
Nov 15 '18 at 16:04
just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn
– JEY
Nov 15 '18 at 16:04
@JEY looks like that works well too!
– Alex K
Nov 15 '18 at 16:10
@JEY looks like that works well too!
– Alex K
Nov 15 '18 at 16:10
I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions
– Stephanie Joyce
Nov 15 '18 at 16:11
I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions
– Stephanie Joyce
Nov 15 '18 at 16:11
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53322630%2fangular-6-extract-value-from-decoded-string-base-64%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
You could try using a regex to match only that part of the string. Something like
/xlink:href="([^"]*)"/– Alex K
Nov 15 '18 at 15:46
1
It's a svg you can parse it using DOMParser
– JEY
Nov 15 '18 at 15:59
@JEY that's probably the most robust solution :)
– Alex K
Nov 15 '18 at 16:03