Count specific individual letters within a list of strings [duplicate]

This question already has an answer here:

Count multiple letters in string Python

3 answers

Note: NOT a duplicate..I want to know the individual counts of each letter, the one you posted as duplicate gives the total count of each one.

I am trying to count the individual letters from all the strings which are stored in a list.

def countElement(a):
 g = 
 for i in a:
 if i in g: 
 g[i] +=1
 else: 
 g[i] =1
 return g

list : ['a a b b c c', 'a c b c', 'b c c a b']



 for i in range(1000000):
 b = countElement(list)
 print(b)

At the moment this produces the result:

'a a b b c c': 1, 'a c b c': 1, 'b c c a b': 1

But the result that I actually want to achieve is:

a = 4
b = 5
c = 6

Is there a different function that I can use which will count the individual letters within the strings in the list?

edited Nov 13 '18 at 0:17

asked Nov 13 '18 at 0:13

JameshGong

486

marked as duplicate by Prune python
Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
Nov 13 '18 at 0:16

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

This question is slightly different than the one you used to mark as duplicate.
– Naidu
Nov 13 '18 at 0:20

add a comment |

This question already has an answer here:

Count multiple letters in string Python

3 answers

Note: NOT a duplicate..I want to know the individual counts of each letter, the one you posted as duplicate gives the total count of each one.

I am trying to count the individual letters from all the strings which are stored in a list.

def countElement(a):
 g = 
 for i in a:
 if i in g: 
 g[i] +=1
 else: 
 g[i] =1
 return g

list : ['a a b b c c', 'a c b c', 'b c c a b']



 for i in range(1000000):
 b = countElement(list)
 print(b)

At the moment this produces the result:

'a a b b c c': 1, 'a c b c': 1, 'b c c a b': 1

But the result that I actually want to achieve is:

a = 4
b = 5
c = 6

Is there a different function that I can use which will count the individual letters within the strings in the list?

edited Nov 13 '18 at 0:17

asked Nov 13 '18 at 0:13

JameshGong

486

marked as duplicate by Prune python
Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
Nov 13 '18 at 0:16

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

This question is slightly different than the one you used to mark as duplicate.
– Naidu
Nov 13 '18 at 0:20

add a comment |

This question already has an answer here:

Count multiple letters in string Python

3 answers

Note: NOT a duplicate..I want to know the individual counts of each letter, the one you posted as duplicate gives the total count of each one.

I am trying to count the individual letters from all the strings which are stored in a list.

def countElement(a):
 g = 
 for i in a:
 if i in g: 
 g[i] +=1
 else: 
 g[i] =1
 return g

list : ['a a b b c c', 'a c b c', 'b c c a b']



 for i in range(1000000):
 b = countElement(list)
 print(b)

At the moment this produces the result:

'a a b b c c': 1, 'a c b c': 1, 'b c c a b': 1

But the result that I actually want to achieve is:

a = 4
b = 5
c = 6

Is there a different function that I can use which will count the individual letters within the strings in the list?

edited Nov 13 '18 at 0:17

asked Nov 13 '18 at 0:13

JameshGong

486

This question already has an answer here:

Count multiple letters in string Python

3 answers

Note: NOT a duplicate..I want to know the individual counts of each letter, the one you posted as duplicate gives the total count of each one.

I am trying to count the individual letters from all the strings which are stored in a list.

def countElement(a):
 g = 
 for i in a:
 if i in g: 
 g[i] +=1
 else: 
 g[i] =1
 return g

list : ['a a b b c c', 'a c b c', 'b c c a b']



 for i in range(1000000):
 b = countElement(list)
 print(b)

At the moment this produces the result:

'a a b b c c': 1, 'a c b c': 1, 'b c c a b': 1

But the result that I actually want to achieve is:

a = 4
b = 5
c = 6

Is there a different function that I can use which will count the individual letters within the strings in the list?

This question already has an answer here:

Count multiple letters in string Python

3 answers

python python-3.x

edited Nov 13 '18 at 0:17

asked Nov 13 '18 at 0:13

JameshGong

486

edited Nov 13 '18 at 0:17

asked Nov 13 '18 at 0:13

JameshGong

486

edited Nov 13 '18 at 0:17

asked Nov 13 '18 at 0:13

JameshGong

486

asked Nov 13 '18 at 0:13

JameshGong

486

asked Nov 13 '18 at 0:13

JameshGong

486

marked as duplicate by Prune python
Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
Nov 13 '18 at 0:16

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by Prune python
Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
);
);
Nov 13 '18 at 0:16

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

This question is slightly different than the one you used to mark as duplicate.
– Naidu
Nov 13 '18 at 0:20

add a comment |

This question is slightly different than the one you used to mark as duplicate.
– Naidu
Nov 13 '18 at 0:20

This question is slightly different than the one you used to mark as duplicate.
– Naidu
Nov 13 '18 at 0:20

add a comment |

1 Answer
1

active

oldest

votes

Sure! Use collections.Counter:

from collections import Counter


lst = ['a a b b c c', 'a c b c', 'b c c a b']

counter = Counter()
for word in lst:
 counter.update(word)

print(counter)
# Counter(' ': 12, 'c': 6, 'b': 5, 'a': 4)

edited Nov 13 '18 at 0:24

answered Nov 13 '18 at 0:17

Ben

2,67021524

add a comment |

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Sure! Use collections.Counter:

from collections import Counter


lst = ['a a b b c c', 'a c b c', 'b c c a b']

counter = Counter()
for word in lst:
 counter.update(word)

print(counter)
# Counter(' ': 12, 'c': 6, 'b': 5, 'a': 4)

edited Nov 13 '18 at 0:24

answered Nov 13 '18 at 0:17

Ben

2,67021524

add a comment |

Sure! Use collections.Counter:

from collections import Counter


lst = ['a a b b c c', 'a c b c', 'b c c a b']

counter = Counter()
for word in lst:
 counter.update(word)

print(counter)
# Counter(' ': 12, 'c': 6, 'b': 5, 'a': 4)

edited Nov 13 '18 at 0:24

answered Nov 13 '18 at 0:17

Ben

2,67021524

add a comment |

Sure! Use collections.Counter:

from collections import Counter


lst = ['a a b b c c', 'a c b c', 'b c c a b']

counter = Counter()
for word in lst:
 counter.update(word)

print(counter)
# Counter(' ': 12, 'c': 6, 'b': 5, 'a': 4)

edited Nov 13 '18 at 0:24

answered Nov 13 '18 at 0:17

Ben

2,67021524

Sure! Use collections.Counter:

from collections import Counter


lst = ['a a b b c c', 'a c b c', 'b c c a b']

counter = Counter()
for word in lst:
 counter.update(word)

print(counter)
# Counter(' ': 12, 'c': 6, 'b': 5, 'a': 4)

edited Nov 13 '18 at 0:24

answered Nov 13 '18 at 0:17

Ben

2,67021524

edited Nov 13 '18 at 0:24

answered Nov 13 '18 at 0:17

Ben

2,67021524

answered Nov 13 '18 at 0:17

Ben

2,67021524

answered Nov 13 '18 at 0:17

Ben

2,67021524

add a comment |

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Odtnhj