Angular 6 extract value from decoded string base 64










1















I've decoded a string in Base64 with xml2js library and i got this value :



<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>


i cut the encode value because it's to long



I'm blocked for getting the value of xlink:href, is there any technics or library for getting the attribute ?



I mean i want to get this value only : data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=



Thank's










share|improve this question






















  • You could try using a regex to match only that part of the string. Something like /xlink:href="([^"]*)"/

    – Alex K
    Nov 15 '18 at 15:46






  • 1





    It's a svg you can parse it using DOMParser

    – JEY
    Nov 15 '18 at 15:59











  • @JEY that's probably the most robust solution :)

    – Alex K
    Nov 15 '18 at 16:03















1















I've decoded a string in Base64 with xml2js library and i got this value :



<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>


i cut the encode value because it's to long



I'm blocked for getting the value of xlink:href, is there any technics or library for getting the attribute ?



I mean i want to get this value only : data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=



Thank's










share|improve this question






















  • You could try using a regex to match only that part of the string. Something like /xlink:href="([^"]*)"/

    – Alex K
    Nov 15 '18 at 15:46






  • 1





    It's a svg you can parse it using DOMParser

    – JEY
    Nov 15 '18 at 15:59











  • @JEY that's probably the most robust solution :)

    – Alex K
    Nov 15 '18 at 16:03













1












1








1








I've decoded a string in Base64 with xml2js library and i got this value :



<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>


i cut the encode value because it's to long



I'm blocked for getting the value of xlink:href, is there any technics or library for getting the attribute ?



I mean i want to get this value only : data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=



Thank's










share|improve this question














I've decoded a string in Base64 with xml2js library and i got this value :



<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>


i cut the encode value because it's to long



I'm blocked for getting the value of xlink:href, is there any technics or library for getting the attribute ?



I mean i want to get this value only : data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=



Thank's







angular typescript base64






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 15 '18 at 15:23









Stephanie JoyceStephanie Joyce

315




315












  • You could try using a regex to match only that part of the string. Something like /xlink:href="([^"]*)"/

    – Alex K
    Nov 15 '18 at 15:46






  • 1





    It's a svg you can parse it using DOMParser

    – JEY
    Nov 15 '18 at 15:59











  • @JEY that's probably the most robust solution :)

    – Alex K
    Nov 15 '18 at 16:03

















  • You could try using a regex to match only that part of the string. Something like /xlink:href="([^"]*)"/

    – Alex K
    Nov 15 '18 at 15:46






  • 1





    It's a svg you can parse it using DOMParser

    – JEY
    Nov 15 '18 at 15:59











  • @JEY that's probably the most robust solution :)

    – Alex K
    Nov 15 '18 at 16:03
















You could try using a regex to match only that part of the string. Something like /xlink:href="([^"]*)"/

– Alex K
Nov 15 '18 at 15:46





You could try using a regex to match only that part of the string. Something like /xlink:href="([^"]*)"/

– Alex K
Nov 15 '18 at 15:46




1




1





It's a svg you can parse it using DOMParser

– JEY
Nov 15 '18 at 15:59





It's a svg you can parse it using DOMParser

– JEY
Nov 15 '18 at 15:59













@JEY that's probably the most robust solution :)

– Alex K
Nov 15 '18 at 16:03





@JEY that's probably the most robust solution :)

– Alex K
Nov 15 '18 at 16:03












1 Answer
1






active

oldest

votes


















2














You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:






const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;

const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);








share|improve this answer























  • just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn

    – JEY
    Nov 15 '18 at 16:04











  • @JEY looks like that works well too!

    – Alex K
    Nov 15 '18 at 16:10











  • I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions

    – Stephanie Joyce
    Nov 15 '18 at 16:11










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1 Answer
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1 Answer
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active

oldest

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active

oldest

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active

oldest

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2














You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:






const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;

const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);








share|improve this answer























  • just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn

    – JEY
    Nov 15 '18 at 16:04











  • @JEY looks like that works well too!

    – Alex K
    Nov 15 '18 at 16:10











  • I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions

    – Stephanie Joyce
    Nov 15 '18 at 16:11















2














You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:






const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;

const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);








share|improve this answer























  • just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn

    – JEY
    Nov 15 '18 at 16:04











  • @JEY looks like that works well too!

    – Alex K
    Nov 15 '18 at 16:10











  • I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions

    – Stephanie Joyce
    Nov 15 '18 at 16:11













2












2








2







You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:






const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;

const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);








share|improve this answer













You can use DOMParser to parse the xml string. Then you can operate on the resulting Document as usual:






const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;

const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);








const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;

const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);





const xmlString = `<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<svg width="293" height="102"
viewBox="0 0 293 102"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" version="1.2" baseProfile="tiny">
<image
width="293"
height="102"
xlink:href="data:image/png;base64,iVBORw0KGgoAAAANS......pASYAAAAASUVORK5CYII=" />
</svg>`;

const domParser = new DOMParser();
const xmlDoc = domParser.parseFromString(xmlString, 'application/xml');
const imageElement = xmlDoc.getElementsByTagName('image')[0];
const hrefAttr = imageElement.getAttribute('xlink:href');
console.log(hrefAttr);






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 16:01









Alex KAlex K

1,195610




1,195610












  • just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn

    – JEY
    Nov 15 '18 at 16:04











  • @JEY looks like that works well too!

    – Alex K
    Nov 15 '18 at 16:10











  • I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions

    – Stephanie Joyce
    Nov 15 '18 at 16:11

















  • just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn

    – JEY
    Nov 15 '18 at 16:04











  • @JEY looks like that works well too!

    – Alex K
    Nov 15 '18 at 16:10











  • I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions

    – Stephanie Joyce
    Nov 15 '18 at 16:11
















just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn

– JEY
Nov 15 '18 at 16:04





just use querySelector and getAttributeNS like i did stackblitz.com/edit/typescript-yx3fyn

– JEY
Nov 15 '18 at 16:04













@JEY looks like that works well too!

– Alex K
Nov 15 '18 at 16:10





@JEY looks like that works well too!

– Alex K
Nov 15 '18 at 16:10













I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions

– Stephanie Joyce
Nov 15 '18 at 16:11





I've use this : var urlImage = xml.match(/xlink:href="([^"]*)"/); var finalUrl = urlImage[1] and it works Thank's @Alex K and Jey for your solutions

– Stephanie Joyce
Nov 15 '18 at 16:11



















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