SSAS: Get a distinct Count based on two different elements









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I need to create a distinct count of people who fall into two different dimensions.



One is called [Student Research Degree].[Is Research Degree Current].&[Yes]
The other is called [Student Research Degree].[Is Research Degree Complete].&[Yes]



If one or the other are Yes, or both, then I need to count the record.
If both are no, I can exclude it. I have a row counter measure called [Measures].[Student ID Distinct Count Hidden] already in place.



If I use just one element with the measure, I get the right answer, but if I try to cross join the other elements, I get a result of NULL.



eg



AGGREGATE(CROSSJOIN(
[Student Research Degree].[Is Research Degree Current].&[Yes]
,[Student Research Degree].[Is Research Degree Complete].&[Yes]
), [Measures].[Student ID Distinct Count Hidden])


I am aware that I can just land an extra value in the ETL, and have SQL do the work, and in the end this might be the solution. Is there a way of doing an OR statement on this sort of thing?










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  • Distinct count is a very problematic measure. I would strongly suggest doing it via the SQL since the measure that you've got in place won't help you. Look here: blog.tallan.com/2017/02/09/…
    – Hila DG
    Nov 12 at 2:24










  • Does this code work for you ? AGGREGATE( [Student Research Degree].[Is Research Degree Current].&[Yes] ,[Student Research Degree].[Is Research Degree Complete].&[Yes] , [Measures].[Student ID Distinct Count Hidden])
    – NickNick
    Nov 12 at 10:29














up vote
0
down vote

favorite












I need to create a distinct count of people who fall into two different dimensions.



One is called [Student Research Degree].[Is Research Degree Current].&[Yes]
The other is called [Student Research Degree].[Is Research Degree Complete].&[Yes]



If one or the other are Yes, or both, then I need to count the record.
If both are no, I can exclude it. I have a row counter measure called [Measures].[Student ID Distinct Count Hidden] already in place.



If I use just one element with the measure, I get the right answer, but if I try to cross join the other elements, I get a result of NULL.



eg



AGGREGATE(CROSSJOIN(
[Student Research Degree].[Is Research Degree Current].&[Yes]
,[Student Research Degree].[Is Research Degree Complete].&[Yes]
), [Measures].[Student ID Distinct Count Hidden])


I am aware that I can just land an extra value in the ETL, and have SQL do the work, and in the end this might be the solution. Is there a way of doing an OR statement on this sort of thing?










share|improve this question





















  • Distinct count is a very problematic measure. I would strongly suggest doing it via the SQL since the measure that you've got in place won't help you. Look here: blog.tallan.com/2017/02/09/…
    – Hila DG
    Nov 12 at 2:24










  • Does this code work for you ? AGGREGATE( [Student Research Degree].[Is Research Degree Current].&[Yes] ,[Student Research Degree].[Is Research Degree Complete].&[Yes] , [Measures].[Student ID Distinct Count Hidden])
    – NickNick
    Nov 12 at 10:29












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I need to create a distinct count of people who fall into two different dimensions.



One is called [Student Research Degree].[Is Research Degree Current].&[Yes]
The other is called [Student Research Degree].[Is Research Degree Complete].&[Yes]



If one or the other are Yes, or both, then I need to count the record.
If both are no, I can exclude it. I have a row counter measure called [Measures].[Student ID Distinct Count Hidden] already in place.



If I use just one element with the measure, I get the right answer, but if I try to cross join the other elements, I get a result of NULL.



eg



AGGREGATE(CROSSJOIN(
[Student Research Degree].[Is Research Degree Current].&[Yes]
,[Student Research Degree].[Is Research Degree Complete].&[Yes]
), [Measures].[Student ID Distinct Count Hidden])


I am aware that I can just land an extra value in the ETL, and have SQL do the work, and in the end this might be the solution. Is there a way of doing an OR statement on this sort of thing?










share|improve this question













I need to create a distinct count of people who fall into two different dimensions.



One is called [Student Research Degree].[Is Research Degree Current].&[Yes]
The other is called [Student Research Degree].[Is Research Degree Complete].&[Yes]



If one or the other are Yes, or both, then I need to count the record.
If both are no, I can exclude it. I have a row counter measure called [Measures].[Student ID Distinct Count Hidden] already in place.



If I use just one element with the measure, I get the right answer, but if I try to cross join the other elements, I get a result of NULL.



eg



AGGREGATE(CROSSJOIN(
[Student Research Degree].[Is Research Degree Current].&[Yes]
,[Student Research Degree].[Is Research Degree Complete].&[Yes]
), [Measures].[Student ID Distinct Count Hidden])


I am aware that I can just land an extra value in the ETL, and have SQL do the work, and in the end this might be the solution. Is there a way of doing an OR statement on this sort of thing?







sql ssas mdx cube






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asked Nov 12 at 1:52









Peppermallow

387




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  • Distinct count is a very problematic measure. I would strongly suggest doing it via the SQL since the measure that you've got in place won't help you. Look here: blog.tallan.com/2017/02/09/…
    – Hila DG
    Nov 12 at 2:24










  • Does this code work for you ? AGGREGATE( [Student Research Degree].[Is Research Degree Current].&[Yes] ,[Student Research Degree].[Is Research Degree Complete].&[Yes] , [Measures].[Student ID Distinct Count Hidden])
    – NickNick
    Nov 12 at 10:29
















  • Distinct count is a very problematic measure. I would strongly suggest doing it via the SQL since the measure that you've got in place won't help you. Look here: blog.tallan.com/2017/02/09/…
    – Hila DG
    Nov 12 at 2:24










  • Does this code work for you ? AGGREGATE( [Student Research Degree].[Is Research Degree Current].&[Yes] ,[Student Research Degree].[Is Research Degree Complete].&[Yes] , [Measures].[Student ID Distinct Count Hidden])
    – NickNick
    Nov 12 at 10:29















Distinct count is a very problematic measure. I would strongly suggest doing it via the SQL since the measure that you've got in place won't help you. Look here: blog.tallan.com/2017/02/09/…
– Hila DG
Nov 12 at 2:24




Distinct count is a very problematic measure. I would strongly suggest doing it via the SQL since the measure that you've got in place won't help you. Look here: blog.tallan.com/2017/02/09/…
– Hila DG
Nov 12 at 2:24












Does this code work for you ? AGGREGATE( [Student Research Degree].[Is Research Degree Current].&[Yes] ,[Student Research Degree].[Is Research Degree Complete].&[Yes] , [Measures].[Student ID Distinct Count Hidden])
– NickNick
Nov 12 at 10:29




Does this code work for you ? AGGREGATE( [Student Research Degree].[Is Research Degree Current].&[Yes] ,[Student Research Degree].[Is Research Degree Complete].&[Yes] , [Measures].[Student ID Distinct Count Hidden])
– NickNick
Nov 12 at 10:29












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No, the TUPLE of &[YES], &[YES] doesn't create an OR situation, where I want [NO]s when the other is yes.



I started looking at a subtractive approach where I started with the ALL set, and removed the distinct count of invalid combinations in a tuple and subtracted that from the grand total. This approach did work, but ONLY because the data allowed for it. If a person could have been in multiple combinations, this wouldn't have worked.



I'm currently testing that approach with the rest of the cube. By all appearances this works perfectly, but I will go with ETL if any bugs or mismatches can be proven.






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    1 Answer
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    1 Answer
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    up vote
    0
    down vote













    No, the TUPLE of &[YES], &[YES] doesn't create an OR situation, where I want [NO]s when the other is yes.



    I started looking at a subtractive approach where I started with the ALL set, and removed the distinct count of invalid combinations in a tuple and subtracted that from the grand total. This approach did work, but ONLY because the data allowed for it. If a person could have been in multiple combinations, this wouldn't have worked.



    I'm currently testing that approach with the rest of the cube. By all appearances this works perfectly, but I will go with ETL if any bugs or mismatches can be proven.






    share|improve this answer
























      up vote
      0
      down vote













      No, the TUPLE of &[YES], &[YES] doesn't create an OR situation, where I want [NO]s when the other is yes.



      I started looking at a subtractive approach where I started with the ALL set, and removed the distinct count of invalid combinations in a tuple and subtracted that from the grand total. This approach did work, but ONLY because the data allowed for it. If a person could have been in multiple combinations, this wouldn't have worked.



      I'm currently testing that approach with the rest of the cube. By all appearances this works perfectly, but I will go with ETL if any bugs or mismatches can be proven.






      share|improve this answer






















        up vote
        0
        down vote










        up vote
        0
        down vote









        No, the TUPLE of &[YES], &[YES] doesn't create an OR situation, where I want [NO]s when the other is yes.



        I started looking at a subtractive approach where I started with the ALL set, and removed the distinct count of invalid combinations in a tuple and subtracted that from the grand total. This approach did work, but ONLY because the data allowed for it. If a person could have been in multiple combinations, this wouldn't have worked.



        I'm currently testing that approach with the rest of the cube. By all appearances this works perfectly, but I will go with ETL if any bugs or mismatches can be proven.






        share|improve this answer












        No, the TUPLE of &[YES], &[YES] doesn't create an OR situation, where I want [NO]s when the other is yes.



        I started looking at a subtractive approach where I started with the ALL set, and removed the distinct count of invalid combinations in a tuple and subtracted that from the grand total. This approach did work, but ONLY because the data allowed for it. If a person could have been in multiple combinations, this wouldn't have worked.



        I'm currently testing that approach with the rest of the cube. By all appearances this works perfectly, but I will go with ETL if any bugs or mismatches can be proven.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 at 20:46









        Peppermallow

        387




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