How to map object to Array only for first level. JS

I have the object:

obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value'

I need to map this object to an array

['aVal', bSub_1: 'bSub_1_value', bSub_2: 'bSub_2_value']

I try to use Object.values(obj) but this approach cast all object levels to the array, however, I need casting only first.

How I can do this?

asked Nov 14 '18 at 12:52

Pavel

454622

What is the output you are getting when using Object.values(obj) ?

– Hassan Imam
Nov 14 '18 at 13:01

add a comment |

I have the object:

obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value'

I need to map this object to an array

['aVal', bSub_1: 'bSub_1_value', bSub_2: 'bSub_2_value']

I try to use Object.values(obj) but this approach cast all object levels to the array, however, I need casting only first.

How I can do this?

asked Nov 14 '18 at 12:52

Pavel

454622

What is the output you are getting when using Object.values(obj) ?

– Hassan Imam
Nov 14 '18 at 13:01

add a comment |

I have the object:

obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value'

I need to map this object to an array

['aVal', bSub_1: 'bSub_1_value', bSub_2: 'bSub_2_value']

I try to use Object.values(obj) but this approach cast all object levels to the array, however, I need casting only first.

How I can do this?

asked Nov 14 '18 at 12:52

Pavel

454622

I have the object:

obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value'

I need to map this object to an array

['aVal', bSub_1: 'bSub_1_value', bSub_2: 'bSub_2_value']

I try to use Object.values(obj) but this approach cast all object levels to the array, however, I need casting only first.

How I can do this?

javascript arrays

asked Nov 14 '18 at 12:52

Pavel

454622

asked Nov 14 '18 at 12:52

Pavel

454622

asked Nov 14 '18 at 12:52

Pavel

454622

asked Nov 14 '18 at 12:52

Pavel

454622

asked Nov 14 '18 at 12:52

Pavel

454622

What is the output you are getting when using Object.values(obj) ?

– Hassan Imam
Nov 14 '18 at 13:01

add a comment |

What is the output you are getting when using Object.values(obj) ?

– Hassan Imam
Nov 14 '18 at 13:01

What is the output you are getting when using Object.values(obj) ?

– Hassan Imam
Nov 14 '18 at 13:01

add a comment |

2 Answers
2

active

oldest

votes

This answer is more of clarification rather than answer.

.....however, I need casting only first.

That is not quite clear.

It seems pretty straight with Object.values().

The Object.values() method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).

Please notice how the below snippet produces the exact output you expect:

var obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value' 
 


var res = Object.values(obj);
console.log(res);

edited Nov 14 '18 at 13:17

answered Nov 14 '18 at 12:58

Mamun

27.4k71830

wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.

– Pavel
Nov 14 '18 at 16:28

add a comment |

Just another way of doing the same

 Object.keys(obj).map(e => obj[e])

answered Nov 14 '18 at 13:05

Parnab Sanyal

442313

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

This answer is more of clarification rather than answer.

.....however, I need casting only first.

That is not quite clear.

It seems pretty straight with Object.values().

The Object.values() method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).

Please notice how the below snippet produces the exact output you expect:

var obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value' 
 


var res = Object.values(obj);
console.log(res);

edited Nov 14 '18 at 13:17

answered Nov 14 '18 at 12:58

Mamun

27.4k71830

wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.

– Pavel
Nov 14 '18 at 16:28

add a comment |

This answer is more of clarification rather than answer.

.....however, I need casting only first.

That is not quite clear.

It seems pretty straight with Object.values().

The Object.values() method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).

Please notice how the below snippet produces the exact output you expect:

var obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value' 
 


var res = Object.values(obj);
console.log(res);

edited Nov 14 '18 at 13:17

answered Nov 14 '18 at 12:58

Mamun

27.4k71830

wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.

– Pavel
Nov 14 '18 at 16:28

add a comment |

This answer is more of clarification rather than answer.

.....however, I need casting only first.

That is not quite clear.

It seems pretty straight with Object.values().

The Object.values() method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).

Please notice how the below snippet produces the exact output you expect:

var obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value' 
 


var res = Object.values(obj);
console.log(res);

edited Nov 14 '18 at 13:17

answered Nov 14 '18 at 12:58

Mamun

27.4k71830

This answer is more of clarification rather than answer.

.....however, I need casting only first.

That is not quite clear.

It seems pretty straight with Object.values().

The Object.values() method returns an array of a given object's own enumerable property values, in the same order as that provided by a for...in loop (the difference being that a for-in loop enumerates properties in the prototype chain as well).

Please notice how the below snippet produces the exact output you expect:

var obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value' 
 


var res = Object.values(obj);
console.log(res);

var obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value' 
 


var res = Object.values(obj);
console.log(res);

var obj = 
 a: 'aVal',
 b: 
 bSub_1: 'bSub_1_value',
 bSub_2: 'bSub_2_value' 
 


var res = Object.values(obj);
console.log(res);

edited Nov 14 '18 at 13:17

answered Nov 14 '18 at 12:58

Mamun

27.4k71830

edited Nov 14 '18 at 13:17

answered Nov 14 '18 at 12:58

Mamun

27.4k71830

answered Nov 14 '18 at 12:58

Mamun

27.4k71830

answered Nov 14 '18 at 12:58

Mamun

27.4k71830

wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.

– Pavel
Nov 14 '18 at 16:28

add a comment |

wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.

– Pavel
Nov 14 '18 at 16:28

wow, you right! This not precisely quotes from my app because I wanted to make an easy example. But in reality, I make mistake. Probably I should delete this question. My first solution absolutely right but backend send invalid data in the deep of object and I missed it.

– Pavel
Nov 14 '18 at 16:28

add a comment |

Just another way of doing the same

 Object.keys(obj).map(e => obj[e])

answered Nov 14 '18 at 13:05

Parnab Sanyal

442313

add a comment |

Just another way of doing the same

 Object.keys(obj).map(e => obj[e])

answered Nov 14 '18 at 13:05

Parnab Sanyal

442313

add a comment |

Just another way of doing the same

 Object.keys(obj).map(e => obj[e])

answered Nov 14 '18 at 13:05

Parnab Sanyal

442313

Just another way of doing the same

 Object.keys(obj).map(e => obj[e])

answered Nov 14 '18 at 13:05

Parnab Sanyal

442313

answered Nov 14 '18 at 13:05

Parnab Sanyal

442313

answered Nov 14 '18 at 13:05

Parnab Sanyal

442313

answered Nov 14 '18 at 13:05

Parnab Sanyal

442313

add a comment |

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