Fetch with array and for loop










1















I have around five URL(api) i need to fetch. I have made an array with the urls. I need to make a for loop so i can get each url-info into different boxes.
I started earlier with fetch url, then i wrote down +info.name+ etc on each thing i wanted to get out at the page, but it will take to long time, so i need to use a for loop.
How do i do that? So i dont have to fetch and write +info+ so many times?



var urls = ["url i need to fetch",
"url i need to fetch",
"url i need to fetch",];

var url = "url i wanted to fetch";

fetch (url)
.then (result => result.json())
.then ((res) =>
console.log(res);
createCards (res);

)
.catch(err => console.log(err))

function createCards(card) {
var div = document.getElementById('card');



div.innerHTML = `


<h2>`+card.name+`</h2>
<div>
<b>HTML text </b>`+info.from.card+`</div>









share|improve this question






















  • Can you use async/await?

    – ODYN-Kon
    Nov 15 '18 at 15:23











  • Have not used that before, so the best is if someone can help me with how Im gonna fetch it all with a for loop

    – KX0
    Nov 15 '18 at 15:24















1















I have around five URL(api) i need to fetch. I have made an array with the urls. I need to make a for loop so i can get each url-info into different boxes.
I started earlier with fetch url, then i wrote down +info.name+ etc on each thing i wanted to get out at the page, but it will take to long time, so i need to use a for loop.
How do i do that? So i dont have to fetch and write +info+ so many times?



var urls = ["url i need to fetch",
"url i need to fetch",
"url i need to fetch",];

var url = "url i wanted to fetch";

fetch (url)
.then (result => result.json())
.then ((res) =>
console.log(res);
createCards (res);

)
.catch(err => console.log(err))

function createCards(card) {
var div = document.getElementById('card');



div.innerHTML = `


<h2>`+card.name+`</h2>
<div>
<b>HTML text </b>`+info.from.card+`</div>









share|improve this question






















  • Can you use async/await?

    – ODYN-Kon
    Nov 15 '18 at 15:23











  • Have not used that before, so the best is if someone can help me with how Im gonna fetch it all with a for loop

    – KX0
    Nov 15 '18 at 15:24













1












1








1








I have around five URL(api) i need to fetch. I have made an array with the urls. I need to make a for loop so i can get each url-info into different boxes.
I started earlier with fetch url, then i wrote down +info.name+ etc on each thing i wanted to get out at the page, but it will take to long time, so i need to use a for loop.
How do i do that? So i dont have to fetch and write +info+ so many times?



var urls = ["url i need to fetch",
"url i need to fetch",
"url i need to fetch",];

var url = "url i wanted to fetch";

fetch (url)
.then (result => result.json())
.then ((res) =>
console.log(res);
createCards (res);

)
.catch(err => console.log(err))

function createCards(card) {
var div = document.getElementById('card');



div.innerHTML = `


<h2>`+card.name+`</h2>
<div>
<b>HTML text </b>`+info.from.card+`</div>









share|improve this question














I have around five URL(api) i need to fetch. I have made an array with the urls. I need to make a for loop so i can get each url-info into different boxes.
I started earlier with fetch url, then i wrote down +info.name+ etc on each thing i wanted to get out at the page, but it will take to long time, so i need to use a for loop.
How do i do that? So i dont have to fetch and write +info+ so many times?



var urls = ["url i need to fetch",
"url i need to fetch",
"url i need to fetch",];

var url = "url i wanted to fetch";

fetch (url)
.then (result => result.json())
.then ((res) =>
console.log(res);
createCards (res);

)
.catch(err => console.log(err))

function createCards(card) {
var div = document.getElementById('card');



div.innerHTML = `


<h2>`+card.name+`</h2>
<div>
<b>HTML text </b>`+info.from.card+`</div>






javascript arrays for-loop






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 15 '18 at 15:21









KX0KX0

346




346












  • Can you use async/await?

    – ODYN-Kon
    Nov 15 '18 at 15:23











  • Have not used that before, so the best is if someone can help me with how Im gonna fetch it all with a for loop

    – KX0
    Nov 15 '18 at 15:24

















  • Can you use async/await?

    – ODYN-Kon
    Nov 15 '18 at 15:23











  • Have not used that before, so the best is if someone can help me with how Im gonna fetch it all with a for loop

    – KX0
    Nov 15 '18 at 15:24
















Can you use async/await?

– ODYN-Kon
Nov 15 '18 at 15:23





Can you use async/await?

– ODYN-Kon
Nov 15 '18 at 15:23













Have not used that before, so the best is if someone can help me with how Im gonna fetch it all with a for loop

– KX0
Nov 15 '18 at 15:24





Have not used that before, so the best is if someone can help me with how Im gonna fetch it all with a for loop

– KX0
Nov 15 '18 at 15:24












2 Answers
2






active

oldest

votes


















1














You can use Promise.all() to run all requests at the same time:



const urls = [
"url i need to fetch",
"url i need to fetch",
"url i need to fetch"
];
Promise
.all( urls.map( url => fetch( url)))
.then( responses => responses.map( response => response.json()))
.then( results =>
// do something with the results array
)
.catch( error =>
// handle the error
);





share|improve this answer






























    1














    You can use a for loop and use let which creates a block level scope



    var urls = ["url1", "url2", "url3"];

    for (let i = 0; i < urls.length; i++)
    fetch(urls[i])
    .then(result => result.json())
    .then((res) =>
    console.log(res);
    createCards(res);
    )
    .catch(err => console.log(err))


    function createCards(card)
    var div = document.getElementById('card');
    div.innerHTML += `<h2>$card.name</h2>
    <div>
    <b>HTML text </b>$someOtherText</div>`






    share|improve this answer

























    • Should mention that the order of output may not be same as order of url array

      – charlietfl
      Nov 15 '18 at 15:33











    • div.innerHTML += ...., else only the last result to arrive will be rendered.

      – Shilly
      Nov 15 '18 at 15:34










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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    You can use Promise.all() to run all requests at the same time:



    const urls = [
    "url i need to fetch",
    "url i need to fetch",
    "url i need to fetch"
    ];
    Promise
    .all( urls.map( url => fetch( url)))
    .then( responses => responses.map( response => response.json()))
    .then( results =>
    // do something with the results array
    )
    .catch( error =>
    // handle the error
    );





    share|improve this answer



























      1














      You can use Promise.all() to run all requests at the same time:



      const urls = [
      "url i need to fetch",
      "url i need to fetch",
      "url i need to fetch"
      ];
      Promise
      .all( urls.map( url => fetch( url)))
      .then( responses => responses.map( response => response.json()))
      .then( results =>
      // do something with the results array
      )
      .catch( error =>
      // handle the error
      );





      share|improve this answer

























        1












        1








        1







        You can use Promise.all() to run all requests at the same time:



        const urls = [
        "url i need to fetch",
        "url i need to fetch",
        "url i need to fetch"
        ];
        Promise
        .all( urls.map( url => fetch( url)))
        .then( responses => responses.map( response => response.json()))
        .then( results =>
        // do something with the results array
        )
        .catch( error =>
        // handle the error
        );





        share|improve this answer













        You can use Promise.all() to run all requests at the same time:



        const urls = [
        "url i need to fetch",
        "url i need to fetch",
        "url i need to fetch"
        ];
        Promise
        .all( urls.map( url => fetch( url)))
        .then( responses => responses.map( response => response.json()))
        .then( results =>
        // do something with the results array
        )
        .catch( error =>
        // handle the error
        );






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 15:29









        ShillyShilly

        5,8331717




        5,8331717























            1














            You can use a for loop and use let which creates a block level scope



            var urls = ["url1", "url2", "url3"];

            for (let i = 0; i < urls.length; i++)
            fetch(urls[i])
            .then(result => result.json())
            .then((res) =>
            console.log(res);
            createCards(res);
            )
            .catch(err => console.log(err))


            function createCards(card)
            var div = document.getElementById('card');
            div.innerHTML += `<h2>$card.name</h2>
            <div>
            <b>HTML text </b>$someOtherText</div>`






            share|improve this answer

























            • Should mention that the order of output may not be same as order of url array

              – charlietfl
              Nov 15 '18 at 15:33











            • div.innerHTML += ...., else only the last result to arrive will be rendered.

              – Shilly
              Nov 15 '18 at 15:34















            1














            You can use a for loop and use let which creates a block level scope



            var urls = ["url1", "url2", "url3"];

            for (let i = 0; i < urls.length; i++)
            fetch(urls[i])
            .then(result => result.json())
            .then((res) =>
            console.log(res);
            createCards(res);
            )
            .catch(err => console.log(err))


            function createCards(card)
            var div = document.getElementById('card');
            div.innerHTML += `<h2>$card.name</h2>
            <div>
            <b>HTML text </b>$someOtherText</div>`






            share|improve this answer

























            • Should mention that the order of output may not be same as order of url array

              – charlietfl
              Nov 15 '18 at 15:33











            • div.innerHTML += ...., else only the last result to arrive will be rendered.

              – Shilly
              Nov 15 '18 at 15:34













            1












            1








            1







            You can use a for loop and use let which creates a block level scope



            var urls = ["url1", "url2", "url3"];

            for (let i = 0; i < urls.length; i++)
            fetch(urls[i])
            .then(result => result.json())
            .then((res) =>
            console.log(res);
            createCards(res);
            )
            .catch(err => console.log(err))


            function createCards(card)
            var div = document.getElementById('card');
            div.innerHTML += `<h2>$card.name</h2>
            <div>
            <b>HTML text </b>$someOtherText</div>`






            share|improve this answer















            You can use a for loop and use let which creates a block level scope



            var urls = ["url1", "url2", "url3"];

            for (let i = 0; i < urls.length; i++)
            fetch(urls[i])
            .then(result => result.json())
            .then((res) =>
            console.log(res);
            createCards(res);
            )
            .catch(err => console.log(err))


            function createCards(card)
            var div = document.getElementById('card');
            div.innerHTML += `<h2>$card.name</h2>
            <div>
            <b>HTML text </b>$someOtherText</div>`







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 15 '18 at 15:34

























            answered Nov 15 '18 at 15:31









            brkbrk

            29.1k32243




            29.1k32243












            • Should mention that the order of output may not be same as order of url array

              – charlietfl
              Nov 15 '18 at 15:33











            • div.innerHTML += ...., else only the last result to arrive will be rendered.

              – Shilly
              Nov 15 '18 at 15:34

















            • Should mention that the order of output may not be same as order of url array

              – charlietfl
              Nov 15 '18 at 15:33











            • div.innerHTML += ...., else only the last result to arrive will be rendered.

              – Shilly
              Nov 15 '18 at 15:34
















            Should mention that the order of output may not be same as order of url array

            – charlietfl
            Nov 15 '18 at 15:33





            Should mention that the order of output may not be same as order of url array

            – charlietfl
            Nov 15 '18 at 15:33













            div.innerHTML += ...., else only the last result to arrive will be rendered.

            – Shilly
            Nov 15 '18 at 15:34





            div.innerHTML += ...., else only the last result to arrive will be rendered.

            – Shilly
            Nov 15 '18 at 15:34

















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