Create multiple new variables that are calculated from existing variables
I'm trying to figure out how to create multiple new variables that are calculated using variables currently in my dataset
Here's some example data
library(tidyverse)
df <- data.frame(
a1 = rnorm(100),
a2 = rnorm(100),
b1 = rnorm(100),
b2 = rnorm(100),
c1 = rnorm(100),
c2 = rnorm(100)
)
Essentially, I want to create a new variable for each a, b, c pair that divides a1 by a2, b1 by b2, etc. For example:
df <- df %>%
mutate(a3 = a1/a2)
The variables in my dataset don't follow these naming conventions, so I feel like I need to assign names to vectors:
numerators <- c('a1', 'b1', 'c1')
denominators <- c('a2', 'b2', 'c2')
And then creating a new variable would follow the basic convention
mutate(newvars = numerators/denominators)
But I'm stuck as to how to actually do this. Any help would be much appreciated -- thanks!
r dplyr iteration purrr
asked Nov 14 '18 at 0:57
EkholmeEkholme
605
add a comment |
I'm trying to figure out how to create multiple new variables that are calculated using variables currently in my dataset
Here's some example data
library(tidyverse)
df <- data.frame(
a1 = rnorm(100),
a2 = rnorm(100),
b1 = rnorm(100),
b2 = rnorm(100),
c1 = rnorm(100),
c2 = rnorm(100)
)
Essentially, I want to create a new variable for each a, b, c pair that divides a1 by a2, b1 by b2, etc. For example:
df <- df %>%
mutate(a3 = a1/a2)
The variables in my dataset don't follow these naming conventions, so I feel like I need to assign names to vectors:
numerators <- c('a1', 'b1', 'c1')
denominators <- c('a2', 'b2', 'c2')
And then creating a new variable would follow the basic convention
mutate(newvars = numerators/denominators)
But I'm stuck as to how to actually do this. Any help would be much appreciated -- thanks!
r dplyr iteration purrr
asked Nov 14 '18 at 0:57
EkholmeEkholme
605
add a comment |
I'm trying to figure out how to create multiple new variables that are calculated using variables currently in my dataset
Here's some example data
library(tidyverse)
df <- data.frame(
a1 = rnorm(100),
a2 = rnorm(100),
b1 = rnorm(100),
b2 = rnorm(100),
c1 = rnorm(100),
c2 = rnorm(100)
)
Essentially, I want to create a new variable for each a, b, c pair that divides a1 by a2, b1 by b2, etc. For example:
df <- df %>%
mutate(a3 = a1/a2)
The variables in my dataset don't follow these naming conventions, so I feel like I need to assign names to vectors:
numerators <- c('a1', 'b1', 'c1')
denominators <- c('a2', 'b2', 'c2')
And then creating a new variable would follow the basic convention
mutate(newvars = numerators/denominators)
But I'm stuck as to how to actually do this. Any help would be much appreciated -- thanks!
r dplyr iteration purrr
asked Nov 14 '18 at 0:57
EkholmeEkholme
605
I'm trying to figure out how to create multiple new variables that are calculated using variables currently in my dataset
Here's some example data
library(tidyverse)
df <- data.frame(
a1 = rnorm(100),
a2 = rnorm(100),
b1 = rnorm(100),
b2 = rnorm(100),
c1 = rnorm(100),
c2 = rnorm(100)
)
Essentially, I want to create a new variable for each a, b, c pair that divides a1 by a2, b1 by b2, etc. For example:
df <- df %>%
mutate(a3 = a1/a2)
The variables in my dataset don't follow these naming conventions, so I feel like I need to assign names to vectors:
numerators <- c('a1', 'b1', 'c1')
denominators <- c('a2', 'b2', 'c2')
And then creating a new variable would follow the basic convention
mutate(newvars = numerators/denominators)
But I'm stuck as to how to actually do this. Any help would be much appreciated -- thanks!
r dplyr iteration purrr
r dplyr iteration purrr
asked Nov 14 '18 at 0:57
EkholmeEkholme
605
asked Nov 14 '18 at 0:57
EkholmeEkholme
605
asked Nov 14 '18 at 0:57
EkholmeEkholme
605
asked Nov 14 '18 at 0:57
EkholmeEkholme
605
asked Nov 14 '18 at 0:57
EkholmeEkholme
605
605
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Here is an option to split the dataset into a list of data.frame based on the column name pattern, then reduce it by dividing elementwise on each pair of columns in each of the dataset and bind with the original dataset
library(tidyverse)
df %>%
split.default(sub("\d+", "", names(.))) %>%
map_df(reduce, `/`) %>%
rename_all(~paste0(., 3)) %>%
bind_cols(df, .)
answered Nov 14 '18 at 4:07
akrunakrun
405k13196270
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53291670%2fcreate-multiple-new-variables-that-are-calculated-from-existing-variables%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here is an option to split the dataset into a list of data.frame based on the column name pattern, then reduce it by dividing elementwise on each pair of columns in each of the dataset and bind with the original dataset
library(tidyverse)
df %>%
split.default(sub("\d+", "", names(.))) %>%
map_df(reduce, `/`) %>%
rename_all(~paste0(., 3)) %>%
bind_cols(df, .)
answered Nov 14 '18 at 4:07
akrunakrun
405k13196270
add a comment |
Here is an option to split the dataset into a list of data.frame based on the column name pattern, then reduce it by dividing elementwise on each pair of columns in each of the dataset and bind with the original dataset
library(tidyverse)
df %>%
split.default(sub("\d+", "", names(.))) %>%
map_df(reduce, `/`) %>%
rename_all(~paste0(., 3)) %>%
bind_cols(df, .)
answered Nov 14 '18 at 4:07
akrunakrun
405k13196270
add a comment |
Here is an option to split the dataset into a list of data.frame based on the column name pattern, then reduce it by dividing elementwise on each pair of columns in each of the dataset and bind with the original dataset
library(tidyverse)
df %>%
split.default(sub("\d+", "", names(.))) %>%
map_df(reduce, `/`) %>%
rename_all(~paste0(., 3)) %>%
bind_cols(df, .)
answered Nov 14 '18 at 4:07
akrunakrun
405k13196270
Here is an option to split the dataset into a list of data.frame based on the column name pattern, then reduce it by dividing elementwise on each pair of columns in each of the dataset and bind with the original dataset
library(tidyverse)
df %>%
split.default(sub("\d+", "", names(.))) %>%
map_df(reduce, `/`) %>%
rename_all(~paste0(., 3)) %>%
bind_cols(df, .)
answered Nov 14 '18 at 4:07
akrunakrun
405k13196270
answered Nov 14 '18 at 4:07
akrunakrun
405k13196270
answered Nov 14 '18 at 4:07
akrunakrun
405k13196270
answered Nov 14 '18 at 4:07
akrunakrun
405k13196270
405k13196270
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53291670%2fcreate-multiple-new-variables-that-are-calculated-from-existing-variables%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
