How can I bean-validate on a char?
I just found that @Pattern
might work (only) with CharSequence
s.
How can I validate a single char?
//@Pattern(regex = "[YN]") // @@?
private char someYn; // 'Y' or 'N'
Will it blend?
Using an AttributeConverter is not an option.
Oh, is a single char
also a CharSequence
?
java bean-validation
add a comment |
I just found that @Pattern
might work (only) with CharSequence
s.
How can I validate a single char?
//@Pattern(regex = "[YN]") // @@?
private char someYn; // 'Y' or 'N'
Will it blend?
Using an AttributeConverter is not an option.
Oh, is a single char
also a CharSequence
?
java bean-validation
1
@Pattern(regexp = "^[Y|N]1$", message ="Must be Y or N") try this.You cannot use @Pattern for Character variable, You will get exception
– GauravRai1512
Nov 14 '18 at 1:31
@GauravRai1512 Is1
part necessary? I'm not asking about theregex
, anyway, thanks.
– Jin Kwon
Nov 14 '18 at 1:36
Yes, 1 is necessary to match any character.
– GauravRai1512
Nov 14 '18 at 1:39
1
@GauravRai1512 That is not true.1
is completely redundant.
– VGR
Nov 14 '18 at 1:43
add a comment |
I just found that @Pattern
might work (only) with CharSequence
s.
How can I validate a single char?
//@Pattern(regex = "[YN]") // @@?
private char someYn; // 'Y' or 'N'
Will it blend?
Using an AttributeConverter is not an option.
Oh, is a single char
also a CharSequence
?
java bean-validation
I just found that @Pattern
might work (only) with CharSequence
s.
How can I validate a single char?
//@Pattern(regex = "[YN]") // @@?
private char someYn; // 'Y' or 'N'
Will it blend?
Using an AttributeConverter is not an option.
Oh, is a single char
also a CharSequence
?
java bean-validation
java bean-validation
asked Nov 14 '18 at 1:26
Jin KwonJin Kwon
10k666106
10k666106
1
@Pattern(regexp = "^[Y|N]1$", message ="Must be Y or N") try this.You cannot use @Pattern for Character variable, You will get exception
– GauravRai1512
Nov 14 '18 at 1:31
@GauravRai1512 Is1
part necessary? I'm not asking about theregex
, anyway, thanks.
– Jin Kwon
Nov 14 '18 at 1:36
Yes, 1 is necessary to match any character.
– GauravRai1512
Nov 14 '18 at 1:39
1
@GauravRai1512 That is not true.1
is completely redundant.
– VGR
Nov 14 '18 at 1:43
add a comment |
1
@Pattern(regexp = "^[Y|N]1$", message ="Must be Y or N") try this.You cannot use @Pattern for Character variable, You will get exception
– GauravRai1512
Nov 14 '18 at 1:31
@GauravRai1512 Is1
part necessary? I'm not asking about theregex
, anyway, thanks.
– Jin Kwon
Nov 14 '18 at 1:36
Yes, 1 is necessary to match any character.
– GauravRai1512
Nov 14 '18 at 1:39
1
@GauravRai1512 That is not true.1
is completely redundant.
– VGR
Nov 14 '18 at 1:43
1
1
@Pattern(regexp = "^[Y|N]1$", message ="Must be Y or N") try this.You cannot use @Pattern for Character variable, You will get exception
– GauravRai1512
Nov 14 '18 at 1:31
@Pattern(regexp = "^[Y|N]1$", message ="Must be Y or N") try this.You cannot use @Pattern for Character variable, You will get exception
– GauravRai1512
Nov 14 '18 at 1:31
@GauravRai1512 Is
1
part necessary? I'm not asking about the regex
, anyway, thanks.– Jin Kwon
Nov 14 '18 at 1:36
@GauravRai1512 Is
1
part necessary? I'm not asking about the regex
, anyway, thanks.– Jin Kwon
Nov 14 '18 at 1:36
Yes, 1 is necessary to match any character.
– GauravRai1512
Nov 14 '18 at 1:39
Yes, 1 is necessary to match any character.
– GauravRai1512
Nov 14 '18 at 1:39
1
1
@GauravRai1512 That is not true.
1
is completely redundant.– VGR
Nov 14 '18 at 1:43
@GauravRai1512 That is not true.
1
is completely redundant.– VGR
Nov 14 '18 at 1:43
add a comment |
1 Answer
1
active
oldest
votes
You can write your own ConstraintValidator:
https://docs.oracle.com/javaee/7/api/javax/validation/ConstraintValidator.html
Where you can provide annotation and validation type
for which you can define your logic
And then you can annotate your field with your custom annotation
Here is link with steps how to make it :
https://dzone.com/articles/create-your-own-constraint-with-bean-validation-20
As per javax validation documentation :
@Pattern(regex=, flag=) String.
Additionally supported by HV: any sub-type of CharSequence.
Checks if the annotated string matches the regular expression regex considering the given flag
So actually with Character using @Pattern you will get the error
Thanks
Sir, request to confirm,@Pattern
doesn't work forchar
? Thanks.
– Jin Kwon
Nov 14 '18 at 1:46
You can refer to post stackoverflow.com/questions/12599069/…
– Mykhailo Moskura
Nov 14 '18 at 1:53
Updated answer thanks
– Mykhailo Moskura
Nov 14 '18 at 1:59
1
Yes as per javax.validation says we cannot use Character
– Mykhailo Moskura
Nov 14 '18 at 2:04
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can write your own ConstraintValidator:
https://docs.oracle.com/javaee/7/api/javax/validation/ConstraintValidator.html
Where you can provide annotation and validation type
for which you can define your logic
And then you can annotate your field with your custom annotation
Here is link with steps how to make it :
https://dzone.com/articles/create-your-own-constraint-with-bean-validation-20
As per javax validation documentation :
@Pattern(regex=, flag=) String.
Additionally supported by HV: any sub-type of CharSequence.
Checks if the annotated string matches the regular expression regex considering the given flag
So actually with Character using @Pattern you will get the error
Thanks
Sir, request to confirm,@Pattern
doesn't work forchar
? Thanks.
– Jin Kwon
Nov 14 '18 at 1:46
You can refer to post stackoverflow.com/questions/12599069/…
– Mykhailo Moskura
Nov 14 '18 at 1:53
Updated answer thanks
– Mykhailo Moskura
Nov 14 '18 at 1:59
1
Yes as per javax.validation says we cannot use Character
– Mykhailo Moskura
Nov 14 '18 at 2:04
add a comment |
You can write your own ConstraintValidator:
https://docs.oracle.com/javaee/7/api/javax/validation/ConstraintValidator.html
Where you can provide annotation and validation type
for which you can define your logic
And then you can annotate your field with your custom annotation
Here is link with steps how to make it :
https://dzone.com/articles/create-your-own-constraint-with-bean-validation-20
As per javax validation documentation :
@Pattern(regex=, flag=) String.
Additionally supported by HV: any sub-type of CharSequence.
Checks if the annotated string matches the regular expression regex considering the given flag
So actually with Character using @Pattern you will get the error
Thanks
Sir, request to confirm,@Pattern
doesn't work forchar
? Thanks.
– Jin Kwon
Nov 14 '18 at 1:46
You can refer to post stackoverflow.com/questions/12599069/…
– Mykhailo Moskura
Nov 14 '18 at 1:53
Updated answer thanks
– Mykhailo Moskura
Nov 14 '18 at 1:59
1
Yes as per javax.validation says we cannot use Character
– Mykhailo Moskura
Nov 14 '18 at 2:04
add a comment |
You can write your own ConstraintValidator:
https://docs.oracle.com/javaee/7/api/javax/validation/ConstraintValidator.html
Where you can provide annotation and validation type
for which you can define your logic
And then you can annotate your field with your custom annotation
Here is link with steps how to make it :
https://dzone.com/articles/create-your-own-constraint-with-bean-validation-20
As per javax validation documentation :
@Pattern(regex=, flag=) String.
Additionally supported by HV: any sub-type of CharSequence.
Checks if the annotated string matches the regular expression regex considering the given flag
So actually with Character using @Pattern you will get the error
Thanks
You can write your own ConstraintValidator:
https://docs.oracle.com/javaee/7/api/javax/validation/ConstraintValidator.html
Where you can provide annotation and validation type
for which you can define your logic
And then you can annotate your field with your custom annotation
Here is link with steps how to make it :
https://dzone.com/articles/create-your-own-constraint-with-bean-validation-20
As per javax validation documentation :
@Pattern(regex=, flag=) String.
Additionally supported by HV: any sub-type of CharSequence.
Checks if the annotated string matches the regular expression regex considering the given flag
So actually with Character using @Pattern you will get the error
Thanks
edited Nov 14 '18 at 2:05
answered Nov 14 '18 at 1:42
Mykhailo MoskuraMykhailo Moskura
838113
838113
Sir, request to confirm,@Pattern
doesn't work forchar
? Thanks.
– Jin Kwon
Nov 14 '18 at 1:46
You can refer to post stackoverflow.com/questions/12599069/…
– Mykhailo Moskura
Nov 14 '18 at 1:53
Updated answer thanks
– Mykhailo Moskura
Nov 14 '18 at 1:59
1
Yes as per javax.validation says we cannot use Character
– Mykhailo Moskura
Nov 14 '18 at 2:04
add a comment |
Sir, request to confirm,@Pattern
doesn't work forchar
? Thanks.
– Jin Kwon
Nov 14 '18 at 1:46
You can refer to post stackoverflow.com/questions/12599069/…
– Mykhailo Moskura
Nov 14 '18 at 1:53
Updated answer thanks
– Mykhailo Moskura
Nov 14 '18 at 1:59
1
Yes as per javax.validation says we cannot use Character
– Mykhailo Moskura
Nov 14 '18 at 2:04
Sir, request to confirm,
@Pattern
doesn't work for char
? Thanks.– Jin Kwon
Nov 14 '18 at 1:46
Sir, request to confirm,
@Pattern
doesn't work for char
? Thanks.– Jin Kwon
Nov 14 '18 at 1:46
You can refer to post stackoverflow.com/questions/12599069/…
– Mykhailo Moskura
Nov 14 '18 at 1:53
You can refer to post stackoverflow.com/questions/12599069/…
– Mykhailo Moskura
Nov 14 '18 at 1:53
Updated answer thanks
– Mykhailo Moskura
Nov 14 '18 at 1:59
Updated answer thanks
– Mykhailo Moskura
Nov 14 '18 at 1:59
1
1
Yes as per javax.validation says we cannot use Character
– Mykhailo Moskura
Nov 14 '18 at 2:04
Yes as per javax.validation says we cannot use Character
– Mykhailo Moskura
Nov 14 '18 at 2:04
add a comment |
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1
@Pattern(regexp = "^[Y|N]1$", message ="Must be Y or N") try this.You cannot use @Pattern for Character variable, You will get exception
– GauravRai1512
Nov 14 '18 at 1:31
@GauravRai1512 Is
1
part necessary? I'm not asking about theregex
, anyway, thanks.– Jin Kwon
Nov 14 '18 at 1:36
Yes, 1 is necessary to match any character.
– GauravRai1512
Nov 14 '18 at 1:39
1
@GauravRai1512 That is not true.
1
is completely redundant.– VGR
Nov 14 '18 at 1:43