Problem: dropna() method is returning NaN values










1















Having problems with the .dropna() method. I have created a new variable energy_c which is a copy of energy but with mont being more or equal to 0.1.



I then took out the columns with nothing in after printing them and then am trying to drop all rows that have NaN values in the remaining columns. However my output is returning NaN values even after using .dropna().



energy_c = energy.loc[energy.loc[:, 'mont'] >= 0.1].copy()
energy_c.columns[energy.isna().all()].tolist()
drop_cols = energy_c.loc[:,['EndDate', 'Ref', 'dis']]
energy_c.drop(drop_cols, axis=1, inplace=True)
energy_c.dropna()
print(energy_c)


Could someone advise as to what I have done wrong?



Thanks.










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    1















    Having problems with the .dropna() method. I have created a new variable energy_c which is a copy of energy but with mont being more or equal to 0.1.



    I then took out the columns with nothing in after printing them and then am trying to drop all rows that have NaN values in the remaining columns. However my output is returning NaN values even after using .dropna().



    energy_c = energy.loc[energy.loc[:, 'mont'] >= 0.1].copy()
    energy_c.columns[energy.isna().all()].tolist()
    drop_cols = energy_c.loc[:,['EndDate', 'Ref', 'dis']]
    energy_c.drop(drop_cols, axis=1, inplace=True)
    energy_c.dropna()
    print(energy_c)


    Could someone advise as to what I have done wrong?



    Thanks.










    share|improve this question


























      1












      1








      1








      Having problems with the .dropna() method. I have created a new variable energy_c which is a copy of energy but with mont being more or equal to 0.1.



      I then took out the columns with nothing in after printing them and then am trying to drop all rows that have NaN values in the remaining columns. However my output is returning NaN values even after using .dropna().



      energy_c = energy.loc[energy.loc[:, 'mont'] >= 0.1].copy()
      energy_c.columns[energy.isna().all()].tolist()
      drop_cols = energy_c.loc[:,['EndDate', 'Ref', 'dis']]
      energy_c.drop(drop_cols, axis=1, inplace=True)
      energy_c.dropna()
      print(energy_c)


      Could someone advise as to what I have done wrong?



      Thanks.










      share|improve this question
















      Having problems with the .dropna() method. I have created a new variable energy_c which is a copy of energy but with mont being more or equal to 0.1.



      I then took out the columns with nothing in after printing them and then am trying to drop all rows that have NaN values in the remaining columns. However my output is returning NaN values even after using .dropna().



      energy_c = energy.loc[energy.loc[:, 'mont'] >= 0.1].copy()
      energy_c.columns[energy.isna().all()].tolist()
      drop_cols = energy_c.loc[:,['EndDate', 'Ref', 'dis']]
      energy_c.drop(drop_cols, axis=1, inplace=True)
      energy_c.dropna()
      print(energy_c)


      Could someone advise as to what I have done wrong?



      Thanks.







      python pandas






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      edited Dec 12 '18 at 13:38









      Helena Martins

      936218




      936218










      asked Nov 15 '18 at 15:23









      geds133geds133

      818




      818






















          2 Answers
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          1














          dropna is not an inplace method, try energy_c = energy_c.dropna().






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            2














            Try



            energy_c.dropna(inplace = True)


            This does the operation inplace and returns None, according to the documentation.






            share|improve this answer






















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              2 Answers
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              2 Answers
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              active

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              active

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              1














              dropna is not an inplace method, try energy_c = energy_c.dropna().






              share|improve this answer



























                1














                dropna is not an inplace method, try energy_c = energy_c.dropna().






                share|improve this answer

























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                  1








                  1







                  dropna is not an inplace method, try energy_c = energy_c.dropna().






                  share|improve this answer













                  dropna is not an inplace method, try energy_c = energy_c.dropna().







                  share|improve this answer












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                  share|improve this answer










                  answered Nov 15 '18 at 15:25









                  vlizanavlizana

                  1,011316




                  1,011316























                      2














                      Try



                      energy_c.dropna(inplace = True)


                      This does the operation inplace and returns None, according to the documentation.






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                        2














                        Try



                        energy_c.dropna(inplace = True)


                        This does the operation inplace and returns None, according to the documentation.






                        share|improve this answer

























                          2












                          2








                          2







                          Try



                          energy_c.dropna(inplace = True)


                          This does the operation inplace and returns None, according to the documentation.






                          share|improve this answer













                          Try



                          energy_c.dropna(inplace = True)


                          This does the operation inplace and returns None, according to the documentation.







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Dec 12 '18 at 13:28









                          Lenka VranáLenka Vraná

                          1,1221225




                          1,1221225



























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