Tkinter Optionmenu StringVar.get() returning blank
I am creating a Tkinter window with a 'for loop' so it can self-adjust if later on, I decide to add more questions. My issue is that I can't save the inputted value on the optionmenu. So far all I got was a list1 = ['', '', '']
while the Strg_var = [StringVar, StringVar, StringVar]
and it prints only the blanks and the variables PY_numbers.
import tkinter as tk
from tkinter import *
LARGE_FONT = ("Arial", 12)
window=Tk()
def _save():
print(*list1, sep = ", ")
print(*Strg_var, sep = ", ")
Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]
choices = ['-', 'Yes', 'No']
n = 0
Strg_var=[0]*len(Questionlist)
list1=
for n in range(len(Questionlist)):
Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
a = tk.StringVar(window)
OptionMenu(window, a, choices[0], *choices).grid(row = n, column=2, padx=10, sticky="WE")
list1.append(a.get())
tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")
window.mainloop()
Can someone help me to sort this out on how to save the optionmenu user selections into a list or any other way?
python tkinter optionmenu
add a comment |
I am creating a Tkinter window with a 'for loop' so it can self-adjust if later on, I decide to add more questions. My issue is that I can't save the inputted value on the optionmenu. So far all I got was a list1 = ['', '', '']
while the Strg_var = [StringVar, StringVar, StringVar]
and it prints only the blanks and the variables PY_numbers.
import tkinter as tk
from tkinter import *
LARGE_FONT = ("Arial", 12)
window=Tk()
def _save():
print(*list1, sep = ", ")
print(*Strg_var, sep = ", ")
Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]
choices = ['-', 'Yes', 'No']
n = 0
Strg_var=[0]*len(Questionlist)
list1=
for n in range(len(Questionlist)):
Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
a = tk.StringVar(window)
OptionMenu(window, a, choices[0], *choices).grid(row = n, column=2, padx=10, sticky="WE")
list1.append(a.get())
tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")
window.mainloop()
Can someone help me to sort this out on how to save the optionmenu user selections into a list or any other way?
python tkinter optionmenu
add a comment |
I am creating a Tkinter window with a 'for loop' so it can self-adjust if later on, I decide to add more questions. My issue is that I can't save the inputted value on the optionmenu. So far all I got was a list1 = ['', '', '']
while the Strg_var = [StringVar, StringVar, StringVar]
and it prints only the blanks and the variables PY_numbers.
import tkinter as tk
from tkinter import *
LARGE_FONT = ("Arial", 12)
window=Tk()
def _save():
print(*list1, sep = ", ")
print(*Strg_var, sep = ", ")
Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]
choices = ['-', 'Yes', 'No']
n = 0
Strg_var=[0]*len(Questionlist)
list1=
for n in range(len(Questionlist)):
Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
a = tk.StringVar(window)
OptionMenu(window, a, choices[0], *choices).grid(row = n, column=2, padx=10, sticky="WE")
list1.append(a.get())
tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")
window.mainloop()
Can someone help me to sort this out on how to save the optionmenu user selections into a list or any other way?
python tkinter optionmenu
I am creating a Tkinter window with a 'for loop' so it can self-adjust if later on, I decide to add more questions. My issue is that I can't save the inputted value on the optionmenu. So far all I got was a list1 = ['', '', '']
while the Strg_var = [StringVar, StringVar, StringVar]
and it prints only the blanks and the variables PY_numbers.
import tkinter as tk
from tkinter import *
LARGE_FONT = ("Arial", 12)
window=Tk()
def _save():
print(*list1, sep = ", ")
print(*Strg_var, sep = ", ")
Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]
choices = ['-', 'Yes', 'No']
n = 0
Strg_var=[0]*len(Questionlist)
list1=
for n in range(len(Questionlist)):
Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
a = tk.StringVar(window)
OptionMenu(window, a, choices[0], *choices).grid(row = n, column=2, padx=10, sticky="WE")
list1.append(a.get())
tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")
window.mainloop()
Can someone help me to sort this out on how to save the optionmenu user selections into a list or any other way?
python tkinter optionmenu
python tkinter optionmenu
edited Nov 13 '18 at 16:58
Miraj50
2,7351824
2,7351824
asked Nov 13 '18 at 14:57
Rafael Castelo BrancoRafael Castelo Branco
395
395
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can make a list of StringVar
(Do Initialise them, I haven't done that in my code). Every time an option is selected the corresponding item will change. So I would do it like this.
import tkinter as tk
LARGE_FONT = ("Arial", 12)
window=tk.Tk()
def _save():
print(list(map(lambda x: x.get(), a)))
Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]
choices = ['-', 'Yes', 'No']
a = [tk.StringVar(window) for i in range(len(Questionlist))]
n = 0
for n in range(len(Questionlist)):
tk.Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
Strg_var = tk.StringVar(window)
tk.OptionMenu(window, a[n], *choices).grid(row = n, column=2, padx=10, sticky="WE")
tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")
window.mainloop()
Output:
['No', '-', 'Yes']
One issue that appeared is that if user decides to change its answer the list won't understand that, so I can't manipulate the end result, which is one of the objectives of the program. Do you have any idea on how to solve that?
– Rafael Castelo Branco
Nov 13 '18 at 16:01
@RafaelCasteloBranco Edited my answer. See if it fits your description.
– Miraj50
Nov 13 '18 at 16:35
Thanks! it worked with a small adjustment as the list becomes a local variable and I can't work with it, but setting it as a global variable 'z' makes the charm work def _save(): global z z= list(map(lambda x: x.get(), a)) print(z)
– Rafael Castelo Branco
Nov 13 '18 at 17:01
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can make a list of StringVar
(Do Initialise them, I haven't done that in my code). Every time an option is selected the corresponding item will change. So I would do it like this.
import tkinter as tk
LARGE_FONT = ("Arial", 12)
window=tk.Tk()
def _save():
print(list(map(lambda x: x.get(), a)))
Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]
choices = ['-', 'Yes', 'No']
a = [tk.StringVar(window) for i in range(len(Questionlist))]
n = 0
for n in range(len(Questionlist)):
tk.Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
Strg_var = tk.StringVar(window)
tk.OptionMenu(window, a[n], *choices).grid(row = n, column=2, padx=10, sticky="WE")
tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")
window.mainloop()
Output:
['No', '-', 'Yes']
One issue that appeared is that if user decides to change its answer the list won't understand that, so I can't manipulate the end result, which is one of the objectives of the program. Do you have any idea on how to solve that?
– Rafael Castelo Branco
Nov 13 '18 at 16:01
@RafaelCasteloBranco Edited my answer. See if it fits your description.
– Miraj50
Nov 13 '18 at 16:35
Thanks! it worked with a small adjustment as the list becomes a local variable and I can't work with it, but setting it as a global variable 'z' makes the charm work def _save(): global z z= list(map(lambda x: x.get(), a)) print(z)
– Rafael Castelo Branco
Nov 13 '18 at 17:01
add a comment |
You can make a list of StringVar
(Do Initialise them, I haven't done that in my code). Every time an option is selected the corresponding item will change. So I would do it like this.
import tkinter as tk
LARGE_FONT = ("Arial", 12)
window=tk.Tk()
def _save():
print(list(map(lambda x: x.get(), a)))
Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]
choices = ['-', 'Yes', 'No']
a = [tk.StringVar(window) for i in range(len(Questionlist))]
n = 0
for n in range(len(Questionlist)):
tk.Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
Strg_var = tk.StringVar(window)
tk.OptionMenu(window, a[n], *choices).grid(row = n, column=2, padx=10, sticky="WE")
tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")
window.mainloop()
Output:
['No', '-', 'Yes']
One issue that appeared is that if user decides to change its answer the list won't understand that, so I can't manipulate the end result, which is one of the objectives of the program. Do you have any idea on how to solve that?
– Rafael Castelo Branco
Nov 13 '18 at 16:01
@RafaelCasteloBranco Edited my answer. See if it fits your description.
– Miraj50
Nov 13 '18 at 16:35
Thanks! it worked with a small adjustment as the list becomes a local variable and I can't work with it, but setting it as a global variable 'z' makes the charm work def _save(): global z z= list(map(lambda x: x.get(), a)) print(z)
– Rafael Castelo Branco
Nov 13 '18 at 17:01
add a comment |
You can make a list of StringVar
(Do Initialise them, I haven't done that in my code). Every time an option is selected the corresponding item will change. So I would do it like this.
import tkinter as tk
LARGE_FONT = ("Arial", 12)
window=tk.Tk()
def _save():
print(list(map(lambda x: x.get(), a)))
Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]
choices = ['-', 'Yes', 'No']
a = [tk.StringVar(window) for i in range(len(Questionlist))]
n = 0
for n in range(len(Questionlist)):
tk.Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
Strg_var = tk.StringVar(window)
tk.OptionMenu(window, a[n], *choices).grid(row = n, column=2, padx=10, sticky="WE")
tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")
window.mainloop()
Output:
['No', '-', 'Yes']
You can make a list of StringVar
(Do Initialise them, I haven't done that in my code). Every time an option is selected the corresponding item will change. So I would do it like this.
import tkinter as tk
LARGE_FONT = ("Arial", 12)
window=tk.Tk()
def _save():
print(list(map(lambda x: x.get(), a)))
Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]
choices = ['-', 'Yes', 'No']
a = [tk.StringVar(window) for i in range(len(Questionlist))]
n = 0
for n in range(len(Questionlist)):
tk.Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
Strg_var = tk.StringVar(window)
tk.OptionMenu(window, a[n], *choices).grid(row = n, column=2, padx=10, sticky="WE")
tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")
window.mainloop()
Output:
['No', '-', 'Yes']
edited Nov 13 '18 at 16:34
answered Nov 13 '18 at 15:27
Miraj50Miraj50
2,7351824
2,7351824
One issue that appeared is that if user decides to change its answer the list won't understand that, so I can't manipulate the end result, which is one of the objectives of the program. Do you have any idea on how to solve that?
– Rafael Castelo Branco
Nov 13 '18 at 16:01
@RafaelCasteloBranco Edited my answer. See if it fits your description.
– Miraj50
Nov 13 '18 at 16:35
Thanks! it worked with a small adjustment as the list becomes a local variable and I can't work with it, but setting it as a global variable 'z' makes the charm work def _save(): global z z= list(map(lambda x: x.get(), a)) print(z)
– Rafael Castelo Branco
Nov 13 '18 at 17:01
add a comment |
One issue that appeared is that if user decides to change its answer the list won't understand that, so I can't manipulate the end result, which is one of the objectives of the program. Do you have any idea on how to solve that?
– Rafael Castelo Branco
Nov 13 '18 at 16:01
@RafaelCasteloBranco Edited my answer. See if it fits your description.
– Miraj50
Nov 13 '18 at 16:35
Thanks! it worked with a small adjustment as the list becomes a local variable and I can't work with it, but setting it as a global variable 'z' makes the charm work def _save(): global z z= list(map(lambda x: x.get(), a)) print(z)
– Rafael Castelo Branco
Nov 13 '18 at 17:01
One issue that appeared is that if user decides to change its answer the list won't understand that, so I can't manipulate the end result, which is one of the objectives of the program. Do you have any idea on how to solve that?
– Rafael Castelo Branco
Nov 13 '18 at 16:01
One issue that appeared is that if user decides to change its answer the list won't understand that, so I can't manipulate the end result, which is one of the objectives of the program. Do you have any idea on how to solve that?
– Rafael Castelo Branco
Nov 13 '18 at 16:01
@RafaelCasteloBranco Edited my answer. See if it fits your description.
– Miraj50
Nov 13 '18 at 16:35
@RafaelCasteloBranco Edited my answer. See if it fits your description.
– Miraj50
Nov 13 '18 at 16:35
Thanks! it worked with a small adjustment as the list becomes a local variable and I can't work with it, but setting it as a global variable 'z' makes the charm work def _save(): global z z= list(map(lambda x: x.get(), a)) print(z)
– Rafael Castelo Branco
Nov 13 '18 at 17:01
Thanks! it worked with a small adjustment as the list becomes a local variable and I can't work with it, but setting it as a global variable 'z' makes the charm work def _save(): global z z= list(map(lambda x: x.get(), a)) print(z)
– Rafael Castelo Branco
Nov 13 '18 at 17:01
add a comment |
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